Good evening.
I have this jquery code which allows me, once you press the Enter key, to post a comment.
Fattio that I run an append with the username and the content that the user wants to publish.
In addition to the username I would also like to "hang" the profile picture using their path. How do I post a photo?
Thanks for your help. Here's the code:
function commento_post(id_post)
{
$('.form-commento'+id_post).click(function ()
{
$('#ins_commento'+id_post).keydown(function (e)
{
var message = $("#commento"+id_post).val();
var username = $("#username").val();
var id_user = $("#id_user").val();
if(e.keyCode === 13)
{
$.ajax(
{
type: 'POST',
url: 'http://localhost/laravel/public/index.php/post/ins_commento',
data: { commento: message, id_post: id_post },
success: function(data)
{
$('#commento'+id_post).val('');
$('#commentscontainer'+id_post).append
(
/*$(".username-commento"+id_post).html
(*/
$('<a/>',
{
text : username, href : 'http://localhost/laravel/public/index.php/utente/'+id_user
}).css({'font-weight':'bold'})
//)
).append(' ').append(message).append($('<br/>'));
var el = $('#numero_commenti'+id_post);
var num = parseInt(el.text());
el.text(num + 1);
}
});
}
});
});
}
In your success function, you could simplify everything quite a bit in the following way while not using jQuery append so much, but just using a variable to store your code and then appending it in one go. This will allow you to append all sort of elements, it's easily parseable for the you and it reduces the amount of calls you have to make.
// Add whatever you want your final HTML to look like to this variable
var html = "<a href='http://localhost/laravel/public/index.php/utente/" + id_user + "' style='font-weight: bold;'>" + username + "</a>";
html += message;
// add an image
html += "<img src='path/to/image.jpg' />"
html += "<br />";
// append to code you constructed above in one go
$('#commentscontainer' + id_post).append(html);
Update
I amended an incorrect quote and changed + id_user + "to + id_user + "', which makes everything after it work.
Related
I use jQuery ajax to read context on my page dynamicly. But part of DOM is load in javaScript function call by getScript in ajax .done. But just after I load new content I need to get elements by class and use it in next function. Unfortunatly I can't find elements, that I create in javaScript function, and script with that function I call using jQuery getScript.
ok, my code:
$(document).ready(function() {
$('.link').click(function(){
var subpage = $(this).attr('data-subpage');
var src = 'subpages/'+ subpage + '/' + subpage +'.php';
var script = 'subpages/'+ subpage + '/js/' + subpage +'.js';
$.ajax({
url: src,
context: document.body,
dataType: 'html',
success: function(responseText){
$('#text').html(responseText); // responseText has only container <div id="insideText"></div> that I use in one function and load there by html() several divs. One of this div has class 'translate'. I need it in function Translator
}
})
.done(function(){
$.getScript(script); // here I call script where I load several divs to #insideText
Translator($('.active').attr('data-lang')).getTranslation() // part of function have to find all div.translate, but can't find it if they're load in script call in getScript. And this is a problem.
})
})
})
I hope, I explaine my problem quite clear. If not, plaese ask, I'll try again.
There's some way to do that?
//update//
After this script, call by getScript I still have problem with second 'done':
const Presenter = function(){
var presented, show, fullDesc, cont;
presented = [
{
url: 'demo/colorsGame/',
name: 'Graj w kolorki!',
desc: 'Graj w kolorki! Wybierz taki sam kolor, w jakim napisana jest nazwa wylosowanego koloru. Spiesz się, czas ucieka coraz szybciej i szybciej. Uważaj, bo mózg może cię oszukać i uznać za ważniejsze to, co jest napisane, a nie to co widzisz. Zobacz ile punktów jesteś w stanie zdobyć zanim popełnisz trzy błędy. Ćwicz swoją koncentrację.'
},
{
url: 'demo/sampleUserProfile/',
name: 'Sample User Profil',
desc: 'Mała próbka możliwości reactJS. Wkonany z użyciem biblioteki reactJS, menadzera pakietów webpack oraz na środowisku nodeJS przykładowy profil użytkownika. Like-uj i obserwuj do woli, a jeśli chcesz, wypowiedz się pod profilem.'
}
];
show = function(url, desc, name) {
fullDesc =
"<a href ='" + url + "'>" +
"<h1 class='translate'>" + name + "</h1>" +
"</a>" +
"<div>" +
"<p class='translate'>" + desc + "</p>" +
"</div>";
cont =
"<div id='webmin' class='clearfix'>" +
"<div>" +
fullDesc +
"</div>" +
"<div>" +
"<iframe src='" + url + "' scrolling='no'>" +
"ups, twoja przeglądarka nie obsługuje ramek" +
"</iframe>" +
"</div>"+
"</div>";
return cont;
};
return {
show: show,
presented: presented
}
};
display = function(){
var len, url, name, desc;
len = Presenter().presented.length;
for(let i = 0; i <= len; i++){
url = Presenter().presented[i].url;
name = Presenter().presented[i].name;
desc = Presenter().presented[i].desc;
$('#insidetext.apps').append(Presenter().show(url, desc, name));
}
};
display();
Hmm, I'm wondering, if iframe is not a problem here? And don't let script to be done to end?
getScript is just another ajax call and returns an xhr object which exposes done and fail methods. Use those methods to ensure your dom is properly loaded before trying to access it.
