I have the following code and i am trying to retrieve the userid , firstname and some values from JSON but I am getting undefined.
How can i fix this?
function getVal(val1,val2) {
var myval2 =URL +"webUser?email="+email;
var uId='';
$.ajax({
url: myval2,
dataType: "json",
cache: false,
success: function(data, textStatus, jqXHR) {
jQuery.each(data, function(k,v) {
console.log( " k " +k + " v" + v);
uId =v.uId;
});
},
error: function(jqXHR, textStatus, errorThrown) {
console.log('FAILED to get JSON from AJAX call' + jqXHR + textStatus + errorThrown);
}
});
console.log("userid " +userId);
return userId;
}
JSON
{
"userId": 2,
"emailAddress": "some#some.com",
"roleId": 1,
"firstName": "Hulk",
"lastName": "Ogan",
"company": "MTT",
"title": "Lord Vader",
"phoneWork": "",
"phoneMobile": "",
"lastModifiedBy": "system",
"versionNumber": 1
}
You can simply get value of userid and other properties like this
userID = data.userId;
No need of loop because your data is only a single object you will need loop if your data was an array of objects
One problem I can see is that your json record is just that: a single record; so, you don't need $.each to iterate through the ajax result - that would only be necessary if your returned data consisted of a json array with potentially many records.
Other than that, you will just need to do some bug tracking:
Is your http action on your website set up to handle GET actions? If it needs a POST action you will need to specify that in your ajax call.
Leading on from 1 - are you certain that your call to the url does return a json result? Can you navigate to that url in a browser and see the json result?
If both of those are taken care of, check what "data" contains when it returns. If it is empty or not well formed json, figure out why.
You don't need to jQuery.each, because you don't have a JsonArray and you have JsonObject.
You can easily get you data with:
userID = data.userId;
and
userID = data['userId'];
(like as Madalin & Leopars answers)
You can simply get value of userid and other properties like this
userID = data['userId'];
var data = {
"userId": 2,
"emailAddress": "some#some.com",
"roleId": 1,
"firstName": "Hulk",
"lastName": "Ogan",
"company": "MTT",
"title": "Lord Vader",
"phoneWork": "",
"phoneMobile": "",
"lastModifiedBy": "system",
"versionNumber": 1
};
console.log(data['userId']);
Note: you can't return any values from a asynchronous ajax request, do all your logic in the success function of your ajax call
Related
Im trying to send a request to a rest API and granted my knowledge using jquery is not advance however through numerous tutorials I'm struggling a bit to build a request based on this swagger documentation.
{
"fields": {
"": [
{
"NAME": "NAME"
},
{
"ADDRESS": "ADDRESS"
},
{
"EMAIL": "EMAIL"
}
]
}
}
This is the model of how i need to send the Rest request, im able to do this using postman however i struggle to do this in javascript.
var data = {};
var json = [{ "NAME": "name", "ADDRESS": "address", "EMAIL": "email" }];
data.fields ={json};
My problem is that in the model there is an empty quotation which im unable to replicate. I suspect that either the rest API is not the best or im missing something quite vital in building a request. See below for the actual ajax jquery request.
var request = $.ajax({
type: "POST",
url: urlBase,
contentType: 'application/json',
data: JSON.stringify({json}),
});
request.done(function (msg) {
alert(msg);
$("#log").html(msg);
});
request.fail(function (jqXHR, textStatus) {
alert("Request failed: " + textStatus);
});
}
Error message based on the above request
Invalid field groups: [json] used in the search fields not found in duplicate store schema
You can create a json like this:
var obj = {
"": [{
"NAME": "NAME"
},
{
"ADDRESS": "ADDRESS"
},
{
"EMAIL": "EMAIL"
}
]
}
console.log(obj)
Hope it helps. Revert for any doubts.
I am trying to get a ID from a JSON call, and not sure what the issue is. I have a Callback function set up to set a global variable as such.
GOAL: Make a call to a DB, get the ID from the results returning.
STEP 1 - Make call to JSON and Parse Results
callAjaxGet(<set url>,function(myReturn){
var noteID = ''
$.each(myReturn.results, function(i, note){
noteID = JSON.parse(note.id);
});
})
STEP 2 - JSON/Callback Function
function callAjaxGet(url, callBack){
$.ajax({
url: url,
type: 'GET',
timeout: 10000,
success: function(data,textStatus,xhr){
return callBack(xhr);
},
error: function(xhr, status, error){
console.log(xhr.responseText);
}
});
}
STEP 3 - The Returning JSON
{
"next": "http://selleck.beta.org/playlist/notes/?limit=20&offset=20&play=437",
"previous": null,
"results": [
{
"id": 258,
"url": "/playlist/notes/258/",
"content": "testing",
"play": 437
}
]
}
No matter what I'm doing, the noteID comes back without value. I've looked in Google Development Tools, XHR, and can see the JSON coming back, so thinking I've misunderstood something.
Thank you for any thoughts and suggestions
Steve
Figured it out. Two things were wrong.
Was using XHR instead of Data
Wasn't parsing the JSON properly, the ID is in an array, so had to set the first entry, so
noteID = myReturn.results[0].id;
Thanks A.Sharma and ron tornambe for the pointer on the XHR error
Steve
I want to get the data response from my login webservice. Here is my web service
http://41.128.183.109:9090/api/Data/getloginer?medid=a&pass=a
(for testing). Here is my code:
$("#login").click(function () {
var url = "http://41.128.183.109:9090/api/Data/getloginer?medid=a&pass=a";
$.ajax({
url: url,
type: 'Get',
success: function (data) {
alert(data.Medical_id);
},
});
});
The alert() shows me undefined. Please advise on what the problem could be.
