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The objective is not to use any of build in functions related to math to determine "isEven", but what is isEven(-n) suppose to do, and for those pondering what (n-2) does is that it subtracts a variable to a point of arriving to 1 or 0 (I don't belief that the book explains what the exercise is, so just looked at the answer).
function isEven(n) {
if (n == 0)
return true;
else if (n == 1)
return false;
else if (n < 0)
return isEven(-n);
else
return isEven(n - 2);
}
Looks like that just turns any negative number into a positive number, so for instance:
-10, 10, 8, 6, 4, 2,0 => even
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it is hard to find a solution to this question, so I have a short way to do that. To find the count of numbers that's divisible to 3 and 4 between 1 and 100 we have a formula in Math: |b - a|: LCM (Lowest Common Multiple) + 1. I have all the stuff that is needed to create this program but I had a few issues with my code so I couldn't finish it. Can someone help me?
var totalCount3=0;
var totalCount4=0;
for(var i=1;i<=100;i++){
if(i % 3 == 0){
totalCount3 += 1;
}
if(i%4 == 0){
totalCount4 += 1;
}
}
console.log(totalCount3);
console.log(totalCount4);
The range of values you are checking is very limited (1-100) so you can use a bruteforce approach. You can simply scanning all values from to 100 and then check if each value is divisible using the module operator. I suppose you use javascript:
var counter = 0;
for(var i = 1; i<=100; i++){
if((i%3==0)||(i%4==0)){
counter++
}
}
console.log(counter);
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I have only one number like "100000"
I wan't to split this number same as [20000,20000,20000,20000,20000] in array
so if number is 138000 then it should be like [20000,20000,20000,20000,20000,20000,18000]
How to do this?
let num = 118000,
num_array = [];
while (num > 0) {
if (num >= 20000) {
num_array.push(20000);
num -= 20000;
} else {
num_array.push(num);
break;
}
}
console.log(num_array);
I think this is what you want, please post what you tried, so that it helps to understand where you failed.
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I do not have any JavaScript experience and would like some assistance in creating a function as I am not sure on how to do it.
I would like to create a Function that validates that x between 1 and 17 it can also be equal to 1 and 17
If the value is not valid a simple messagebox/alert could be used to notify the user
I know this is a really stupid question but thank you in advance
A function like that would look something like:
function validateNumber(n) {
var ok = n >= 1 && n <= 17;
if (!ok) alert('The value is not valid. Values from 1 to 17 are allowed.');
return ok;
}
You can call it, and you get the status back if you want to use it for something:
if (validateNumber(x)) {
// the number was valid
} else {
// the number wasn't valid
}
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I'm taking online class to learn JS and I'm stuck. The quiz is asking me to:
Returns the cube of the sum of an input and 2.
So I coded this:
var returnCubed = function(num){ return (num + 2) * 3;};
But it doesn't pass. What else can I do to take in a parameter, add two to it, then cube it? Or am I not understanding the directions?
Try
var returnCubed = function(num){
return (num+2) * (num+2) * (num+2);
};
*3 will always multiply with 3.
Hope this can solve your problem.
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returns the index where pattern starts in string (or -1 if not found).
The search is to be case sensitive if the 3rd parameter is true otherwise it is case insensitive.
Examples
index("abAB12","AB",true) returns 2 but index("abAB12","AB",false) returns 0
index("abAB12","BA",true) returns -1 and index("abAB12","BA",false) returns 1
Maybe something like:
var str = "abAB12";
var i = str.indexOf("AB");
if (i < str.length / 2) {
//stuff
} else {
//other stuff
}