We Keep Coding

Get string from other string with match()

I try to get the 00-8.
Why this code do not returns me the 00-8 ?
<script>
var pageDetailsSecond = "a='00-8'b='13-'a+='00-2'b+='3333'c='4'";
var phone1 = pageDetailsSecond.match("a='(.*)'");
var phone1 = phone1[0];
var card_Phone = phone1;
alert(card_Phone);
</script>
Actually I get a='00-8'.

Because what you try to match includes a=....
But when you find it, you can strip it from the match found.
Checked with jsfiddle: http://jsfiddle.net/pbo5x9dx/
var pageDetailsSecond = "a='00-8'b='13-'a+='00-2'b+='3333'c='4'";
alert(pageDetailsSecond)
var phones = pageDetailsSecond.match("a='(.*?)'");
var phone1 = phones[1];
alert(phone1)
** edit: ** fix for non-greedy match, checked with http://jsfiddle.net/pbo5x9dx/1/

Because the array returned by match() will contain the entire match in the first array slot, and the capture groups in subsequent elements.
The array contents will be:
[
[0] = "a='00-8'",
[1] = '00-8'
]
What you want is phone1[1] instead of phone1[0], which contains just the portion of the match specified by your capture group (.*).
Based on the updated question, the regex pattern should be changed to:
"a='(.*?)'"
By default, regex patterns try to match as much as possible (known as "greedy"). The pattern is saying "match any number of any characters between ' characters. This now includes 00-8'b='13-'a+='00-2'b+='3333'c='4. By adding the ?, this changes the behaviour to "lazy". In other words, match as little as possible, and your regex is back to matching only 00-8 as before.

How to get everything in between these two strings?

How can I get everything between these two strings?
ATemp.runFunct( <I WANT EVERYTHING IN BETWEEN THESE TWO PARENS> ), // comment
I want everything in between the parens above, with the outside strings as a constant.
I have tried multiple regex expressions, but they have not worked, such as:
ATemp\.runFunct\(*.?\), \/\/ comment
Any ideas? Thanks! (PS, I'm using javascript)

*.? should be .*?. Otherwise you are matching zero or more (. You probably also want to use a capture group so that you can actually reference that part later on: (.*?)
Example:
var match = /ATemp\.runFunct\((.*?)\), \/\/ comment/.exec('ATemp.runFunct( <I WANT EVERYTHING IN BETWEEN THESE TWO PARENS> ), // comment');
alert(match[1]);
.exec returns an array, where the first element is the complete match and the second element is the value of the first capture group (and so on).

Here is the FIDDLE: http://jsfiddle.net/mikea80/kSuk4/
var str = "(Hello world!)";
var startIndex = str.indexOf("(");
var endIndex = str.indexOf(")");
var res = str.substring(startIndex + 1, endIndex);
alert(res);

String manipulation - getting value after the last position of a char

How I can get the value after last char(. ; + _ etc.):
e.g.
string.name+org.com
I want to get "com".
Is there any function in jQuery?

Use lastIndexOf and substr to find the character and get the part of the string after it:
var extension = name.substr(name.lastIndexOf(".") + 1);
Demo: http://jsfiddle.net/Guffa/K3BWn/

A simple and readable approch to get the substring after the last occurrence of a character from a defined set is to split the string with a regular expression containing a character class and then use pop() to get the last element of the resulting array:
The pop() method removes the last element from an array and returns that element.
See a JS demo below:
var s = 'string.name+org.com';
var result = s.split(/[.;+_]/).pop();
console.log(result);
to split at all non-overlapping occurrences of the regex by default.
NOTE: If you need to match ^, ], \ or -, you may escape them and use anywhere inside the character class (e.g. /[\^\-\]\\]/). It is possible to avoid escaping ^ (if you do not put it right after the opening [), - (if it is right after the opening [, right before the closing ], after a valid range, or between a shorthand character class and another symbol): /[-^\]\\]/.
Also, if you need to split with a single char, no regex is necessary:
// Get the substring after the last dot
var result = 'string.name+org.com'.split('.').pop();
console.log(result);

