I am trying to get multiple random documents from a dynamic collection. Until know, I have thought to do it using simple queries, something like this:
Pseudocode
arr = [];
while (arr.length < 5) {
// Start the query at a random position
startAt = Math.random() * collection.size;
randomDoc = await dbRef.startAt(startAt).limit(1).get( ... );
arr.push(randomDoc);
}
Here, firstly, I have to get the collection size, as it can be 0 or bigger. Then, select a random document using a kind of "db random pointer/index".
My question is if there is any way to get the same result but without all the loop stuff, only with the query syntax.
Thank you.
Clever use of startAt and limit!
As you can see in the reference, there are no built-in methods that would return random documents.
In order to avoid the loop, you can use Promise.all:
const indices = getRandomIndices(collection.size);
const docs = await Promise.all(indices.map(i => {
return dbRef.startAt(i).limit(1).get();
}));
And for the getRandomIndices, I suggest: create an array [0, 1, 2, ...], shuffle it as describe in this SO answer, and slice its 5 first elements.
I hope I am using the correct terms as I am a beginner with JS so please correct me if the terms I am using are incorrect. I am collecting sku numbers from my website via a dataLayer and turning it into a variable called DL - Product Detail - SKUs .When the variable comes across it, it's put into a string. Some products may just come across with a single product sku string (sku1) while other pages have multiple product sku string (sku1, sku2, sku3). What I am trying to do now is this: Create them as single variables, something like this:
SKUS: sku1
SKUS: sku2
SKUS: sku3
I honestly have no idea where to even start. So any suggestions would be appreciated. I have something like this but I don't believe this is the correct direction I need to go.
FYI the {{...}} are to call the SKUs string from the dataLayer using Google Tag Manager.
The _ltk.Activity.AddProductBrowse(productskus); is where I need to call the SKUs out individually.
(function() {
var productskus = "{{DL - Product Details - SKUs}}";
return productskus('|');
_ltk.Activity.AddProductBrowse(productskus);
_ltk.Activity.Submit();
});
I am not really sure how to give a good minimal example but maybe this will help
This is the object that is pulling through:
object
{
id: '24513',
model: 'Government',
skus: '965000050,965000070,965000146,965000147,965000185,965000244',
}
So I created a variable that calls the skus out into a string.
var sku = ('965000050,965000070,965000146,965000147,965000185,965000244')
from that sku variable, I now need each item to be it's own item for lack of knowing the correct term.
You can build an array of SKUs by doing this.
var productskus = "{{DL - Product Details - SKUs}}";
var skuArray = productskus.skus.split(',');
Once you have that array you can iterate over them and call the AddProductBrowse method:
skuArray.forEach(function(sku) {
_ltk.Activity.AddProductBrowse(sku);
});
I think this might be what you are looking to do.
I wanted to follow up in case anyone else ever has an issue like this.
I had to create another GTM variable to split the string of SKUs:
function(){
var productSKUs = {{DL - Product Details - SKUs}}.split(',');
return productSKUs
}
The I had to update my Custom HTML tag to call out the split sku variable I created above and put it in a for loop to call out each different sku:
function() {
// Repeat this function for every item purchased -> done.
var productsku = {{JS - Split - Skus}};
for (var i = 0; i < productsku.length; i++) {
_ltk.Activity.AddProductBrowse(productsku[i]);
}
And once I ran that I was seeing the data I needed in the network tab!
Thanks for all the help.
I'm building an API for my site (using Node.js and Mongoose) and I would like to incorporate pagination in it. My problem is the following: if the page size is for example 15 and I make a request for the first page so it sends me the first 15 items ordered by date of creation but then what if before I make the request for the second page, 15 new items are created in the database, the returned data will be the same as previously if I just use a skip on mongoose.
Is there a way to avoid doublons with mongoose? What I have at the moment is an "exclude" parameter in the query so it excludes all items already loaded but I'm thinking if there are lots of loaded items, the URL might be very long and I'm not sure that's a good thing...
Is there a better way to do this or do I have to just leave it with the risk of having doublons?
