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Get last two params of an URL - javascript

My URL looks like this
stackoverflow.com/questions/ask/format/return
I need to get only format/return from the above URL. I'm able to assign the complete URL to a variable. Currently i'm doing it on split
url.split("/")[4]
url.split("/")[5]
And this is not Generic. What is the better way to achieve this?

The shortest, cleanest way to do this is by using slice on the splitted URL:
url.split("/").slice(-2).join("/")

Just use the length to help you index from the end:
var res = url.split('/')
var last = res[res.length-1]
var pre_last = res[res.length-2]

A genetic solution,
Var URL = url.split("/"); //
Last = URL[URL.length-1]; // return
LastBefore = URL[URL.length-1]; //format
url = "stackoverflow.com/questions/ask/format/return"
URL = url.split("/");
console.log(URL[URL.length-1]) // return
console.log(URL[URL.length-2]) //format

Look for the last and penultimate values:
let spl = url.split("/");
alert(spl[spl.length-2]+' and '+spl[spl.length-1]);

I'd parse the url to a URL, then use match on the pathname. This way it will also work should you have any searchparams (?foo=bar) in your url
const s = "https://stackoverflow.com/questions/ask/format/return";
const uri = new URL(s);
const m = uri.pathname.match(/([^\/]*)\/([^\/]*)$/);
console.log(m);
Note that you'll get an array holding three entries - 0 being the path combined, 1 the first and 2 the last param.

You can use a simple regex /.*\/(.*\/.*)/) to extract exactly what you want.
str.match(/.*\/(.*\/.*)/).pop()
var str = "stackoverflow.com/questions/ask/format/return",
res = str.match(/.*\/(.*\/.*)/).pop();
console.log(res);

var parts = url.split("/");
lastTwo = [parts.pop(), parts.pop()].reverse().join("/");

Javascript how to remove parameter from URL sting by value?

How to remove parameters with value = 3 from URL string?
Example URL string:
https://www.example.com/test/index.html?param1=4&param2=3&param3=2&param4=1&param5=3

If you are targeting browsers that support URL and URLSearchParams you can loop over the URL's searchParams object, check each parameter's value, and delete() as necessary. Finally using URL's href property to get the final url.
var url = new URL(`https://www.example.com/test/index.html?param1=4&param2=3&param3=2&param4=1&param5=3`)
//need a clone of the searchParams
//otherwise looping while iterating over
//it will cause problems
var params = new URLSearchParams(url.searchParams.toString());
for(let param of params){
if(param[1]==3){
url.searchParams.delete(param[0]);
}
}
console.log(url.href)

There is a way to do this with a single regex, using some magic, but I believe that would require using lookbehinds, which most JavaScript regex engines mostly don't yet support. As an alternative, we can try splitting the query string, then just examining each component to see if the value be 3. If so, then we remove that query parameter.
var url = "https://www.example.com/test/index.html?param1=4&param2=3&param3=2&param4=1&param5=3";
var parts = url.split(/\?/);
var params = parts[1].replace(/^.*\?/, "").split(/&/);
var param_out = "";
params.forEach(function(x){
if (!/.*=3$/.test(x))
param_out += x;
});
url = parts[0] + (param_out !== "" ? "?" + param_out : "");
console.log(url);

You could use a regular expression replace. Split off the query string and then .replace &s (or the initial ^) up until =3s:
const str = 'https://www.example.com/test/index.html?param1=4&param2=3&param3=2&param4=1&param5=3';
const [base, qs] = str.split('?');
const replacedQs = qs.replace(/(^|&)[^=]+=3\b/g, '');
const output = base + (replacedQs ? '?' + replacedQs : '');
console.log(output);

How can I extract a part of this url with JavaScript?

I have an url that looks like this:
http://localhost/assets/upload/img/hw6dNDBT-36x36.jpg
I want to extract hw6dNDBT.jpg, from the url above.
I tried playing around with regex patterns /img\/.*-/ but that
matches with img/hw6dNDBT-.
How can I do this in JavaScript?

try this:
var url = 'http://localhost/assets/upload/img/hw6dNDBT-36x36.jpg';
var filename = url.match(/img\/(.*)-[^.]+(\.[^.]+)/).slice(1).join('');
document.body.innerHTML = filename;

i would use split() method:
var str = "http://localhost/assets/upload/img/hw6dNDBT-36x36.jpg";
var strArr = str.split("/");
var size = strArr.length - 1;
var needle = strArr[size].split("-");
var fileTypeArr = strArr[size].split(".");
var name = needle[0]+"."+fileTypeArr[fileTypeArr.length-1];
name should now be your searched String so far it contains no / inside it
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/split

/[^\/]+$/ should match all characters after the last / in the URL, which seems to be what you want to match.

