First of all, I have to say that I'm beginner with using Ajax... So help me guys.
I want to insert the data into db without refreshing the page. So far, I have following code...
In blade I have a form with an id:
{!! Form::open(['url' => 'addFavorites', 'id' => 'ajax']) !!}
<img align="right" src="{{ asset('/img/icon_add_fav.png')}}">
<input type="hidden" name = "idUser" id="idUser" value="{{Auth::user()->id}}">
<input type="hidden" name = "idArticle" id="idArticle" value="{{$docinfo['attrs']['sid']}}">
<input type="submit" id="test" value="Ok">
{!! Form::close() !!}
And in controller I have:
public function addFavorites()
{
$idUser = Input::get('idUser');
$idArticle = Input::get('idArticle');
$favorite = new Favorite;
$favorite->idUser = $idUser;
$favorite->idArticle = $idArticle;
$favorite->save();
if ($favorite) {
return response()->json([
'status' => 'success',
'idUser' => $idUser,
'idArticle' => $idArticle]);
} else {
return response()->json([
'status' => 'error']);
}
}
I'm trying with ajax to insert into database:
$('#ajax').submit(function(event){
event.preventDefault();
$.ajax({
type:"post",
url:"{{ url('addFavorites') }}",
dataType="json",
data:$('#ajax').serialize(),
success: function(data){
alert("Data Save: " + data);
}
error: function(data){
alert("Error")
}
});
});
Also in my web.php I have a route for adding favorites. But when I submit the form, it returns me JSON response like this: {"status":"success","idUser":"15","idArticle":"343970"}... It actually inserts into the db, but I want the page not to reload. Just to display alert box.
As #sujivasagam says it's performing a regular post action. Try to replace your javascript with this. I also recognized some syntax error but it is corrected here.
$("#ajax").click(function(event) {
event.preventDefault();
$.ajax({
type: "post",
url: "{{ url('addFavorites') }}",
dataType: "json",
data: $('#ajax').serialize(),
success: function(data){
alert("Data Save: " + data);
},
error: function(data){
alert("Error")
}
});
});
You could just replace <input type="submit"> with <button>instead and you'll probably won't be needing event.preventDefault() which prevents the form from posting.
EDIT
Here's an example of getting and posting just with javascript as asked for in comments.
(function() {
// Loads items into html
var pushItemsToList = function(items) {
var items = [];
$.each(items.data, function(i, item) {
items.push('<li>'+item.title+'</li>');
});
$('#the-ul-id').append(items.join(''));
}
// Fetching items
var fetchItems = function() {
$.ajax({
type: "GET",
url: "/items",
success: function(items) {
pushItemsToList(items);
},
error: function(error) {
alert("Error fetching items: " + error);
}
});
}
// Click event, adding item to favorites
$("#ajax").click(function(event) {
event.preventDefault();
$.ajax({
type: "post",
url: "{{ url('addFavorites') }}",
dataType: "json",
data: $('#ajax').serialize(),
success: function(data){
alert("Data Save: " + data);
},
error: function(data){
alert("Error")
}
});
});
// Load items (or whatever) when DOM's loaded
$(document).ready(function() {
fetchItems();
});
})();
You are using button type "Submit" which usually submit the form. So make that as button and on click of that call the ajax function
Change your button type to type="button" and add onclick action onclick="yourfunction()". and just put ajax inside your funciton.
Replace input type with button and make onClick listener. Make sure you use this input id in onclick listener:
So:
$('#test').on('click', function(event){
event.preventDefault()
... further code
I would also change the id to something clearer.
Related
When I submit my form, the page gets redirected to a new window with the raw json object instead of showing the alerts that I have set up for testing. I'm guessing that it has something to do with returning a Json result from the controller, but I'm not experienced enough with ajax or json to know why this is happening.
Partial View (named _FooterButtons)
<div class="row col-12">
<div class="col-12 footerbuttons">
<button type="button" onclick="submit()" id="submit-form" class="btn btn-primary" value="Print" style="display: inline-block">Print</button>
<input type="button" class="btn btn-secondary" value="Cancel" />
</div>
</div>
Main View
#using (Html.BeginForm("Daily", "Reports", FormMethod.Post, new { id = "reportForm", #class = "report-form col-9" }))
{
...