You can use mongoose-paginate-v2
And to prevent any duplicates from returned documents, you can pass (last document id & limit)
And your query should be like :
import { PaginateModel } from 'mongoose-paginate-v2';
constructor(
private readonly _paginateModel: PaginateModel<any>
) {}
const query = this._paginateModel
.find({ _id: { $lt: lastId } });
this._paginateModel.paginate(query, { limit: 10 });
You can use skip and limit function in which you can pass min and max value .
like in first page if you get 15 records values for min and max will be :
min = 0 and max = 15
for page 2
min = 15 and max = 30
I'm trying to test out Firebase to allow users to post comments using push. I want to display the data I retrieve with the following;
fbl.child('sell').limit(20).on("value", function(fbdata) {
// handle data display here
}
The problem is the data is returned in order of oldest to newest - I want it in reversed order. Can Firebase do this?
Since this answer was written, Firebase has added a feature that allows ordering by any child or by value. So there are now four ways to order data: by key, by value, by priority, or by the value of any named child. See this blog post that introduces the new ordering capabilities.
The basic approaches remain the same though:
1. Add a child property with the inverted timestamp and then order on that.
2. Read the children in ascending order and then invert them on the client.
Firebase supports retrieving child nodes of a collection in two ways:
by name
by priority
What you're getting now is by name, which happens to be chronological. That's no coincidence btw: when you push an item into a collection, the name is generated to ensure the children are ordered in this way. To quote the Firebase documentation for push:
The unique name generated by push() is prefixed with a client-generated timestamp so that the resulting list will be chronologically-sorted.
The Firebase guide on ordered data has this to say on the topic:
How Data is Ordered
By default, children at a Firebase node are sorted lexicographically by name. Using push() can generate child names that naturally sort chronologically, but many applications require their data to be sorted in other ways. Firebase lets developers specify the ordering of items in a list by specifying a custom priority for each item.
The simplest way to get the behavior you want is to also specify an always-decreasing priority when you add the item:
var ref = new Firebase('https://your.firebaseio.com/sell');
var item = ref.push();
item.setWithPriority(yourObject, 0 - Date.now());
Update
You'll also have to retrieve the children differently:
fbl.child('sell').startAt().limitToLast(20).on('child_added', function(fbdata) {
console.log(fbdata.exportVal());
})
In my test using on('child_added' ensures that the last few children added are returned in reverse chronological order. Using on('value' on the other hand, returns them in the order of their name.
Be sure to read the section "Reading ordered data", which explains the usage of the child_* events to retrieve (ordered) children.
A bin to demonstrate this: http://jsbin.com/nonawe/3/watch?js,console
Since firebase 2.0.x you can use limitLast() to achieve that:
fbl.child('sell').orderByValue().limitLast(20).on("value", function(fbdataSnapshot) {
// fbdataSnapshot is returned in the ascending order
// you will still need to order these 20 items in
// in a descending order
}
Here's a link to the announcement: More querying capabilities in Firebase
To augment Frank's answer, it's also possible to grab the most recent records--even if you haven't bothered to order them using priorities--by simply using endAt().limit(x) like this demo:
var fb = new Firebase(URL);
// listen for all changes and update
fb.endAt().limit(100).on('value', update);
// print the output of our array
function update(snap) {
var list = [];
snap.forEach(function(ss) {
var data = ss.val();
data['.priority'] = ss.getPriority();
data['.name'] = ss.name();
list.unshift(data);
});
// print/process the results...
}
Note that this is quite performant even up to perhaps a thousand records (assuming the payloads are small). For more robust usages, Frank's answer is authoritative and much more scalable.
This brute force can also be optimized to work with bigger data or more records by doing things like monitoring child_added/child_removed/child_moved events in lieu of value, and using a debounce to apply DOM updates in bulk instead of individually.
DOM updates, naturally, are a stinker regardless of the approach, once you get into the hundreds of elements, so the debounce approach (or a React.js solution, which is essentially an uber debounce) is a great tool to have.
