I have three images in <section>
<section class="one">
<img src="one.png" />
</section>
<section class="two">
<img src="two.png" />
</section>
<section class="three">
<img src="three.png" />
</section>
I have added some css to position the sections:
$('.one').css({
position:'absolute',
top:100
});
$('.two').css({
position:'absolute',
top:800
});
$('.three').css({
position:'absolute',
top:1600
});
My problem is in the js - I want to position each element dynamically so for example the first section would be top 100px the section one would be 200px and the third one would be 300px. This is what i have managed so far:
$.fn.inView = function(){
var win = $(window);
obj = $(this);
var scrollPosition = win.scrollTop();
var visibleArea = win.scrollTop() + win.height();
var objEndPos = (obj.offset().top + obj.outerHeight());
var visible =(visibleArea >= objEndPos && scrollPosition <= objEndPos);
$.each( obj, function( index ) {
if(visible){
//console.log(index);
$(obj).css({
position:'fixed',
top: index*100//Problem here
});
}
});
};
The main problem you had there was that you set the css of the obj jquery selector, and not on the img that was in the obj selector.
In order to get to the img element you could use any of $(this) or add a second parameter to the callback function inside the $.each, which is the current element:
$.each(obj, function(index, el) {
$(el).css
Here is a complete snippet:
$(function() {
obj = $('section img');
$.each(obj, function(index) {
$(this).css({
position:'fixed',
top: index*100
});
});
});
section img {
width: 50px;
height: 50px;
border: 1px solid black;
}
section.one img {
border-color: red;
}
section.two img {
border-color: green;
}
section.three img {
border-color: blue;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section class="one">
<img src="one.png" alt="one"/>
</section>
<section class="two">
<img src="two.png" alt="two" />
</section>
<section class="three">
<img src="three.png" alt="three" />
</section>
Related
I'm trying to make a jquery code where you can show different images (1-3 different images) when you move the mouse around.
The images will be right beside the cursor, and they will only appear 1-3, not more than that. And each time the mouse moves, these images will change.
I currently have this as my html code,
<div class="mainbody">
<section class="container">
<div class="img_div">
</div>
</section>
</div>
And my jquery code looks like this:
let img_array = ['./img/awards_icon.png', './img/norinuri_icon.png'];
$("div.mainbody").mousemove(function(e) {
for(i=0; i<img_array.length; i++){
$('.img_div').append("<img src='" + img_array[i] +"'/>");
$('.img_div').fadeIn("5000");
$('.img_div').finish().fadeOut("5000");
$('.img_div').offset({
left: e.pageX,
top: e.pageY + 20
});
}
});
The 2 images that I have in my jquery array appears when the mouse moves, but instead of only having 2 images these images add continuously, without stopping.
So each time I would move my mouse, the images would continue to add infinitely.
I will add more images in the jquery array for sure,
but how should I have only two images added, and change these images as I move the mouse?
Use background-image
var imageArr=["https://www.w3schools.com/css/paper.gif","https://www.w3schools.com/css/gradient_bg.png","https://www.w3schools.com/css/img_tree.png"];
var count=0;
$( ".mainbody" ).mouseover(function() {
$( ".img_div" ).css('background-image', 'url("' + imageArr[count] + '")');
if(count == imageArr.length-1)
count=0;
else
count++;
});
.mainbody{
width: 500px;
height: 500px;
border:1px solid red;
}
.img_div{
width: 200px;
height: 200px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="mainbody">
<section class="container">
<div class="img_div">
</div>
</section>
</div>
Here is working fiddle;
USING mousemove (to avoid the images to change so many times while mouse move I use timeout)
var imageArr=["https://www.w3schools.com/css/paper.gif","https://www.w3schools.com/css/gradient_bg.png","https://www.w3schools.com/css/img_tree.png"];
var count=0;
var timeoutid = 0;
function setImage() {
$( ".img_div" ).css('background-image', 'url("' + imageArr[count] + '")');
if(count == imageArr.length-1)
count=0;
else
count++;
}
$(".mainbody").mousemove(function() {
clearTimeout(timeoutid);
timeoutid = setTimeout(setImage, 100);
});
.mainbody{
width: 500px;
height: 500px;
border:1px solid red;
}
.img_div{
width: 200px;
height: 200px;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="mainbody">
<section class="container">
<div class="img_div">
</div>
</section>
</div>
화이팅!
