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Ajax select list

I want to retrive the result of this kind of data list with CakePHP 3
<?= $this->Form->select('notif_message',
[ 'oui' => 'oui', 'non' => 'non'], array('id' => 'notifmess')); ?>
<?= $this->Form->hidden('notifmessage', ['value' => $notif_message]) ;?>
The goal is when a user chosse a value, an Ajax call to this controller be done
public function notifmessage() // mise à jour des paramètres de notifications 0 = non, 1 = oui
{
if ($this->request->is('ajax')) {
$notifmessage = $this->request->data('notifmessage');
if($notifmessage == 'oui')
{
$new_notif_message = 'non';
}
else
{
$new_notif_message = 'oui';
}
$query = $this->Settings->query()
->update()
->set(['notif_message' => $new_notif_message])
->where(['user_id' => $this->Auth->user('username') ])
->execute();
$this->response->body($new_notif_message);
return $this->response;
}
}
And i would like to do this call in Ajax without reloading , i have this script
<script type="text/javascript">
$(document).ready(function() {
$('.notif_message').change(function(){
$.ajax({
type: 'POST',
url: '/settings-notif_message',
data: 'select.notif_message' + val,
success: function(data) {
alert('ok');
},
error: function(data) {
alert('fail');
}
});
});
});
</script>
he doesn't work, nothing happend but i don't know why, i don't have any message in log, i can't debug without indication what doesn't not work
Thanks

In yout javascript you should use $('#notifmess').change(… or $('[notif_message]').change(… instead of $('.notif_message').change(….
In CakePHP the first argument of the select method will be used as the name attribute of the select tag.
Update:
In your controller you are retrieving the value of $_POST['notifmessage'], which is the name of the hidden input field.
To get the user's choice you either should use $this->request->data('notif_message'); in the controller, or setting up the ajax request to send the data with notifmessage like so:
$('[name="notif_message"]').change(function(){
$.ajax({
type: 'POST',
url: '/settings-notif_message',
data: {'notifmessage' : this.value},
success: function(data) {
// To change selected value to the one got from the server
$('#notifmess').val(data);
alert('ok');
},
error: function(data) {
alert('fail');
}
});
});
(Where in this case this is referring to <select> tag.)

i'm close to success: my ajax call is working, database update is working , i juste need to put the 'selected' to the other , i'm trying with this jquery code
<script type="text/javascript">
$(document).ready(function() {
$('#notifmess').change(function(){
var id = $('#notifmess').val();
$.ajax({
type: 'POST',
url: '/instatux/settings-notif_message',
data: {'id' : id},
success: function(data){
$('#notifmess option[value="'+data.id+'"]').prop('selected', true);
},
error: function(data)
{
alert('fail');
}
});
});
});

Laravel & Ajax - Insert data into table without refreshing

First of all, I have to say that I'm beginner with using Ajax... So help me guys.
I want to insert the data into db without refreshing the page. So far, I have following code...
In blade I have a form with an id:
{!! Form::open(['url' => 'addFavorites', 'id' => 'ajax']) !!}
<img align="right" src="{{ asset('/img/icon_add_fav.png')}}">
<input type="hidden" name = "idUser" id="idUser" value="{{Auth::user()->id}}">
<input type="hidden" name = "idArticle" id="idArticle" value="{{$docinfo['attrs']['sid']}}">
<input type="submit" id="test" value="Ok">
{!! Form::close() !!}
And in controller I have:
public function addFavorites()
{
$idUser = Input::get('idUser');
$idArticle = Input::get('idArticle');
$favorite = new Favorite;
$favorite->idUser = $idUser;
$favorite->idArticle = $idArticle;
$favorite->save();
if ($favorite) {
return response()->json([
'status' => 'success',
'idUser' => $idUser,
'idArticle' => $idArticle]);
} else {
return response()->json([
'status' => 'error']);
}
}
I'm trying with ajax to insert into database:
$('#ajax').submit(function(event){
event.preventDefault();
$.ajax({
type:"post",
url:"{{ url('addFavorites') }}",
dataType="json",
data:$('#ajax').serialize(),
success: function(data){
alert("Data Save: " + data);
}
error: function(data){
alert("Error")
}
});
});
Also in my web.php I have a route for adding favorites. But when I submit the form, it returns me JSON response like this: {"status":"success","idUser":"15","idArticle":"343970"}... It actually inserts into the db, but I want the page not to reload. Just to display alert box.