No regex:
//this is a hack that lets the anchor tag do some parsing for you
var parser = document.createElement('a');
parser.href = 'http://localhost/assets/upload/img/hw6dNDBT-36x36.jpg';
//optional if you know you can always trim the start of the path
var path = parser.pathname.replace('/assets/uploads/');
var parts = path.split('/');
var img = '';
for(var i=0; i<parts.length; i++) {
if (parts[i] == 'img') {
//since we know the .jpg always follows 'img/'
img = parts[i+1];
}
}

Ah, you were so close! You just need to take your regex and use a capturing group, and then add a littttle bit more!
img\/(.*)-.*(\..*)
So, you can use that in this manner:
var result = /img\/(.*)-.*(\..*)/.exec();
var filename = result[1] + result[2];
Honestly capturing the .jpg, is a little excessive, if you know they are all going to be JPG images, you can probably just take out the second half of the regex.
Incase you are wondering, why do we uses result[1] and result[2]? Because result[0] stores the entire match, which is what you were getting back. The captured groups, which is what we create when we use the parentheses, are stored as the indexes after 0.

Here is some one-liner:
var myUrl = 'http://localhost/assets/upload/img/hw6dNDBT-36x36.jpg',
myValue = myUrl.split('/').pop().replace(/-(?=\d).[^.]+/,'');
We take everything after the last slash then cut out the dimension part.

How to split a word for getting a specific value in Javascript or Jquery? [duplicate]

How do I get the last segment of a url? I have the following script which displays the full url of the anchor tag clicked:
$(".tag_name_goes_here").live('click', function(event)
{
event.preventDefault();
alert($(this).attr("href"));
});
If the url is
http://mywebsite/folder/file
how do I only get it to display the "file" part of the url in the alert box?

You can also use the lastIndexOf() function to locate the last occurrence of the / character in your URL, then the substring() function to return the substring starting from that location:
console.log(this.href.substring(this.href.lastIndexOf('/') + 1));
That way, you'll avoid creating an array containing all your URL segments, as split() does.

var parts = 'http://mywebsite/folder/file'.split('/');
var lastSegment = parts.pop() || parts.pop(); // handle potential trailing slash
console.log(lastSegment);

window.location.pathname.split("/").pop()

The other answers may work if the path is simple, consisting only of simple path elements. But when it contains query params as well, they break.
Better use URL object for this instead to get a more robust solution. It is a parsed interpretation of the present URL:
Input:
const href = 'https://stackoverflow.com/boo?q=foo&s=bar'
const segments = new URL(href).pathname.split('/');
const last = segments.pop() || segments.pop(); // Handle potential trailing slash
console.log(last);
Output: 'boo'
This works for all common browsers. Only our dying IE doesn't support that (and won't). For IE there is a polyfills available, though (if you care at all).

Just another solution with regex.
var href = location.href;
console.log(href.match(/([^\/]*)\/*$/)[1]);

Javascript has the function split associated to string object that can help you:
const url = "http://mywebsite/folder/file";
const array = url.split('/');
const lastsegment = array[array.length-1];

Shortest way how to get URL Last Segment with split(), filter() and pop()
function getLastUrlSegment(url) {
return new URL(url).pathname.split('/').filter(Boolean).pop();
}
console.log(getLastUrlSegment(window.location.href));
console.log(getLastUrlSegment('https://x.com/boo'));
console.log(getLastUrlSegment('https://x.com/boo/'));
console.log(getLastUrlSegment('https://x.com/boo?q=foo&s=bar=aaa'));
console.log(getLastUrlSegment('https://x.com/boo?q=foo#this'));
console.log(getLastUrlSegment('https://x.com/last segment with spaces'));
Works for me.

Or you could use a regular expression:
alert(href.replace(/.*\//, ''));

var urlChunks = 'mywebsite/folder/file'.split('/');
alert(urlChunks[urlChunks.length - 1]);

Returns the last segment, regardless of trailing slashes:
var val = 'http://mywebsite/folder/file//'.split('/').filter(Boolean).pop();
console.log(val);

I know, it is too late, but for others:
I highly recommended use PURL jquery plugin. Motivation for PURL is that url can be segmented by '#' too (example: angular.js links), i.e. url could looks like
http://test.com/#/about/us/
or
http://test.com/#sky=blue&grass=green
And with PURL you can easy decide (segment/fsegment) which segment you want to get.
For "classic" last segment you could write:
var url = $.url('http://test.com/dir/index.html?key=value');
var lastSegment = url.segment().pop(); // index.html

Get the Last Segment using RegEx
str.replace(/.*\/(\w+)\/?$/, '$1');
$1 means using the capturing group. using in RegEx (\w+) create the first group then the whole string replace with the capture group.
let str = 'http://mywebsite/folder/file';
let lastSegment = str.replace(/.*\/(\w+)\/?$/, '$1');
console.log(lastSegment);

