I am creating a simple gallery with an overlay to display enlarged image when clicked.
In my gallery, every 3 images are grouped into a container as
<div class='overlay'>
<a class='next control'>Next</a>
</div>
<div class="container">
<div class="image">
<img src="http://dummyimage.com/100&text=Image1"/>
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image2" />
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image3"/>
</div>
</div>
<div class="container">
<div class="image">
<img src="http://dummyimage.com/100&text=Image4"/>
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image5" />
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image6"/>
</div>
</div>
JQuery
$(document).ready(function () {
var src;
var currentElement;
$(".image").click(function () {
currentElement = $(this);
src = $(currentElement).find("img").attr("src");
$(".overlay").css("background-image", "url('" + src + "')");
$(".overlay").show();
});
$(".next").click(function () {
if ($(currentElement).next().length) {
currentElement = currentElement.next();
src = $(currentElement).find("img").attr("src");
}
else {
currentElement = $(currentElement).parent().next().find(".image:first");
src = $(currentElement).find("img").attr("src");
}
$(".overlay").css("background-image", "url('" + src + "')");
});
});
I am able to get the next image on clicking next. But my problem is How to disable the next button when last image reaches ?.
I am unable to find a logic to get the last image.
Note: the images in last container may vary from 1 to 3
Here is the demo : https://jsfiddle.net/y5fwgz25/1/
here is my solution but i do not like this code, but works fine
<div class='overlay'>
<a class='next'></a>
</div>
<div id="gallery">
<div class="container">
<div class="image">
<img src="http://dummyimage.com/100&text=Image1"/>
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image2" />
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image3"/>
</div>
</div>
<div class="container">
<div class="image">
<img src="http://dummyimage.com/100&text=Image4"/>
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image5" />
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image6"/>
</div>
</div>
</div>
<script type="text/javascript">
$(document).ready(function () {
var src;
var currentElement;
var last_img = $("#gallery .container:last-child .image:last-child");
$(".image").click(function () {
currentElement = $(this);
src = $(currentElement).find("img").attr("src");
$(".overlay").css("background-image", "url('" + src + "')");
$(".overlay").show();
if ( $(currentElement)[0] == $(last_img)[0] ) {
$(".overlay .next").hide();
}
});
$(".next").click(function () {
if ( $(currentElement).next()[0] == $(last_img)[0] ) {
$(".overlay .next").hide();
}
if ($(currentElement).next().length) {
currentElement = currentElement.next();
src = $(currentElement).find("img").attr("src");
}else {
currentElement = $(currentElement).parent().next().find(".image:first");
src = $(currentElement).find("img").attr("src");
}
$(".overlay").css("background-image", "url('" + src + "')");
});
});
</script>
why don't you use jquery last method to get the last sibling and compare any of its attributes with the same attributes of the current element.
If they are the same, hide or disable the next button.
You can add one if condition. If the length of currentElement is zero then hide .next.
Updated Fiddle-
$(document).ready(function () {
var src;
var currentElement;
$(".image").click(function () {
currentElement = $(this);
src = $(currentElement).find("img").attr("src");
$(".overlay").css("background-image", "url('" + src + "')");
$(".overlay").show();
});
$(".next").click(function () {
if ($(currentElement).next().length) {
currentElement = currentElement.next();
src = $(currentElement).find("img").attr("src");
}
else {
currentElement = $(currentElement).parent().next().find(".image:first");
src = $(currentElement).find("img").attr("src");
}
if($(currentElement).length==0) {
$(".next").hide();
}
$(".overlay").css("background-image", "url('" + src + "')");
});
});
.overlay {
position: fixed;
top: 0;
left: 0;
display: none;
width: 100%;
height: 100%;
background: rgba(0, 0, 0, 0.9) no-repeat;
background-position: center;
}
.next {
position: absolute;
width: 50px;
height: 50px;
top: 50%;
background-image: url("http://dummyimage.com/50&text=Next");
right: 8em;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class='overlay'>
<a class='next'></a>
</div>
<div class="container">
<div class="image">
<img src="http://dummyimage.com/100&text=Image1"/>
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image2" />
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image3"/>
</div>
</div>
<div class="container">
<div class="image">
<img src="http://dummyimage.com/100&text=Image4"/>
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image5" />
</div>
<div class="image">
<img src="http://dummyimage.com/100&text=Image6"/>
</div>
</div>
Related
I am trying to make a script that will take the images from one div element and put it to div rndmImage randomly on button click, I should see images when document is loaded, but the new div where images should go after click must be empty until click heapends. And I need only JavaScript, no jQuery, alse i can not change the html, and it has to work for any number of images. So if you have some ideas that would be great. Here's my code.