As #sujivasagam says it's performing a regular post action. Try to replace your javascript with this. I also recognized some syntax error but it is corrected here.
$("#ajax").click(function(event) {
event.preventDefault();
$.ajax({
type: "post",
url: "{{ url('addFavorites') }}",
dataType: "json",
data: $('#ajax').serialize(),
success: function(data){
alert("Data Save: " + data);
},
error: function(data){
alert("Error")
}
});
});
You could just replace <input type="submit"> with <button>instead and you'll probably won't be needing event.preventDefault() which prevents the form from posting.
EDIT
Here's an example of getting and posting just with javascript as asked for in comments.
(function() {
// Loads items into html
var pushItemsToList = function(items) {
var items = [];
$.each(items.data, function(i, item) {
items.push('<li>'+item.title+'</li>');
});
$('#the-ul-id').append(items.join(''));
}
// Fetching items
var fetchItems = function() {
$.ajax({
type: "GET",
url: "/items",
success: function(items) {
pushItemsToList(items);
},
error: function(error) {
alert("Error fetching items: " + error);
}
});
}
// Click event, adding item to favorites
$("#ajax").click(function(event) {
event.preventDefault();
$.ajax({
type: "post",
url: "{{ url('addFavorites') }}",
dataType: "json",
data: $('#ajax').serialize(),
success: function(data){
alert("Data Save: " + data);
},
error: function(data){
alert("Error")
}
});
});
// Load items (or whatever) when DOM's loaded
$(document).ready(function() {
fetchItems();
});
})();

You are using button type "Submit" which usually submit the form. So make that as button and on click of that call the ajax function

Change your button type to type="button" and add onclick action onclick="yourfunction()". and just put ajax inside your funciton.

Replace input type with button and make onClick listener. Make sure you use this input id in onclick listener:
So:
$('#test').on('click', function(event){
event.preventDefault()
... further code
I would also change the id to something clearer.

jQuery Ajax not sending Post data to PHP file

I'm trying to send variables from my JavaScript to a PHP file using AJAX but it's not working. I've looked through all the similar asked questions (there are a bunch) but have yet to find a solution.
This is my first php file (one with the form, sends data to JavaScript):
<option value="imageOne" data-cuteform-image='assets/SketchThumbnails/imageOne.png></option>
<input id="inputURLID" type="text" name="inputURL">
<button type="submit" onclick="handleInputs(document.getElementById('sketch').value, document.getElementById('inputURLID').value); return false;">Submit</button>
JavaScript (where AJAX call is):
var content = {
'sketch': pickedSketch,
'songUrl': enteredURL
};
$.ajax({
type: "POST",
url: "loadSketch.php",
data: content,
success: function (data, text) {
// alert("success");
// console.log(data);
// console.log(text);
window.location.href = "loadSketch.php";
},
error: function (request, status, error) {
alert(request.responseText);
}
});
PHP (loadSketch.php):
if(isset($_POST['songUrl']))
{
$temp = $_POST['songUrl'];
echo $temp;
echo "received AJAX data";
} else {
echo "nothing in post variable";
}
When I get redirected to loadSketch.php (from the successful ajax call), "nothing in post variable" gets echoed out. Any ideas what I'm doing wrong?
Any insight is much appreciated! :)

Nothing is in songURL because when your Ajax function returns it is redirecting to the same page you just posted to. It is creating a new HTTP request to that PHP file with no data sending to it. Remove the comments on the console messages and you'll see the correct echo messages.
$.ajax({
type: "POST",
url: "loadSketch.php",
data: content,
success: function (data, text) {
alert("success");
console.log(data);
},
error: function (request, status, error) {
alert(request.responseText);
}
});

You should not use a submit button because it makes the whole page reload; instead use normal buttons and handle the click events calling your AJAX function.
HTML:
<button onclick="doAjaxFunction(param1, param2);">Calling Ajax Function<button>
JavaScript:
function doAjaxFunction(val1,val2){
$.ajax({
type: "POST",
url: "loadSketch.php",
dataType: "json",
data: {"'value1':'"+ val1+"', 'value2':'"+ val2+"'"},
success: function (data, text) {
// alert("success");
// console.log(data);
// console.log(text);
window.location.href = "loadSketch.php";
},
error: function (request, status, error) {
alert(request.responseText);
}
});
Then just pick your POST parameters in loadSketch.php and use them.
PHP:
$x = $_POST['value1'];
$y = $_POST['value2'];

unable to get value in controller from jquery, ajax in php code igniter

AJAX:
$(document).ready(function () {
$('.my_button').click(function () {
var data = $(this).val();
//alert(BASE_URL);
$.ajax({
type: "POST",
ContentType: 'application/json',
data: data,
url: BASE_URL + 'index.php?deo/dashboard',
error: function () {
alert("An error occoured!");
},
success: function (msg) {
alert('result from controller');
}
});
alert(data);
});
});
CONTROLLER:
public function dashboard() {
$data = $this->input->post('data');
$data = json_decode($data);
echo "<script>alert('count ".$data."');</script>";
}
Am trying to send value from my jquery, ajax to controller, am able to get value from my view page to jquery page and able to print that. But unable to send the value from ajax page to controller page, after sending the data i got the success data. but unable to get and print the data in my controller page. Thanks in advance