I have created a working example for you. You can try it now:
<div class="mainbody">
<section class="container">
<div class="img_div">
hello
</div>
</section>
css
.mainbody {
border:1px solid red;
display:block;
height:1000px
}
jquery
let img_array = ['https://anotherjavaduke.files.wordpress.com/2018/08/avataaars-2.png',
'https://images2.minutemediacdn.com/image/upload/c_crop,h_1192,w_2121,x_0,y_111/f_auto,q_auto,w_1100/v1554921884/shape/mentalfloss/22461-istock-176984635.jpg'];
$("div.mainbody").on('mousemove', function(e) {
var i;
$('.img_div').html('')
for (i = 0; i < img_array.length; i++) {
console.log($('.img_div').has('img').length)
if ($('.img_div').has('img').length < img_array.length) {
$('.img_div').append("<img style='width:100px; height:100px' src='" + img_array[i] + "'/>");
$('.img_div').fadeIn("5000");
$('.img_div').finish().fadeOut("5000");
$('.img_div').offset({
left: e.pageX,
top: e.pageY + 20
});
}
}
});
Working example
[Codepen] https://codepen.io/prashen/pen/ZEEqJEo
Hello I use skrollr js to create parallax website but because we don't know the height of section because section height depend on the content so what I need is find the last attribute and change number value only with section height.
for example:
for section 1 the data-800 (attr) will be data-800="position:fixed;top:-$('section 1').height;"
for section 2 the data-900 (attr) will be data-900="position:fixed;top:-$('section 2').height;"
my goal is get height for any section and set it in the attribute
$('section').attr('data-800', 'position:fixed;top:-' + $('.section').height());
var s = skrollr.init({
render: function(data) {
console.log(data.curTop);
}
});
html,
body {
margin: 0;
height:100%;
}
.grad0 {
height:100%;
position:fixed;
top:0px;
background-color: #FFAAAA;
background-image: url(https://production-assets.codepen.io/assets/profile/profile-bg-8ff33bd9518be912289d4620cb48f21eb5c9a2e0b9577484126cfe10a5fb354f.svg);
}
.grad1 {
position:fixed;
background-color: #00FF00
}
.grad2 {
position:fixed;
top:800px;
background-color: #0000FF
}
.grad3 {
position:fixed;
top:1200px;
height:400px;
background-color: #00FFFF
}
section {
width:100%;
}
img {
position: absolute;
top:150px;
}
<section class="grad0 w60" data-0="top:0px;" data-400="top:0px;" data-800="position:fixed;top:-400px;">
<img src="http://www.cs.cmu.edu/~chuck/lennapg/len_top.jpg" data-0="left:0px" data-400="left:1600px;">
</section>
<section class="grad1" data-400="position:fixed;top:638px;" data-900="position:fixed;top:-400px;">
<h1>Hello World</h1>
</section>
<section class="grad2" data-0="position:fixed;top:800px;" data-400="position:fixed;top:800px;" data-800="position:fixed;top:000px;">
content
</section>
<section class="grad3" data-0="position:fixed;top:1200px;" data-400="position:fixed;top:1200px;" data-800="position:fixed;top:400px;">
content
</section>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src='https://cdnjs.cloudflare.com/ajax/libs/skrollr/0.6.30/skrollr.min.js'></script>
Updated:
As you commented for each of the last data attribute should be targeted:
$('section').each(function() {
var $this = $(this)
var dataset = Object.keys(this.dataset);
$.each(dataset, function(i, item) {
if (i === dataset.length - 1) {
$this.attr('data-' + dataset[i], 'position:fixed;top:-' + $this.height());
console.log($this[0].dataset);
}
})
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<section class="grad0 w60" data-0="top:0px;" data-400="top:0px;" data-800="position:fixed;top:-400px;">
<img src="http://www.cs.cmu.edu/~chuck/lennapg/len_top.jpg" data-0="left:0px" data-400="left:1600px;">
</section>
<section class="grad1" data-400="position:fixed;top:638px;" data-900="position:fixed;top:-400px;">
<h1>Hello World</h1>
</section>
<section class="grad2" data-0="position:fixed;top:800px;" data-400="position:fixed;top:800px;" data-800="position:fixed;top:000px;">
content
</section>
<section class="grad3" data-0="position:fixed;top:1200px;" data-400="position:fixed;top:1200px;" data-800="position:fixed;top:400px;">
content
</section>
I am making a one page website and in the middle of the site i have a few images that i want to appear when the user is scrolling down. when the user is scrolling down, i want the image to fade in and stay at 100% opacity. Ive gone through loads of different scripts and none work. I have found a good code snipped but it still doesnt seem to be working. It just displays the image but with low opacity.
Here is the code:
<script>
var $win = $(window);
var $img = $('.fadeInScroll'); // Change this to affect your desired element.