window.addEventListener('load', start, false);
function start() {
var butt = document.getElementsByTagName('button')[0];
var rnImg = document.getElementsByClassName('ekran');
var pictures = document.getElementsByTagName('img');
var choose = Math.floor(Math.random()*pictures.length);
butt.addEventListener('click', menjaj, false);
function menjaj(e) {
var new = e.button;
var img = [];
for(var i = 0; i< pictures.length; i++) {
var dodaj = img[i];
img.push(dodaj);
}
//ekran.src = 'slike/' + slike[izbor] + '.jpg';
}
}
<body>
<div class="wrapper">
<div>
<img src="slike/leto1.jpg" alt="leto1">
<img src="slike/leto2.jpg" alt="leto2">
<img src="slike/leto3.jpg" alt="leto3">
<img src="slike/leto4.jpg" alt="leto4">
<img src="slike/leto5.jpg" alt="leto5">
<img src="slike/leto6.jpg" alt="leto6">
<img src="slike/leto7.jpg" alt="leto7">
<img src="slike/leto8.jpg" alt="leto8">
<img src="slike/leto9.jpg" alt="leto9">
</div>
<div>
<button type="button">choose</button>
</div>
<div class="rndmImage"></div>
</div>
</body>
This is a working snippet of your code:
window.addEventListener('load', start, false);
function start () {
var butt = document.getElementsByTagName('button')[0];
var rnImg = document.getElementsByClassName('rndmImage')[0]; //Change selector to existing class and select the first (the only) one
var pictures = document.getElementsByTagName('img');
butt.addEventListener('click', menjaj, false);
function menjaj (e) {
// var new = e.button;// 'new' is reserved word in JS, you can't use it as variable name
// var btn = e.button;// but this line is useless
var choose = Math.floor(Math.random() * pictures.length); //better move this line inside this function to get rundom image every button clicks
var img = document.createElement('img'); //creates new img tag
img.src = pictures[choose].src;
rnImg.innerHTML = ''; //to delete previous image
rnImg.appendChild(img);
// var img = []; //useless lines of code
// for(var i = 0; i< pictures.length; i++) {
// var dodaj = img[i];
// img.push(dodaj);
// }
//ekran.src = 'slike/' + slike[izbor] + '.jpg';
}
}
welcome to StackOverflow!
I would first hide the .wrapper > div img as that will prevent the images to show, then, append a data-pos to help select the position and simply randomize them and pick the src to show on the placeholder
and remember that you have a <div> as placeholder, so you can't assign src, only if you change it to <img>
so, something like this 😊
function chooseImg() {
// get total images available
var totalImages = document.querySelectorAll('.wrapper > div img').length
log('totalImages', totalImages)
// get a random position
var rndPosition = Math.floor(Math.random() * totalImages)
log('rndPosition', rndPosition)
// get hold of the image for such position
var rndImage = document.querySelector('.wrapper > div img[data-pos="' + rndPosition + '"]')
log('rndImage', rndImage)
// assign the source to the DIV
document.querySelector('.rndmImage').style = 'background-image: url("' + rndImage.src + '")'
}
function log(txt, obj) {
console.log(txt, obj)
}
.wrapper > div img {
display: none;
}
.rndmImage {
background-size: contain;
background-repeat: no-repeat;
width: 100px;
height: 100px;
}
<div class="wrapper">
<div>
<img data-pos="0" src="https://randomwordgenerator.com/img/picture-generator/54e5d2434953a514f1dc8460962e33791c3ad6e04e507440742f7cd09645cc_640.jpg" alt="leto1">
<img data-pos="1" src="https://randomwordgenerator.com/img/picture-generator/54e2d1404a57a814f1dc8460962e33791c3ad6e04e5074417c2d78d19f44c4_640.jpg" alt="leto2">
<img data-pos="2" src="https://randomwordgenerator.com/img/picture-generator/57e2d5444851a414f1dc8460962e33791c3ad6e04e50744172287ad2914fc4_640.jpg" alt="leto3">
<img data-pos="3" src="https://randomwordgenerator.com/img/picture-generator/51e8d0444f56b10ff3d8992cc12c30771037dbf85254794e722c73d19245_640.jpg" alt="leto4">
