Firebase - AngularJS - Get parent by child's value / key / name [duplicate] - javascript

Given the data structure below in firebase, i want to run a query to retrieve the blog 'efg'. I don't know the user id at this point.
{Users :
"1234567": {
name: 'Bob',
blogs: {
'abc':{..},
'zyx':{..}
}
},
"7654321": {
name: 'Frank',
blogs: {
'efg':{..},
'hij':{..}
}
}
}

The Firebase API only allows you to filter children one level deep (or with a known path) with its orderByChild and equalTo methods.
So without modifying/expanding your current data structure that just leaves the option to retrieve all data and filter it client-side:
var ref = firebase.database().ref('Users');
ref.once('value', function(snapshot) {
snapshot.forEach(function(userSnapshot) {
var blogs = userSnapshot.val().blogs;
var daBlog = blogs['efg'];
});
});
This is of course highly inefficient and won't scale when you have a non-trivial number of users/blogs.
So the common solution to that is to a so-called index to your tree that maps the key that you are looking for to the path where it resides:
{Blogs:
"abc": "1234567",
"zyx": "1234567",
"efg": "7654321",
"hij": "7654321"
}
Then you can quickly access the blog using:
var ref = firebase.database().ref();
ref.child('Blogs/efg').once('value', function(snapshot) {
var user = snapshot.val();
ref.child('Blogs/'+user+'/blogs').once('value', function(blogSnapshot) {
var daBlog = blogSnapshot.val();
});
});
You might also want to reconsider if you can restructure your data to better fit your use-case and Firebase's limitations. They have some good documentation on structuring your data, but the most important one for people new to NoSQL/hierarchical databases seems to be "avoid building nests".
Also see my answer on Firebase query if child of child contains a value for a good example. I'd also recommend reading about many-to-many relationships in Firebase, and this article on general NoSQL data modeling.

Given your current data structure you can retrieve the User that contains the blog post you are looking for.
const db = firebase.database()
const usersRef = db.ref('users')
const query = usersRef.orderByChild('blogs/efg').limitToLast(1)
query.once('value').then((ss) => {
console.log(ss.val()) //=> { '7654321': { blogs: {...}}}
})
You need to use limitToLast since Objects are sorted last when using orderByChild docs.

It's actually super easy - just use foreslash:
db.ref('Users').child("userid/name")
db.ref('Users').child("userid/blogs")
db.ref('Users').child("userid/blogs/abc")
No need of loops or anything more.

Related

How to push an array value in Firebase Firestore

I am trying to push an array element but am destroying all the content there and replacing with the pushed data:
db .collection('households')
.doc(householdId)
.set( { users: [uid], }, { merge: true }, )
.then(() => { resolve(); })
.catch(() => reject());
I thought the merge true doesn't destroy the data that is already there? Struggling a little with the firestore api docs.
This is the structure of my data:
households
2435djgnfk
users [
0: user1
1: user2
]
Thank you!
You should use Firestore Transaction for this.
const householdRef = db.collection('households').doc(householdId);
const newUid = '1234'; // whatever the uid is...
return db.runTransaction((t) => {
return t.get(householdRef).then((doc) => {
// doc doesn't exist; can't update
if (!doc.exists) return;
// update the users array after getting it from Firestore.
const newUserArray = doc.get('users').push(newUid);
t.set(householdRef, { users: newUserArray }, { merge: true });
});
}).catch(console.log);
Updating an array or a stored object without getting it first will always destroy the older values inside that array/object in firestore.
This is because they are fields and not actual document themselves. So, you have to first get the document and then update the value after that.
I think now you can do it better with the update command on document by using FieldValue.arrayUnion without destroying data that was added meanwhile. Like this:
const admin = require('firebase-admin');
let db = admin.firestore();
const FieldValue = admin.firestore.FieldValue;
let collectionRef = db.collection(collection);
let ref = collectionRef.doc(id);
let setWithOptions = ref.update(arrayFieldName, FieldValue.arrayUnion(value));
As described in https://firebase.googleblog.com/2018/08/better-arrays-in-cloud-firestore.html
Arrays in Firestore don't work like this. According to the documentation:
Although Cloud Firestore can store arrays, it does not support querying array members or updating single array elements.
If you want to change any element in an array, you have to read the array values from the document first, make changes to it in the client, then write the entire array back out.
There are probably other ways to model your data that are better for your use case. That page of documentation linked above has some solutions.