$win.on('scroll', function() {
var scrollTop = $win.scrollTop();
$img.each(function() {
var $self = $(this);
var prev = $self.offset();
if (prev) {
var pt = 0;
pt = prev.top - $win.height();
$self.css({
opacity: (scrollTop - pt) / ($self.offset().top - pt)
});
} else {
$self.css({
opacity: 1
});
}
});
}).scroll();
</script>
<section id="about">
<h2><center>Header</center></h2>
<div class="fadeInScroll" display:="" opacity:="0" style="opacity: 0.1;"> <img src="/ap/wsf1.png" alt="trulycode-responsive" class="aligncenter size-medium wp-image-555"></div>
</section>
Ok. So if I correctly understand what you want, you can block your fade effect when your images are already fade in this way :
var $win = $(window);
$win.on('scroll', function () {
var scrollTop = $win.scrollTop();
$('img.hidden').each(function () {
var $self = $(this);
var prev=$self.offset();
if(prev){
var pt=prev.top-$win.height();
var opacity = (scrollTop-pt) / ($self.offset().top-pt);
$self.css({
opacity: opacity
});
if(opacity >= 1) $self.removeClass('hidden');
}
else{
$self.css({
opacity: 1
});
}
});
}).scroll();
.wrapper {
background: orange;
height: 2000px;
}
.wrapper img {
width: 300px;
position: absolute;
opacity: 0;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<div class="wrapper">
<img class="hidden" style="top: 400px;" src="http://sport-nc.com/wp-content/uploads/2015/06/India_Surf_Tours_-_17__1_.jpg"/>
<img class="hidden" style="top: 1000px;" src="http://sport-nc.com/wp-content/uploads/2015/06/India_Surf_Tours_-_17__1_.jpg"/>
<img class="hidden" style="top: 1600px;" src="http://sport-nc.com/wp-content/uploads/2015/06/India_Surf_Tours_-_17__1_.jpg">
</div>
Try changing the part where you have the inline style of style="opacity: 0.1; . Usually inline styles override the CSS you might have in the style tag. Look at this example I set the inline style to blue but the set it in the css to red the blue wins. maybe that is what is cause your opacity to stay the same.
#element{
color:red;
}
<div id="element" style = "color:blue;">element</div>
That's one reason why it's better to add and remove classes for you styles
I see that your overriding the inline styles with other inline styles so the above may not have caused you problems anyways Here is your snippet working. I don't know exactly what you want. It fades in
$(function(){
var $win = $(window);
var $img = $('.fadeInScroll'); // Change this to affect your desired element.
$win.on('scroll', function () {
var scrollTop = $win.scrollTop();
$img.each(function () {
var $self = $(this);
var prev=$self.offset();
if(prev){
var pt=0;
pt=prev.top-$win.height();
$self.css({
opacity: (scrollTop-pt)/ ($self.offset().top-pt)
});
}
else{
$self.css({
opacity: 1
});
}
});
}).scroll();
})
.top{
height: 100vh;
background: rgba(120, 30, 200, 0.3);
}
.fadeInScroll{
width: 300px;
height: 500px;
background: blue;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.0/jquery.min.js"></script>
<div class="top"></div>
<section id="about">
<h2><center>Header</center></h2>
<div class="fadeInScroll" display:="" opacity:="0" style="opacity: 0.1;">
<img src="/ap/wsf1.png" alt="trulycode-responsive" class="aligncenter size-medium wp-image-555">
</div>
<div class="fadeInScroll" display:="" opacity:="0" style="opacity: 0.1;">
<img src="/ap/wsf1.png" alt="trulycode-responsive" class="aligncenter size-medium wp-image-555">
</div>
<div class="fadeInScroll" display:="" opacity:="0" style="opacity: 0.1;">
<img src="/ap/wsf1.png" alt="trulycode-responsive" class="aligncenter size-medium wp-image-555">
</div>
<div class="fadeInScroll" display:="" opacity:="0" style="opacity: 0.1;">
<img src="/ap/wsf1.png" alt="trulycode-responsive" class="aligncenter size-medium wp-image-555">
</div>
</section>
So I have this:
https://jsfiddle.net/ysr50m2m/1/
Html
class="photoset">
<img src="http://inspirebee.com/wp-content/uploads/2013/04/animal-fashion-parade.jpg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals18.jpg" />
<img src="http://inspirebee.com/wp-content/uploads/2013/04/animal-in-fashion.jpg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals20.jpg" />
</div>
<div class="photoset">
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals26.jpeg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals14.jpg" />
<img src="http://inspirebee.com/wp-content/uploads/2013/04/animal-fashion.jpg" />
<img src="https://framboisemood.files.wordpress.com/2013/04/fashion-zoo-animals13.jpg" />
<img src="http://www.fubiz.net/wp-content/uploads/2013/03/Fashion-Zoo-Animals9.jpg" />
</div>
CSS
.photoset > img:not(:first-child) {
display: none;
}
JavaScript
$(document).ready(function() {
$('.photoset').each(function(){
$(this).data('counter', 0);
});
var showCurrent = function(photoset) {
$items = photoset.find('img');
var counter = photoset.data('counter');
var numItems = $items.length;
var itemToShow = Math.abs(counter % numItems);
$items.fadeOut();
$items.eq(itemToShow).fadeIn();
};
$('.photoset').on('click', function(e) {
e.stopPropagation();
var photoset = $(this);
var pWidth = photoset.innerWidth();
var pOffset = photoset.offset();
var x = e.pageX - pOffset.left;
if (pWidth / 2 > x) {
photoset.data('counter', photoset.data('counter') - 1);
showCurrent(photoset);
} else {
photoset.data('counter', photoset.data('counter') + 1);
showCurrent(photoset);
}
});
});
and I want the images to overlap. When I click an image, the next one appears first on the bottom and then it appears in place of the first image.
