Changing script from request to axios - log pending promise - javascript

I'd like some help please as I'm quite new in node.js and working with node packages.
I'm having the following script which makes a GET http request running on node using request which is deprecated now
const foo = (bar, callback) => {
const url = 'https://some.api.com?key=abc123';
request({url: url, json: true}, (error, response) => {
if (error) {
callback('Oops, there is an error!', undefined);
} else if(response.body.foobarArray.length === 0) {
callback('No data found', undefined);
} else {
callback(undefined, {
foobar1: response.body.foobar1,
foobar2: response.body.foobar2,
})
}
});
}
console.log(foo('Hello')); // this logs {foobar1: 'Hello', foobar2: 'World'}
I'm trying to rewrite it using axios instead, so this is my code
const foo = async (bar) => {
const url = 'https://some.api.com?key=abc123';
try {
const response = await axios.get(url);
if (response.body.foobarArray.length === 0) {
return 'No data found';
} else {
return {
foobar1: response.body.foobar1,
foobar2: response.body.foobar2,
};
}
} catch (error) {
return 'Ooops! Something went wrong :(';
}
};
console.log(foo('Hello')); // This logs `Promise { <pending> }`
I'm not sure what I'm doing wrong here as I'm not very familiar how promises work exactly, but how can I fix this?

const foo = async (bar) => {
const url = 'https://some.api.com?key=abc123';
try {
return await axios.get(url).then(response => {
return new Promise((resolve, reject) => {
if (response.body.foobarArray.length === 0) {
return reject('No data found');
} else {
return resolve({
foobar1: response.body.foobar1,
foobar2: response.body.foobar2,
});
}
})
}).catch(err => {
return Promise.reject(err);
});
} catch (error) {
// return 'Ooops! Something went wrong :(';
return Promise.reject(`an error occurred : ${error}`);
}
};
foo('hello').then(result => {
console.log(result);
}).catch(err => {
console.log(`error ! : ${err}`);
});
async functions returns a promise. async functions use an implicit Promise to return its result. Even if you don't return a promise explicitly async function makes sure that your code is passed through a promise
as you are using axios asynchronous , it's response is a promise which must be handled inside .then().catch() functions .
if no error occurs you can access the response inside your .then() , else you will have access to your error on .catch()
inside your .then() you can now do what you want with data , returning a new Promise , using resolve() for success and reject() for failure .

You have 2 options here:
Option 1
Any async function returns a Promise (behind the scenes) so:
foo('Hello').then(console.log).error(console.error);
Option 2
You need to await for the result of foo function but, at the moment, you can't use await out of function scope level. So:
async function main() {
try {
const result = await foo('Hello');
console.log(result);
} catch (err) {
console.error(err);
}
}
main();
In future Node.js releases, using await at global scope will be allowed.

Related

How to wait for a function, which contains promises

If we have this function
const getData = () => {
foo()
.then(result => {
return result;
})
.catch(error => {
return error;
});
};
Although getData is not a promise itself, but it contains a promise, which is asyncrnous.
So what is the best way to wait for getData to return something. Async / Await doesn't work cause they work with promises.
Thanks.
Currently, getData() doesn't return anything. You need to make it return a Promise, so you can await it or chain .then() to it.
const getData = () => {
return foo() // <-- here
.then(result => {
return result;
})
.catch(error => {
throw error;
});
};
// Now you can do :
getData().then(...)
// or :
const data = await getData();
In this case, you can also omit the curly braces and the explicit return, and make it implicit :
const getData = () => foo()
.then(result => {
return result;
})
.catch(error => {
throw error;
});
Hey but what's that :
.then(result => {
return result;
})
This does nothing. It takes a value and simply returns it without doing anything. You can remove it.
You can now rewrite getData() this way :
const getData = async () => {
try {
return await foo()
} catch (error) {
throw error;
}
}
For that matter, this :
.catch(error => { throw error; });
or this :
catch (error) { throw error; }
are also pretty useless, they just "relay" (bubble up) the error that has to be caught in the calling function.
Now it's obvious getData does pretty much only one thing, it's returning foo(), which is a Promise. It's only a wrapper around a Promise... so it's actually pretty useless.
Bottom line, detData() is useless altogether. foo is a Promise; writing a function that returns a Promise so you can use it like a Promise is just... a Promise with an extra step. Just use foo directly.
let result;
try {
result = await foo();
} catch (error) {
console.log(error);
}
console.log(result);
This will not work because getData is not returning a value. You can add a return statement before foo call and wait for the return value.
const getData = () => {
return foo();
};
getData().then(data => {
console.log(data);
}).catch(err => {
console.log(err);
});
To wait for an operation you must return a Promise or use a callback. The code snippet below runs and should illustrate how this works. I implemented a sample foo function that is actually asynchronous (wait for 1 second before returning the data '12345'). I used async/await to illustrate how that can work, but you can equally return the result of foo and use then instead.
const foo = () => {
return new Promise(resolve => {
setTimeout(() => resolve('12345'), 1000);
});
}
const getData = async () => {
const data = await foo();
console.log(`Data is ${data}`);
return data;
};
getData()
.then(() => console.log('complete'))
.catch(err => console.log(`oops: ${err}`));
console.log('this prints first since async operation is still pending');