<img data-pos="4" src="https://randomwordgenerator.com/img/picture-generator/53e4d2464a56a914f1dc8460962e33791c3ad6e04e507440722d7cd39345c1_640.jpg" alt="leto5">
<img data-pos="5" src="https://randomwordgenerator.com/img/picture-generator/57e9dc434b5ba414f1dc8460962e33791c3ad6e04e50744172297bd5934cc4_640.jpg" alt="leto6">
<img data-pos="6" src="https://randomwordgenerator.com/img/picture-generator/55e1dc4b4254ad14f1dc8460962e33791c3ad6e04e507440722d72d09249c7_640.jpg" alt="leto7">
<img data-pos="7" src="https://randomwordgenerator.com/img/picture-generator/57e9d4474e54a814f1dc8460962e33791c3ad6e04e50744172297cdd974cc0_640.jpg" alt="leto8">
<img data-pos="8" src="https://randomwordgenerator.com/img/picture-generator/53e6dc404951b10ff3d8992cc12c30771037dbf852547848702e7ed19348_640.jpg" alt="leto9">
</div>
<div>
<button type="button" onclick="chooseImg()">choose</button>
</div>
<div class="rndmImage"></div>
</div>
<div class="wrapper">
<img src="../Assets1/Image/1.svg" alt="" />
<img src="../Assets1/Image/2.svg" alt="" />
<img src="../Assets1/Image/3.svg" alt="" />
</div>
<button>Click</button>
<div class="randomImageContainer"></div>
const button = document.querySelector('button');
button.addEventListener('click', randomImage);
function randomImage() {
const image = document.querySelectorAll('.wrapper > img');
const randomImageContainer = document.querySelector('.randomImageContainer');
let randomNumber = Math.floor(Math.random() * image.length);
const img = document.createElement('img');
img.src = image[randomNumber].src;
randomImageContainer.appendChild(img);
}
You can do this with plain javascript like this:
document.querySelector("button").addEventListener("click", () => {
var imgElements = document.querySelectorAll(".wrapper img");
document.querySelector(".rndmImage").innerHTML = imgElements[Math.floor(Math.random() * imgElements.length)].outerHTML;
});
<div class="wrapper">
<div>
<img src="slike/leto1.jpg" alt="leto1">
<img src="slike/leto2.jpg" alt="leto2">
<img src="slike/leto3.jpg" alt="leto3">
<img src="slike/leto4.jpg" alt="leto4">
<img src="slike/leto5.jpg" alt="leto5">
<img src="slike/leto6.jpg" alt="leto6">
<img src="slike/leto7.jpg" alt="leto7">
<img src="slike/leto8.jpg" alt="leto8">
<img src="slike/leto9.jpg" alt="leto9">
</div>
<div>
<button type="button">choose</button>
</div>
<div class="rndmImage"></div>
</div>
If you're able to use randojs, you can even simplify the randomness and make it all cryptographically secure like this:
document.querySelector("button").addEventListener("click", () => document.querySelector(".rndmImage").innerHTML = rando(document.querySelectorAll(".wrapper img")).value.outerHTML);
<script src="https://randojs.com/2.0.0.js"></script>
<div class="wrapper">
<div>
<img src="slike/leto1.jpg" alt="leto1">
<img src="slike/leto2.jpg" alt="leto2">
<img src="slike/leto3.jpg" alt="leto3">
<img src="slike/leto4.jpg" alt="leto4">
<img src="slike/leto5.jpg" alt="leto5">
<img src="slike/leto6.jpg" alt="leto6">
<img src="slike/leto7.jpg" alt="leto7">
<img src="slike/leto8.jpg" alt="leto8">
<img src="slike/leto9.jpg" alt="leto9">
</div>
<div>
<button type="button">choose</button>
</div>
<div class="rndmImage"></div>
</div>
Try this:
this is my image in HTML file
<snap id="image" class="btn btn-warning" onclick="changeImage()">Image</snap>
<image id="imagechange" src="https://picsum.photos/200/300" ></image>
my javascript file
imgcount = 0;
function changeImage() {
document.getElementById("imagechange").src =
"https://picsum.photos/200/" + (300 + imgcount);
imgcount++;
}
everytime you click button you get a new image
I have a series of images with the class of .piece in a div called #pieces. Only the first image #piece0 is shown initially, and as you click on #piece0, #piece1 appears on top of #piece0. And then when you click on #piece1, #piece2 appears on top. My current code doesn't do that. How do I fix that?