Firestore - get specific fields from document

What I need:
I want to save articles or notes in Firestore with their respective fields:
Title
Content (texts or paragraphs)
Creation date
Owners (to share that article with other
people and who can edit them like: https://firebase.google.com/docs/firestore/solutions/role-based-access)
But when I show the list of articles I don't need the "content" field (to save bandwidth). I've read that (maybe I'm wrong), it is not possible to make a query to get only specific fields from a document with Firestore.
If it were normal SQL to obtain specific columns from articles (without its content) It would be something like:
SELECT title, creation_date, ...
FROM table_name;
So I've opted to separate the content for two root-level collections (for flexibility and scalability)
My current structure:
Articles collection:
- `articles` [collection]
- `ARTICLE_ID` [document]
- `creatorId` [field]
- `title` [field]
- `date` [field]
- `owners` [obj field]
- {user1_id}: true
- {user2_id}: true
...
Contents collection:
- `contents` [collection]
- `{ARTICLE_ID}` [document]
- `content` [field]
To get articles list in realtime:
firebase.firestore().collection('articles')
.where(`owners.${user.uid}`, '==', true)
.onSnapshot(querySnapshot => {
const articles = []
querySnapshot.forEach((doc) => {
articles.push({
id: doc.id,
...doc.data()
})
})
// do something with articles array
})
To show in another view and get the entire article with its content:
const db = firebase.firestore()
const articleRef = db.collection('articles').doc(articleId)
const contentRef = db.collection('contents').doc(articleId) // same Id as article
articleRef.get().then(articleDoc => {
if (articleDoc.exists) {
contentRef.get().then(contentDoc => {
if (contentDoc.exists) {
const article = {
...articleDoc.data(),
...contentDoc.data()
}
// full article obj
}
})
}
})
My questions
Do you think it's better to do two queries (getArticle and getContent) at the same time and wait with Promise.all() instead of nesting the querys like I do?
Is there a better way to get the article and its content with one query or more efficiently? Some tips or ideas?
Thank you very much in advance!
According to the Firestore Query.select documentation you should be able to select the fields you want.
let collectionRef = firestore.collection('col');
let documentRef = collectionRef.doc('doc');
return documentRef.set({x:10, y:5}).then(() => {
return collectionRef.where('x', '>', 5).select('y').get();
}).then((res) => {
console.log(`y is ${res.docs[0].get('y')}.`);
});
Neither approach is pertinently better than the other. But there are a few key differences.
When you nest the reads, the second read only starts after the first read has completed. When you use Promise.all() both reads start at the same time, so can (partially) run in parallel.
On the other hand: when you use Promise.all() your completion handler (the code you run in then()) won't execute until both documents have loaded. If you nest the calls, you can update the UI after just the first document has loaded.
In the end, the differences are likely to be small. But since they may be significant to your use-case, measure the results and see what works best for you.
In order to output a single field from a Firestore document (version 9) - for example the 'title' in the articles collection you can use the following code snippet:
const q = query(collection(db, 'articles'))
let results = [];
await getDocs(q);
results = getLocation.docs.map((doc) => doc.data()['title']);
results.sort()
The results array will contain only the title field, sorted alphabetically
(Note you have to reference the Firestore db and import 'getDocs', 'query' and 'collection' modules from Firestore)
Firebase Hosting would be your best bet for static content such as articles. If you look at AMP-HTML for example, they strongly make the case for ultra-fast page loads and highlight benefits of edge caching. Firebase hosting is advertised to also support global edge caching.
Firestore and Firebase Realtime Database are database engines. These are not the proper tool for serving up articles.

Match value of array from database object in Firebase Cloud Functions

This is my first app project using Google Cloud Functions & Firebase. I'm trying to find away to get a single value of the array that I'm returning and compare it to a set variable and if it matches, update another child's value in that same account.
My App users can add records to the database under their login/user_id that is stored in the database. I'm trying to get a list of the "RecordName" that is a child under that login/user_id that every user has stored in their account.
So basically every "RecordName" in the entire database. When I want to run specials for those records, I need to match the name of that record to the name of the record I have on special and if there is a match, update another child value under that user's account ("special" = true.). This way, when they load their app next time, I have it highlighting that record so they know it's on special.
When I use..
const ref = admin.database().ref(`/store`);
...with the following code...
ref.on('value', function(snapshot) {
// puts ALL items of the object into array using function ..
console.log(snapshotToArray(snapshot));
});
... and the function...
function snapshotToArray(snapshot) {
var returnArr = [];
snapshot.forEach(function(childSnapshot) {
var item = childSnapshot.val();
item.key = childSnapshot.key;
returnArr.push(item);
});
return returnArr;
};
... I get the entire array just as it is in the database:
-store
-{ones_users_id}
-recordname: value1
-special: false
-{anothers_users_id}
-recordname: value2
-special: false
ect. ect.
If my record on special is called, "Newbie Record", what would be the best way to take out every individual value for the key: "recordname" from the array, compare each one to var = "Newbie Record" and if they match, update the value of the key: "special" to be true?
I'm new to JSON and NodeJS, I've been searching on here for answers and can't find exactly what I'm looking for. Your feedback would be very helpful.
It sounds like you're looking to query your database for nodes that have "recordname": "Newbie Record" and update them.
An easy way to do this:
const ref = admin.database().ref(`/store`);
const query = ref.orderByChild("recordname").equalTo("Newbie Record");
query.once('value', function(snapshot) {
snapshot.forEach(function(child) {
child.ref.update({ special: true })
});
});
Main differences with your code:
We now use a query to read just the nodes that we want to modify.
We now use once() to read the data only once.
We loop over the children of the snapshot, since a query may result in multiple nodes.
We use the reference of each child and then update its special property.
I recommend reading a bit more about Firebase queries in the documentation.

