We Keep Coding

Click the same option again in a select with JQuery

I have the next code with a Select:
http://jsfiddle.net/pdkg1mzo/18/
The problem is that I want to launch the alert every time a select option is clicked, although the option that was clicked is the one that is currently selected.

This may work:
$(function(){
$(".normal").on("change",function(){
//alert("trigger");
var selectedName = $('#selectId').find(":selected").text();
console.log('selectedName is: ', selectedName)
alert(selectedName)
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select class="normal" id="selectId">
<option value="18">John</option>
<option value="18">Lorry</option>
<option value="19">Jerry</option>
<option value="20">Smith</option>
</select>
You could add a half second delay to the alert, so it shows the name after the selection has been made:
$(function(){
$(".normal").on("change",function(){
//alert("trigger");
var selectedName = $('#selectId').find(":selected").text();
console.log('selectedName is: ', selectedName)
setTimeout(function () {
//do something once
alert(selectedName)
}, 500);
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select class="normal" id="selectId">
<option value="18">John</option>
<option value="18">Lorry</option>
<option value="19">Jerry</option>
<option value="20">Smith</option>
</select>

Try this,
$(function(){
$(".normal option").on("click",function(){
alert("trigger");
});
});

try this,
<select class="normal" name="mysel" onChange="show(this);">
<option value="18">John</option>
<option value="18">Lorry</option>
<option value="19">Jerry</option>
<option value="20">Smith</option>
</select>
pure javascript
<script>
function show(m){
var k=m.options[m.selectedIndex].value;
alert(k);
}
</script>
Try this it perfectly works.

I think you can't do this, but perhaps you can try Chosen: https://plugins.jquery.com/chosen/.
I don't know why do you want to do this, do you want to reload de page, load Ajax results. Maybe it is unnecessary for user experience and you will not improve it at all.

Add selected select option to jquery form submit

Just having a little trouble with part of my code.
Basically new elements are added into the page through .html() and ajax response. An example of added elements are commented in the code. Because the codes were added into the page through .html the form wasn't submitting the added fields. So I used .append($('.newfields') which works perfectly on the checkbox but fails on the select box which is the purpose of this question.
Any way to include the new select boxes on form submit?
Thank you all in advance for you help!
$('.button').click(function(){
$('#domaincheckform').append($('.newfields'));
$( "#domaincheckform" ).submit();
});
<form action="cart.php" id="domaincheckform" method="post">
<select form="domaincheckform" name="termselect[]">
<option value="1">1 year</option>
<option value="2">2 year</option>
</select>
<input type="checkbox" name="did[]" value="example1">
<!--EXAMPLE ADDED FIELD-->
<select form="domaincheckform" class="newfields" name="termselect[]">
<option value="1">1 year</option>
<option value="2">2 year</option>
</select>
<input type="checkbox" class="newfields" name="did[]" value="example2">
<!--END OF EXAMPLE ADDED FIELD-->
<span class="button">Button</span>
</form>

You need to wrap your select inside a div
try this
<form action="cart.php" id="domaincheckform" method="post">
<select form="domaincheckform" name="termselect[]">
<option value="1">1 year</option>
<option value="2">2 year</option>
</select>
<input type="checkbox" name="did[]" value="example1">
<!--EXAMPLE ADDED FIELD-->
<div class="append_content"><select form="domaincheckform" class="newfields" name="termselect[]">
<option value="1">1 year</option>
<option value="2">2 year</option>
</select> </div>
<input type="checkbox" class="newfields" name="did[]" value="example2">
<!--END OF EXAMPLE ADDED FIELD-->
<span class="button">Button</span>
</form>
Also make changes in your js like this
<script>
$(document).ready(function() {
$('.button').click(function(){
$('#domaincheckform').append($('.append_content').html());
$( "#domaincheckform" ).submit();
});
});
</script>
now the select is inside a div append_content its easy to fetch its content as select has multiple html content so it will return object if you use only selector name $(".newfields")

$(selector).click(function(){}) sometimes fails to work. Try using $(selector).on("click", function(){})
It worked here: https://jsbin.com/vemuxukehi/edit?html,js,output