<div id="pieces">
<img class="piece" id="piece0" style="display:block;"/>
<img class="piece" id="piece1" style="display:none;"/>
<img class="piece" id="piece2" style="display:none;"/>
<img class="piece" id="piece3" style="display:none;"/>
</div>
<script>
var pieceNum = $("#pieces").children().size();
var i = 0;
if (i < pieceNum) {
$("#piece" + i).click(function({
i++;
$("piece" + i).css("display", "block");
}));
}
</script>
If you want to get element children size(length) , use $("#pieces img").length . But for your problem that is not necessary .
You can catch image click by $("pieces img").on("click".. and get next element by .next() then the last element have no next , for that case you can check by next().length . 0 will return if next element have no exist
$("#pieces img").on("click",function() {
$(this).next().show();
$("#pieces").append($(this));
});
#pieces {
display: flex;
flex-direction: column;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pieces">
<img class="piece" id="piece0" style="display:block;" alt="one"/>
<img class="piece" id="piece1" style="display:none;" alt="two"/>
<img class="piece" id="piece2" style="display:none;" alt="three"/>
<img class="piece" id="piece3" style="display:none;" alt="four"/>
</div>
$(document).ready(function(){
var pieceNum = $("#pieces").children();
var i = 0;
if (i < pieceNum.length) {
$("#piece" + i).click(function(){
$("#piece" + i).css("display", "none");
i++;
$("#piece" + i).css("display", "block");
});
}
})
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pieces">
<img class="piece" id="piece0" style="display:block;" src="http://placekitten.com/g/200/300"/>
<img class="piece" id="piece1" style="display:none;" src="http://placekitten.com/g/200/400"/>
<img class="piece" id="piece2" style="display:none;" src="http://placekitten.com/g/200/300"/>
<img class="piece" id="piece3" style="display:none;" src="http://placekitten.com/g/200/100"/>
</div>
Try this:
var pieceNum = $("#pieces").children().size();
var i = 0;
if (i < pieceNum) {
$("#piece" + i).click(function({
$("piece" + i).css("display", "none");
i++;
$("piece" + i).css("display", "block");
}));
}
You don't need to write multiple click events, You can have single click event attached to all elements and do traversing using .next() to show next element :
$(".piece").click(function({
var $nextPiece = $(this).next();
if($nextPiece.length > 0)
$nextPiece.css("display", "block");
}));
You can use the next() to access next child and show() to display the img. Also, you will need to add position: absolute; to make images overlap each other.