<partial name="../Shared/_FooterButtons" />
}
JavaScript
$(document).ready(function () {
$("#startdatepicker").datepicker();
$("#enddatepicker").datepicker();
// Add the listener only when everything is loaded
window.onload = function () {
// Get the form
let rform = document.getElementById('reportForm');
console.log(rform);
// Add the listener
rform.addEventListener('submit', function (e) {
// Avoid normal form process, so no page refresh
// You'll receive and process JSON here, instead of on a blank page
e.preventDefault();
// Include here your AJAX submit:
console.log("Form submitted");
$.ajax({
type: 'POST',
data: $('#reportForm').serialize(),
url: '#Url.Action("Daily","Reports")',
contentType: 'application/json; charset=utf-8',
success: function (data) {
if (data.success) {
alert("Data Success");
} else {
alert("Data Fail");
$('#errorsModal').modal('toggle');
$('#errorsModal .modal-body label').html(data.message);
}
}
});
});
};
});
Controller
[HttpPost]
public IActionResult Daily(Daily dailyReport)
{
var dr = new ReportDaily();
var rc = new ReportDailyCriteria();
dr.Preview(rc, IntPtr.Zero, out Notification notification);
//dr.CreateReportAsPDF(ReportCriteria(), #"C:/");
if (notification.HasErrors)
{
return Json(new
{
success = false,
message = notification.GetConcatenatedErrorMessage(Environment.NewLine + Environment.NewLine)
});
}
return Json(new { success = true });
}
Json object that gets returned in a new window
{"success":false,"message":"Must select a payment Source, County and/or Municipal.\r\n\r\nMust select at least one payment type.\r\n\r\nMust select at least one user.\r\n\r\n"}
You need to avoid the normal form process and you have 2 options:
First: Add return false to onclick event.
<button type="button" onclick="submit(); return false" id="submit-form" class="btn btn-primary" value="Print" style="display: inline-block">Print</button>
This first option will be executed only if button is clicked, but maybe not if ENTER key is pressed while typing on an input.
Second and better option: Add an event listener to your form:
<script>
// Add the listener only when everything is loaded
window.onload = function() {
// Get the form
let rform = document.getElementById('reportForm');
// Add the listener
rform.addEventListener('submit', function(e) {
// Avoid normal form process, so no page refresh
// You'll receive and process JSON here, instead of on a blank page
e.preventDefault();
// Include here your AJAX submit:
console.log("Form submitted");
$.ajax({
type: 'POST',
data: $('#reportForm').serialize(),
url: '#Url.Action("Daily","Reports")',
contentType: 'application/json; charset=utf-8',
success: function (data) {
if (data.success) {
alert("Data Success");
} else {
alert("Data Fail");
$('#errorsModal').modal('toggle');
$('#errorsModal .modal-body label').html(data.message);
}
}
});
});
};
</script>
Edit: Since you're using jQuery .ready(), things are a bit different:
$(document).ready(function () {
$("#startdatepicker").datepicker();
$("#enddatepicker").datepicker();
// Not really sure if window.onload inside .ready() was the problem,
// but it could be
// Get the form and add the listener
$("#reportForm").on('submit', function (e) {
// Avoid normal form process, so no page refresh
// You'll receive and process JSON here, instead of on a blank page
e.preventDefault();
console.log("Form submitted");
$.ajax({
type: 'POST',
data: $('#reportForm').serialize(),
url: '#Url.Action("Daily","Reports")',
contentType: 'application/json; charset=utf-8',
success: function (data) {
if (data.success) {
alert("Data Success");
} else {
alert("Data Fail");
$('#errorsModal').modal('toggle');
$('#errorsModal .modal-body label').html(data.message);
}
}
});
});
});
I used a method similar to what Triby has suggested, but instead of adding an event listener on the form submit, I added one onto the submit button click.
