I have this URL
https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id1=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request
Here I am getting sys_id two times with different parameters. So I need to remove the second & sign and all text after that.
I tried this
location.href.split('&')[2]
I am sure it doesn't work. Can anyone provide some better solution?
Firstly, you should split the string into an array then use slice to set the starting index number of the element which is 2 in your case and then join the array again into the string.
Read more about these methods JavaScript String split() Method, jQuery slice() Method and JavaScript Array join() Method
var url = 'https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request';
url = url.split("&").slice(0,2).join("&");
console.log(url);
Maybe like this:
var url='https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request';
var first=url.indexOf('&');
var second=url.indexOf('&',first+1);
var new_url=url.substring(0,second);
console.log(new_url);
You need to find the 2nd occurrence of &sys_id. From there onwards remove all text.
Below is working code:
let url='https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request';
let str1=url.indexOf('&sys_id');
let str2=url.indexOf('&sys_id',str1+1);
console.log(url.substring(0,str2));
This is a bit more verbose, but it handles all duplicate query params regardless of their position in the URL.
function removeDuplicateQueryParams(url) {
var params = {};
var parsedParams = '';
var hash = url.split('#'); // account for hashes
var parts = hash[0].split('?');
var origin = parts[0];
var retURL;
// iterate over all query params
parts[1].split('&').forEach(function(param){
// Since Objects can only have one key of the same name, this will inherently
// filter out duplicates and keep only the latest value.
// The key is param[0] and value is param[1].
param = param.split('=');
params[param[0]] = param[1];
});
Object.keys(params).forEach(function(key, ndx){
parsedParams += (ndx === 0)
? '?' + key +'='+ params[key]
: '&' + key +'='+ params[key];
});
return origin + parsedParams + (hash[1] ? '#'+hash[1] : '');
}
console.log( removeDuplicateQueryParams('http://fake.com?q1=fu&bar=fu&q1=fu&q1=diff') );
console.log( removeDuplicateQueryParams('http://fake.com?q1=fu&bar=fu&q1=fu&q1=diff#withHash') );
var url = "https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id1=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request"
url = url.slice(0, url.indexOf('&', url.indexOf('&') + 1));
console.log(url);
Try this :)
Try this:
var yourUrl = "https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request"
var indexOfFirstAmpersand = yourUrl.search("&"); //find index of first &
var indexOfSecondAmpersand = indexOfFirstAmpersand + yourUrl.substring((indexOfFirstAmpersand + 1)).search("&") + 1; //get index of second &
var fixedUrl = yourUrl.substring(0, indexOfSecondAmpersand)
$(".answer").text(fixedUrl);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<p class="answer">
</p>
You can manipulate the url using String.prototype.substring method. In the example below I created a function that takes a url string and checks for a duplicate parameter - it returns a new string with the second occurrence removed.
var url = "https://myApp-ajj.com/sp?id=cat_item&sys_id=cf9f149cdbd25f00d080591e5e961920&sys_id=cf9f149cdbd25f00d080591e5e961920&sysp_Id=a691acd9dbdf1bc0e9619fb&sysparm_CloneTable=sc_request&sysparm_CloneTable=sc_request";
function stripDuplicateUrlParameter(url, parameterName) {
//get the start index of the repeat occurrance
var repeatIdx = url.lastIndexOf('sys_id');
var prefix = url.substring(0, repeatIdx);
var suffix = url.substring(repeatIdx);
//remove the duplicate part from the string
suffix = suffix.substring(suffix.indexOf('&') + 1);
return prefix + suffix;
}
console.log(stripDuplicateUrlParameter(url));
This solves your specific problem, but wouldn't work if the parameter occurred more than twice or if the second occurrence of the string wasn't immediately following the first - you would probably write something more sophisticated.
As someone already asked - why is the url parameter being duplicated in the string anyway? Is there some way to fix that? (because the question asked seems to me to be a band-aid solution with this being the root issue).
I have this URL
http://192.168.22.124:3000/temp/box/c939c38adcf1873299837894214a35eb
I want to replace the last part of my URL which is c939c38adcf1873299837894214a35eb with something else.