$(document).ready(function() {
$('.piece').on('click', function() {
$(this).next().show();
});
});
img {
max-width: 100px;
margin-right: 1em;
position: absolute;
}
<script src="https://code.jquery.com/jquery-3.4.1.min.js" integrity="sha256-CSXorXvZcTkaix6Yvo6HppcZGetbYMGWSFlBw8HfCJo=" crossorigin="anonymous"></script>
<div id="pieces">
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_250,h_250,c_mfit/w_700/sample.jpg" />
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_300,h_200,c_crop/sample.jpg" style="display:none;" />
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_250,h_250,c_mfit/w_700/sample.jpg" style="display:none;" />
<img class="piece" src="https://res.cloudinary.com/demo/image/upload/w_300,h_200,c_crop/sample.jpg" style="display:none;" />
</div>
Try this
$(".piece").on('click', function(){
$(".piece").hide();
let id = (parseInt(this.id.slice(-1)) +1)%4;
$("#piece" +id).show();
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="pieces">
<img class="piece" id="piece0" style="display:block;" alt="piece 0"/>
<img class="piece" id="piece1" style="display:none;" alt="piece 1"/>
<img class="piece" id="piece2" style="display:none;" alt="piece 2"/>
<img class="piece" id="piece3" style="display:none;" alt="piece 3"/>
</div>
I'm trying to create an image slideshow with setInterval which starts playing when the mouse is over .project-img and pauses when the mouse leaves .project-img. The problem i'm having is calling clear interval on to pause the slideshow when the mouse leaves, I'm currently receiving the error:
Uncaught ReferenceError: cycle is not defined
Where am I going wrong?
var Image = {
init: function() {
Image.setupImages();
Image.bindEvents();
},
bindEvents: function() {
$('.project-img').hover(function() {
var hovered = $(this);
var thumbnailIndex = 0
var thumbnailArray = hovered.children()
console.log(thumbnailArray);
var cycle = setInterval(function(){
thumbnailIndex++
if (thumbnailIndex === thumbnailArray.length) {
thumbnailIndex = 0;
thumbnailArray.removeClass('active');
thumbnailArray.eq(0).addClass('active');
} else {
var $visible = thumbnailArray.eq(thumbnailIndex);
thumbnailArray.removeClass('active');
$visible.addClass('active');
}
}, 700);
}, function() {
clearInterval(cycle);
});
},
setupImages: function() {
var projectImage = $('.project-img');
projectImage.each(function(project) {
$(this).find('.project-thumbnail:eq(0)').addClass('active');
});
}
}
$(document).ready(function() {
Image.init();
});
.project-thumbnail {
visibility: hidden;
display: none;
}
.active {
visibility: visible;
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="project-img">
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/ffffff/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/ffffff/000000">
</div>
</div>
<div class="project-img">
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/ffffff/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/000000">
</div>
</div>
This is a scope issue, you have defined cycle within a function, so it can't leave. Put var cycle above var Image and your problems will be solved! Alternatively if you wanted to keep it scoped inside the Image var, you can replace cycle with Image.cycle and that will also work.
The variable cycle is in a different scope. Instead of using hover use each, declaring the cycle variable in an outer scope of hover like so:
var Image = {
init: function() {
Image.setupImages();
Image.bindEvents();
},
bindEvents: function() {
$('.project-img').each(function() {
var hovered = $(this);
var cycle;
hovered.hover(function() {
var thumbnailIndex = 0;
var thumbnailArray = hovered.children();
cycle = setInterval(function() {
thumbnailIndex++
if (thumbnailIndex === thumbnailArray.length) {
thumbnailIndex = 0;
thumbnailArray.removeClass('active');
thumbnailArray.eq(0).addClass('active');
} else {
var $visible = thumbnailArray.eq(thumbnailIndex);
thumbnailArray.removeClass('active');
$visible.addClass('active');
}
}, 700);
}, function() {
clearInterval(cycle);
});
});
},
setupImages: function() {
var projectImage = $('.project-img');
projectImage.each(function(project) {
$(this).find('.project-thumbnail:eq(0)').addClass('active');
});
}
}
$(document).ready(function() {
Image.init();
});
.project-thumbnail {
visibility: hidden;
display: none;
}
.active {
visibility: visible;
display: block;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="project-img">
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/ffffff/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/ffffff/000000">
</div>
</div>
<div class="project-img">
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/ffffff/000000">
</div>
<div class="project-thumbnail">
<img src="http://via.placeholder.com/250/000000">
</div>
</div>
I'm trying to implement a function like Google Image Search, which is that when you click a picture, a subpage appears in the screen below the picture. And it takes a whole line. The screenshot is showing below.
http://www.wy19900814fun.com/thumbnails/test.png
Here's my code. Is there anyone helping me to implement or at least give me some advise? I'm trying to do a function like when you click a picture, the second div class shows below the picture you click. It needs to take a whole line.
