I am using JQuery slideUp/slideDown to add an overlay to an image that is hidden until mouseover and then slides up from the bottom of the image.
The div that is sliding up is given a background color, but it doesn't show up over the image, it shows up behind it (the text shows up on top of the image, but I can just see the bottom edge of the div's background color because of the margins I set). Z-index is already set to 100.
Any ideas? Thanks!
(function($) {
$(document).ready(function() {
$(".slider").attr("style", "display: none;");
if ($(".slider")) {
$('.image').mouseover(function() {
$(this).find(".slider").slideDown("400");
}).mouseout(function() {
$(this).find(".slider").slideUp("400");
});
}
});
}(jQuery));
.image{
height: 300px;
width: 300px;
background: #000000;
}
.slider {
background-color: #333333 !important;
background: #333333 !important;
background-position: 0% 100%;
color: #ffffff;
margin: -90px 0 0 0;
height: 90px;
width: 100%;
z-index: 100 !important;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="image">
</div>
<div class="slider">
<div class="title">Title</div>
<div class="text">Text</div>
</div>
</div>
It's better to define display: none; for slider in css rule.
Also to bind mouseenter and mouseleave to container will prevent jumping slider when mouse is leaving image and moving over slider.
$('.container').on("mouseenter", function() {
$(".slider").slideDown();
});
$('.container').on("mouseleave", function() {
$(".slider").slideUp("400");
});
.container {
width: 300px;
}
.image{
height: 300px;
width: 300px;
background: #000000;
}
.slider {
background-color: #333333;
color: #ffffff;
margin: -90px 0 0 0;
height: 90px;
width: 100%;
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="image">
</div>
<div class="slider">
<div class="title">Title</div>
<div class="text">Text</div>
</div>
</div>
z-index only works on positioned elements (position:absolute, position:relative, or position:fixed).
If you do not define position, element will be static, as that's default position for block elements.
M.
Related
Basically I have a fixed size div that contains an <img> tag. I cannot change the structure.
Often these images are much larger than the container due to keeping them 100% width and filling the box. Most times this results in too much of the image shown at top and not cropped to the center of the image.
So using jQuery (or pure CSS if possible) I want to adjust the position of the image to move it up so the top is cropped off instead of the bottom.
Also, this should remain responsive as the viewport changes width.
Here is a fiddle
.container {
height: 200px;
width: 100%;
overflow: hidden;
margin: 0 0 30px;
}
<div class="container">
<img src="http://placekitten.com/900/500/">
</div>
<div class="container">
<img src="http://placekitten.com/901/500/">
</div>
It's doable with known height container, like your demo. We can set the container to position:relative, and set the image to position:absolute, plus some extra set ups as follows.
.container {
height: 200px;
width: 100%;
overflow: hidden;
margin: 0 0 30px;
position: relative;
}
.container img {
position: absolute;
left: 0;
top: 50%;
transform: translateY(-50%);
max-width: 100%;
height: auto;
}
<div class="container">
<img src="http://placekitten.com/900/500/">
</div>
<div class="container">
<img src="http://placekitten.com/901/500/">
</div>
jsfiddle
If you are OK with using the images as the div background, you can do the following:
Option1:
HTML:
<div class="container" id="first"></div>
<div class="container" id="second"></div>
CSS:
.container {
height: 200px;
width:100%;
overflow: hidden;
margin: 0 0 30px;
border: solid;
background-position: center center;
background-repeat: no-repeat;
}
#first {
background-image: url('http://placekitten.com/901/500/');
}
#second {
background-image: url('http://placekitten.com/900/500/');
}
Update- Option2:
without using the image as background.
HTML:
<div class="container">
<img class="centered" src="http://placekitten.com/900/500/" />
</div>
<div class="container">
<img class="centered" src="http://placekitten.com/901/500/" />
</div>
CSS:
.container {
height: 200px;
width:100%;
overflow: hidden;
margin: 0 0 30px;
border: solid;
}
.centered {
object-fit: none;
object-position: center;
width: 100%;
height: inherit;
}
Please check this option1, option2
For now I'm going to use:
$("img").each(function(){
var hHeight = $(this).height()/2;
$(this).css("top", - hHeight);
});
I would love to see other solutions, especially if they are better.