Heres is a simple working example that adds the and displays it in the submitted form data
https://jsfiddle.net/uapejgu5/
$(function () {
$("#submit").click(function () {
$("#result").html($('#myform').serialize())
return false
})
$("#add").click(function () {
var select = $("<select>", {
name: "newSelect"
})
$(select).append($("<option>", {
text: "myNewOption",
value: "myNewValue"
}))
$("#myform").append(select)
})
})

Check out this fiddle:
https://jsfiddle.net/bbdkr9g5/1/
Basically what you wrote, plus some code to print out the form result in the console. And you had the same name attributes on both your static and your dynamically-inserted elements, which is probably not what you wanted.

You should clone the elements and remove the newfields class before adding them to the form.
$('.button').click(function(){
$('#domaincheckform').append($('.newfields').clone().removeClass('newfields'));
$('#domaincheckform').submit();
});
Here is a JSFiddle example that skips the actual submit: JSFiddle

Change the CSS attribute if an option selected with jQuery

I have this code:
<select>
<option disabled selected>Select Method</option>
<option value="question">Question</option>
<option value="password">Password</option>
<option value="email">Email</option>
<option value="none">None</option>
</select>
Now I want when user select each of them some div that hidden in css with display:none; get visible for example when user select Question the div that have question id get visible or when Password selected the div that have password id get visible.
I try this but not work:
$(document).ready(function(){
if ($("#auth option:selected").text() == "question"){
$("#question").css("display","block");
}
});
So how can I do this?

If you follow the pattern you have done so far, you have to write code for each option. If your options and div elements are coupled with value and id, you can simply do like this,
$("select").change(function() {
$("div").hide();
$("#" + $(this).val()).show();
});
Demo Fiddle

Here is Demo for this , remove disabled from select tag so that user can select the options
Jsfiddle
http://jsfiddle.net/adarshkr/z9gcf40r/2/
Code
HTML
<select id="showdiv">
<option disabled selected>Select Method</option>
<option value="question">Question</option>
<option value="password">Password</option>
<option value="email">Email</option>
<option value="none">None</option>
</select>
<div id="question" class="hide">
<p>question</p>
</div>
<div id="password" class="hide">
<p>password</p>
</div>
<div id="email" class="hide">
<p>email</p>
</div>
<div id="none" class="hide">
<p>none</p>
</div>
CSS
.hide{
display:none
}
JAVASCRIPT
$("select").change(function(){
$("div").hide();
$("#"+$(this).val()).show();
});

try this,
$('#auth').on('change', function() {
var that = $(this).val();
if (that === "question"){
$("#question").css("display","block");
}
});

Better check value than the text.
$(document).ready(function(){
if ($("#auth option:selected").val() == "question"){
$("#question").css("display","block");
}
});

Jquery/Js: Hide/Show Divs based on select box option values

These are Dynamic dependent select controls. The sets of values of (1-3, 4-6, 7-9) determine the use hide/show divs function. The problem is the function i have only hide/show depending on the div id. How can i make the function hide/show div depended on the values(1-3, 4-6, 7-9) found in the selectbox?
Jquery
$('#select').change(function() {
$('#sub1, #sub2, #sub3').hide();
$('#sub' + $(this).find('option:selected').attr('id')).show();
});
Html Setup
<html>
<select size="6" id="category">
<option value="">categories 1-3 </option>
<option value="">----</option>
<option value="">----</option>
</select>
<div id="sub1" style="display:none">
<select name="subc1" size="6">
<option value="1">subcategories 4-6</option>
<option value="2">---</option>
<option value="3">---</option>
</select>
</div>
<div id="sub2" style="display:none">
<select name="subc2" size="6">
<option value="4">subcategories 7-9</option>
<option value="5">----</option>
<option value="6">----</option>
</select>
</div>
<div id="sub3" style="display:none">
<select name="subc3" size="6">
<option value="7">End</option>
<option value="8">----</option>
<option value="9">----</option>
</select>
</div>
</html>

select the value from drop down change function and do the operation depends on the value of drop down, following is the sample code
$(function() // Shorthand for $(document).ready(function() {
$('select').change(function() {
if($(this).val() == 1)
{
$('#sub1').hide();
$('#sub2').show();
}
});
});

