I have (and need) one on click cycler-through-images and use this piece of code for this purpose:
$(".wrapper").on("click", function() {
var $content = $(this).find(".content_stack");
if ($content.length > 1) {
var $curr = $content.filter(":visible");
var $next = $curr.is($content.last()) ? $content.first() : $curr.next();
$curr.fadeOut(1000, function() {
$next.fadeIn(1000)
})
}
});
^ JSFiddle
And I have also found on SO (and "adapted") an automatic "twin" for it:
$(".wrapper").each(function() {
var $crossfade = $(this).find(".crossfade_square");
var $zindex = -1;
function loop() {
++$zindex;
$crossfade.eq($zindex % $crossfade.length)
.fadeIn(1000)
.delay(2000)
.fadeOut(1000, loop);
}
loop();
});
^ JSFiddle
UPDATE: Both are working as intended, separately. I need both of them (on click version and automatic version of cycling images). The codes are so different because I can't tweak either of them to work for both cases.:|
The problem: complete fade out>>fade in looks too distracting/"flickering"/"abrupt".
I would greatly appreciate if someone can help me make the crossfade smoother/more subtle/...like one image is turning into another... (if it is possible without adding absolute/relative position in CSS).
Use one function to loop and handle click event.
I split animation in to functions with queue of functions. If FadeIn being called by .onclick the queue is being cleared by .stop(true) method to stop animation and drop the queue.
$(".wrapper").each(function() {
var $this = $(this),
$curr = null,
$crossfade = $this.find(".crossfade_square");
var zindex = -1,
length = $crossfade.length;
function fadeOut() {
if($curr)
$curr.stop(true, false)
.fadeOut(1000, fadeIn);
else
fadeIn();
}
function fadeIn() {
++zindex;
$curr = $crossfade.eq(zindex % length)
.fadeIn(1000)
.delay(5000)
.queue(fadeOut);
}
$this.on("click", fadeOut);
fadeIn();
});
I have updated JSFiddle sample.
Related
This seems like something that should be really simple. I have a few images animating on a page, but I want the user to be able to click on any one of them at any time and then go to a related page.
Problem is, evidently clicks stopped being listened for at some point if I use a loop to search through an array of clickable items. I thought having a function separate from the one that handles the animation would allow it to constantly listen no matter what the animated images were doing, but it seems once the "complete" function is called (for the "animate" function), the function that is listening for clicks (wholly separate from the animation, and using setInterval to listen for clicks) stops listening.
Oddly enough, I believe I did not have this problem when just listening for "img" instead of an array of different images.
Ideas as to what I'm doing wrong? More info needed? I tried to remove any irrelevant code below.
var links = ["#portfolio", "#animations", "#games"];
$(function() {
setInterval(function(){
for (var i=0; i<links.length; i++) {
$(links[i]).click(function(){
window.location.replace("http://www.gog.com");
});
}
}, 500);
});
$(document).ready(function() {
links.forEach(function(current){
//various vars
var link = $(current);
var footer3 = $(".footer3");
var over = true;
var randomTime = 3000*(Math.random()+1);
//dust vars
...
//image vars
var imageUrlShadow = 'images/home/non-char/shadow-pngs/shadow';
var imageUrlCharacter = 'images/home/char-pngs/';
var portfolioSrc;
var animationsSrc;
var gamesSrc;
//animate the characters
link.animate({
top: '0'
}, {
duration: randomTime,
easing: 'easeOutBounce',
step: function(now, tween) {
/*handle shadows*/
...
/*handle characters*/
if (now < -25 && over == false) {
...
} else if (now >= -25) {
...
}
$("#"+ link.data("portfolio")).attr('src', portfolioSrc);
$("#"+ link.data("animations")).attr('src', animationsSrc);
$("#"+ link.data("games")).attr('src', gamesSrc);
/*handle dust*/
var dustDoneMoving = '-50px';
var dustNotMoving = '0px';
//if link is NOT touching footer3
...
