I am trying to send a image with AJAX.Though I keep on getting this error.
TypeError: 'append' called on an object that does not implement interface FormData.
This is my code:
$(document).ready(function(){
$('#post').on('submit', function(e){
e.preventDefault();
var data = new FormData(this);
$.ajax(
{
url: 'post_ajax/savePost',
type: 'POST',
dataType: false,
contentType: false,
pocessData: false,
data: data,
success: function (resultado) {
console.log(resultado)
}
}
).done(
function(json){
if(json.data){
console.log('Ajax correcto');
}else{
console.log('No se ha podido guardar el post');
}
}
).fail(
function(){
console.log('fallo en ajax');
}
);
});
});
And this is my html form:
<form id="post" enctype='multipart/form-data'>
<textarea id="texto" rows="4" cols="50" placeholder="¿Que esta pasando?"></textarea>
<input type="file" id="media"/>
<input type="submit" value="Submit"/>
</form>
Thanks you!!
I found this answer here:
var formData = new FormData(form[0]);
formData.append('texto', texto);
formData.append('media', archivo);
$.ajax({
url: 'post_ajax/savePost',
data: formData,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
console.log(data);
}
});
Thanks everyone for all
Related
Can anyone help my code structure? What's wrong with it?
HTML
<form method="post">
<div class="col-md-4">
<div class="field name-box">
<input class="btn" name="image_file" id="image_file" type="file" style="font-size:15px;width:100%;margin-bottom:2px;" required=""/>
</div>
</div>
</form>
JS
var form_data = new FormData();
$.ajax({
type: "POST",
url: baseUrlAction() + '?btn=add_product_image',
data: form_data,
contentType: false,
cache: false,
processData:false,
success: function(data){
alert("Successfully");
},
error: function(ts){
}
});
AJAX_CONTROLLER
public function add_product_image(){
if(is_array($_FILES)){
if(is_uploaded_file($_FILES['image_file']['tmp_name'])){
$sourcePath = $_FILES['image_file']['tmp_name'];
$targetPath = "product_images/"."sample_img_name".".png";
if(move_uploaded_file($sourcePath,$targetPath)){
// echo '<script>alert("Successfully Save")</script>';
}
}
}
}
But I've been wondering why I will get a success response on my ajax form? even my upload_file doesn't work properly. Can anyone help me?
you need to append data with form_data in your js file and send response
formData.append('image_file', $('#image_file')[0].files[0];);
var form_data = new FormData();
formData.append('image_file', $('#image_file')[0].files[0]);
$.ajax({
type: "POST",
url: baseUrlAction() + '?btn=add_product_image',
data: form_data,
contentType: false,
cache: false,
processData:false,
success: function(data){
alert("Successfully");
},
error: function(){
}
});
pass form Element to FormData
let form = document.getElementById("yourFormId");
var form_data = new FormData(form);
I have this form:
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.12.0/jquery.min.js"> </script>
<link rel="stylesheet" href="https://ajax.googleapis.com/ajax/libs/jqueryui/1.11.4/themes/smoothness/jquery-ui.css">
<div class='col-sm-6' style="padding-left:0px;" >
<form action="/main/" method="post" id="my_form" enctype="multipart/form-data">
{% csrf_token %}
<br>
<div> <input type="text" name="description" id="id_description" /> </div>
<div> <input type="file" name="image" id="id_image" /> </div>
<button type="submit" disabled style="display: none" aria-hidden="true"></button>
<input class="btn btn-success" type="submit" name="submit" value="Gem" />
</form>
</div>
This successfully sends the form and it is valid on the server side. But I can´t access the image from the form on the server.