How to properly handle reject in Promises

We have this function in our code that is used to log in a user
const userLogin = loginData => {
return new Promise(async (resolve, reject) => {
try {
const res = await auth.post("/login", loginData);
resolve(res);
} catch (error) {
reject(error);
}
});
};
// Calling function
const loginSubmit = async values => {
try {
const res = await userLogin(values);
console.info(res);
} catch (error) {
console.error("Catch: ", error);
}
};
But from this stackoverflow answer, try-catch blocks are redundant in Promises. I wanted to try and clean this code, so I changed the code above into:
const userLogin = loginData => {
return new Promise(async (resolve, reject) => {
const res = await auth.post("/login", loginData);
if (res.status !== 201) {
reject(new Error("Error"));
}
resolve(res);
});
};
However, when I tried to login with incorrect credentials, the console logs an Uncaught (in promise) Error: Request failed with status code 400
I'm not really familiar with creating my own promises, so I don't know how to do this properly.
Couple of problems in your code:
You are unnecessarily creating a promise; auth.post(..) already returns a promise, so you don't need to create a promise yourself and wrap auth.post(...) inside a promise constructor.
Another problem in your code is that executor function (function passed to the promise constructor) is marked as async; it should not be an async function.
Your function could be re-written as:
const userLogin = async (loginData) => {
const res = await auth.post("/login", loginData);
if (res.status !== 201) {
throw new Error("Error"));
}
return res;
};
You could also re-write your function as:
const userLogin = async (loginData) => {
return auth.post("/login", loginData);
};
Don't forget to use the catch in the code that calls this function.
You might want to read the following article to understand whether you need the try-catch block: await vs return vs return await
I think that in your case since you call to async function inside the constructor of the promise you need to use try catch.
The answer you referred is correct as long as the error happened while you are in the constructor (i.e. the Promise object is in the making), however in your case the rejection of the auth function happens long after the Promise was constructed and therefore it is not rejecting it.
BTW - You don't have to await in the promise. You may do the following:
const userLogin = loginData => {
return new Promise(async (resolve, reject) => {
const prom = auth.post("/login", loginData)
.then((res) => {
if (res.status !== 201) {
reject(new Error("Error"));
}
resolve(res);
});
resolve(prom);
});
};
Since you resolve the async auth call, any rejection by the auth call will be reflect as a rejection from you function

Confusion around 'nested' try/catch statements in Javascript

Essentially I have an async function containing a try/catch that calls another async function also containing a try catch, and I'm getting a bit confused about how to properly implement what I'm doing. Some "pseudocode" showing my current implementation:
const main = async () => {
try {
const test = await secondFunc();
console.log(test);
} catch(err) {
console.log('Found an error!');
console.log(err);
}
const secondFunc = async () => {
try {
await performSomeRequestExample();
} catch(err) {
if (err.x === 'x') {
doSomething();
} else {
//********
throw err;
//********
}
}
So what I'm trying to do is get the throw(err) (surrounded by the asterisks) to be caught by the catch in main() which will also call the console.log('Found an error!'), but what currently happens is the error is thrown from secondFunc(), the catch in main() is never hit and I get an unhandled promise rejection.
Any guidance on what I'm doing wrong?
My advice is to minimize using try/catch unless absolutely necessary. With async functions (or any functions that return a Promise object) you can usually simplify things by not worrying about try/catch blocks unless you need to do something specific with certain errors. You can also use .catch rather than try/catch blocks to make things easier to read.
For example your code above could be written like this:
const main = async () => {
const test = await secondFunc().catch(err => {
console.log("Found an error from secondFunc!", err);
throw err; // if you want to send it along to main's caller
});
if (test) {
console.log("Test", test);
}
};
const secondFunc = () => {
return performSomeRequestExample().catch(err => {
if (err.x === "x") {
doSomething();
} else {
throw err;
}
});
};
const performSomeRequestExample = () => Promise.reject("bad");
main().then(
() => console.log("worked"),
err => console.log("failed from main", err)
);
In secondFunc we don't need to use async since we can just return the promise coming back from performSomeRequestExample and handle any failures in the .catch.
You should use
const secondFunc = async () => {
performSomeRequestExample().then(res =>{
console.log(res);
})
.catch(err => {
console.log(err);
}
)
Add a return before the await of performSomeRequestExample.
const secondFunc = async () => {
try {
return await performSomeRequestExample();
} catch (err) {
if (err.x === 'x') {
console.log('x');
} else {
throw err;
}
}
}
or you can also use .catch() after the awaited function.
Another solution can be like this
const main = async() => {
try {
const test = await secondFunc();
console.log(test);
} catch(err) {
console.log('Found an error!');
console.log(err);
}
}
const secondFunc = async () => {
//return await performSomeRequestExample(); //for success
return await performSomeRequestExample(2); //for error
}
const performSomeRequestExample = async(abc=1) => {
return new Promise(function(resolve,reject){
if(abc ==1){
setInterval(resolve("yes"),400);
}else{
setInterval(reject("opps"),400);
}
});
}
main();
Test this code at this link:
https://repl.it/repls/JoyfulSomberTelevision

