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How does manipulating multiple checkbox selection code work?

I am following ag-grid's official tutorial:
https://www.ag-grid.com/angular-getting-started/?utm_source=ag-grid-readme&utm_medium=repository&utm_campaign=github
I reached the part where I have to manipulate the information regarding the selected checkboxes. However, the documentation is not detailed; It does not explain how the code actually works. Perhaps, this makes sense since it is not their job to explain in detail. However, for someone like me who doesn't have solid experience with working with angular technology and who wants to truly understand how things work, this is troublesome!
In the html file, I have been asked to add this:
<button (click)="getSelectedRows()">Get Selected Rows</button>
And in app.component.ts, I have been asked to add this:
getSelectedRows() {
const selectedNodes = this.agGrid.api.getSelectedNodes();
const selectedData = selectedNodes.map(node => node.data);
const selectedDataStringPresentation = selectedData.map( node => node.make + ' ' + node.model).join(', ');
alert('Selected nodes: ${selectedDataStringPresentation}');
}
If someone could explain what the typescript code is doing exactly, that would be very generous.
Thank you!

I guess agGrid is the service storing your mock values, this simply gets an array of data from somwhere.
selectedData is another array that is created by transforming (transforms the array while providing a new reference, thus not modifying the original array) the selectedNodes array and only selecting the data property of each node.
selectedDataStringPresentation is the same, but this time it provides an array of formatted strings by merging the properties make and model of each object from selectedData.
What you probably fail to grasp is the usage of the ES6 (JavaScript standard) functions that are used here, and especially the map() function.
Here is the official documentation of the map() function for arrays : https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Map
Simply explained, it is a function that iterates over an array, and transforming each object by applying the function declared in the map, returning the results in a new array.
If you take the example of selectedData, you can translate the operation into this :
Loop over each object of selectedNodes, and return only the property data of the current object. Push the results in a new array.
This is especially useful when you want to work on different arrays that serve different purposes. For example, imagine you have a service that contains a list of objects. A backend service will provide you an array of numbers representing the IDs of the objects you have in your service.
You can then use the map() function to transform the array of IDs into an array of your Objects stored in your service easily.

Darn #Alex Beugnet(upvote) beat me to the punch! I'm going to post anyway as I was in the middle of writing it all.
Firstly I'm not sure how much of TypeScript you already know, I apologize if much of these becomes trivial, the purpose is only to ensure maximum clarification to the question in understanding the logic.
In the Enable Selection portion of the guide, you are essentially enabling multiple row selection in the grid and having the button return the data from those selected rows.
In order to see what's happening with the getMultipleRows() function, it would be best to visualize it via the Debugger provided in browsers, I'm using Chrome Developer Tools (hit F12), I would highly recommend it for understanding what is happening in the logic.
const selectedNodes
Let's start by selecting say 2 rows, I have selected the Porsche Boxster 72000 and Ford Mondeo 32000. After selecting them I click on the 'Get Selected Rows' button which triggers the getSelectedRows() function:
const selectedNodes = this.agGrid.api.getSelectedNodes();
The above line is assigning the constant variable 'selectedNodes' the RowNodes from AgGrid. Here you are using the AgGridNg2 method getSelectedNodes() to return the selected node data, which you would be returned an array in the form of:
[RowNode, RowNode] //(each for the row we have selected)
Looking into a RowNode we get:
These are all the RowNode properties provided by the AgGrid framework, you can ignore all of these object properties as you are only concerned with the 'data' property as you'll see in the next line of code!
const SelectedData
const selectedData = selectedNodes.map(node => node.data);
Here we are setting 'selectedData' as an array of RowNode.data, basically trying to get the data property from the RowNodes into an array.
The above line can basically be assumed as:
let selectedData = [];
for (let i = 0; i <= selectedNodes.length - 1; i++){
selectedData[i] = selectedNodes[i].data;
}
In which we are just trying to get the data property into a new constant variable 'selectedData'. Look at the documentation in order to better understand this: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/map
const selectedData would be returned as:
[
{
make: "Porsche",
model: "Boxster",
price: 72000,
},
{
make: "Ford",
model: "Mondeo",
price: 32000
}
]
const selectedDataStringPresentation
const selectedDataStringPresentation = selectedData.map( node => node.make + ' ' + node.model).join(', ');
We take the selectedData array and concatenate the Make and Model as a single element for the array and adding a comma in the end. We would get "Porsche Boxter, Ford Mondeo".
let selectedData = [
{
make: "Porsche",
model: "Boxster",
price: 72000,
},
{
make: "Ford",
model: "Mondeo",
price: 32000
}
]
let selectedDataStringPresentation = [];
for (let i = 0; i <= selectedData.length - 1; i++){
selectedDataStringPresentation[i] = selectedData[i].make + ' ' + selectedData[i].model;
}
selectedDataStringPresentation = selectedDataStringPresentation.join(', ');
console.log(selectedDataStringPresentation);
alert()
And the last line,
alert('Selected nodes: ${selectedDataStringPresentation}');
You are going to send an alert in the browser that will display the selectedDataStringPresentation array.