//set to "sitting" images when animation is done
complete: function() {
...
setTimeout(function() {
...
}, 1000);
}
})
})
});
var links = ["#portfolio", "#animations", "#games"];
$(function() {
$(links.join(',')).click(function(){
window.location.replace("http://www.gog.com");
});
});
One time only and listener will be attached to the image.
Consider listening via window
var links = ["#portfolio", "#animations", "#games"];
$(window).on('click', links.join(', '), function() {
// do what you wanna
});
I apologize, it turns out that, apparently, the problem was related to the z-index. There were some other divs with 0 opacity "covering up" the array divs.
Setting the z-index to 2 for the array items has fixed the matter. Again, my apologies.
I have modified your code. See, if this works now.
I have added one more array which contains some URLs. So, the intention is that on click of a particular element, its respective URL should be opened.
So, the sequence in these array will matter with respect to each other.
Also, I have made use of 'on', so that 'click' event should be handled even during animation.
var links = ["#portfolio", "#animations", "#games"];
var sites = ["http://www.gog.com", "http://www.gog1.com", "http://www.gog2.com"]; //change these to the expected URLs
$(function() {
for (var i=0; i<links.length; i++) {
$(document ).on("click",links[i],function(){
window.location.replace(sites[i]);
});
}
});
Hi I have problem with my slider please visit this site and check http://paruyr.bl.ee/
after click on my arrows it becomes work in an asynchronous way, ones it changes very fast and then slow and it repeats.
I think it is from start slider and stop slider.
var sliderPrev = 0,
sliderNext = 1;
$("#slider > img").fadeIn(1000);
startSlider();
function startSlider(){
count = $("#slider > img").size();
loop = setInterval(function(){
if (sliderNext>(count-1)) {
sliderNext = 0;
sliderPrev = 0;
};
$("#slider").animate({left:+(-sliderNext)*100+'%'},900);
sliderPrev = sliderNext;
sliderNext=sliderNext+1;
},6000)
}
function prev () {
var newSlide=sliderPrev-1;
showSlide(newSlide);
}
function next () {
var newSlide=sliderPrev+1;
showSlide(sliderNext);
}
function stopLoop () {
window.clearInterval(loop);
}
function showSlide(id) {
stopLoop();
if (id>(count-1)) {
id = 0;
} else if(id<0){
id=count-1;
}
$("#slider").animate({left:+(-id)*100+'%'},900);
sliderPrev = id;
sliderNext=id+1;
startSlider();
};
$("#slider, .arrows").hover(function() {
stopLoop()
}, function() {
startSlider()
});
function onlyNext () {
var newSlide=sliderPrev+1;
onlyShowSlide(newSlide);
}
function onlyShowSlide(id) {
if (id>(count-1)) {
id = 0;
} else if(id<0){
id=count-1;
}
$("#slider").animate({left:+(-id)*100+'%'},900);
sliderPrev = id;
sliderNext=id+1;
};
I think the best option would be to check if the animation is in progress and prevent the action if it is, something like this:
function prev () {
if(!$('#slider').is(":animated"))
{
var newSlide=sliderPrev-1;
showSlide(newSlide);
}
}
function next () {
if(!$('#slider').is(":animated"))
{
var newSlide=sliderPrev+1;
showSlide(sliderNext);
}
}
To illustrate the difference between this and just sticking a stop() in, check this JSFiddle. You will notice some choppy movements if you click multiple times in the stop() version.
What I would do is add a class to your slider when the animation starts and remove the class when it finishes:
$("#slider").animate({left:+(-id)*100+'%'}, {
duration: 900,
start: function() {
$('#slider').addClass('blocked');
},
complete: function() {
$('#slider').removeClass('blocked');
}
});
Now check on each click event if the slider is blocked or not:
function next () {
if (!$('#slider').hasClass('blocked')) {
var newSlide=sliderPrev+1;
showSlide(sliderNext);
}
}
This is a very simple solution, I'm sure there is a better one.
