for loop to set javascript variable = to a php variable - javascript

I am working on a project that requires create hundreds of variables in javascript with PHP values. I can write each one line by line like so:
var M1 = <?php echo json_encode($$mn[0]); ?>;
var M2 = <?php echo json_encode($$mn[1]); ?>;
var M3 = <?php echo json_encode($$mn[2]); ?>;
As I said there are hundreds of these though and if it is possible to do in a loop I would be very interested in learning. I have searched all over and can't find a direct answer. It may very well be that this is not possible. I am new to coding and still learning what certain code can and cannot do.
Any insight or direction on this topic would be greatly appreciated!
If this is not an option is it possible to use an array index for the javascript variable name? I have created an array for the JS and PHP. The PHP works fine above but if I try to use an array index for the JS like below, it breaks:
var mcirc[0] = <?php echo json_encode($$mn[0]); ?>;
I have output the array and the values are coming up correctly but when I run this I get the message:
[object HTMLDivElement]
instead of the actually value that should show up.
UPDATE
$mn array:
for ($m1 = 1; $m1 < 6; $m1++) {
$mn[] = 'M'.$m1;
}
UPDATE
Select SQL creating array:
$sqlMC = "SELECT * FROM tblmaincircles";
$result = $conn->query($sqlMC);
while($row = $result->fetch_assoc()) {
$$row["mcID"]= $row["mcName"];
}
The array for mcID looks like this:
M1 = "text1"
M2 = "text2"
M3 = "text3"
M4 = "text4"
M5 = "text5"
UPDATE
end result desired:
var M1 = "text1";
var M2 = "text2";
var M3 = "text3";
var M4 = "text4";
var M5 = "text5";
Where "text1, ...2, ...3, ...4, ...5" are coming from the MySQL database.
UPDATE
Here is the final code that got this working:
$sqlMC = "SELECT mcID, mcName FROM tblmaincircles";
$result = $conn->query($sqlMC);
while($row = $result->fetch_assoc()) {
$mcID[] = $row["mcID"];
$mcName[] = $row["mcName"];
}
<?php for ($m1 = 0; $m1 <5; $m1++) { ?>
var <?php echo $mcID[$m1]; ?> = <?php echo json_encode($mcName[$m1]); ?>;
<?php } ?>

Simply put JSON into variable
var json = <?php echo json_encode($$mn); ?>;
And then process the JSON way you want:
eg.
var json=[{key:someValue},
{key:someValue2},
{key:someValue3}
];
json.forEach(function(a){
console.log(a.key);
})

First in your query part, declare a variable to hold the result that you want. I'm assuming the M1 is mcID in your table and text1 is the mcName. For example:
$sqlMC = "SELECT * FROM tblmaincircles";
$result = $conn->query($sqlMC);
$mac = [];//or $mac = array(); Depends on your PHP version.
while($row = $result->fetch_assoc()) {
$mac[$row["mcID"]] = $row["mcName"];
}
And then, iterate through the $mac array with foreach loop. I'm assuming you are using PHP codes within HTML. The $key will be the mcID and the $value will be the mcName.
//php tag for the foreach opening
<?php foreach ($mac as $key => $value) { ?>
var <?php echo $key; ?> = <?php echo "'$value';"; ?>
//php tag for the foreach closing
<?php } ?>
OR, if you want to use javascript associative array.
var macJs = {};
<?php foreach ($mac as $key => $value) { ?>
macJs.<?php echo $key; ?> = <?php echo "'$value';"; ?>
<?php } ?>
And you can access the element like this in javascript macJs.M1.

You should use JSON to 'export' your objects/array through different languages, in that case:
var json = '<?= json_encode($your_array); ?>';
After this you can parse this Json, what should return your array:
var your_array = JSON.parse(json);

Related

How to access PHP array element using JavaScript variable as key?

