I would like to be able to add an animation to this simple query for when the div is transitioned to its new position.
<div class="container">
<div class="left-side-bar">
<div class="long blue" id="1">
1
</div>
<div class="short red" id="2">
2
</div>
</div>
<div class='middle-side-bar'>
<div class='long green' id="3">
3
</div>
</div>
<div class='right-side-bar'>
<div class='short yellow' id="4">
4
</div>
</div>
</div>
the CSS
.left-side-bar{
clear: both;
width: 32%;
text-align: center;
float: left;
margin-top: 1%;
margin-bottom: 100px;
}
.middle-side-bar{
width: 32%;
text-align: center;
float: left;
margin: 1% 0 1% 1.6%;
}
.right-side-bar{
width: 32%;
text-align: center;
float: left;
margin: 1% 0 1% 1.6%;
}
.green {
background-color: green;
}
.long {
height: 300px;
}
.short {
height: 200px;
}
.red {
background-color: red;
}
.blue {
background-color: blue;
}
.yellow {
background-color: yellow;
}
Basically I want the div to be moved to its new place as an animated transition, rather than have it simply appear.
here is the jsfiddle
DEMO
Unfortunately, the replaceWith method does not work with animate in jQuery. Instead, you will probably need to find an alternative method to your solution. Here's one that slowly transitions the red box on top of the yellow box... http://jsfiddle.net/aeyg89rd/4/
I added the following jQuery, note that I used offset() to get the left and top properties of the yellow box, then I moved the red box to those left and top positions using animate() :
$(document).ready(function () {
var num4 = $("#4").offset();
$("#2").animate({ top: num4.top, left: num4.left }, 1000);
});
And I changed some CSS attributes for .red class so that I can move it around with the jQuery code above. More specifically, I changed its position to absolute, and gave it a width dimension:
.red {
position: absolute;
top: 320px;
background-color: red;
width: 150px;
}
Related
This question already has answers here:
Why can't an element with a z-index value cover its child?
(5 answers)
Closed 1 year ago.
**Here is a simple code **
div {
border: 1px solid blue;
}
.one {
background-color: red;
width: 300px;
height: 300px;
}
.two {
background-color: orange;
width: 300px;
height: 300px;
position: relative;
top: 100px;
left: 100px;
z-index: 10;
}
.twenty {
background-color: pink;
width: 300px;
height: 300px;
position: relative;
top: 100px;
left: 100px;
z-index: 500;
}
.three {
margin-top: -10px;
margin-left: 10px;
background-color: yellow;
width: 300px;
height: 300px;
}
.four {
background-color: green;
width: 300px;
height: 300px;
position: relative;
top: 80px;
left: 120px;
z-index: 11;
}
<div class="one">
<div class="two">
<div class="twenty">
Can pink be above green?
</div>
</div>
</div>
<div class="three">
<div class="four">
</div>
</div>
How to make the pink square to be above the green square? Is it possible with CSS changes only without HTML changes? Why z-index applied to the .twenty class doesn't work in this case?
Thank you.
This question is NOT a duplicate of Why can't an element with a z-index value cover its child? :
In this question we'd like the child to cover, not the parent!
All layers, except the twentieth, should not have Z order. We specify absolute an order and an order of a layer on Z.
.twenty{
position: absolute;
...
z-index: 1;
}
You should set .four with a lower z-index than .two which is the element that contains .twenty but this may not be the expected result (green also becomes under the orange).
It's not possible without changing the HTML structure, like putting .twenty inside .four, or redefining all the indexes. This is how the stacking context works.
Given this code:
<div class="A">
<div class="One"></div>
<div class="Two"></div>
</div>
<div class="B">
<div class="Three"></div>
</div>
From the top view
From the side view
Lear more about the stacking context:
CSS stacking contexts and z-index made easy
The stacking context
Yes, we can ;)... if orange gets a higher z-index than green...
.two {
...
z-index: 12;
}
It's because pink is a child of orange...