$(document).ready(function() {
$('.link').click(function(){
var subpage = $(this).attr('data-subpage');
var src = 'subpages/'+ subpage + '/' + subpage +'.php';
var script = 'subpages/'+ subpage + '/js/' + subpage +'.js';
$.ajax({
url: src,
context: document.body,
dataType: 'html'
})
.done(function(responseText){
$('#text').html(responseText);
$.getScript(script).done(function() {
Translator($('.active').attr('data-lang')).getTranslation() ;
}
})
})
})
Also, you should implement the .fail methods, in case your ajax requests fail.
I'm kinda new to php + javascript.
I have set up "cute file browser" to look at a shared folder on my computer.
it works fine displays all files & folders no problem.
Now im trying to use OMDB to search for movie posters and then display them for each movie name.
Currently it works but only with the first movie title. when inspecting the element in FF it does show all the other posters but only within the first
This is the code i made for the OMDB...
var filmName;
var realName;
filmName = finfo;
realName = filmName.split('.')[0];
var omdbUrl = "http://www.omdbapi.com/?t=" + realName;
$.ajax({
url: omdbUrl,
//force to handle it as text
dataType: "text",
success: function(data) {
//data downloaded so we call parseJSON function
//and pass downloaded data
var json = $.parseJSON(data);
//now json variable contains data in json format
//let's display a few items
document.getElementById("folders").innerHTML += "<img id='imgposter' class='imgPoster' src='" + json.Poster + "'></img>";
}
});
And this is the code for displaying my movie folders:
if(scannedFolders.length) {
scannedFolders.forEach(function(f) {
var itemsLength = f.items.length,
name = escapeHTML(f.name);
if(itemsLength) {
icon = '<span class="icon folder full"></span>';
}
if(itemsLength == 1) {
itemsLength += ' item';
}
else if(itemsLength > 1) {
itemsLength += ' items';
getPoster(name);
}
else {
itemsLength = 'Empty';
}
var folder = $('<li id="folders" class="folders"><span class="name">' + name + '</span> </li>');
folder.appendTo(fileList);
});
}
This is the error i get
As i said i am new here. if anyone could give me any tips would be great thanks
I'm trying to get all facebook comments with profile pictures of commentators through fb.api() call. Currently all comments gets outputed i just can't get profile pictures to append to appropriate comment.
In for loop which loops through all comments is another FB.api call which gets the profile pic of user who commented on video and than append them into single comment block. With this code i get profile pictures of all users who commented in every single comment.
What am i doing wrong?? Thank you in advance!
var komentarji_length = response.comments.data.length;
for (var i = 0; i < komentarji_length; i++) {
var user_id = response.comments.data[i].from.id;
FB.api("/" + user_id + "/picture", {
access_token: access_token
}, function (response) {
var profile_pic_link = response.data.url;
$(".comments_profile_pic" + i).append("<img src=" + comments_profile_pic_link + ">");
});
var ime = response.comments.data[i].from.name;
var message = response.comments.data[i].message;
$(".fb_comments").append('<div class="single_comment"><div class="comments_profile_pic' + i + '"></div><div class="name">' + name + '  says:</div><div class="single_message">' + message + '</div></div>');
}
Issue 1: comments_profile_pic_link is not defined, the variable is: profile_pic_link.
But then also the problem will not be solved. When you call "/" + user_id + "/picture" it is redirected to the image url automatically. So you can directly use the image url as: https://graph.facebook.com/{user-id}/picture. No need to make the API call unnecessarily.
Example
Still if you wish to get the proper image url (not required though), use redirect=0 with your call-
FB.api("/" + user_id + "/picture?redirect=0", {
access_token: access_token
}, function (response) {
var profile_pic_link = response.data.url;
$(".comments_profile_pic" + i).append("<img src=" + comments_profile_pic_link + ">");
});
My below code working well but i need to import XML data from xml URL not from HTML file like this
if i need to retrieve image from XML how i can do that.
var xml = "<shows><show><date>9/8</date><place>Toads Place</place><location>New Haven, CT</location><time>9PM</time></show></shows>"
$(document).ready(function(){
//$('#table').append('<h2>SHOWS</h2>');
$('#table').append('<table id="show_table">');
$(xml).find('show').each(function(){
var $show = $(this);
var date = $show.find('date').text();
var place = $show.find('place').text();
var location = $show.find('location').text();
var time = $show.find('time').text();
var html = '<tr><td class="bold">' + date + '</td><td class="hide">' + place + '</td><td>' + location + '</td><td class="bold">' + time + '</td></tr>';
$('#show_table').append(html);
});
//alert($('#show_table').html());
})
all what i need is change this var xml = "9/8 ... " to let the JQuery code read from the ONLINE URL
If you need to load XML data from the URL, you need to execute AJAX request, it may be something like this:
$(function() {
$.ajax({
type: "get",
url: "http://yoursite.com/yourfile.xml",
dataType: "xml",
success: function(data) {
/* handle data here */
$("#show_table").html(data);
},
error: function(xhr, status) {
/* handle error here */
$("#show_table").html(status);
}
});
});
Keep in mind, if you use AJAX you can place .xml file on the same domain name. In other case you need to set up cross-origin resource sharing (CORS).