How can I do it?
Try this:
var url = 'http://192.168.22.124:3000/temp/box/c939c38adcf1873299837894214a35eb';
somethingelse = 'newhash';
var newUrl = url.substr(0, url.lastIndexOf('/') + 1) + somethingelse;
Note, using the built-in substr and lastIndexOf is far quicker and uses less memory than splitting out the component parts to an Array or using a regular expression.
You can follow this steps:
split the URL with /
replace the last item of array
join the result array using /
var url = 'http://192.168.22.124:3000/temp/box/c939c38adcf1873299837894214a35eb';
var res = url.split('/');
res[res.length-1] = 'someValue';
res = res.join('/');
console.log(res);
Using replace we can try:
var url = "http://192.168.22.124:3000/temp/box/c939c38adcf1873299837894214a35eb";
var replacement = 'blah';
url = url.replace(/(http.*\/).*/, "$1" + replacement);
console.log(url);
We capture everything up to and including the final path separator, then replace with that captured fragment and the new replacement.
Complete guide:
// url
var urlAsString = window.location.href;
// split into route parts
var urlAsPathArray = urlAsString.split("/");
// create a new value
var newValue = "routeValue";
// EITHER update the last parameter
urlAsPathArray[urlAsPathArray.length - 1] = newValue;
// OR replace the last parameter
urlAsPathArray.pop();
urlAsPathArray.push(newValue);
// join the array with the slashes
var newUrl = urlAsPathArray.join("/");
// log
console.log(newUrl);
// output
// http://192.168.22.124:3000/temp/box/routeValue
You could use a regular expression like this:
let newUrl = /^.*\//.exec(origUrl)[0] + 'new_ending';
I find it hard to believe this hasn't been asked but I can find no references anywhere. I need to add a URI hash fragment and update the value if it already is in the hash. I can currently get it to add the hash but my regex doesn't appear to catch if it exists so it adds another instead of updating.
setQueryString : function() {
var value = currentPage;
var uri = window.location.hash;
var key = "page";
var re = new RegExp("([#&])" + key + "=.*#(&|$)", "i");
var separator = uri.indexOf('#') !== -1 ? "&" : "#";
if (uri.match(re)) {
return uri.replace(re, '$1' + key + "=" + value + '$2');
}
else {
return uri + separator + key + "=" + value;
}
},
Also if this can be made any cleaner while preserving other url values/hashes that would be great.
example input as requested
Starting uri value:
www.example.com#page=1 (or no #page at all)
then on click of "next page" setQueryString gets called so the values would equal:
var value = 2;
var uri = '#page1'
var key = 'page'
So the hopeful output would be '#page2'.
As to your regex question, testing if the pattern #page=(number) or &page=(number) is present combined with capturing the number, can be done with the regex /[#&]page\=(\d*)/ and the .match(regex) method. Note that = needs escaping in regexes.
If the pattern exists in the string, result will contain an array with the integer (as a string) at result[1]. If the pattern does not exist, result will be null.
//match #page=(integer) or &page=(integer)
var test = "#foo=bar&page=1";
var regex = /[#&]page\=(\d*)/;
var result = test.match(regex);
console.log(result);
If you want to dynamically set the key= to something other than "page", you could build the regex dynamically, like the following (note that backslashes needs escaping in strings, making the code a bit more convoluted):
//dynamically created regex
var test = "#foo=bar&page=1";
var key = "page"
var regex = new RegExp("[#&]" + key + "\\=(\\d*)");
var result = test.match(regex);
console.log(result);
How do I get the last segment of a url? I have the following script which displays the full url of the anchor tag clicked:
$(".tag_name_goes_here").live('click', function(event)
{
event.preventDefault();
alert($(this).attr("href"));
});
If the url is
http://mywebsite/folder/file
how do I only get it to display the "file" part of the url in the alert box?