I am bit troubled in aligning the content as shown in the image. Along with that I need to redirect to page 1 by clicking on content section and redirect to page 2 by clicking the icon separately. How can I solve it using javascript?
These things can be achieved without the use of JavaScript besides the point that it's generally bad practice to manipulate DOM with JavaScript as much can be done with css rules, animations, basic html.
To align the icon first you should try these css rules applied on icon element:
.your-icon {
top: 0;
right: 0;
}
Assuming your icon in html is declared like this:
<img src="foo.img" class="your-icon">
Although it depends on current rules applied (e.g. you should use other rule set if flex is enabled on parent element). Perhaps spacing with fixed values between content section is involved that is pushing the icon out of the way (padding, margin rules applied?).
As for navigation html href is good enough
.a {
/* width:400px; */
height: 300px;
border: 1px solid;
}
.b {
width: 100%;
float: left;
/* border:1px solid red; */
}
.c {
width: 70%;
/* border:1px solid; */
float: left;
/* display:flex; */
float: left;
}
.c div{padding: 5px;}
.d {
border: 1px solid;
}
.box {
width: 29%;
float: left;
border: 1px solid;
height: 100%;
}
.rTable {
display: block;
width: 100%;
}
.rTableHeading,
.rTableBody,
.rTableFoot,
.rTableRow {
clear: both;
}
.rTableHead,
.rTableFoot {
/* background-color: #DDD; */
font-weight: bold;
}
.rTableCell,
.rTableHead {
/* border: 1px solid #999999; */
float: left;
height: 17px;
overflow: hidden;
padding: 5px;
width: 20%;
}
.rTable:after {
visibility: hidden;
display: block;
font-size: 0;
content: " ";
clear: both;
height: 0;
}
<div class='a'>
<div class='b'>
<div class='c'>
<div>Name</div>
<div>Address</div>
<div>PIN</div>
</div>
<div class='box'>ICON</div>
</div>
<div class='d'>
<div class="rTable">
<div class="rTableRow">
<div class="rTableHead"><strong>Time</strong></div>
<div class="rTableHead"><span style="font-weight: bold;">Duration</span></div>
<div class="rTableHead"><strong>Amount</strong></div>
<div class="rTableHead"><strong>Position</strong></div>
</div>
<div class="rTableRow">
<div class="rTableCell">5</div>
<div class="rTableCell">2</div>
<div class="rTableCell">3</div>
<div class="rTableCell">4</div>
</div>
</div>
</div>
</div>
Here the second div is positioned absolute. first div is taking 60% of outer div width, but the second div is taking 60% width of the whole screen. I know that by giving position: relative for the first div will solve the problem.Is there a way to solve it other than by giving position: relative?
.outer {
height: 100px;
width: 100px;
}
.first {
background: black;
width: 60%;
color: white;
}
.second {
position: absolute;
width: inherit;
background: yellow;
color: black;
}
<div class="outer">
<div class="first">
parent
<div class="second">
child
</div>
</div>
</div>
If the outer div will have a defined width you can rely on CSS variable to define the percentage and inherit will work like expected:
.outer {
height: 100px;
--w:100px;
width: var(--w);
}
.first {
background: black;
width: calc(0.6 * var(--w));
color: white;
}
.second {
position: absolute;
width: inherit;
background: yellow;
color: black;
}
<div class="outer">
<div class="first">
parent
<div class="second">
child
</div>
</div>
</div>
If you don't know in advance the width of your parent, you can compute its width in javascript with a document.getElementById('parentID').getBoundingRect().width and use that value to resize your child element to 60% of this value.
But why would you not want to use position: relative on the parent ?
I am using JQuery slideUp/slideDown to add an overlay to an image that is hidden until mouseover and then slides up from the bottom of the image.
The div that is sliding up is given a background color, but it doesn't show up over the image, it shows up behind it (the text shows up on top of the image, but I can just see the bottom edge of the div's background color because of the margins I set). Z-index is already set to 100.
Any ideas? Thanks!