There is really no way but seems we have the recyclerview we can have this
query=mCommentsReference.orderByChild("date_added");
query.keepSynced(true);
// Initialize Views
mRecyclerView = (RecyclerView) view.findViewById(R.id.recyclerView);
mManager = new LinearLayoutManager(getContext());
// mManager.setReverseLayout(false);
mManager.setReverseLayout(true);
mManager.setStackFromEnd(true);
mRecyclerView.setHasFixedSize(true);
mRecyclerView.setLayoutManager(mManager);
I have a date variable (long) and wanted to keep the newest items on top of the list. So what I did was:
Add a new long field 'dateInverse'
Add a new method called 'getDateInverse', which just returns: Long.MAX_VALUE - date;
Create my query with: .orderByChild("dateInverse")
Presto! :p
You are searching limitTolast(Int x) .This will give you the last "x" higher elements of your database (they are in ascending order) but they are the "x" higher elements
if you got in your database {10,300,150,240,2,24,220}
this method:
myFirebaseRef.orderByChild("highScore").limitToLast(4)
will retrive you : {150,220,240,300}
In Android there is a way to actually reverse the data in an Arraylist of objects through the Adapter. In my case I could not use the LayoutManager to reverse the results in descending order since I was using a horizontal Recyclerview to display the data. Setting the following parameters to the recyclerview messed up my UI experience:
llManager.setReverseLayout(true);
llManager.setStackFromEnd(true);
The only working way I found around this was through the BindViewHolder method of the RecyclerView adapter:
#Override
public void onBindViewHolder(final RecyclerView.ViewHolder holder, int position) {
final SuperPost superPost = superList.get(getItemCount() - position - 1);
}
Hope this answer will help all the devs out there who are struggling with this issue in Firebase.
Firebase: How to display a thread of items in reverse order with a limit for each request and an indicator for a "load more" button.
This will get the last 10 items of the list
FBRef.child("childName")
.limitToLast(loadMoreLimit) // loadMoreLimit = 10 for example
This will get the last 10 items. Grab the id of the last record in the list and save for the load more functionality. Next, convert the collection of objects into and an array and do a list.reverse().
LOAD MORE Functionality: The next call will do two things, it will get the next sequence of list items based on the reference id from the first request and give you an indicator if you need to display the "load more" button.
this.FBRef
.child("childName")
.endAt(null, lastThreadId) // Get this from the previous step
.limitToLast(loadMoreLimit+2)
You will need to strip the first and last item of this object collection. The first item is the reference to get this list. The last item is an indicator for the show more button.
I have a bunch of other logic that will keep everything clean. You will need to add this code only for the load more functionality.
list = snapObjectAsArray; // The list is an array from snapObject
lastItemId = key; // get the first key of the list
if (list.length < loadMoreLimit+1) {
lastItemId = false;
}
if (list.length > loadMoreLimit+1) {
list.pop();
}
if (list.length > loadMoreLimit) {
list.shift();
}
// Return the list.reverse() and lastItemId
// If lastItemId is an ID, it will be used for the next reference and a flag to show the "load more" button.
}
I'm using ReactFire for easy Firebase integration.
Basically, it helps me storing the datas into the component state, as an array. Then, all I have to use is the reverse() function (read more)
Here is how I achieve this :
import React, { Component, PropTypes } from 'react';
import ReactMixin from 'react-mixin';
import ReactFireMixin from 'reactfire';
import Firebase from '../../../utils/firebaseUtils'; // Firebase.initializeApp(config);
#ReactMixin.decorate(ReactFireMixin)
export default class Add extends Component {
constructor(args) {
super(args);
this.state = {
articles: []
};
}
componentWillMount() {
let ref = Firebase.database().ref('articles').orderByChild('insertDate').limitToLast(10);
this.bindAsArray(ref, 'articles'); // bind retrieved data to this.state.articles
}
render() {
return (
<div>
{
this.state.articles.reverse().map(function(article) {
return <div>{article.title}</div>
})
}
</div>
);
}
}
There is a better way. You should order by negative server timestamp. How to get negative server timestamp even offline? There is an hidden field which helps. Related snippet from documentation:
var offsetRef = new Firebase("https://<YOUR-FIREBASE-APP>.firebaseio.com/.info/serverTimeOffset");
offsetRef.on("value", function(snap) {
var offset = snap.val();
var estimatedServerTimeMs = new Date().getTime() + offset;
});
To add to Dave Vávra's answer, I use a negative timestamp as my sort_key like so
Setting
const timestamp = new Date().getTime();
const data = {
name: 'John Doe',
city: 'New York',
sort_key: timestamp * -1 // Gets the negative value of the timestamp
}
Getting
const ref = firebase.database().ref('business-images').child(id);
const query = ref.orderByChild('sort_key');
return $firebaseArray(query); // AngularFire function
This fetches all objects from newest to oldest. You can also $indexOn the sortKey to make it run even faster
I had this problem too, I found a very simple solution to this that doesn't involved manipulating the data in anyway. If you are rending the result to the DOM, in a list of some sort. You can use flexbox and setup a class to reverse the elements in their container.