<script>
var frm = $('#my_form');
frm.submit(function (e) {
e.preventDefault(e);
$.ajax({
async: true,
type: frm.attr('method'),
url: frm.attr('action'),
data: frm.serialize(),
success: function (data) {
console.log("success")
},
error: function(request, status, error) {
console.log("error")
}
});
});
</script>
This solution sends the FormData with the image file, but it does not include the other form data and the form is not valid on the server side:
<script type="text/javascript">
var frm = $('#my_form');
frm.submit(function (e) {
e.preventDefault(e);
var formData = new FormData();
formData.append(
"image",
document.getElementById("id_image").files[0]
);
$.ajax({
async: true,
type: frm.attr('method'),
url: frm.attr('action'),
data: formData,
cache: false,
processData: false,
contentType: false,
type: 'POST',
success: function (data) {
console.log("success")
},
error: function(request, status, error) {
console.log("error")
}
});
});
</script>
Is there a way to send both the file and the other form dara at the same time?
Try passing this to FormData Also, you were setting type twice.
var frm = $('#my_form');
frm.submit(function (e) {
e.preventDefault(e);
var formData = new FormData(this);
$.ajax({
async: true,
type: frm.attr('method'),
url: frm.attr('action'),
data: formData,
cache: false,
processData: false,
contentType: false,
success: function (data) {
console.log("success")
},
error: function(request, status, error) {
console.log("error")
}
});
});
Your last block using formData is only appending the file. This is why data only contains the file no other form data. Be sure to fully populate formData first.
I am trying to upload an image by using form data with ajax. Though below line seems to be working fine and saving the image on my local machine.
<form ref='uploadForm' id='uploadForm' action='/tab10/uploadImage' method='post' encType="multipart/form-data">
<input type="file" class="btn btn-default" name="file" />
<input type='submit' class="btn btn-default" value='Broadcast Image' />
</form>
But when instead of specifying action as a form attribute, i try to make the call using ajax, things didn't seem to be working fine.Below is the code that i am using to make the post API call using ajax.
HTML
<form ref='uploadForm' id='uploadForm' encType="multipart/form-data">
Jquery
$("form#uploadForm").submit(function (event) {
//disable the default form submission
event.preventDefault();
var formData = $(this).serialize();
console.log(formData);
$.ajax({
url: '/tab10/uploadImage',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function () {
alert('Form Submitted!');
},
error: function(){
alert("error in ajax form submission");
}
});
return false;
});
Below is the code i am using for saving the image.
exports.uploadImage = function(req, resp) {
var res = {};
let file = req.files.file;
file.mv('./images/image', function(err) {
if (err) {
res.status = 500;
res.message = err;
// return res.status(500).send(err);
return resp.send(res);
}
res.status = 200;
res.message = 'File uploaded!';
return resp.send(res);
});
};
When i checked the request data in my uploadimage function, it seems that in the request, parameter called "files" is not being send in the later case.
I think you have to create FormData, after you can append the file to the formData, add an ID to the input <input type="file" class="btn btn-default" name="file" id="uploadFile"/>
$("form#uploadForm").submit(function (event) {
//disable the default form submission
event.preventDefault();
var formData = new FormData();
formData.append('file',$('#uploadFile')[0].files[0]);
$.ajax({
url: '/tab10/uploadImage',
type: 'POST',
data: formData,
contentType: false,
processData: false,
success: function () {
alert('Form Submitted!');
},
error: function(){
alert("error in ajax form submission");
}
});
});
use
$("#uploadForm").submit(function () {
var formData = new FormData(this);
$.ajax({
url: '/tab10/uploadImage',
type: 'POST',
data: formData,
async: false,
cache: false,
contentType: false,
processData: false,
success: function () {
alert('Form Submitted!');
},
error: function(){
alert("error in ajax form submission");
}
});
return false;
});
Use this format to fire ajax.because file is multipart or jquery serialize() method not serialize multipart content,so we need to put it manual.
//get choosen file
var fileContent = new FormData();
fileContent.append("file",$('input[type=file]')[0].files[0]);
$.ajax({
type: "POST",
enctype:"multipart/form-data",
url: "/tab10/uploadImage",
data: fileContent,
processData: false,
contentType: false,
success: function(response) {
}
});
I'm having trouble getting an ajax-loaded form (#ajaxLoadedForm) to submit via ajax. The formData object gathers no data. I figure I've got to attach an event-handler to the form so the DOM recognizes it, but I can't figure out how.