EDIT: As marcjae pointed out, you could stop the animations from queuing. This means when you double click, the slideshow still will move 2 slides. With my approach the second click will be ignored completely.
You can use a variable flag to control if the animation is still being done, or simply use .stop() to avoid stacking the animation.
$("#pull").click(function(){
$("#togle-menu").stop().slideToggle("slow");
});
It is occurring because your animations are being queued.
Try adding:
.stop( true, true )
Before each of your animation methods. i.e.
$("#slider").stop( true, true ).animate({left:+(-id)*100+'%'},900);
The answers about stop are good, but you have a bigger issue that is causing the described behavior. The issue is here:
$("#slider, .arrows").hover(function() {
stopLoop()
}, function() {
startSlider()
});
You have bound this to the .arrows as well as the #slider and the arrows are contained within the slider. So, when you mouse out of an arrow and then out of the entire slider, you are calling start twice in a row without calling stop between. You can see this if you hover onto the arrow and then off of the slider multiple times in a row. The slides will change many times after 6 seconds.
Similarly, consider the case of a single click:
Enter the `#slider` [stopLoop]
Enter the `.arrows` [stopLoop]
Click the arrow [stopLoop]
[startSlider]
Leave the `.arrows` [startSlider]
Leave the `#slider` [startSlider]
As you can see from this sequence of events, startSlider is called 3 times in a row without calling stopLoop inbetween. The result is 3 intervals created, 2 of which will not be stopped the next time stopLoop is called.
You should just have this hover on the #slider and more importantly, add a call to stopLoop as the first step in startSlider. That will ensure that the interval is always cleared before creating a new one.
$("#slider").hover(function() {
stopLoop()
}, function() {
startSlider()
});
function startSlider(){
stopLoop();
/* start the slider */
}
What I need to achieve is if we click on submit button, there is particular div should show up.
Here is my code:
http://jsfiddle.net/7tn5d/
But if I click on submit button multiple times, the function calls sort of queue up and run one after other.
Is there a way to invalidate other onclicks when current animation is running?
Code:
animating = 0;
doneanim = 0;
$(function () {
$("#submit_tab").click(function (e) {
if (animating == 1) return;
animating = 1;
$("#submit_cont").show("blind", {}, 1000);
animating = 0;
});
});
To prevent it from performing the action multiple times, simple cease the previous animation. So:
$('#submit_cont').stop().show("blind",{},1000);
However, I have noticed that you have attempted to prevent the animation from running, if an animation is already running. Although it takes 1 second or 1000 milliseconds to show the div, the execution of the condition does not pause until the animation is complete. You must define a function to run after the animation is complete, like so:
animating = 0;
doneanim = 0;
$(function () {
$("#submit_tab").click(function (e) {
if (animating == 1) return;
animating = 1;
$("#submit_cont").show("blind", 1000, function() { animation = 0; });
});
});
Hope that helped...
You almost got it right with the semaphore! It's just that, in jQuery's show(), you would have to put the semaphore reset as an argument. Here's the fixed version - http://jsfiddle.net/snikrs/xe5A3/
animating = 0;
doneanim = 0;
$(function () {
$("#submit_tab").click(function (e) {
if (animating == 1) return;
animating = 1;
$("#submit_cont").show("blind", 1000, function() {
animating = 0;
});
});
});
You can use the :animated selector to check:
$(function () {
$("#submit_tab").click(function (e) {
var $cont = $("#submit_cont");
if (!$cont.is(':animated')) {
$cont.show("blind", {}, 1000);
}
});
});
Now if you stick with the external semaphore idea then its better to stick that on the elemnt with .data() instead of using a global variable:
$(function () {
$("#submit_tab").click(function (e) {
var $cont = $('#submit_cont'),
animating = $cont.data('isAnimating');
if (animating) {
return;
} else {
$cont.data('isAnimating', 1);
$("#submit_cont").show("blind", 1000, function() { $cont.data('isAnimating', 0); });
}
});
});
Something like this (see documentation) :)
$("#submit_cont").show("blind", function(){
animating = 0;
});
You can add a $("#submit_cont").clearQueue(); after the animation finished :
$("#submit_tab").click(function (e) {
$("#submit_cont").show("blind", 1000, function() {
$("#submit_cont").clearQueue();
});
});
Updated JSFiddle
I found a different solution for this, which in my opinion looks cleaner:
var tab = $("submit_tag");
tab.on("click", function(){
var cont = $("submit_cont");
var animating = tab.queue("fx").length;
if(animating === 0){
cont.show("blind", {}, 1000);
}
});
There are three images that I have made a tooltip for each.