I want to retrive the result of this kind of data list with CakePHP 3
<?= $this->Form->select('notif_message',
[ 'oui' => 'oui', 'non' => 'non'], array('id' => 'notifmess')); ?>
<?= $this->Form->hidden('notifmessage', ['value' => $notif_message]) ;?>
The goal is when a user chosse a value, an Ajax call to this controller be done
public function notifmessage() // mise à jour des paramètres de notifications 0 = non, 1 = oui
{
if ($this->request->is('ajax')) {
$notifmessage = $this->request->data('notifmessage');
if($notifmessage == 'oui')
{
$new_notif_message = 'non';
}
else
{
$new_notif_message = 'oui';
}
$query = $this->Settings->query()
->update()
->set(['notif_message' => $new_notif_message])
->where(['user_id' => $this->Auth->user('username') ])
->execute();
$this->response->body($new_notif_message);
return $this->response;
}
}
And i would like to do this call in Ajax without reloading , i have this script
<script type="text/javascript">
$(document).ready(function() {
$('.notif_message').change(function(){
$.ajax({
type: 'POST',
url: '/settings-notif_message',
data: 'select.notif_message' + val,
success: function(data) {
alert('ok');
},
error: function(data) {
alert('fail');
}
});
});
});
</script>
he doesn't work, nothing happend but i don't know why, i don't have any message in log, i can't debug without indication what doesn't not work
Thanks
In yout javascript you should use $('#notifmess').change(… or $('[notif_message]').change(… instead of $('.notif_message').change(….
In CakePHP the first argument of the select method will be used as the name attribute of the select tag.
Update:
In your controller you are retrieving the value of $_POST['notifmessage'], which is the name of the hidden input field.
To get the user's choice you either should use $this->request->data('notif_message'); in the controller, or setting up the ajax request to send the data with notifmessage like so:
$('[name="notif_message"]').change(function(){
$.ajax({
type: 'POST',
url: '/settings-notif_message',
data: {'notifmessage' : this.value},
success: function(data) {
// To change selected value to the one got from the server
$('#notifmess').val(data);
alert('ok');
},
error: function(data) {
alert('fail');
}
});
});
(Where in this case this is referring to <select> tag.)
i'm close to success: my ajax call is working, database update is working , i juste need to put the 'selected' to the other , i'm trying with this jquery code
<script type="text/javascript">
$(document).ready(function() {
$('#notifmess').change(function(){
var id = $('#notifmess').val();
$.ajax({
type: 'POST',
url: '/instatux/settings-notif_message',
data: {'id' : id},
success: function(data){
$('#notifmess option[value="'+data.id+'"]').prop('selected', true);
},
error: function(data)
{
alert('fail');
}
});
});
});
This is my code for Javascript Ajax Jquery send data do purchase item.
$('.reserve-button').click(function(e){
var book_id = $(this).parent().data('id');
e.preventDefault();
$.ajax({
url: "/php/insertpurchase.php",
type: "POST",//type of posting the data
data: {"bookID": book_id},
success: function (data) {
alertify.alert("This item was add to your cart.", function(){
alertify.message('OK');
});
},
error: function (result, status, err) {
console.log('error', err, status);
},
timeout : 15000//timeout of the ajax call
});
});
This is HTML code for submit.
<div class="col-md-4">
<?php $bookID = $row['id'];?>
<div class= "obutton feature2" data-id="<?php echo $bookID;?>">
<button class="reserve-button"><?php echo $row['price'];?></button>
In PHP dont receive POST value ->
if(isset($_POST['bookID']))
{
$idProduct = $_POST['bookID'];
I think you should to define this code:
success: function (data) {
console.log(data);
});
Replace of this code:
success: function (data) {
alertify.alert("This item was add to your cart.", function(){
alertify.message('OK');
});
Now you see what result you get in the console.
I am using the following code to get data from an input field and send it to PHP by POST but its not working
<script type="text/javascript">
$(document).ready(function () {
$("#id_1").change(function () {
var rat1 = $(this).val();
$.ajax({
url: "upload.php",
type: "post",
data: rat1,
success: function (response) {
// you will get response from your php page (what you echo or print)
},
error: function(jqXHR, textStatus, errorThrown) {
console.log(textStatus, errorThrown);
}
});
});
});
</script>
this is the input form
<input type="number" name="your_awesome_parameter" id="id_1" class="rating" data-clearable="remove"
data-icon-lib="fa" data-active-icon="fa-heart" data-inactive-icon="fa-heart-o"
data-clearable-icon="fa-trash-o"/>
You need to provide a name for the parameter. It should be:
data: { param_name: rat1 }
Then in upload.php you access it with $_POST['param_name']
Just in case, did you imported Jquery into your project?
