I have the object as,
var names =["LET_ABC","PET_DEF","Num_123","Num_456","SET_GHI","RET_JKL"];
Now i have to move the value which contains "Num" to the last which means after the "Num" value there should be no values.
This is how i add the value to the array,
result.each(function () {
var tempObject = {},
attributes = $(this).data();
names.push(attributes.prefix+ '_' + attributes.value)
});
Can i somehow manipulate the above code to make the "Num" values move at last.
I need something like,
var names =["LET_ABC","PET_DEF","SET_GHI","RET_JKL","Num_123","Num_456"];
for(var i=0;i<names.length;i++){
if(names[i].match("^Num")){
names.push(names.splice(i, 1)[0]);
}
}
Working example (with explanation in comments):-
var names =["LET_ABC","LET_DEF","Num_123","Num_456","LET_GHI","LET_JKL"];//your array
function movetoLast(names,checkword){// function with array and checking prefix
$(names).each(function(index,value){ // iterate over array
if(value.indexOf(checkword) >= 0){ // check value have that prefix or not in it
names.push(names.splice(names.indexOf(value), 1)[0]); // if yes move that value to last in array
}
});
return names; // return modified array
}
var names = movetoLast(names,"Num");// call function
console.log(names); // print modified array in console
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Try this.simple use Array#filter and Array#concat
var names = ["LET_ABC", "PET_DEF", "Num_123", "Num_456", "SET_GHI", "RET_JKL"];
console.log(names.filter(a => !a.match(/(\d+)/g)).concat(names.filter(a => a.match(/(\d+)/g))))
I would put the numbers in a separate array to concatenate the two arrays at the end.
result.each(function () {
var tempObject = {}, attributes = $(this).data();
var numsArray = [];
if (attributes.prefix==Num){
numsArray.push(attributes.prefix+ '_' + attributes.value);
}else{
names.push(attributes.prefix+ '_' + attributes.value)
}
names.concat(numsArray);
});
Use push to add a value to the end of an array if it has the "Num" prefix and use unshift to add a value to the beginning of an array if it does not have the "Num" prefix. Working code:
var names =["LET_ABC","PET_DEF","Num_123","Num_456","SET_GHI","RET_JKL"];
$(document).ready(function(){
result_array = [];
$.each(names, function(index, value){
if (value.substring(0,3)=="Num"){
result_array.push(value);
} else{
result_array.unshift(value);
};
});
console.log(result_array);
});
Related
I am trying to loop through some HTML elements, extract the content and set them as a const value with the index number like this...
jQuery('.myitems').each(function (index) {
const myitem + index = [jQuery(this).text()];
console.log(myitem + index);
});
This is not working, can anyone tell me the correct way to achieve?
You can use object instead of count. And your code will be broken.
See the following solution.
jQuery('.myitems').each(function (index) {
const count = {}
count[myitem + index] = [jQuery(this).text()];
console.log(count[myitem + index]);
});
Shouldnt you store the values in an array instead?
const myitem = [];
jQuery('.myitems').each(function (index) {
myitem[index] = jQuery(this).text();
console.log(myitem[index]);
});
You cannot do what you're attempting in JS. An alternative would be to populate an array with the values by using map():
var arr = $('.myitems').map(function() {
return $(this).text();
}).get();
If you still want to use the 'myitem' + index prefix on the values then you could instead use an object:
var obj = {};
$('.myitems').each(function(i) {
obj['myitem' + i] = $(this).text();
});
Here, I have first set constant and then on looping I have set value with index number. Currenlty , I have made output on console. You can check it. Let me know if you do not understand
const staff=[];
$('.staff').each(function(index){
staff[index]=$(this).text();
})
console.log(staff);
I have an array in JavaScript like this
var data = [,A_1_VII,VII,V2,,A_1_VII,VII,V2,,A_1_VII,VII,V2,,B_1_XIV,XIV,V3,,B_2_XVI,XVI,V3]
when I alert in JavaScript it gives as below
,A_1_VII,VII,V2
,A_1_VII,VII,V2
,A_1_VII,VII,V2
,B_1_XIV,XIV,V3
,B_2_XVI,XVI,V3
But I want like this which is duplicates removed array
var unique_data = [,A_1_VII,VII,V2,,B_1_XIV,XIV,V3,,B_2_XVI,XVI,V3]
On alert it should give like this
,A_1_VII,VII,V2
,B_1_XIV,XIV,V3
,B_2_XVI,XVI,V3
First Thing your array contains string as a constant that's not going to work.