<html>
<head>
<style>
.container {
text-align: center;
}
.container img {
display:inline-block;
}
.subpage {
display:none;
}
</style>
<script type="text/javascript">
</script>
</head>
<body>
<div class="container">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20964301401_5d9fdf5c0d_o_large_958fe482-f2e7-4120-b4fe-016fcf612bf5_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20770321799_5c81882577_o_large_c4c19c91-0532-422f-99d0-297b2731c4e3_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17108089939_8d4cefd10a_o_large_3dc1d49b-cb59-432a-a8d7-b118cfd61314_large.jpeg?v=1440873578">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17950190230_114070818c_o_large_60ce5c71-7575-49ab-be75-ed2cfed6768d_large.jpeg?v=1440873577">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15175737319_c0db73446f_o_zps867eecb9_large_858814b0-6a80-4a34-b55d-97acc179cc91_large.jpeg?v=1440873576">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085342999_b8878e538e_o_zps54a2d381_large_f731cd55-f8d0-4e9a-8ba5-c254b4b8241d_large.jpeg?v=1440873575">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085523427_bacc983407_o_zps2c262937_large.jpeg?v=1440873574">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15268975561_ed3f9f5c0b_o_zpsd4857119_large.jpeg?v=1440873573">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15339485796_bed118ac3c_o_zpsf0927ac3_large.jpeg?v=1440873572">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/IMG_9092_zpsc38bd27c_large.jpeg?v=1440873571">
</div>
<div class="subpage">
<p>This is </br>just</br> a test.</br> Please show</br> subpage</p>
</div>
</body>
</html>
$('img').click(function() {
var $img = $(this),
offset = $img.offset(),
subPage = $('#subPage').hide().insertAfter('.container'),
nextImage = $img.next(),
finalImage = $img;
if (!$img.is(':last-child')) {
while (offset.top == nextImage.offset().top) {
nextImage = nextImage.next();
}
finalImage = nextImage.prev();
}
subPage.html('').append($img.clone()).insertAfter(finalImage).slideDown();
});
.container {
text-align: center;
}
.container img {
display:inline-block;
width:32%;
vertical-align:top;
}
#subPage {
background:#222;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20964301401_5d9fdf5c0d_o_large_958fe482-f2e7-4120-b4fe-016fcf612bf5_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/20770321799_5c81882577_o_large_c4c19c91-0532-422f-99d0-297b2731c4e3_large.jpeg?v=1440873580">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17108089939_8d4cefd10a_o_large_3dc1d49b-cb59-432a-a8d7-b118cfd61314_large.jpeg?v=1440873578">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/17950190230_114070818c_o_large_60ce5c71-7575-49ab-be75-ed2cfed6768d_large.jpeg?v=1440873577">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15175737319_c0db73446f_o_zps867eecb9_large_858814b0-6a80-4a34-b55d-97acc179cc91_large.jpeg?v=1440873576">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085342999_b8878e538e_o_zps54a2d381_large_f731cd55-f8d0-4e9a-8ba5-c254b4b8241d_large.jpeg?v=1440873575">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15085523427_bacc983407_o_zps2c262937_large.jpeg?v=1440873574">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15268975561_ed3f9f5c0b_o_zpsd4857119_large.jpeg?v=1440873573">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/15339485796_bed118ac3c_o_zpsf0927ac3_large.jpeg?v=1440873572">
<img src="http://cdn.shopify.com/s/files/1/0251/0700/products/IMG_9092_zpsc38bd27c_large.jpeg?v=1440873571">
</div>
<div id="subPage"></div>
You could do like that :
JS :
$(document).ready(function () {
$('.container img').click(function () {
var src = $(this).attr('src');
var subpage = $('.subpage');
subpage.hide().empty().fadeIn(250);
$('<img>', {'src' : src}).hide(250).appendTo(subpage).fadeIn(250);
});
});
Jsfiddle
I've a next button and back button. I want to show one question div at a time. Then I want next button to change the div to the next div question and the back button should change the div back to the previous div. Only one div should be seen at a time.