.reverse {
display: flex;
flex-direction: column-reverse;
}
myarray.reverse(); or this.myitems = items.map(item => item).reverse();
I did this by prepend.
query.orderByChild('sell').limitToLast(4).on("value", function(snapshot){
snapshot.forEach(function (childSnapshot) {
// PREPEND
});
});
Someone has pointed out that there are 2 ways to do this:
Manipulate the data client-side
Make a query that will order the data
The easiest way that I have found to do this is to use option 1, but through a LinkedList. I just append each of the objects to the front of the stack. It is flexible enough to still allow the list to be used in a ListView or RecyclerView. This way even though they come in order oldest to newest, you can still view, or retrieve, newest to oldest.
You can add a column named orderColumn where you save time as
Long refrenceTime = "large future time";
Long currentTime = "currentTime";
Long order = refrenceTime - currentTime;
now save Long order in column named orderColumn and when you retrieve data
as orderBy(orderColumn) you will get what you need.
just use reverse() on the array , suppose if you are storing the values to an array items[] then do a this.items.reverse()
ref.subscribe(snapshots => {
this.loading.dismiss();
this.items = [];
snapshots.forEach(snapshot => {
this.items.push(snapshot);
});
**this.items.reverse();**
},
For me it was limitToLast that worked. I also found out that limitLast is NOT a function:)
const query = messagesRef.orderBy('createdAt', 'asc').limitToLast(25);
The above is what worked for me.
PRINT in reverse order
Let's think outside the box... If your information will be printed directly into user's screen (without any content that needs to be modified in a consecutive order, like a sum or something), simply print from bottom to top.
So, instead of inserting each new block of content to the end of the print space (A += B), add that block to the beginning (A = B+A).
If you'll include the elements as a consecutive ordered list, the DOM can put the numbers for you if you insert each element as a List Item (<li>) inside an Ordered Lists (<ol>).
This way you save space from your database, avoiding unnecesary reversed data.
Am working on a windows store javascript application. The application uses data from azure mobile services.
Consider the below code:
var itemTable = mobileService.getTable('item');
//item is the table name stored in the azure database
The code fetches the entire table item and saves it to a variable itemTable.
What code will return the no of rows present in itemTable??
What you're looking for is the includeTotalCount method on the table/query object (unfortunately it's missing from the documentation, I'll file a bug to the product team to have it fixed).
When you call read on the query object, it will return by default 50 (IIRC, the number may be different) elements from it, to prevent a naïve call from returning all elements in a very large table (thus either incurring the outbound bandwidth cost for reserved services, or hitting the quota for free ones). So getting all the elements in the table, and getting the length of the results may not be accurate.
If all you want is the number of elements in the table, you can use the code below: returning zero elements, and the total count.
var table = client.getTable('tableName');
table.take(0).includeTotalCount().read().then(function (results) {
var count = results.totalCount;
new Windows.UI.Popups.MessageDialog('Total count: ' + count).showAsync();
});
If you want to query some elements, and also include the total count (i.e., for paging), just add the appropriate take() and skip() calls, and also the includeTotalCount as well.
If anybody comes here and interested in how to get the totalCount only on C# (like me), then this is how you do it:
var table = MobileService.GetTable<T> ();
var query = table.Take(0).IncludeTotalCount();
IList<T> results = await query.ToListAsync ();
long count = ((ITotalCountProvider)results).TotalCount;
Credit goes to this blog post here
You need to execute read() on the table query and then get the length of the results.
var items, numItems;
itemTable.read().then(function(results) { items = results; numItems = items.length; });
If you are only showing a record count and not the entire results - you should just select the ID column to reduce the amount of data transmitted. I don't see a count() method available yet in the JS Query API to fill this need.
var itemTable = mobileService.getTable('item').select('itemID');