The result is an array, so in order to get that field you have to iterate the result or get the first item:
for (var i in data) {
console.log(d[i].Medical_id);
}
Or you can simply get the first result:
$.ajax({
url: 'http://41.128.183.109:9090/api/Data/getloginer?medid=a&pass=a',
type: 'Get',
success: function (data) {
alert(data[0].Medical_id);
}
});
The JSON result you are getting is :
[{"$id":"1","id":8,"Medical_id":"a","Password":"a","Name":null,"Email":null,"gender":null,"Type":null}]
use for each to iterate through the results or
instead of this you can check the result like this :
var data = [{ "$id": "1", "id": 8, "Medical_id": "a", "Password": "a", "Name": null, "Email": null, "gender": null, "Type": null }]
alert(data[0].Medical_id);
If you develop application in localhost then refer this questions also.
"No 'Access-Control-Allow-Origin' header is present on the requested resource"
If you are using chrome, then use this link to use CORS enable plugin.
https://chrome.google.com/webstore/detail/allow-control-allow-origi/nlfbmbojpeacfghkpbjhddihlkkiljbi?hl=en-US
hope this will help
I am new to Yii2 framework and PHP.I used Mongo DB as the backend database.I fetched a document from a collection and returned the data as Json from the controller.The data returned back is given below.
{
"55b08c383e1a36233fdbdc06": {
"_id": { "$id": "55b08c383e1a36233fdbdc06" },
"address": [ "abcdgt", "zxcv" ],
"age": "23",
"email": [ "qwert#gmail.com","abcd#mail.com" ],
"location": "kollam",
"name": "ajiths",
"phoneno": [ "9522585456", "7875642256" ] ,
"sex": "male"
}
}
But I am getting 'Undefined' when trying to alert result.name in Javascript code.The code at the front end is given below.
function loadClient(id){
url = "<?= Yii::getAlias('#serverpathweb')?>/client/showclient?id="+id;
$.ajax({
url: url ,
method: "GET",
success: function(result){
alert(result.name);
}
});
}
The code at the controller end is given below.
public function actionShowclient($id) {
$clientdetail = Yii::$app->mongodb->getCollection('client');
$result = $clientdetail->find(["_id" =>$id]);
Yii::$app->response->format = \yii\web\Response::FORMAT_JSON;
return $result;
}
Can anyone tell me how to get the value result.name.
your getting JSON result with id as key so access ur JSON data like this
first get the key of ur JSON using Object.keys
next using key print the values you need
var id=Object.keys(result)[0]; //it will print your JSON key i.e. "55b08c383e1a36233fdbdc06"
alert(result[id]['name']); // it will print the name
Note if you are getting multiple user details please let me know
Your "result" object is probably a String because you're not telling jQuery otherwise. Trying adding the option dataType:json to your request as in:
$.ajax({ url: url, method: 'GET', dataType: 'json', etc...
Edit: It also looks like there's a simple bug in your code. You need to access your property where it's nested in the resulting object:
result[id].name
How to get display return values from the JSON values.I need to get value the user id
$('User_id').observe('blur', function(e) {
var txt = $('User_id').value;
jQuery.ajax({
type: 'get',
url: BASE_URL + 'admin/index/user_id',
data: {
user_id: txt
},
dataType: 'json',
success: function(data) {
console.log('success' + data.success);
if (data.success) {
var Value = data.location.user_id;
alert(Value);
}
}
});
});
These values are getting in html form. In that I need to store user id in Value varable. But I receive successundefined as a output..
[{
"user_id": "139",
"mobile": "9042843911",
"gender": "male",
"hashcode": "DfAbMqLApAV6nVa1z940",
"username": "anandhsp21",
"password": "74bcff7d1199012e154f364e3f65e31d:8I",
"authorized_person": "Anandh",
"created": "2015-06-08 13:46:55",
"modified": "2015-06-08 06:43:35",
"logdate": "2015-06-08 08:16:55",
"lognum": "12",
"reload_acl_flag": "0",
"is_active": "1",
"extra": "N;",
"rp_token": null,
"rp_token_created_at": null,
"app_name": "",
"api_key": ""
}]
Please some one help. Thanks in Advance
Your get the data in array so use loop in success data
for (var i=0; i<data.length; i++) {
console.log('success' + data[i].user_id );
}
If you know the record length is 1 then use directly
console.log('success' + data[0].user_id );
Your data is an array that contains one object. So you can access this object using :
success: function(data){
console.log('success' + data[0].user_id );
Trying to log success is pointless, because there is no success key whatsoever in the received data.
Make sure that you get the response in proper json format,and as harshad pointed String male should be wrapped in double quotes.
After you get that fixed,you can access the user_id as:
data[0].user_id
data.success is undefined, because the received data is stored directly in data. That's the first argument of the success block. You can access the received data directly by data[0] to get the object inside of the array, or if you have a larger array you can do a for each loop over it, etc..
Try this, simply use json.parse()
$(document).ready(function() {
var v = ['{"user_id":"139","mobile":"9042843911"}'];
var obj = JSON.parse(v);
alert(obj.user_id);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
To get userid please follow below code I edited,
$('User_id').observe('blur', function(e) {
var txt = $('User_id').value;
jQuery.ajax({
type: 'get',
url: BASE_URL + 'admin/index/user_id',
data: {
user_id: txt
},
dataType: 'json',
success: function(data) {
// this below userid is the value user_id you want.
var userid = data[0].user_id;
}
});
});
There is a json error
"gender":male
Strings male should be wrapped in double quotes.
you need to make sure that your response is formatted appropriately and according JSON.org standards.