I tested your code and I with the minor change that Barmar specified and it is working for me.
Try to use this code in your php file and see if you get any response in the developer tools console.
$data = $_POST["param_name"];
echo json_encode([$data]);
Try in this way men
function realizaProceso(valorCaja1, valorCaja2){
var parametros = {
"valorCaja1" : valorCaja1,
"valorCaja2" : valorCaja2
};
$.ajax({
data: parametros,
url: 'ejemplo_ajax_proceso.php',
type: 'post',
beforeSend: function () {
$("#resultado").html("Procesando, espere por favor...");
},
success: function (response) {
$("#resultado").html(response);
}
});
}
change on input type number is not working in older versions of browsers, I think not sure. But try this below solution as you are using input type number.
$("#id_1").on("mouseup keyup",function () {
//your logic here
});
and passing data as already mentioned by others:
data: { param_name: rat1 }
I'm using jQuery ajax call to post process a form.
I want to display a loading message or image while the form is processed and when the action is completed to display a complete message.
How can I do it?
This is my jQuery code.
$s('body').on('click', '#group-update', function() {
var formInputs = $s('input').serializeArray();
var groupId = $s(this).data('group');
var error = $s('#modal .info');
var tr = $s('#dataT-attrgroup').find('tr.on_update');
formInputs.push({
name: 'id',
value: groupId
});
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
success: function(data) {
if(data.response === false){
error.addClass('info-error');
error.html(data.message);
}else{
oTable.row(tr).data(data).draw();
$s('#modal').modal('hide');
tr.removeClass('on_update');
$s.growl.notice({
title: 'Success',
message: 'Grupul de atribute a fost actualizat'
});
}
}
});
});
Before ajax function display your loader and inside the success function from your ajax hide it.
As you can see in my example i inserted $('.loader').show(); and $('.loader').hide();
$('.loader').show();
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
success: function(data) {
if(data.response === false){
error.addClass('info-error');
error.html(data.message);
}else{
oTable.row(tr).data(data).draw();
$s('#modal').modal('hide');
tr.removeClass('on_update');
$s.growl.notice({
title: 'Success',
message: 'Grupul de atribute a fost actualizat'
});
}
$('.loader').hide();
}
});
According to the PHP docs:
The upload progress will be available in the $_SESSION superglobal when an upload is in progress, and when POSTing a variable of the same name as the session.upload_progress.name INI setting is set to. When PHP detects such POST requests, it will populate an array in the $_SESSION, where the index is a concatenated value of the session.upload_progress.prefix and session.upload_progress.name INI options. The key is typically retrieved by reading these INI settings, i.e.
You should take a look at : https://github.com/blueimp/jQuery-File-Upload/wiki/PHP-Session-Upload-Progress
I think this will definitely help you out!
Display your message just before launching $.ajax();
And close it in the success (and error) callback functions.
example :
$s('body').on('click', '#group-update', function() {
var formInputs = $s('input').serializeArray();
var groupId = $s(this).data('group');
var error = $s('#modal .info');
var tr = $s('#dataT-attrgroup').find('tr.on_update');
formInputs.push({
name: 'id',
value: groupId
});
var dlg = $s('<div/>').text('your message').dialog();
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
error:function() {
dlg.dialog('close');
},
success: function(data) {
dlg.dialog('close');
if(data.response === false){
error.addClass('info-error');
error.html(data.message);
}else{
oTable.row(tr).data(data).draw();
$s('#modal').modal('hide');
tr.removeClass('on_update');
$s.growl.notice({
title: 'Success',
message: 'Grupul de atribute a fost actualizat'
});
}
}
});
});
If you go through ajax section of jquery documentation you will notice some more method like success ie error, beforesend, complete etc. Here is the code snippet.
$s.ajax({
type: 'post',
url: 'index.php?controller=attribute&method=updateGroup',
data: formInputs,
dataType: 'JSON',
beforeSend : function(){
// load message or image
},
success: function(data) {
// write code as per requirement
},
complete : function(){
// load complete message where you previously added the message or image, as a result previous one will be overwritten
}
});