Secondly, if all of you value are strings you can do it as follows:
var data =[,"A_1_VII","VII","V2",,"A_1_VII","VII","V2",,"A_1_VII","VII","V2",,"B_1_XIV","XIV","V3",,"B_2_XVI","XVI","V3"];
var uniqueArray = data.filter(function(item, pos) {
return data.indexOf(item) == pos;
})
alert(uniqueArray);
Assuming the variables in your array are well defined, you can clean it up and remove duplicates with a for loop:
var data [/* ... */];
var unique_data = [];
for(let i = 0; i < data.length; i++) {
if (data[i] && unique_data.indexOf(data[i]) === -1) {
unique_data.push(data[i]);
}
}
Please note that the code above assumes that your array contains non-object types, otherwise the solution would need to use something more sophisticated than indexOf().
You can create your unique function to remove duplicate entry and empty value from array like this.
var data =[,"A_1_VII,VII","V2,,A_1_VII","VII","V2",,"A_1_VII","VII","V2",,"B_1_XIV,XIV","V3",,"B_2_XVI,XVI,V3"]
var unique_data = uniqueList(data);
alert(unique_data);
function uniqueList(list) {
var uniqueResult = [];
$.each(list, function(i, e) {
if ($.inArray(e, uniqueResult) == -1 &&$.inArray(e, uniqueResult)!="")// chech for unique value and empty value
uniqueResult.push(e);
});
return uniqueResult ;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
Below javascript code for adding object to a javascript array. I want to add an object to array when it does not exist, if it already exists object.rValue!= new object.rValue then change old rValue=new rValue, otherwise same rVale. Also save it on array.
The problem is the object populate dynamically.
var arr = [];
$(document).ready(function() {
$(".rating").click(function() {
var idx = $(this).closest('td').index();
var userskill = {
tech : $(this).closest('td').siblings('td.tech').text(),
skill : $('#listTable thead th').eq(idx).text(),
rValue : $(this).val()
}
validate(userskill);
});
});
function validate(userskill) {
}
Try this
arr.forEach(function(elem){
if(elem.rValue==newObj.rValue)
elem.rValue = newObj.rValue;
})
I have some code I want to put into a JSON object ultimately. But first I want to create a javascript object and within that object add an array of values. Sounds simple enough but my approach seems wrong. First I create a basic object, the set a few fields. Lastly, iterate over a bunch of checkboxes and then, if one is checked at that value to an array.
At the last step I need to add that array to my object (myData) and then JSONify it.
Any ideas how I can do this, seems myData.push(filters); doesn't work...
Note that the object itself is not an array, I want to place an array IN the object.
var myData = new Object();
myData.deviceId = equipId;
myData.dateTo = dateTo
myData.dateFrom = dateFrom;
myData.numResults = $("#numResults").val();
var i=0;
var filters = [];
$('input[type=checkbox]').each(function () {
if (this.checked) {
allData += $(this).val() + ",";
filters[i] = {
filterIds: $(this).val()
};
++i;
}
});
myData.push(filters);
That's not how to add items to an Object, change
myData.push(filters);
to
myData.filters = filters;
Also, maybe change = new Object to = {}. There's no difference, but it's easier to read, because literal notation takes up less space.
Read more about Array.prototype.push
Use push to add elements to the filters array. Use property assignment to add another property to the myData object.
var myData = {
deviceId: equipId,
dateTo: dateTo,
dateFrom: dateFrom,
numResults: $("#numResults").val()
};
var filters = [];
$('input[type=checkbox]').each(function () {
if (this.checked) {
allData += $(this).val() + ",";
filters.push({
filterIds: $(this).val()
});
}
});
myData.filters = filters;
BTW, don't use new Object() to create an object, use {}.