Also,
var url = $(this).attr("href");
var part = url.substring(url.lastIndexOf('/') + 1);

Building on Frédéric's answer using only javascript:
var url = document.URL
window.alert(url.substr(url.lastIndexOf('/') + 1));

If you aren't worried about generating the extra elements using the split then filter could handle the issue you mention of the trailing slash (Assuming you have browser support for filter).
url.split('/').filter(function (s) { return !!s }).pop()

window.alert(this.pathname.substr(this.pathname.lastIndexOf('/') + 1));
Use the native pathname property because it's simplest and has already been parsed and resolved by the browser. $(this).attr("href") can return values like ../.. which would not give you the correct result.
If you need to keep the search and hash (e.g. foo?bar#baz from http://quux.com/path/to/foo?bar#baz) use this:
window.alert(this.pathname.substr(this.pathname.lastIndexOf('/') + 1) + this.search + this.hash);

To get the last segment of your current window:
window.location.href.substr(window.location.href.lastIndexOf('/') +1)

you can first remove if there is / at the end and then get last part of url
let locationLastPart = window.location.pathname
if (locationLastPart.substring(locationLastPart.length-1) == "/") {
locationLastPart = locationLastPart.substring(0, locationLastPart.length-1);
}
locationLastPart = locationLastPart.substr(locationLastPart.lastIndexOf('/') + 1);

var pathname = window.location.pathname; // Returns path only
var url = window.location.href; // Returns full URL
Copied from this answer

// Store original location in loc like: http://test.com/one/ (ending slash)
var loc = location.href;
// If the last char is a slash trim it, otherwise return the original loc
loc = loc.lastIndexOf('/') == (loc.length -1) ? loc.substring(0,loc.length-1) : loc.substring(0,loc.lastIndexOf('/'));
var targetValue = loc.substring(loc.lastIndexOf('/') + 1);
targetValue = one
If your url looks like:
http://test.com/one/
or
http://test.com/one
or
http://test.com/one/index.htm
Then loc ends up looking like:
http://test.com/one
Now, since you want the last item, run the next step to load the value (targetValue) you originally wanted.
var targetValue = loc.substr(loc.lastIndexOf('/') + 1);
// Store original location in loc like: http://test.com/one/ (ending slash)
let loc = "http://test.com/one/index.htm";
console.log("starting loc value = " + loc);
// If the last char is a slash trim it, otherwise return the original loc
loc = loc.lastIndexOf('/') == (loc.length -1) ? loc.substring(0,loc.length-1) : loc.substring(0,loc.lastIndexOf('/'));
let targetValue = loc.substring(loc.lastIndexOf('/') + 1);
console.log("targetValue = " + targetValue);
console.log("loc = " + loc);

Updated raddevus answer :
var loc = window.location.href;
loc = loc.lastIndexOf('/') == loc.length - 1 ? loc.substr(0, loc.length - 1) : loc.substr(0, loc.length + 1);
var targetValue = loc.substr(loc.lastIndexOf('/') + 1);
Prints last path of url as string :
test.com/path-name = path-name
test.com/path-name/ = path-name

I am using regex and split:
var last_path = location.href.match(/./(.[\w])/)[1].split("#")[0].split("?")[0]
In the end it will ignore # ? & / ending urls, which happens a lot. Example:
https://cardsrealm.com/profile/cardsRealm -> Returns cardsRealm
https://cardsrealm.com/profile/cardsRealm#hello -> Returns cardsRealm
https://cardsrealm.com/profile/cardsRealm?hello -> Returns cardsRealm
https://cardsrealm.com/profile/cardsRealm/ -> Returns cardsRealm

I don't really know if regex is the right way to solve this issue as it can really affect efficiency of your code, but the below regex will help you fetch the last segment and it will still give you the last segment even if the URL is followed by an empty /. The regex that I came up with is:
[^\/]+[\/]?$

I know it is old but if you want to get this from an URL you could simply use:
document.location.pathname.substring(document.location.pathname.lastIndexOf('/.') + 1);
document.location.pathname gets the pathname from the current URL.
lastIndexOf get the index of the last occurrence of the following Regex, in our case is /.. The dot means any character, thus, it will not count if the / is the last character on the URL.
substring will cut the string between two indexes.

if the url is http://localhost/madukaonline/shop.php?shop=79
console.log(location.search); will bring ?shop=79
so the simplest way is to use location.search
you can lookup for more info here
and here

You can do this with simple paths (w/0) querystrings etc.
Granted probably overly complex and probably not performant, but I wanted to use reduce for the fun of it.
"/foo/bar/"
.split(path.sep)
.filter(x => x !== "")
.reduce((_, part, i, arr) => {
if (i == arr.length - 1) return part;
}, "");
Split the string on path separators.
Filter out empty string path parts (this could happen with trailing slash in path).
Reduce the array of path parts to the last one.