You can also use the lastIndexOf() function to locate the last occurrence of the / character in your URL, then the substring() function to return the substring starting from that location:
console.log(this.href.substring(this.href.lastIndexOf('/') + 1));
That way, you'll avoid creating an array containing all your URL segments, as split() does.
var parts = 'http://mywebsite/folder/file'.split('/');
var lastSegment = parts.pop() || parts.pop(); // handle potential trailing slash
console.log(lastSegment);
window.location.pathname.split("/").pop()
The other answers may work if the path is simple, consisting only of simple path elements. But when it contains query params as well, they break.
Better use URL object for this instead to get a more robust solution. It is a parsed interpretation of the present URL:
Input:
const href = 'https://stackoverflow.com/boo?q=foo&s=bar'
const segments = new URL(href).pathname.split('/');
const last = segments.pop() || segments.pop(); // Handle potential trailing slash
console.log(last);
Output: 'boo'
This works for all common browsers. Only our dying IE doesn't support that (and won't). For IE there is a polyfills available, though (if you care at all).
Just another solution with regex.
var href = location.href;
console.log(href.match(/([^\/]*)\/*$/)[1]);
Javascript has the function split associated to string object that can help you:
const url = "http://mywebsite/folder/file";
const array = url.split('/');
const lastsegment = array[array.length-1];
Shortest way how to get URL Last Segment with split(), filter() and pop()
function getLastUrlSegment(url) {
return new URL(url).pathname.split('/').filter(Boolean).pop();
}
console.log(getLastUrlSegment(window.location.href));
console.log(getLastUrlSegment('https://x.com/boo'));
console.log(getLastUrlSegment('https://x.com/boo/'));
console.log(getLastUrlSegment('https://x.com/boo?q=foo&s=bar=aaa'));
console.log(getLastUrlSegment('https://x.com/boo?q=foo#this'));
console.log(getLastUrlSegment('https://x.com/last segment with spaces'));
Works for me.
Or you could use a regular expression:
alert(href.replace(/.*\//, ''));
var urlChunks = 'mywebsite/folder/file'.split('/');
alert(urlChunks[urlChunks.length - 1]);
Returns the last segment, regardless of trailing slashes:
var val = 'http://mywebsite/folder/file//'.split('/').filter(Boolean).pop();
console.log(val);
I know, it is too late, but for others:
I highly recommended use PURL jquery plugin. Motivation for PURL is that url can be segmented by '#' too (example: angular.js links), i.e. url could looks like
http://test.com/#/about/us/
or
http://test.com/#sky=blue&grass=green
And with PURL you can easy decide (segment/fsegment) which segment you want to get.
For "classic" last segment you could write:
var url = $.url('http://test.com/dir/index.html?key=value');
var lastSegment = url.segment().pop(); // index.html
Get the Last Segment using RegEx
str.replace(/.*\/(\w+)\/?$/, '$1');
$1 means using the capturing group. using in RegEx (\w+) create the first group then the whole string replace with the capture group.
let str = 'http://mywebsite/folder/file';
let lastSegment = str.replace(/.*\/(\w+)\/?$/, '$1');
console.log(lastSegment);
Also,
var url = $(this).attr("href");
var part = url.substring(url.lastIndexOf('/') + 1);
Building on Frédéric's answer using only javascript:
var url = document.URL
window.alert(url.substr(url.lastIndexOf('/') + 1));
If you aren't worried about generating the extra elements using the split then filter could handle the issue you mention of the trailing slash (Assuming you have browser support for filter).
url.split('/').filter(function (s) { return !!s }).pop()
window.alert(this.pathname.substr(this.pathname.lastIndexOf('/') + 1));
Use the native pathname property because it's simplest and has already been parsed and resolved by the browser. $(this).attr("href") can return values like ../.. which would not give you the correct result.