Counting a particular word in a string using Zapier code

I use Zapier to automate many of our business functions, which is great, but I got stuck trying to count the number of arrays or, if you like, a particular word pattern that comes from a string. I can tidy up the string with Zapier formatter, but cannot figure out how to carry out a count.
Here is an example of a tidied string where " have been removed:
[{Name:Jon,Surname:Smith},{Name:David,Surname:Michael},{Name:Sam,Surname:Fields},{Name:Katy,Surname:Milnes}]
In this instance I would want the count on say "Name" to return 4.
I have looked at different code examples for counting words but cannot execute them correctly in the code action of Zapier. This is probably really straight forward but I do not come from a coding background so a simple Java (or Python) script to drop into the Zapier code action or some pointers on how to solve this would be greatly appreciated.
Thanks

What are you really trying to achieve by trying to count the word?
Do you just want to know the number of objects the array contains? If that is the case something like this would work. Assuming that the array is in your inputData for the code step.
var data = JSON.stringify([{'Name':'Jon', 'Surname':'Smith'},{'Name':'David','Surname':'Michael'},{'Name':'Sam','Surname':'Fields'},{'Name':'Katy','Surname':'Milnes'}]);
var inputData = {objArr: data};
// Do not insert the above lines in your code step.
// Set the objArr to your array in the inputData step.
var parsedObjArr = JSON.parse(inputData.objArr);
// Skip the above step if the array is not in the inputData object.
var arrLen = parsedObjArr.length
console.log('Array Length: ', arrLen);
// The line below outputs data from the code step.
output = {arrLen}
Also note, you do not need to remove the quotes from the JSON string.
If the array is not in the inputData of the code step, you can just directly use the length method on the array.

Well in Python you can convert the json string into dictionary with key as the name. Length of dictionary is what you are looking for. Here is the example:
import json
from collections import defaultdict
d=defaultdict(list)
x=json.dumps([{'Name':'Jon', 'Surname':'Smith'},{'Name':'David','Surname':'Michael'},{'Name':'Sam','Surname':'Fields'},{'Name':'Katy','Surname':'Milnes'}])
json_string=json.loads(x)
for obj in json_string:
if(obj['Name'] in d):
d[obj['Name']].append([obj['Name']+' '+obj['Surname']])
else:
d[obj['Name']]=[obj['Name']+' '+obj['Surname']]
print(len(d))

Trying to dynamically organize JSON object elements into different arrays based on values

This is the JSON I'm working with:
https://data.cityofnewyork.us/resource/xx67-kt59.json?$where=camis%20=%2230112340%22
I'd be dynamically making the queries using different data, so it'll possibly change.
What I'm essentially trying to do is to somehow organize the elements within this array into different arrays based on inspection_date.
So for each unique inspection_date value, those respective inspections would be put into its own collection.
If I knew the dates beforehand, I could easily iterate through each element and just push into an array.
Is there a way to dynamically create the arrays?
My end goal is to be able to display each group of inspections (based on inspection date) using Angular 5 on a webpage. I already have the site up and working and all of the requests being made.
So, I'm trying to eventually get to something like this. But of course, using whatever dates in the response from the request.
2016-10-03T00:00:00
List the inspections
2016-04-30T00:00:00
List the inspections
2016-04-12T00:00:00
List the inspections
Just for reference, here's the code I'm using:
ngOnInit() {
this.route.params.subscribe(params => {
this.title = +params['camis']; // (+) converts string 'id' to a number
this.q.getInpectionsPerCamis(this.title).subscribe((res) => {
this.inspectionList = res;
console.log(res);
});
// In a real app: dispatch action to load the details here.
});
}
I wish I could give you more info, but at this point, I'm just trying to get started.