How can I solve this issue? Thanks in advance.
Since 2 elements can't occupy the same position unless they're positioned to do so, I absolutely placed the other image above the previous one, and when the previous one disappears, I removed the absolute positioning.
Fiddle:
https://jsfiddle.net/qu1Lxjo1/
CSS:
.photoset {
position: relative;
}
.photoset img {
position: relative;
top: 0px;
left: 0pxx
}
JS:
$items.fadeOut();
$items.eq(itemToShow).fadeIn({done: function() {
$(this).css('position','relative')
}}).css('position', 'absolute');
};
i have 2 css classes , left side and right side of screen and i need to put them togheter, in these classes i have images which look like a puzzle:
By dragging image from the right side to the left side.At drop,must fit with the image from left side. I read about drag and drop but didnt find something like that :(
What i've tried?
EDIT: http://postimg.org/image/je31ptb6d/ (this is an example with my pictures.On top are images separated as classes - class="left" for ca and class="right" for nă.On bottom are images after i drop the image from right to one from left.My question is how to specify the correct drop zone to make images look like bottom one from link after i drop image from right side? )
JS/Jquery:
// shuffle function for right side only
$(document).ready(function() {
var a = $(".right > img").remove().toArray();
for (var i = a.length - 1; i >= 1; i--) {
var j = Math.floor(Math.random() * (i + 1));
var bi = a[i];
var bj = a[j];
a[i] = bj;
a[j] = bi;
}
$(".right").append(a);
});
// drag and drop
$(function() {
$( ".right img" ).draggable
({
cursor: 'move',
revert: 'invalid',
});
$( ".left img" ).droppable({
tolerance: 'fit',
});
});
HTML:
<div class="left">
<img class="piese" id="piesa1" src="images/Text_1.svg" />
<img class="piese" id="piesa2" src="images/Text_2.svg" />
<img class="piese" id="piesa3" src="images/Text_3.svg" />
<img class="piese" id="piesa4" src="images/Text_4.svg" />
</div>
<div class="right">
<img class="piese" id="piesa5" src="images/Text_5.svg" />
<img class="piese" id="piesa6" src="images/Text_6.svg" />
<img class="piese" id="piesa7" src="images/Text_7.svg" />
<img class="piese" id="piesa8" src="images/Text_8.svg" />
</div>
To solve your problem you must build a grid
and use drag drop by taking as a reference the location of the squares of the grid.
This is a simple example to give you an idea.
<!DOCTYPE HTML>
<html>
<head>
<title>Example</title>
<style>
#grid{
background-color: #09F;
height: 130px;
width: 390px;
position:relative;
margin:100px auto;
}
.square{
height: 128px;
width: 128px;
border:1px solid #999;
float:left;
}
#first-image{
position: absolute;
left: 0px;
}
#second-image{
position: absolute;
right: 0px;
}
</style>
</head>
<body>
<!--take two images by 120px with this class and id -->
<div id="grid">
<img class="dr" id="first-image" src="your-image.png" width="128" height="128">
<img class="dr" id="second-image" src="your-image.png" width="128" height="128">
</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$(document).ready(function(){
for(xx = 0; xx < 3; xx++) {
$("#grid").append($('<div class="square"></div>'));
};
$('.dr').on("dragstart", function (event) {
var dt = event.originalEvent.dataTransfer;
dt.setData('Text', $(this).attr('id'));
});
$('div.square').on("dragenter dragover drop", function (event) {
event.preventDefault();
if (event.type === 'drop') {
var data = event.originalEvent.dataTransfer.getData('Text',$(this).attr('id'));
de=$('#'+data).detach();
var x = $(this).position().left;
var y = $(this).position().top;
de.css({'position':'absolute','top':y+'px','left':x+'px'}).appendTo($(this));
};
});
});
</script>
</body>
</html>