So I am trying to make a simple academic system.
I made dynamic boxes which show course information.
Core code looks like this
function addcourses(){ //(numcourses)
var num_courses= <?php echo $_GET['num']?>; //=numcourses
var newdiv;
var divIdName;
var i=0;
for(i=1;i<=num_courses;i++){
var divtoadd = document.getElementById('courselist');
newarticle = document.createElement('article');
divIdName = 'course'+i;
newarticle.setAttribute('id',divIdName);
newarticle.innerHTML ='<div class="box"><h2><?php echo $course_num_arr[i]?></h2><div class="content"><p>Credit Hours: <?php echo $credit_arr[0]?> </p><p>Professor: <?php echo $prof_arr[0]?></p><p>Average GPA: <?php echo $avg_arr[0]?></p><p>GPA: <?php echo $gpa_arr[0]?></p></div></div>';
call_course();
divtoadd.appendChild(newarticle);
}
}
The problem is with <?php echo $course_num_arr[i]?> since i is the variable from javascript, I don't know how to deal with this.
I want to echo $course_num_arr[1] when i = 1 and $course_num_arr[2] when i = 2 and so on.
If you don't want to use ajax call and wants to place the code in the PHP file, your can use json_encode() function. Please refer below code.
<?php
$cources = array( "0" => array ("name" => "maths","credits" => 30),"1"
=> array ("name" => "physics","credits" => 30));
?>
<script>
data=<?php echo json_encode($cources); ?>;
for(i=0;i<data.length;i++){
alert(data[i].name)
var h = document.createElement("H1");
var t = document.createTextNode(data[i].name);
h.appendChild(t);
document.body.appendChild(h);
}
</script>

How to create var javascript via php?

How to create var javascript via php ?
<?PHP
include("connect.php");
$get_data = mysqli_query($db_mysqli,"SELECT * FROM bad_word");
while($resilt_row = mysqli_fetch_array($get_data))
{
$bad_words = $bad_words."".$resilt_row [word].",";
}
//echo $bad_words;
?>
<script>
var bad_words = ["<?PHP echo $bad_words; ?>"];
alert(bad_words);
</script>
I want to get var javascript like this var bad_words = ["fuck", "ass"];
When alert it's get only blank result.
How can i do that ?
<?php
include("connect.php");
$query = mysqli_query($db_mysqli,"SELECT * FROM bad_word");
$badWords = [];
while($row = mysqli_fetch_array($query))
{
$badWords[] = $row['word'];
}
js
<script>
var bad_words = <?= json_encode($badWords); ?>;
alert(bad_words[0]);
console.log(bad_words);
</script>
I don't like gluing the strings if it's an array then pass it as an array with json_encode() function. Also in views it's better to use short syntax with <?= ?> tag
The string you're making is not the one you want.
You're not adding quotes.
Do this instead, using an array is better:
$get_data = mysqli_query($db_mysqli,"SELECT * FROM bad_word");
$bad_words = array();
while($resilt_row = mysqli_fetch_array($get_data))
{
$bad_words[] = "'" . $resilt_row[word]. "'";
}
And then, down in your js:
var bad_words = ["<?php echo implode(",", $bad_words) ?>"];
or (for short)
var bad_words = ["<?= implode(",", $bad_words) ?>"];
If you want alert them as a string you can do it like this:
<script>
var bad_words = ["<?php echo implode('","',$bad_words); ?>"];
alert(bad_words);
</script>
Otherwise, you can print them as an array:
<script>
var bad_words = <?php echo json_encode($bad_words) ?>;
console.log(bad_words);
</script>
<?PHP
include("connect.php");
$get_data = mysqli_query($db_mysqli,"SELECT * FROM bad_word");
while($resilt_row = mysqli_fetch_array($get_data))
{
$bad_words[] = $resilt_row['word'];
}
//echo $bad_words;
?>
<script>
var bad_words = ["<?php print implode('","',$bad_words); ?>"];
alert(bad_words);
</script>