firebase database store list of items

HERE IS MY CODE
//1. Add menu items to the globalMenu and to restaurant, and the restaurantId of the restaurant adding menu.
this.writeNewMenuItem = function(itemName, restaurantId) {
// A post entry.
var menuItem = {
itemName: [itemName]
};
var ref = firebase.database().ref();
// Get a key for a new Post.
var newItem = ref
.child('globalMenu')
.push(menuItem);
ref
.child('restaurants')
.child(restaurantId)
//.child(newItem.key)
.update(menuItem);
}
Also let me know the way we can push and pop these items.
and if duplicate found this should not insert.
I want to fetch matched characters items, like if I pass 'app' in query this should return 'apple, application, appengine' etc. How could I do this?
You should try to avoid "arrays" in a Firebase Database, because:
... for distributed data, they aren't reliable because they lack a unique, permanent way to access each record.
https://firebase.googleblog.com/2014/04/best-practices-arrays-in-firebase.html
Regarding your third question: querying the the database this way is not possible, you need to receive the whole list of all child nodes and do the filtering on the client side. I could recommend reading best practices for structuring the data: https://firebase.google.com/docs/database/admin/structure-data

Firebase - How do I get all objects where companyUid equals companyUid [duplicate]

Given the data structure below in firebase, i want to run a query to retrieve the blog 'efg'. I don't know the user id at this point.
{Users :
"1234567": {
name: 'Bob',
blogs: {
'abc':{..},
'zyx':{..}
}
},
"7654321": {
name: 'Frank',
blogs: {
'efg':{..},
'hij':{..}
}
}
}
The Firebase API only allows you to filter children one level deep (or with a known path) with its orderByChild and equalTo methods.
So without modifying/expanding your current data structure that just leaves the option to retrieve all data and filter it client-side:
var ref = firebase.database().ref('Users');
ref.once('value', function(snapshot) {
snapshot.forEach(function(userSnapshot) {
var blogs = userSnapshot.val().blogs;
var daBlog = blogs['efg'];
});
});
This is of course highly inefficient and won't scale when you have a non-trivial number of users/blogs.
So the common solution to that is to a so-called index to your tree that maps the key that you are looking for to the path where it resides:
{Blogs:
"abc": "1234567",
"zyx": "1234567",
"efg": "7654321",
"hij": "7654321"
}
Then you can quickly access the blog using:
var ref = firebase.database().ref();
ref.child('Blogs/efg').once('value', function(snapshot) {
var user = snapshot.val();
ref.child('Blogs/'+user+'/blogs').once('value', function(blogSnapshot) {
var daBlog = blogSnapshot.val();
});
});
You might also want to reconsider if you can restructure your data to better fit your use-case and Firebase's limitations. They have some good documentation on structuring your data, but the most important one for people new to NoSQL/hierarchical databases seems to be "avoid building nests".
Also see my answer on Firebase query if child of child contains a value for a good example. I'd also recommend reading about many-to-many relationships in Firebase, and this article on general NoSQL data modeling.
Given your current data structure you can retrieve the User that contains the blog post you are looking for.
const db = firebase.database()
const usersRef = db.ref('users')
const query = usersRef.orderByChild('blogs/efg').limitToLast(1)
query.once('value').then((ss) => {
console.log(ss.val()) //=> { '7654321': { blogs: {...}}}
})
You need to use limitToLast since Objects are sorted last when using orderByChild docs.
It's actually super easy - just use foreslash:
db.ref('Users').child("userid/name")
db.ref('Users').child("userid/blogs")
db.ref('Users').child("userid/blogs/abc")
No need of loops or anything more.

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