how to handle new Error() in node.js using ES6 Symbol?

I am creating a endpoint in node.js using ES6 Symbol. Example
// ES6 Symbol Method
const taskCreationMethod = {
[Symbol.taskMethod]() {
return {
storeCheckFunc: async function(storeId, employeeId) {
let store = await resourceModel["stores"].findById(storeId).populate(references["stores"]);
if(!store) {
return new Error("Store not found");
}
let employeeCheck = _.find(store.employees, (empObj) => {
return empObj._id == employeeId
})
if(!employeeCheck) {
return new Error("Employee not found");
}
return employeeCheck;
}
};
}
}
//end point
export const taskCreation = async(req, res) => {
const storeCheck = await taskCreationMethod[Symbol.taskMethod]().storeCheckFunc(req.body.store, req.body.assigned_to);
// here How can I handle return with Error Response?
}
You need to throw that error not just return it if you want to use the mechanisms of error handling. The thrown error will become a rejected promise which you can then handle with .catch() directly on the promise or with try/catch if you are using it in an async function. Here's a simplified example:
function populate() {
// always resolves to undefined
return Promise.resolve(undefined)
}
const taskCreationMethod = {
someMethod() {
return {
storeCheckFunc: async function() {
let store = await populate() // always resolves undefined
if (!store) { // so it always fails
throw new Error("Store not found"); // throw error
}
}
};
}
}
// regular promise then().catch()
taskCreationMethod.someMethod().storeCheckFunc()
.then(res => console.log(res))
.catch(err => console.log("Error:", err.message)) // catch
// OR … async function
async function runit() {
try {
let s = await taskCreationMethod.someMethod().storeCheckFunc()
} catch (err) {
console.log("Error:", err.message)
}
}
runit()

Return or skip from catch in async function

I have a async function whose output (resolve/reject) I translate with then/catch.
I want to end the outer function with return but I can only return within catch somehow.
How can I skip/quit/return on the outside of catch or await?
await this.authService.auth(this.oldUser).then( resolve => {
//went in authService and resolve can be used
}).catch( reject => {
//in catch as authService rejected and want to return to outer
//function
return;
})
//Second attempt should only be done if first attempt "resolved"
await this.authService.auth(this.newUser).then( resolve => {
}).catch( reject => {
return;
})
You can have the .then and .catch return something meaningful that distinguishes them, and then test that distinguishing factor. For example:
const result = await this.authService.auth(this.oldUser).then((authorizedUser) => {
// do stuff with authorizedUser
return authorizedUser;
}).catch((err) => {
// handle errors, if needed
return { err };
});
if (result.err) {
// there was en error, return early:
return;
}
// rest of the code that depends on the first request being successful goes here
await this.authService.auth(this.newUser).then(...)
Note that if you're using await, it might make a bit more sense to use try/catch rather than .thens and awaits:
try {
const authorizedUser = await this.authService.auth(this.oldUser)
// do stuff with authorizedUser
// rest of the code that depends on the first request being successful goes here
const newAuthorizedUser = await this.authService.auth(this.newUser);
// do stuff with newAuthorizedUser
} catch(err) {
// handle errors, if needed
return;
}
private async authenticate(oldUser: User) {
try {
await this.authService.auth(this.oldUser).toPromise();
return;
} catch (reject) {
return;
}
}

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