Change the value of external Javascript with PHP in foreach loop

How can I change the value of a js variable in a PHP foreach loop?
The js needs to be external.
This is a piece of the index.php here I want to get the output $prozent in the javascript, I don't know how to get a PHP variable to execute a js every time in a loop, the js is a chart. I get the chart in the loop in the echo'<div class="chart-wrapper"> with a this chart js.
<?php
$sql = //SQL query
$res = mysql_query($sql);
$i = 0;
$survey = array();
while ($row = mysql_fetch_assoc($res)) {
$survey[$i]['label'] = $row['Label'];
$i++;
}
foreach ($survey as $survey) {
echo '<div class="col-md-4">';
echo '<div class="front face">';
echo "<h3> ".$survey['label']."<br>";
$sql = //SQL Query
$res = mysql_query($sql) ;
$sql = //SQL Query
$resSum = mysql_query($sql) ;
while ($row = mysql_fetch_array($resSum)) {
$survey['ausgabe'] = $row['sum(a.answer)'];
}
$anzahlreihen = mysql_num_rows($res);
if ($anzahlreihen > 0) {
$prozent = $anzahlreihen * $survey['ausgabe'];
//bunch of ifelse statements
//This is the variable i want to get in the js
echo (round( $prozent, 2));
echo '</font>';
}
}
echo '</div>';
echo '<div class="back face center">';
echo'<div class="chart-wrapper">
}
There are two ways PHP and Javascript can interact.
Use AJAX to request a PHP script which returns JSON or have PHP output the following example HTML;
<script type="text/javascript">
var variable = value;
</script>

get MySql Data to PHP array and convert to Javascript array

I have mysql table like this
table = tbl_tst`
clm_num clm_amnt
1 - 25000
2 - 31700
5 - 52900
8 - 45000
I want to get that table data to php array like this
$temp = array([1,25000],[2,31700],[5,52900],[8,45000]);
After i'll convert php array into the javascript using this code
var jsArray = <? echo json_encode($temp); ?>;
Problem is when i run my code it's retrieve nothing. sometimes it's retrieving "Object" :(
This is my full php code
<?php
$con=mysql_connect("localhost","user","pass") or die("Failed to connect with database!!!!");
mysql_select_db("db", $con);
$query = "SELECT * FROM tblnum";
$result = mysql_query($query) or die(mysql_error());
$valueMap = array();
while($row = mysql_fetch_array($result)){
$valueMap[$row['clm_num'] & $row['clm_amnt']];
}
?>
<script>
var jsArray = <? echo json_encode($valueMap); ?>;
for(var i=0; i < jsArray .length; i++){
document.write("<li>"+jsArray [i]+"</li>");
}
</script>
Please help me to find this issue.
Thanks in advance!
You should enable PHP displaying errors, which would tell you there is an error while constructing your array.
<?php
## Turn on error reporting
error_reporting(-1);
ini_set('display_errors', 'On');
....
$valueMap = array();
while($row = mysql_fetch_assoc($result)){
$valueMap[$row['clm_num']] = $row['clm_amnt'];
}
?>
edit:
You requested a different sort of array I see:
while($row = mysql_fetch_assoc($result)){
$valueMap[] = array($row['clm_num'], $row['clm_amnt']);
}
MySQL is no longer maintained, please start using MySQLI or PDO http://rudiv.se/Development/Resource/when-to-use-mysql-vs-mysqli-vs-pdo-in-php
edit:
<?php
$temp = array(
array(1,2500),
array(2,31700)
);
?>
<ul id="list"></ul>
<script>
var json_array = <?php echo json_encode($temp, true);?>;
console.log(json_array);
var ul = document.getElementById("list");
for(i in json_array){
var li = document.createElement("li");
li.appendChild(document.createTextNode(json_array[i][0]+','+json_array[i][1]));
ul.appendChild(li);
}
</script>
First you have to check your php array is come or not. if it will be coming than use this code:
<script type='text/javascript'>
var js_data = <?php echo json_encode($valueMap); ?>;
var jsArray = js_data.toString().split(',');
for(var i=0; i < jsArray.length; i++){
alert(jsArray[i]);
}
</script>
This one for one array or one dimensional array like array['amount'].
i used this code for
$valueMap = array('25000','31700','52900','45000'); // php array
check this.
change this $valueMap[$row['clm_num'] & $row['clm_amnt']]; To $valueMap[] =array($row['clm_num'], $row['clm_amnt']);
$valueMap = array();
while($row = mysql_fetch_assoc($result)){
$valueMap[] =array($row['clm_num'], $row['clm_amnt']);
}
?>
<script>
var jsArray = <?php echo json_encode($temp); ?>;//change <? to <?php it's give error when sort tag is not enable
for(var i=0; i < jsArray .length; i++){
document.write("<li>"+jsArray [i]+"</li>");
}
</script>
//output
1,25000
2,31700
5,52900
8,45000
Try this:
while($row = mysql_fetch_array($result)){
$valueMap[$row['clm_num']] = $row['clm_amnt'];
}
And then in js:
for(var i in jsArray){
if (jsArray.hasOwnProperty(i)) {
document.write("<li>"+jsArray[i]+"</li>");
}
}