I’m having a little trouble with this template: basically, I’m trying to add functionality where if you click a box it will expand sliding the other ones off-screen, but instead sliding the div off-screen it’s disappearing completely.
Here is what I have so far: JSFiddle.
$(function() {
$(".box").click(function() {
var isopened = $(this).attr("isopen");
if (isopened == "true") {
$(this).css("position", "relative").css("width", $(this).attr("data-ow"));
$(this).attr("isopen", "false");
}
else {
$(this).attr("data-ow", $(this).css("width"));
$(this).css("position", "relative").css("width", "40%");
$(this).attr("isopen", "true");
}
});
});
* {
margin: 0;
padding: 0;
}
.container {
width: 100%;
max-width: 100%;
max-height: 600px;
overflow: hidden;
}
.box {
height: 600px;
display: block;
width: 13.33333333%;
border: 1px solid white;
background-color: black;
float: right;
position: relative;
}
.box:first-of-type {
width: 29.0%;
background-color: orange;
}
.box:last-of-type {
width: 29.0%;
background-color: blue;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="container">
<div class="box"></div>
<div class="box"></div>
<div class="box"></div>
<div class="box"></div>
<div class="box"></div>
</div>
What I ultimately want is when one of the boxes is clicked it expands and instead of the entire div being hidden only the part which is off-screen is hidden:
I think you might like this flexbox solution as you can do what you want without usign any jQuery/JS. Pure CSS and HTML:
body {
background-color: black
}
#container {
display: flex;
width: 100%;
height: 50vh;
}
#container > div {
flex: 1;
min-width: 0;
transition:min-width 0.2s ease;
outline:0;
}
#container > div:focus {
min-width: 50vw;
}
<div id="container">
<div tabindex="0" style="background-color:blue"></div>
<div tabindex="0" style="background-color:orange"></div>
<div tabindex="0" style="background-color:green"></div>
<div tabindex="0" style="background-color:white"></div>
<div tabindex="0" style="background-color:blue"></div>
</div>
I used tabindex to give me the ability to use the :focus selector.
i have a little css problem. i've got a div whit an input in it that will stick to the top of the page when page is scrolled down. it works great except images from the page get over it and it looks awfull. i need to make it "on top" of the other content if i can. or at least have an overflow of some sort that will push the scroll just from it, if that makes any sense.
i have to say my css skills are below avarage. here's what ive got so far
HTML:
<div class="searchbox" id="sticky" style="width:60%; padding-left:20%; background-color:white; padding-top:5px; margin-bottom:25px; padding-right:20%; height:35px;">
<form method="get">
<input style="width:80%;" name="title" placeholder="Search..." type="search">
</form>
</div>
the searchbox is not initially on the top of the page so to make it stick when it gets there i have this javascript that adds / removes position fixed
Javascript:
<script>
var header = document.querySelector('.searchbox');
var origOffsetY = header.offsetTop;
function onScroll(e) {
window.scrollY >= origOffsetY ? header.classList.add('sticky') :
header.classList.remove('sticky');
}
document.addEventListener('scroll', onScroll);
</script>
CSS:
<style>
.sticky {
position: fixed;
top: 0;
}
</style>
If somethign else jumps on top of your content, use
css z-index to order things according to how you would like.
_ quick edit for potential future visitors_
hover slides to bring the slide under the mouse on top of others.
fiddle: Fiddle demo
Html
<div id="slides">
<div id="obj1">obj 1</div>
<div id="obj2">obj 2</div>
<div id="obj3">obj 3</div>
</div>
Css:
#slides {
position: relative
font-size: 20px;
}
#slides > div {
border: 1px solid gray;
min-height: 3em;
position: absolute;
top: 1em;
background: green;
cursor: pointer;
text-align: center;
min-width: 4em;
}
#slides > div#obj2 {
top: 2em;
background: red;
left: 2em;
}
#slides > div#obj3 {
top: 3em;
background: blue;
left: 4em;
}
JavaScript:
$("#slides > div").mouseover(function(evt) {
$("#slides > div").css("z-index", "inherit");
$(evt.target).css("z-index", 4);
});
I would like to be able to add an animation to this simple query for when the div is transitioned to its new position.