Remove the need for an extra array and i.
var myData = {}
myData.deviceId = equipId;
myData.dateTo = dateTo
myData.dateFrom = dateFrom;
myData.numResults = $("#numResults").val();
myData.filters = [];
$('input[type=checkbox]').each(function () {
if (this.checked) {
allData += $(this).val() + ",";
myData.filters.push({
filterIds: $(this).val()
});
}
});
EDIT 2
Check the fiddle - http://jsfiddle.net/SN5zT/2/
Following is the fiddle for which I am not sure why I am getting undefined in dropdown.
My fiddle - http://jsfiddle.net/z6GDj/
var res = '{"allSportPosition":{"25":"Forwards (Strickers)","27":"Fullbacks (Defenders)","28":"Goalkeeper ","26":"Midfielders"}}';
try {
var sportPositionOptions = '';
var parsedJson = JSON.parse(res);
var allSportPosition = parsedJson.allSportPosition;
var values = new Array();
$.each(allSportPosition, function (index, value) {
values[index] = value;
});
//alert(values.length);
values.sort();
$.each(values, function (atIndex, atValue) {
sportPositionOptions = sportPositionOptions + '<option value="' + atIndex + '">' + atValue + '</option>';
});
$(sportPositionOptions).appendTo("#player");
} catch (e) {
alert("Parsing error:" + e);
}
$.each is automatically sorting keys to 25,26,27,28 for res.
Please explain the reason of this and why I am getting undefined ?
Let me know If i need to explain it more, I will surely do it :)
EDIT
Please explain the reason why it is getting sorted automatically http://jsfiddle.net/SN5zT/
Try
values.push(value);
instead of
values[index] = value;
Fiddle Link
The following script is working, I also figured out where the "undefineds" came from.
http://jsfiddle.net/z6GDj/3/
var res = '{"allSportPosition":{"25":"Forwards (Strickers)","27":"Fullbacks (Defenders)","28":"Goalkeeper ","26":"Midfielders"}}';
try{
var sportPositionOptions = '';
var parsedJson = JSON.parse(res);
var allSportPosition = parsedJson.allSportPosition;
var values = allSportPosition;
//$.each(allSportPosition, function(index, value) {
// values[index] = value;
//});
//alert(values.length);
$.each(values,function(atIndex, atValue){
sportPositionOptions = sportPositionOptions+'<option value="'+atIndex+'">'+atValue+'</option>';
});
$(sportPositionOptions).appendTo("#player");
}
catch(e){
alert("Parsing error:"+ e);
}
The array is sorted automatically, because the keys are set correctly.
see http://www.w3schools.com/js/js_obj_array.asp. "An array can hold
many values under a single name, and you can access the values by
referring to an index number."
Or: Change the index, and you´re changing the order. (index indicates the order).
The undefined values are created by javascript default, check the last answer in here (How to append something to an array?)
"Also note that you don't have to add in order and you can actually
skip values, as in
myArray[myArray.length + 1000] = someValue;
In which case the values in between will have a value of undefined."
Since you are passing an object to each(), jquery passes the key as the index parameter. In your object, the keys are ranged from 25 to 28. Setting the array using the values[25] on an empty array will expand the array to index 25, with the first 25 elements undefined. Using values.push(value) will append the value at the end of the array.
$.each is doing the following assignment that is why you are getting so many undefined
values[25] = "Forwards (Strickers)"
values[26] = "Midfielders"
values[27] = "Fullbacks (Defenders)"
values[28] = "Goalkeeper"
During $.each browsers will automatically sort the keys if the keys are integer, one way to avoid this is use non integer keys
What you need to do is define your options before you sort them , and then append them to your select:
var res = '{"allSportPosition":{"25":"Forwards (Strickers)","27":"Fullbacks (Defenders)","28":"Goalkeeper ","26":"Midfielders"}}';
try {
var sportPositionOptions = '',
parsedJson = JSON.parse(res),
allSportPosition = parsedJson.allSportPosition,
options = new Array();
$.each(allSportPosition, function (index, value) {
options[index] = $('<option></option>', {
value: index,
text: value
});
});
$.each(options, function (index) {
$('#player').append(options[index]);
});
} catch (e) {
alert("Parsing error:" + e);
}
jsfiddle: http://jsfiddle.net/z6GDj/11/