If you need to keep the search and hash (e.g. foo?bar#baz from http://quux.com/path/to/foo?bar#baz) use this:
window.alert(this.pathname.substr(this.pathname.lastIndexOf('/') + 1) + this.search + this.hash);
To get the last segment of your current window:
window.location.href.substr(window.location.href.lastIndexOf('/') +1)
you can first remove if there is / at the end and then get last part of url
let locationLastPart = window.location.pathname
if (locationLastPart.substring(locationLastPart.length-1) == "/") {
locationLastPart = locationLastPart.substring(0, locationLastPart.length-1);
}
locationLastPart = locationLastPart.substr(locationLastPart.lastIndexOf('/') + 1);
var pathname = window.location.pathname; // Returns path only
var url = window.location.href; // Returns full URL
Copied from this answer
// Store original location in loc like: http://test.com/one/ (ending slash)
var loc = location.href;
// If the last char is a slash trim it, otherwise return the original loc
loc = loc.lastIndexOf('/') == (loc.length -1) ? loc.substring(0,loc.length-1) : loc.substring(0,loc.lastIndexOf('/'));
var targetValue = loc.substring(loc.lastIndexOf('/') + 1);
targetValue = one
If your url looks like:
http://test.com/one/
or
http://test.com/one
or
http://test.com/one/index.htm
Then loc ends up looking like:
http://test.com/one
Now, since you want the last item, run the next step to load the value (targetValue) you originally wanted.
var targetValue = loc.substr(loc.lastIndexOf('/') + 1);
// Store original location in loc like: http://test.com/one/ (ending slash)
let loc = "http://test.com/one/index.htm";
console.log("starting loc value = " + loc);
// If the last char is a slash trim it, otherwise return the original loc
loc = loc.lastIndexOf('/') == (loc.length -1) ? loc.substring(0,loc.length-1) : loc.substring(0,loc.lastIndexOf('/'));
let targetValue = loc.substring(loc.lastIndexOf('/') + 1);
console.log("targetValue = " + targetValue);
console.log("loc = " + loc);
Updated raddevus answer :
var loc = window.location.href;
loc = loc.lastIndexOf('/') == loc.length - 1 ? loc.substr(0, loc.length - 1) : loc.substr(0, loc.length + 1);
var targetValue = loc.substr(loc.lastIndexOf('/') + 1);
Prints last path of url as string :
test.com/path-name = path-name
test.com/path-name/ = path-name
I am using regex and split:
var last_path = location.href.match(/./(.[\w])/)[1].split("#")[0].split("?")[0]
In the end it will ignore # ? & / ending urls, which happens a lot. Example:
https://cardsrealm.com/profile/cardsRealm -> Returns cardsRealm
https://cardsrealm.com/profile/cardsRealm#hello -> Returns cardsRealm
https://cardsrealm.com/profile/cardsRealm?hello -> Returns cardsRealm
https://cardsrealm.com/profile/cardsRealm/ -> Returns cardsRealm
I don't really know if regex is the right way to solve this issue as it can really affect efficiency of your code, but the below regex will help you fetch the last segment and it will still give you the last segment even if the URL is followed by an empty /. The regex that I came up with is:
[^\/]+[\/]?$
I know it is old but if you want to get this from an URL you could simply use:
document.location.pathname.substring(document.location.pathname.lastIndexOf('/.') + 1);
document.location.pathname gets the pathname from the current URL.
lastIndexOf get the index of the last occurrence of the following Regex, in our case is /.. The dot means any character, thus, it will not count if the / is the last character on the URL.
substring will cut the string between two indexes.
if the url is http://localhost/madukaonline/shop.php?shop=79
console.log(location.search); will bring ?shop=79
so the simplest way is to use location.search
you can lookup for more info here
and here
You can do this with simple paths (w/0) querystrings etc.
Granted probably overly complex and probably not performant, but I wanted to use reduce for the fun of it.
"/foo/bar/"
.split(path.sep)
.filter(x => x !== "")
.reduce((_, part, i, arr) => {
if (i == arr.length - 1) return part;
}, "");
Split the string on path separators.
Filter out empty string path parts (this could happen with trailing slash in path).
Reduce the array of path parts to the last one.