Moving data from SQL database to an array in JavaScript via PHP

Ive been trying this for hours now but it wont quite get there.
I have a database which amongst other things contains geocodes, lat and lon. I have accessed these using the following PHP
<?php
mysql_connect("localhost", "tompublic", "public") or die(mysql_error());
mysql_select_db("first_section") or die(mysql_error());
$data = mysql_query("SELECT geo_lat, geo_lon FROM first_page_data")
or die(mysql_error());
while ($row = mysql_fetch_assoc($data)){
$lat[] = $row['geo_lat'];
$lon[] = $row['geo_lon'];
}
?>
These values in $lat and $lon then need to be put into an array in a javascript function like so:
var latit = [];
var longi = [];
latit = '<?php echo $lat[]; ?>';
longi = '<?php echo $lon[]; ?>';
But it wont work! Any ideas?
Try:
var latit = <?php echo json_encode($lat); ?>;
var longi = <?php echo json_encode($lon); ?>;
Edit: Also, the mysql_ functions are deprecated.
You could try this:
var latit = [<?php echo implode(",",$lat) ?>];
var longi = [<?php echo implode(",",$lon) ?>];
First thing is first try to switch to MySQLi due to the fact that Mysql is depreciated.
But try
var latit = <?php echo json_encode($lat); ?>;
var longi = <?php echo json_encode($lon); ?>;
You can either do as #Robbert stated
OR
Using php json_encode convert it to JSON string and you need to JSON.parse() it to convert it to javascript object
var latit = JSON.parse("<?php echo json_encode($lat); ?>");
var longi = JSON.parse("<?php echo json_encode($lon); ?>");
JavaScript arrays are created using a comma separated list surrounded by brackets
var latit = [];
To use your PHP values
var latit = [<?PHP echo implode(",",$lat); ?>];
This assumes your values are numbers. If not, you'll need to include quotes.
var latit = ['<?PHP echo implode("','",$lat); ?>'];
Finally, json_encode is a good option as many of the other answers indicate.
Try this:
<?php
mysql_connect("localhost", "tompublic", "public") or die(mysql_error());
mysql_select_db("first_section") or die(mysql_error());
$data = mysql_query("SELECT geo_lat, geo_lon FROM first_page_data")
or die(mysql_error());
while ($row = mysql_fetch_assoc($data)){
$lat[] = $row['geo_lat'];
$lon[] = $row['geo_lon'];
}
echo '
<script type="text/javascript">
var latit = '.json_encode($lat).';
var longi = '.json_encode($lon).';
</script>
';
?>

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