EDITED:
I modified your code, now it appends td element to your table. But xml is still inside html.
var xml = "<shows><show><date>9/8</date><place>Toads Place</place><location>New Haven, CT</location><time>9PM</time></show></shows>"
$(function() {
$(xml).find('show').each(function() {
console.log(this);
var $show = $(this);
var date = $show.find('date').text();
var place = $show.find('place').text();
var location = $show.find('location').text();
var time = $show.find('time').text();
var html = '<tr><td class="bold">' + date + '</td><td class="hide">' + place + '</td><td>' + location + '</td><td class="bold">' + time + '</td></tr>';
$('#show_table').append($(html));
});
});
But you need to modify your html file, check my solution here: http://jsfiddle.net/a4m73/
EDITED: full solution with loading xml from URL
I combined two parts described above, check here: http://jsfiddle.net/a4m73/1/
Use jquery-xpath, then you can easily do what you want like:
$(xml).xpath("//shows/show");
if you want know more about xpath just take a look on XML Path Language (XPath) document.
var xml = "<shows><show><date>9/8</date><place>Toads Place</place><location>New Haven, CT</location><time>9PM</time></show></shows>";
$(document).ready(function () {
//$('#table').append('<h2>SHOWS</h2>');
$('#table').append('<table id="show_table">');
$(xml).xpath("//shows/show").each(function () {
var $show = $(this);
var date = $show.find('date').text();
var place = $show.find('place').text();
var location = $show.find('location').text();
var time = $show.find('time').text();
var html = '<tr><td class="bold">' + date + '</td><td class="hide">' + place + '</td><td>' + location + '</td><td class="bold">' + time + '</td></tr>';
$('#show_table').append(html);
});
})
I am attempting to access Google Books in order to an ISBN Code to get details of a book, I have a number of problem, which are:
A) I am trying to assemble a script request e.g. with the ISBN code concatenated into the URL. I have not managed to do this successfully - and I don't know why.
B) I then want to update a div in the DOM with this generated script dynamically, such that it will then execute.
C) I am finding it a bit of a puzzle as to the format of the returned data and the argument name of the function call contained in the Google response.
Has anyone else encountered the same problem and can offer guidance re A thru C above.
I enclose JavaScript code below.
$(document).ready(function() {
$('#viewbook-button').live('click', function() {
isbnCode = this.text;
alert("ISBN is : " + isbnCode + " " + this.text + " as well");
alert("Getting JSONP Google Books data");
isbnCode = "0451526538";
JSONPstr = '<' + 'script ' + 'src="' + 'https://www.googleapis.com/books/v1/volumes?q=ISBN' + isbnCode;
JSONPstr = JSONPstr + '&callback=handleJSONPResponse">' + '</script>';
alert("un-Escaped JSONP string" + JSONPstr);
escJSONPstr = escape( escJSONPstr );
alert("Escaped JSONP string");
//divstr = "";
//divstr = divstr + escape(<script src=");
//divstr = divstr + encodeURIComponent(https://www.googleapis.com/books/v1/volumes?q=ISBN);
//divstr = divstr + escape(isbnCode);
//divstr = divstr + encodeURIComponent(&callback=handleJSONPResponse);
//divstr = divstr + escape("></);
//divstr = divstr + escape(script);
//divstr = divstr + escape(>);
$('#jsonp-call').html(escJSONPstr);
// This will cause the handleJSONPResponse function to execute when the script is dynamically loadedinto div.
// The data wrapped in a function call will be returned from the Google Books server.
// This will cause the handleJSONPResponse function to execute below.
}); // end viewbook-button
}); // end document.ready
function handleJSONPResponse(response) {
var tmp = response;
alert(tmp);
};
</script>
</head>
<body>
<h2>Show Details of Books Ordered by a Customer</h2>
Get Customer Details
<br/><br/>
<div id="tablist">Tables will be Listed Here</div>
<br/><br/>
<div id="Google-call">The JSONP generated src= statement will go here and execute</div>
</body>
</html>
EDIT:
Problem solved - thanks everyone.
You're reinventing the wheel: jQuery has built-in JSONP support, so you don't need to faff about implementing it yourself. Use the $.ajax method:
$.ajax({
url: 'https://www.googleapis.com/books/v1/volumes?q=ISBN' + isbnCode,
dataType: 'jsonp',
success: function(response) {
console.log(response); // log the response object to the console
}
});
That should be all you need to do.