This question already has answers here:
What is the JavaScript >>> operator and how do you use it?
(7 answers)
How do I convert an integer to binary in JavaScript?
(17 answers)
Closed 5 years ago.
I found this code on W3schools for converting decimal into binary.
function dec2bin(dec){
return (dec >>> 0).toString(2);
}
I don't understand what is the purpose for making zero fill right shift in this case? What is the use of setting the shift to 0 (i.e. dec >>> 0) since as I know it doesn't push any binary digit to the right at all?
I am a JS beginner. Thanks!
Related
This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 1 year ago.
as the title
when I use toFixed to convert the float
(0.2).toFixed(4) -> 0.2000
(444.2).toFixed(4) -> 444.2000
(0.2).toFixed(14) -> 0.20000000000000
(444.2).toFixed(14) -> 444.19999999999999 //why ?!!!
I could not understand that what causes this result.
Is any javascript method to avoid this problem?
Floating point numbers cannot represent all decimals precisely in binary. one way to overcome this problem is using parseFloat:
console.log(parseFloat((444.2).toFixed(14)));
This question already has answers here:
Is floating point math broken?
(31 answers)
Get decimal portion of a number with JavaScript
(29 answers)
Closed 3 years ago.
The goal is to isolate the decimal value (with simply turning the integer into a string and splitting it).
To that affect I have:
var x = 1001.1;
var roundedDown = Math.floor(x); // Produces 1001
var decimal = x - roundedDown;
The expected value of decimal should be 0.1 (1001.1 - 1001). But instead I get 0.0999999 recurring.
I have tried with Math.trunc as well but get the same results.
Would anyone know why this is?
This question already has answers here:
javascript large integer round because precision? (why?)
(2 answers)
Javascript long integer
(3 answers)
Closed 4 years ago.
this is code
const str = '1111';
console.log(Number(str));
But When String's length over 17, it will be have problem
const str = '111100000123121221234'
console.log(Number(str)); // 111100000123121220000
I want to know, what's the principle of convert string to Integer of Number Object. Why convert wrong
Thank You Very Much
Because "Integers (numbers without a period or exponent notation) are accurate up to 15 digits". See: https://www.w3schools.com/js/js_numbers.asp
This question already has an answer here:
JavaScript parseInt is giving me wrong number, what I'm doing wrong? [duplicate]
(1 answer)
Closed 7 years ago.
Why?
parseInt((10152174800132377).toString(16),16) ==
10152174800132376
Where the number of lost?
The number is lost, as it is to large to be representable exactly in JavaScript's Number type (it is a IEEE 754 double):
$ node
> 10152174800132377
10152174800132376
This question already has answers here:
Large numbers erroneously rounded in JavaScript
(6 answers)
Closed 7 years ago.
I have the folowing code:
Click
function Add(id) {
alert(id);
}
The value in the alert is 23905762501722144 (-2) from the original value.
Why does this happen?
https://jsfiddle.net/wvtqostd/4/
log2(23905762501722146) ~= 54.408
JavaScript stores all numbers - including integers - as double precision floats. Double precision mantissa/significand contains 52 bits of information, so some information gets lost storing so long/precise number as you have.
Because 23905762501722144 is to big to represent as integer value... try sending it as string value.