<div class="container">
<div class="left-side-bar">
<div class="long blue" id="1">
1
</div>
<div class="short red" id="2">
2
</div>
</div>
<div class='middle-side-bar'>
<div class='long green' id="3">
3
</div>
</div>
<div class='right-side-bar'>
<div class='short yellow' id="4">
4
</div>
</div>
</div>
the CSS
.left-side-bar{
clear: both;
width: 32%;
text-align: center;
float: left;
margin-top: 1%;
margin-bottom: 100px;
}
.middle-side-bar{
width: 32%;
text-align: center;
float: left;
margin: 1% 0 1% 1.6%;
}
.right-side-bar{
width: 32%;
text-align: center;
float: left;
margin: 1% 0 1% 1.6%;
}
.green {
background-color: green;
}
.long {
height: 300px;
}
.short {
height: 200px;
}
.red {
background-color: red;
}
.blue {
background-color: blue;
}
.yellow {
background-color: yellow;
}
Basically I want the div to be moved to its new place as an animated transition, rather than have it simply appear.
here is the jsfiddle
DEMO
Unfortunately, the replaceWith method does not work with animate in jQuery. Instead, you will probably need to find an alternative method to your solution. Here's one that slowly transitions the red box on top of the yellow box... http://jsfiddle.net/aeyg89rd/4/
I added the following jQuery, note that I used offset() to get the left and top properties of the yellow box, then I moved the red box to those left and top positions using animate() :
$(document).ready(function () {
var num4 = $("#4").offset();
$("#2").animate({ top: num4.top, left: num4.left }, 1000);
});
And I changed some CSS attributes for .red class so that I can move it around with the jQuery code above. More specifically, I changed its position to absolute, and gave it a width dimension:
.red {
position: absolute;
top: 320px;
background-color: red;
width: 150px;
}
This is a very simple example of sticking an element at the top of another element's visible area. When .container is scrolled, .fixed stays at the top.
<div class="container">
<div class="fixed">fixed content</div>
<div class="content">regular content<br/>regular content<br/>regular content<br/>regular content<br/>regular content</div>
</div>
<style type="text/css">
.container {
position: relative;
border: 1px solid blue;
overflow: auto;
width: 250px;
height: 250px;
}
.content {
height: 500px;
width: 500px;
}
.fixed {
position: absolute;
width: 500px;
margin-top: 2rem;
border 1px solid red;
}
</style>
<script type="text/javascript">
$('.container').scroll(function () {
var top = $('.container').prop('scrollTop');
console.log(top);
$('.fixed').css('top', top);
});
</script>
The problem with this is that if the browser is not fast enough, the .fixed element flickers when I scroll. It lags behind the scroll (compare the position of the text in .fixed to the text in .content as you're scrolling). On my desktop it works flawlessly, but when I try running this in Chromium in a virtual machine, I can see the flicker.
Is there any other way to catch the scroll event and set the position of my .fixed element before the browser renders the page?
edit Updated example to include horizontal scrolling. The fixed element should only be fixed vertically.
Use a double container:
<div class="container-wrapper">
<div class="fixed">fixed content</div>
<div class="container">
<div class="content">regular content<br/>regular content<br/>regular content<br/>regular content<br/>regular content</div>
</div>
</div>
With the CSS:
.container-wrapper {
position: relative;
border: 1px solid blue;
overflow: hidden;
width: 250px;
height: 250px;
}
.container {
overflow: auto;
width: 100%;
height: 100%;
}
.content {
height: 500px;
}
.fixed {
position: absolute;
top: 0px;
left: 0px;
width: 245px;
border 1px solid red;
z-index: 10;
}
This way you won't need jQuery to reposition the .fixed div when you scroll, and it won't flicker.
EDIT To address the horizontal scrolling...
$('.container').on('scroll', function() {
var left = this.scrollLeft;
$('.fixed').css('left', -left + 'px');
});
This should move the .fixed div without flickering. In your solution, the flickering was caused because the browser moved your div while scrolling, and the event handler then moved it again. Now it will only move once.