<input type="image" src="forward.gif" alt="Next">
<input type="image" src="back.gif" alt="Back">
<div class="question_one">
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question_two">
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question_three">
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question_four">
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
Here's a simple JavaScript which solves this kind of problem:
<script>
var next = document.getElementById('next'),
back = document.getElementById('back'),
questions = document.getElementsByTagName('div'),
current = 0;
next.onclick = function showNext() {
if (questions[current+1]) {
questions[current].style.display = 'none';
questions[current+1].style.display = 'block';
current++;
} else {
return false;
}
}
back.onclick = function showPrev() {
if (questions[current-1]) {
questions[current].style.display = 'none';
questions[current-1].style.display = 'block';
current--;
} else {
return false;
}
}
</script>
And at first you should hide the questions with CSS (except the first one):
<style>
div:not(:first-of-type) {
display: none;
}
</style>
EDIT: here is your HTML...
<input type="image" src="forward.gif" alt="Next" id="next">
<input type="image" src="back.gif" alt="Back" id="back">
<div class="question_one">
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question_two">
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question_three">
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question_four">
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
First, regroup your class with unique name and add id to your back and forward button (To apply clicks events). Example :
<input type="image" src="forward.gif" alt="Next" id="forwardQ">
<input type="image" src="back.gif" alt="Back" id="nextQ">
<div class="question">
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question">
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question">
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question">
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
With JQuery:
var actual = 0; // select by default the first question
$(document).ready(function() {
var number_of_question = $('.question').length; // get number of questions
$('.question:gt(' + actual + ')').hide(); // Hide unselect question
$('#nextQ').click(function() {
if(actual < number_of_question - 1 ) {
changeQuestion(actual + 1); // display select question
}
});
$('#forwardQ').click(function() {
if(actual) {
changeQuestion(actual - 1); // display select question
}
});
});
function changeQuestion( newQuestion ) {
$('.question:eq(' + actual +')').hide(); // hide current question
$('.question:eq(' + newQuestion +')').show(); // show new question
actual = newQuestion; // memorize actual selection
}
You can achieve this by combining HTML, CSS and jQuery.
In the below example I am displaying only the div elements with class active and hiding the other divs. And adding the class active to appropriate divs when ever the user clicks on the Next or Previous button.
HTML Code
<input type="button" value="Next" id="next_qs">
<input type="button" value="Back" id="prev_qs">
<div class="question_one">
QS1
</div>
<div class="question_two">
QS2
</div>
<div class="question_three">
QS3
</div>
<div class="question_four">
QS4
</div>
CSS Code
div {
width: 300px; height: 200px; border: 1px solid #333; clear: both; display: none;
}
div.active {
display: block;
}
jQuery Code
$("div:first").addClass('active')
$("#next_qs").click(function() {
$("div.active").removeClass('active').next().addClass('active');
});
$("#prev_qs").click(function() {
$("div.active").removeClass('active').prev().addClass('active');
});
http://jsfiddle.net/27gwy14f/
HTML
<div id="container">
<input type="image" src="back.gif" alt="Back">
<input type="image" src="forward.gif" alt="Next">
<div class="question_one question active">
1
<img src ="images/green_question1.png" width="100%" height="100%"></img>
</div>
<div class="question_two question">
2
<img src ="images/green_question2.png" width="100%" height="100%"></img>
</div>
<div class="question_three question ">
3
<img src ="images/green_question3.png" width="100%" height="100%"></img>
</div>
<div class="question_four question">
4
<img src ="images/green_question4.png" width="100%" height="100%"></img>
</div>
</div>
Jquery
<script>
var $container = $("#container") // caches the jquery object
$container.find('input[alt="Next"]').on("click",function(){
var active = $container.find(".active")
if(active.next(".question").length === 0){
return false
}else{
active.removeClass("active")
active.next(".question").addClass("active")
}
})
$container.find('input[alt="Back"]').on("click",function(){
var active = $container.find(".active")
if(active.prev(".question").length === 0){
return false
}else{
active.removeClass("active")
active.prev(".question").addClass("active")
}
})
</script>
CSS
<style>
#container .question{
display:none
}
#container .active{
display:inline-block;
}
</style>
JS FIDDLE
http://jsfiddle.net/vrnxL9n8/
edit: added js fiddle link