(function($) {
$(document).ready(function() {
$(".slider").attr("style", "display: none;");
if ($(".slider")) {
$('.image').mouseover(function() {
$(this).find(".slider").slideDown("400");
}).mouseout(function() {
$(this).find(".slider").slideUp("400");
});
}
});
}(jQuery));
.image{
height: 300px;
width: 300px;
background: #000000;
}
.slider {
background-color: #333333 !important;
background: #333333 !important;
background-position: 0% 100%;
color: #ffffff;
margin: -90px 0 0 0;
height: 90px;
width: 100%;
z-index: 100 !important;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="image">
</div>
<div class="slider">
<div class="title">Title</div>
<div class="text">Text</div>
</div>
</div>
It's better to define display: none; for slider in css rule.
Also to bind mouseenter and mouseleave to container will prevent jumping slider when mouse is leaving image and moving over slider.
$('.container').on("mouseenter", function() {
$(".slider").slideDown();
});
$('.container').on("mouseleave", function() {
$(".slider").slideUp("400");
});
.container {
width: 300px;
}
.image{
height: 300px;
width: 300px;
background: #000000;
}
.slider {
background-color: #333333;
color: #ffffff;
margin: -90px 0 0 0;
height: 90px;
width: 100%;
display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<div class="image">
</div>
<div class="slider">
<div class="title">Title</div>
<div class="text">Text</div>
</div>
</div>
z-index only works on positioned elements (position:absolute, position:relative, or position:fixed).
If you do not define position, element will be static, as that's default position for block elements.
M.
I want to change the CSS of a div when hovering its parent div.
This is my HTML:
<div id="box1" class="hover-on-div-1">
<img src="images/1.png" alt="" />
<div id="line1"></div>
<div class="text_align"><span>Text here</span>
</div>
</div>
Here is the CSS:
#box1 {
height: 295px;
width: 220px;
background-color: #86d1f4;
float: left;
margin-left: 30px;
margin-right: 120px;
margin-top: 55px;
color: #0081C5;
}
#box1:hover {
background-color: #494c5b;
color: #BFB6AF;
}
#line1 {
height:1px;
background:#0081C5;
width:126px;
margin-top:67px;
margin-left:40px;
position:absolute;
}
Note: .hover-on-div-1 is the class I use for a JQuery function that changes the image, the <span> is used only for a text-transform and the text-align class is pretty self explanatory.
How do I change the .line1 div when hovering over #box1?
I managed to change everything inside the #box1 div when I hover but not the .line1. Did some search on SO but since I'm a total noob when it comes to JQuery/JavaScript it didn't helped too much.
https://jsfiddle.net/nLg8Lr7x/
You don't need JS for this - your #line1 div is child of #box1 div.
Just add some css like this:
#box1:hover #line1 {
/* Changes for #line1 when #box1 hovered */
}
Here is examle on jsbin.
If you want to do it with jQuery you can make use of mouseover and mouseleave functions to change css like below.
Notes: I suggest you to make use of addClass and removeClass functions instead of setting hard codded css in functions.
$('#box1').mouseover(function() {
$('#line1').css("background", "red"); // change css
});
$('#box1').mouseleave(function() {
$('#line1').css("background", "#0081C5"); // change back css as it was
});
$('#box1').mouseover(function() {
$('#line1').css("background", "red");
});
$('#box1').mouseleave(function() {
$('#line1').css("background", "#0081C5");
});
#box1 {
height: 295px;
width: 220px;
background-color: #86d1f4;
float: left;
margin-left: 30px;
margin-right: 120px;
margin-top: 55px;
color: #0081C5;
}
#box1:hover {
background-color: #494c5b;
color: #BFB6AF;
}
#line1 {
height: 1px;
background: #0081C5;
width: 126px;
margin-top: 67px;
margin-left: 40px;
position: absolute;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="box1" class="hover-on-div-1">
<img src="images/1.png" alt="" />
<div id="line1"></div>
<div class="text_align"><span>Text here</span>
</div>
</div>