If your using firefox a good thing to use is firebug add on and then you can use the console to check for errors on there. To see if the ajax has any errors while sending.
Remove question mark after index.php? and I think your base url is not working correct try just.
Url
// With index.php
url: 'index.php/deo/dashboard',
// Or without index.php
url: 'deo/dashboard',
Or
// With index.php
url: <?php echo site_url('index.php/deo/dashboard');?>,
// Or without index.php
url: <?php echo site_url('deo/dashboard');?>,
Script
$(document).ready(function () {
$('.my_button').click(function () {
var data = $(this).val();
$.ajax({
type: "POST",
data: data,
url: 'index.php/deo/dashboard',
// url: <?php echo site_url('index.php/deo/dashboard');?>,
success: function (msg) {
alert('result from controller');
},
error: function () {
alert("An error occoured!");
}
});
alert(data);
});
});
Controller
public function dashboard() {
$data = $this->input->post('data');
echo "<script>alert('count ".$data."');</script>";
}

How to Get Button to Trigger Ajax Request in Bootstrap

I have a modal form with Bootstrap that is associated with a specific item that is customized by the user before being added to the cart. I'm trying to trigger an Ajax request when the "Add to Cart" button is clicked. But the button doesn't seem to be triggering anything. I'm using a modified version of Bootstrap's sample code: http://getbootstrap.com/javascript/#modals-related-target
Any suggestions on how to get the button to trigger an ajax request properly?
UPDATE: I've added the PHP code below in case that might be the issue.
HTML:
<div class="modal-body">
<form name="formBasic" id="formBasic">
<input type="hidden" name="function" value="basic-form">
<div class="form-group">
<label for="message-text" class="control-label">Enter customized information</label>
<textarea class="form-control" id="customized-information"></textarea>
</div>
</form>
</div>
<div class="modal-footer">
<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
<button type="button" class="btn btn-primary" id="basic-submit">Add to Cart</button>
</div>
Javascript:
$(document).ready(function () {
var formBasic = function () {
var formData = $("#formBasic").serialize();
$(form).ajaxSubmit({
type: 'post',
data: formData,
dataType: 'json',
url: 'http://localhost/forms.php'
error: function () {
console.log(output);
alert("There was an error processing this page.");
return false;
},
complete: function (output) {
$('#formBasicResults').html(output.responseText);
}
});
return false;
};
$("#basic-submit").on("click", function (e) {
e.preventDefault();
formBasic();
});
});
PHP:
//formBasic Processing
function formBasic(){
$output = 'Output from Form Basic:
';
foreach ($_POST as $key => $value) {
$output .= $key . ': ' . $value . '
';
}
echo $output;
}
//FormAdvanced Processing
//. . .
if(in_array($_POST['function'], array('formBasic','formAdvanced'))){
$_POST['function']();
}else{
echo 'There was an error processing the form';
}

Your code should be:
$(document).ready(function () {
var formBasic = function () {
var formData = $("#formBasic").serialize();
$.ajax({
type: 'post',
data: formData,
dataType: 'json',
url: 'http://localhost/forms.php',
error: function () {
alert("There was an error processing this page.");
return false;
},
complete: function (output) {
$('#formBasicResults').html(output.responseText);
}
});
return false;
};
$("#basic-submit").on("click", function (e) {
e.preventDefault();
formBasic();
});
});
Issues:
1- Missing comma on line:
url: 'http://localhost/forms.php'
2- form not defined:
$(form).ajaxSubmit({
Working fiddle: http://jsfiddle.net/p9v2eg4u/2/

$('#basic-submit').click(function() {
var formData = $("#formBasic").serialize();
console.log(formData);
added a console.log(); of the value of form data
$('#formBasic').ajaxSubmit({
type: 'POST',
data: formData,
dataType: 'JSON',
url: 'http://localhost/forms.php',
added missing comma after URL
error: function () {
alert("There was an error processing this page.");
return false;
},
complete: function (output) {
console.log(output);
another console.log of output object
$('#formBasicResults').html(output.responseText);
},
success: function(output) {}
consider using success instead of complete, complete will execute if success or error.
});
return false;
});