I wrote this in jQuery just because it was faster for me, but it should translate fairly well to Angular (I just don't want to fiddle with an angular app right now)
Let me know if you have any questions.
$(function() {
let byDateObj = {};
$.ajax({
url: 'https://data.cityofnewyork.us/resource/xx67-kt59.json?$where=camis%20=%2230112340%22'
}).then(function(data) {
//probably do a check to make sure the data is an array, im gonna skip that
byDateObj = data.reduce(function(cum, cur) {
if (!cum.hasOwnProperty(cur.inspection_date)) cum[cur.inspection_date] = [];
//if the cumulative array doesn't have the inspection property already, add it as an empty array
cum[cur.inspection_date].push(cur);
//push to inspection_date array.
return cum;
//return cumulatie object
}, byDateObj);
//start with an empty object by default;
console.log(byDateObj);
}, console.error);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

MongoDB count and results

I would really appreciate if someone could help me with something: I need to make a normal query to the database but, as my collection is very large (10000 documents) I need to do the query and use $limit and $skip. That part I solved but now I want to have a count to all the documents, even if the returned ones are less. The output should be something like this:
{
count: 1150,
data: [/*length of 50*/]
}
Could anyone help please? Thank you very much.

Since you mentioned you are making a normal query, its not wise to go for aggregation. find() will be a much better option here. Instead you can use the find query itself. The commands to do this in mongoDB console is shown below:
> var docs = db.collection.find().skip(10).limit(50)
> docs.count()
189000
> docs.length()
50

You can do this using one query itself. In Node.js and Express.js, you will have to use it like this to be able to use the "count" function along with the toArray's "result".
var curFind = db.collection('tasks').find({query});
Then you can run two functions after it like this (one nested in the other)
curFind.count(function (e, count) {
// Use count here
curFind.skip(0).limit(10).toArray(function(err, result) {
// Use result here and count here
});
});

I don't think it is possible in a single query to get the total count of the result along with the paginated data without using aggregation.
You can probably achieve this via aggregation but since you mentioned, your collection is very large, you should avoid it and break the query into two parts. I'm providing you an example of considering user collection having a rating field with more than 10,000 records:
var finalResult = {};
var query = {
rating: {$gt: 2}
};
// Get first 50 records of users having rating greater than 2
var users = db.user.find(query).limit(50).skip(0).toArray();
// Get total count of users having rating greater than 2
var totalUsers = db.user.cound(query);
finalResult.count = totalUsers;
finalResult.data = users;
And your final output can be like:
finalResult == {
count: 1150,
data: [/*length of 50 users*/]
}
Hope, this make sense to you. Some of the famous technologies like Grails internally do that to achieve pagination.
Another cleaner approach could be:
var finalResult = {};
var query = {
rating: {$gt: 2}
};
var cursor = db.user.find(query).limit(50).skip(0);
// Get total count of users having rating greater than 2
// By default, the count() method ignores the effects of the cursor.skip() and cursor.limit()
finalResult.count = cursor.count();;
finalResult.data = cursor.toArray();

As mentioned by Sarath Nair you can use count, as it ignores skip and limit. Check: MongoDB Count
By the way, this is duplication from another StackOverflow question: Limiting results in MongoDB but still getting the full count?

Display posts in descending posted order

I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?

Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console

Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase

To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.

There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);

I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p

You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}

In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.

Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}

I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}

There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});

To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster

I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}

myarray.reverse(); or this.myitems = items.map(item => item).reverse();

I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});

Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.

You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.

just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},

For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.

PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.