Adding up to the great Sebastian Barth answer.
if href is a variable that you are parsing, new URL will throw a TypeError so to be in the safe side you should try - catch
try{
const segments = new URL(href).pathname.split('/');
const last = segments.pop() || segments.pop(); // Handle potential trailing slash
console.log(last);
}catch (error){
//Uups, href wasn't a valid URL (empty string or malformed URL)
console.log('TypeError ->',error);
}

I believe it's safer to remove the tail slash('/') before doing substring. Because I got an empty string in my scenario.
window.alert((window.location.pathname).replace(/\/$/, "").substr((window.location.pathname.replace(/\/$/, "")).lastIndexOf('/') + 1));

Bestway to get URL Last Segment Remove (-) and (/) also
jQuery(document).ready(function(){
var path = window.location.pathname;
var parts = path.split('/');
var lastSegment = parts.pop() || parts.pop(); // handle potential trailing slash
lastSegment = lastSegment.replace('-',' ').replace('-',' ');
jQuery('.archive .filters').before('<div class="product_heading"><h3>Best '+lastSegment+' Deals </h3></div>');
});

A way to avoid query params
const urlString = "https://stackoverflow.com/last-segment?param=123"
const url = new URL(urlString);
url.search = '';
const lastSegment = url.pathname.split('/').pop();
console.log(lastSegment)

How to parse a url using Javascript and Regular Expression?

I want to parse some urls's which have the following format :-
var url ="http://www.example.com/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p&mycracker=ch_vn_clothing_subcategory_Puma&ref=b41c8097-8efe-4acf-8919-0fa81bcb590a"
Its not necessary that the domain name and other parts would be same for all url's, they can vary i.e I am looking at a general solution.
Basically I want to strip off all the other things and get only the part:
/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p
I thought to parse this using JavaScript and Regular Expression
I am doing like this:
var mapObj = {"/^(http:\/\/)?.*?\//":"","(&mycracker.+)":"","(&ref.+)":""};
var re = new RegExp(Object.keys(mapObj).join("|"),"gi");
url = url.replace(re, function(matched){
return mapObj[matched];
});
But its returning this
http://www.example.com/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43pundefined
Where am I not doing the correct thing? Or is there another approach with an even easier solution?

You can use :
/(?:https?:\/\/[^\/]*)(\/.*?)(?=\&mycracker)/
Code :
var s="http://www.example.com/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p&mycracker=ch_vn_clothing_subcategory_Puma&ref=b41c8097-8efe-4acf-8919-0fa81bcb590a";
var ss=/(?:https?:\/\/[^\/]*)(\/.*?)(?=\&mycracker)/;
console.log(s.match(ss)[1]);
Demo
Fiddle Demo
Explanation :

Why don't you just map a split array?
You don't quite need to regex the URL, but you will have to run an if statement inside the loop to remove specific GET params from them. In this particular case (key word particular) you just have to substring till the indexOf "&mycracker"
var url ="http://www.example.com/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p&mycracker=ch_vn_clothing_subcategory_Puma&ref=b41c8097-8efe-4acf-8919-0fa81bcb590a"
var x = url.split("/");
var y = [];
x.map(function(data,index) { if (index >= 3) y.push(data); });
var path = "/"+y.join("/");
path = path.substring(0,path.indexOf("&mycracker"));

Change the following code a little bit and you can retrieve any parameter:
var url = "http://www.example.com/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p&mycracker=ch_vn_clothing_subcategory_Puma&ref=b41c8097-8efe-4acf-8919-0fa81bcb590a"
var re = new RegExp(/http:\/\/[^?]+/);
var part1 = url.match(re);
var remain = url.replace(re, '');
//alert('Part1: ' + part1);
var rf = remain.split('&');
// alert('Part2: ' + rf);
var part2 = '';
for (var i = 0; i < rf.length; i++)
if (rf[i].match(/(p%5B%5D|sid)=/))
part2 += rf[i] + '&';
part2 = part2.replace(/&$/, '');
//alert(part2)
url = part1 + part2;
alert(url);

var url ="http://www.example.com/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p&mycracker=ch_vn_clothing_subcategory_Puma&ref=b41c8097-8efe-4acf-8919-0fa81bcb590a";
var newAddr = url.substr(22,url.length);
// newAddr == "/cooks/cooking-dress-wine/~no-order/pr?p%5B%5D=sort%3Dfeatured&sid=bks%2C43p&mycracker=ch_vn_clothing_subcategory_Puma&ref=b41c8097-8efe-4acf-8919-0fa81bcb590a"
22 is where to start slicing up the string.
url.length is how much of it to include.
This works as long as the domain name remains the same on the links.