I wanted to show tooltips within timed intervals say for 2 seconds first tooltip shows and for the second interval the 2nd tooltips fades in and so on.
for example it can be done with this function
function cycle(id) {
var nextId = (id == "block1") ? "block2": "block1";
$("#" + id)
.delay(shortIntervalTime)
.fadeIn(500)
.delay(longIntervalTime)
.fadeOut(500, function() {cycle(nextId)});
}
now what i want is to stop the cycle function when moseover action occurs on each of the images and show the corresponding tooltip. And again when the mouse went away again the cycle function fires.
If I understand everthing correctly, than try this code. Tt stops the proccess if you hover the image and continues if you leave the image. The stop() function will work on custom functions if you implement them like the fadeOut(), slideIn(), ... functions of jquery.
$('#' + id)
.fadeIn(500, function () {
var img = $(this).find('img'),
self = $(this),
fadeOut = true;
img.hover(function () {
fadeOut = false;
},
function () {
window.setTimeout(function () {
self.fadeOut(500);
}, 2000);
}
);
window.setTimeout(function () {
if (fadeOut === false) {
return;
}
self.fadeOut(500);
}, 2000);
});
I have been sitting on this for a few hours and cannot figure this out. I am trying to create an slideshow (3 slides) that loops endlessly. Each slide is a li inside #slideshow. I have walked through this with a debugger and all variables get set correctly, but I don't understand why the animations dont actually happen. I have this which ends up displaying all images on the page:
$(document).ready(function() {
$slideshow = $('#slideshow');
$slideshowItems = $slideshow.find('li');
$slideshowItems.hide();
nextI = function(x) {
if ((x+1) < $slideshowItems.length) {
return x+1;
}
else {
return 0;
}
}
animation = function(i) {
$slideshowItems.eq(i).fadeIn(500).delay(1000).fadeOut(500, animation(nextI(i)));
}
animation(0);
If I do:
$slideshowItems.eq(0).fadeIn(500).delay(1000).fadeOut(500,
$slideshowItems.eq(1).fadeIn(500).delay(1000).fadeOut(500,
$slideshowItems.eq(2).fadeIn(500).delay(1000).fadeOut(500));
This works as expected, but it seems ugly and does not loop.
Any idea why I can't get this to work? I feel it is something with my expectations of how JQuery/ JS modifies the DOM or the sequence that the browser uses to execute animations. Thank you for the help!
var $slideshowItems = $('#slideshow').find('li'),
i = 0;
(function loop() {
$slideshowItems.eq( i ).fadeIn(500).delay(1000).fadeOut(500, loop);
i = ++i % $slideshowItems.length;
})();
JSFIDDLE DEMO
You should specify a callback method but your "animation(nextI(i))" returns nothing, so nothing remains to do after the fade out is complete.
Something like this I think will work:
var animation = function(i) {
$slideshowItems.eq(i).fadeIn(500).delay(1000).fadeOut(500, function (){
animation(nextI(i));
});
}
I would try setting that as a function and then using setInterval:
setInterval(function(){
$slideshowItems.eq(0).fadeIn(500).delay(1000).fadeOut(500, function() {
$slideshowItems.eq(1).fadeIn(500).delay(1000).fadeOut(500, function() {
$slideshowItems.eq(2).fadeIn(500).delay(1000).fadeOut(500);
});
});
}, 6000); // 6000 milliseconds before loops