A couple of notes: I'm bypassing the 'submit' method and using a button (#button), so I can't attach the handler to that. The form itself is a sibling to #button, not a child.
<form id="ajaxLoadedForm" enctype="multipart/form-data" action="destination.php" method="POST">
<input type="hidden" name="state" value="1" />
<label for="fullname">Your Full Name</label>
<input type="text" id="name" autocapitalize="off" autocorrect="off" name="fullname" placeholder="your name" value="" />
</form>
<div id="button">Submit me!</div>
$('#button').click(function(){
var uploadData = new FormData($("#ajaxLoadedForm")[0]);
jQuery.ajax({
url: 'destination.php',
data: uploadData,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
data = JSON.parse(data);
if (data['pass'] == false) {
console.log('fail');
} else {
console.log('success');
}
}
});
});
Try using the submit handler on the form itself
$('#ajaxLoadedForm').submit(function(e){
e.preventDefault();
var uploadData = new FormData(this);
});
Then make your button for submit a submit type
<button type='submit'>Submit</button>
In your php side, test the data coming by doing this:
print_r($_POST);
you can use serialize function for sending form data . Like below
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.2.1/jquery.min.js"></script>
<script >
$('#button').click(function(){
var uploadData = $('#ajaxLoadedForm').serialize();
jQuery.ajax({
url: 'destination.php',
data: uploadData,
cache: false,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
data = JSON.parse(data);
if (data['pass'] == false) {
console.log('fail');
} else {
console.log('success');
}
}
});
});
</script>
Try below code..
$('#button').click(function(){
var uploadData = new FormData();
uploadData.append('fullName',$('#fullName').val());
jQuery.ajax({
url: 'destination.php',
data: uploadData,
contentType: false,
processData: false,
type: 'POST',
success: function(data){
}
});
});
And try to access full name in php
Here is mycode
function addPackage(elem)
{
var dataimg = new FormData();
dataimg.append('', $("#browseimg"+elem).prop('files')[0]);
var startdate=$("#from_date"+elem).val();
var enddate=$("#to_date"+elem).val();
$.ajax({
url: "addpackage/",
type:"post",
contentType:false,
data:{startdate:startdate,enddate:enddate,packageid:elem,img:dataimg},
success: function(data) {
}
});
}
I tried post method ajax to upload image and input field data without form. In ajax call it showing [object object]. How to post image with input field without form in jquery ajax?
You can do it like following. Hope this will help you.
function addPackage(elem)
{
var dataimg = new FormData();
dataimg.append('startdate', $("#from_date"+elem).val());
dataimg.append('enddate', $("#to_date"+elem).val());
dataimg.append('packageid', elem);
dataimg.append('img', $("#browseimg"+elem)[0].files[0]);
$.ajax({
url: "addpackage/",
type:"post",
cache : false,
contentType : false,
processType : false,
data: dataimg,
success: function(data) {
}
});
}
You can try this:
Your JS Code:
<script type="text/javascript">
var data = new FormData(document.getElementById("yourFormID")); //your form ID
var url = $("#yourFormID").attr("action"); // action that you mention in form action.
$.ajax({
type: "POST",
url: url,
data: data,
enctype: 'multipart/form-data',
processData: false, // tell jQuery not to process the data
contentType: false, // tell jQuery not to set contentType
dataType: "json",
success: function(response)
{
// some code after succes from php
},
beforeSend: function()
{
// some code before request send if required like LOADING....
}
});
</script>
Dummy HTML:
<form method="post" action="addpackage/" id="yourFormID">
<input type="text" name="firstvalue" value="some value">
<input type="text" name="secondvalue" value="some value">
<input type="file" name="imagevalue">
</form>
in addpackage php file:
print_r($_POST);
print_r($_FILES);