You nee to change minor change in your category select
<select size="6" id="category">
<option value="1">categories 1-3 </option>
<option value="2">----</option>
<option value="3">----</option>
</select>
$('select#category').on('change', function() {
$('div[id=^sub]:visible').hide();
$('div#sub' + this.value).show();
});
can also use .change() instead of .on('change').
$('select#category').change(function() {
$('div[id=^sub]:visible').hide();
$('div#sub' + this.value).show();
});
NOTE:
$('div[id=^sub]:visible') will point to all divs that have id start with sub and visible.
You are trying with $('#select') which need to be $('#category') or $('select#category').
According to your comment:
Complete solution will look like following:
function isOnlyDashed(text) {
return text.replace(/-/g, '').length === 0;
}
$('select#category').change(function() {
var text = $('option:selected', this).text();
if (!isOnlyDashed(text)) {
$('div[id=^sub]:visible').hide();
$('div#sub' + this.value).show();
}
});
$('select[name^=subc]').change(function() {
var text = $('option:selected', this).text();
if (!isOnlyDashed(text)) {
$(this).parent() // jump to parent div
.next('div[id^=sub]:hidden') // go to next hidden div
.show();
}
});
Complete Workout

The problem with your code is that you have an incorrect selector.
$('#select')...
should be
$('select')...
Also, this part is wrong
$('#sub' + $(this).find('option:selected').attr('id')).show();
Replace it with this
$('#sub' + $(this).val()).show();
Finally, having different elements with the same name/id "sub1" is probably a bad idea, though technically not illegal. It is certainly confusing.

working demo http://jsfiddle.net/FwBb2/1/
I have made minor changes in your Jquery code as well as added value in your first select drop-down list which was missing rest hope this helps.
Please lemme know if I missed anything! B-)
code
$('select').change(function() {
$('#sub1, #sub2, #sub3').hide();
$('#sub' + $(this).val()).show();
});​
HTML
<html>
<select id="category">
<option value="1">categories 1-3 </option>
<option value="2">----</option>
<option value="3">----</option>
</select>
<div id="sub1" style="display:none">
<select name="subc1" size="6">
<option value="1">subcategories 4-6</option>
<option value="2">---</option>
<option value="3">---</option>
</select>
</div>
<div id="sub2" style="display:none">
<select name="subc2" size="6">
<option value="4">subcategories 7-9</option>
<option value="5">----</option>
<option value="6">----</option>
</select>
</div>
<div id="sub3" style="display:none">
<select name="subc3" size="6">
<option value="7">End</option>
<option value="8">----</option>
<option value="9">----</option>
</select>
</div>
</html>​

jQuery: Show/Hide Elements based on Selected Option from Dropdown

UPDATE: The original question asked was answered. However, the code revealed for all. So, I've modified my question below:
So I have the following dynamically generated html via php
<div class="image-link link-posttypes mainSelector1">
<select id="wp_accordion_images[20110630022615][post_type]" name="wp_accordion_images[20110630022615][post_type]">
<option value="">default</option>
<option value="post" class="post-type">Post</option><option value="page" class="post-type">Page</option><option value="dp_menu_items" class="post-type">Menu Items</option>
<option value="wps_employees" class="post-type">Employees</option><option value="custom-link">Custom Link</option>
</select>
</div>
<div class="image-link link-pages1">
<select id="wp_accordion_images[20110630022615][page_id]" name="wp_accordion_images[20110630022615][page_id]">
<option value="50" class="level-0">About</option>
<option value="65" class="level-0">Contact</option>
<option value="2" class="level-0">Sample Page</option>
<option value="60" class="level-0">Staff</option>
</select>
</div>
<div class="image-link link-posts1">
<select onchange="javascript:dropdown_post_js(this)" id="wp_accordion_images[20110630022615][post_id]" name="wp_accordion_images[20110630022615][post_id]">
<option value="http://localhost/tomatopie/?p=1" class="level-0">Hello world!</option>
</select>
</div>
<div class="image-link link-custom1">
<input type="text" size="25" value="" name="wp_accordion_images[20110630022615][image_links_to]">
</div>
***THEN IT REPEATS four times: where the #1 goes to 2..3...4 (max to 4 at this time).
I have the ability to label div .classes, select #ids, and option classes. However, what I want to be able to do is based on the option selected from div .link-posttypes, I want to reveal .link-pages (if page is selected) or .link-posts (if post is selected) and .link-custom for all others (except the default).
So as written on the screen there should only be the initial div, and once the user selects an item, the appropriate div appears.
I have never developed anything in jQuery or javascript. This is my maiden voyage. Any help will be greatly appreciated!
***Also, this will be loaded via an external js file.