Adding up to the great Sebastian Barth answer.
if href is a variable that you are parsing, new URL will throw a TypeError so to be in the safe side you should try - catch
try{
const segments = new URL(href).pathname.split('/');
const last = segments.pop() || segments.pop(); // Handle potential trailing slash
console.log(last);
}catch (error){
//Uups, href wasn't a valid URL (empty string or malformed URL)
console.log('TypeError ->',error);
}
I believe it's safer to remove the tail slash('/') before doing substring. Because I got an empty string in my scenario.
window.alert((window.location.pathname).replace(/\/$/, "").substr((window.location.pathname.replace(/\/$/, "")).lastIndexOf('/') + 1));
Bestway to get URL Last Segment Remove (-) and (/) also
jQuery(document).ready(function(){
var path = window.location.pathname;
var parts = path.split('/');
var lastSegment = parts.pop() || parts.pop(); // handle potential trailing slash
lastSegment = lastSegment.replace('-',' ').replace('-',' ');
jQuery('.archive .filters').before('<div class="product_heading"><h3>Best '+lastSegment+' Deals </h3></div>');
});
A way to avoid query params
const urlString = "https://stackoverflow.com/last-segment?param=123"
const url = new URL(urlString);
url.search = '';
const lastSegment = url.pathname.split('/').pop();
console.log(lastSegment)
I am trying to select just what comes after name= and before the & in :
"/pages/new?name=J&return_url=/page/new"
So far I have..
^name=(.*?).
I am trying to return in this case, just the J, but its dynamic so it could very several characters, letters, or numbers.
The end case situation would be allowing myself to do a replace statement on this dynamic variable found by regex.
/name=([^&]*)/
remove the ^ and end with an &
Example:
var str = "/pages/new?name=J&return_url=/page/new";
var matches = str.match(/name=([^&]*)/);
alert(matches[1]);
The better way is to break all the params down (Example using current address):
function getParams (str) {
var queryString = str || window.location.search || '';
var keyValPairs = [];
var params = {};
queryString = queryString.replace(/.*?\?/,"");
if (queryString.length)
{
keyValPairs = queryString.split('&');
for (pairNum in keyValPairs)
{
var key = keyValPairs[pairNum].split('=')[0];
if (!key.length) continue;
if (typeof params[key] === 'undefined')
params[key] = [];
params[key].push(keyValPairs[pairNum].split('=')[1]);
}
}
return params;
}
var url = "/pages/new?name=L&return_url=/page/new";
var params = getParams(url);
params['name'];
Update
Though still not supported in any version of IE, URLSearchParams provides a native way of retrieving values for other browsers.
The accepted answer includes the hash part if there is a hash right after the params. As #bishoy has in his function, the correct regex would be
/name=([^&#]*)/
Improving on previous answers:
/**
*
* #param {string} name
* #returns {string|null}
*/
function getQueryParam(name) {
var q = window.location.search.match(new RegExp('[?&]' + name + '=([^&#]*)'));
return q && q[1];
}
getQueryParam('a'); // returns '1' on page http://domain.com/page.html?a=1&b=2
here is the full function (tested and fixed for upper/lower case)
function getParameterByName (name)
{
name = name.replace(/[\[]/, "\\\[").replace(/[\]]/, "\\\]");
var regexS = "[\\?&]" + name.toLowerCase() + "=([^&#]*)";
var regex = new RegExp(regexS);
var results = regex.exec(window.location.search.toLowerCase());
if (results == null)
return "";
else
return decodeURIComponent(results[1].replace(/\+/g, " "));
}
The following should work:
\?name=(.*?)&
var myname = str.match(/\?name=([^&]+)&/)[1];
The [1] is because you apparently want the value of the group (the part of the regex in brackets).
var str = "/pages/new?name=reaojr&return_url=/page/new";
var matchobj = str.match(/\?name=([^&]+)&/)[1];
document.writeln(matchobj); // prints 'reaojr'
Here's a single line answer that prevents having to store a variable (if you can't use URLSearchParams because you still support IE)
(document.location.search.match(/[?&]name=([^&]+)/)||[null,null])[1]
By adding in the ||[null,null] and surrounding it in parentheses, you can safely index item 1 in the array without having to check if match came back with results. Of course, you can replace the [null,null] with whatever you'd like as a default.
You can get the same result with simple .split() in javascript.
let value = url.split("name=")[1].split("&")[0];
This might work:
\??(.*=.+)*(&.*=.+)?