Here is the final answer that worked:
jQuery(document).ready(function($) {
$(".link-posttypes select").change(function(){
var selectedVal = $(":selected",this).val();
if(selectedVal=="post"){
$(this).parent().nextAll(".link-pages").hide();
$(this).parent().nextAll(".link-posts").slideDown('slow');
$(this).parent().nextAll(".link-custom").hide();
}else if(selectedVal=="page"){
$(this).parent().nextAll(".link-pages").slideDown('slow');
$(this).parent().nextAll(".link-posts").hide();
$(this).parent().nextAll(".link-custom").hide();
}else if(selectedVal!=""){
$(this).parent().nextAll(".link-pages").hide();
$(this).parent().nextAll(".link-posts").hide();
$(this).parent().next().nextAll(".link-custom").slideDown('slow');
}else{
$(this).parent().nextAll(".link-pages").hide();
$(this).parent().nextAll(".link-posts").hide();
$(this).parent().nextAll(".link-custom").hide();
}
});
});
jQuery(document).ready(function($) {
$(".image-content select").change(function(){
var selectedVal = $(":selected",this).val();
if(selectedVal=="content-limit"){
$(this).parent().next().nextAll(".content-limit-chars").slideDown('slow');
$(this).parent().nextAll(".content-custom").hide();
}else if(selectedVal=="custom-content"){
$(this).parent().nextAll(".content-limit-chars").hide();
$(this).parent().next().nextAll(".content-custom").slideDown('slow');
}
});
});
Thanks for your help!

Assuming that you're outputting proper IDs, you can do something like this (note I replaced the id):
$(window).load(function(){
// hide all the divs except the posttypes
$('.image-link').not('.link-posttypes').hide();
$('#wp_accordion_images_20110630022615_post_type').change(function() {
var divSelector = '.link-' + $(this).val();
$('.image-link').not('.link-posttypes').hide();
$(divSelector).show();
});
});
Also, consider changing your options like this:
<option value="posts" class="post-type">Post</option>
<option value="pages" class="post-type">Page</option>
<option value="menu_items" class="post-type">Menu Items</option>
<option value="wps_employees" class="post-type">Employees</option>
<option value="custom">Custom Link</option>
Here's a jsfiddle for this: http://jsfiddle.net/JrPeR/

There's my understandable jquery script
jQuery(document).ready(function($) {
$(".link-pages").hide();
$(".link-posts").hide();
$(".link-custom").hide();
$(".link-posttypes select").change(function(){
var selectedVal = $(":selected",this).val();
if(selectedVal=="post"){
$(".link-pages").hide();
$(".link-posts").show();
$(".link-custom").hide();
}else if(selectedVal=="page"){
$(".link-pages").show();
$(".link-posts").hide();
$(".link-custom").hide();
}else if(selectedVal!=""){
$(".link-pages").hide();
$(".link-posts").hide();
$(".link-custom").show();
}else{
$(".link-pages").hide();
$(".link-posts").hide();
$(".link-custom").hide();
}
});
});
Demo here. Take me couple minute to make you easy to understand. Have fun.

http://jsfiddle.net/JrPeR/3/
added a conditional so if its not the two variables it defaults to the custom.