Not jQuery, just JavaScript: lastIndexOf and substring would do it (not since the update indicating multiple characters). As would a regular expression with a capture group containing a character class followed by an end-of-string anchor, e.g. /([^.;+_]+)$/ used with RegExp#exec or String#match.
E.g. (live copy | source):
var match = /([^.;+_]+)$/.exec(theStringToTest),
result = match && match[1];

var s = "string.name+org.com",
lw = s.replace(/^.+[\W]/, '');
console.log(lw) /* com */
this will also work for
string.name+org/com
string.name+org.info

You can use RegExp Object.
Try this code:
"http://stackoverflow.com".replace(/.*\./,"");

I'll throw in a crazy (i.e. no RegExp) one:
var s = 'string.name+org.com';
var a = s.split('.'); //puts all sub-Strings delimited by . into an Array
var result = a[a.length-1]; //gets the last element of that Array
alert(result);​
EDIT: Since the update of the question is demanding mutiple delimiters to work this is probably not the way to go. Too crazy.....

use javascript function like
url.substr(url.length - 3);

maybe this is too late to consider, this codes works fine for me using jquery
var afterDot = value.substr(value.lastIndexOf('_') + 1);
You could just replate '_' to '.'
var myString = 'asd/f/df/xc/asd/test.jpg'
var parts = myString.split('/');
var answer = parts[parts.length - 1];
console.log(answer);

Javascript Regexp - Match Characters after a certain phrase

I was wondering how to use a regexp to match a phrase that comes after a certain match. Like:
var phrase = "yesthisismyphrase=thisiswhatIwantmatched";
var match = /phrase=.*/;
That will match from the phrase= to the end of the string, but is it possible to get everything after the phrase= without having to modify a string?

You use capture groups (denoted by parenthesis).
When you execute the regex via match or exec function, the return an array consisting of the substrings captured by capture groups. You can then access what got captured via that array. E.g.:
var phrase = "yesthisismyphrase=thisiswhatIwantmatched";
var myRegexp = /phrase=(.*)/;
var match = myRegexp.exec(phrase);
alert(match[1]);
or
var arr = phrase.match(/phrase=(.*)/);
if (arr != null) { // Did it match?
alert(arr[1]);
}

phrase.match(/phrase=(.*)/)[1]
returns
"thisiswhatIwantmatched"
The brackets specify a so-called capture group. Contents of capture groups get put into the resulting array, starting from 1 (0 is the whole match).

It is not so hard, Just assume your context is :
const context = "https://example.com/pa/GIx89GdmkABJEAAA+AAAA";
And we wanna have the pattern after pa/, so use this code:
const pattern = context.match(/pa\/(.*)/)[1];
The first item include pa/, but for the grouping second item is without pa/, you can use each what you want.

Let try this, I hope it work
var p = /\b([\w|\W]+)\1+(\=)([\w|\W]+)\1+\b/;
console.log(p.test('case1 or AA=AA ilkjoi'));
console.log(p.test('case2 or AA=AB'));
console.log(p.test('case3 or 12=14'));

If you want to get value after the regex excluding the test phrase, use this:
/(?:phrase=)(.*)/
the result will be
0: "phrase=thisiswhatIwantmatched" //full match
1: "thisiswhatIwantmatched" //matching group

regular expression (javascript) How to match anything beween two tags any number of times

I'm trying to find all occurrences of items in HTML page that are in between <nobr> and </nobr> tags.
EDIT:(nobr is an example. I need to find content between random strings, not always tags)
I tried this
var match = /<nobr>(.*?)<\/nobr>/img.exec(document.documentElement.innerHTML);
alert (match);
But it gives only one occurrence. + it appears twice, once with the <nobr></nobr> tags and once without them. I need only the version without the tags.

you need to do it in a loop
var match, re = /<nobr>(.*?)<\/nobr>/img;
while((match = re.exec(document.documentElement.innerHTML)) !== null){
alert(match[1]);
}

use the DOM
var nobrs = document.getElementsByTagName("nobr")
and you can then loop through all nobrs and extract the innerHTML or apply any other action on them.

(Since I can't comment on Rafael's correct answer...)
exec is doing what it is supposed to do - finding the first match, returning the result in the match object, and setting you up for the next exec call. The match object contains (at index 0) the whole of the string matched by the whole of the regex. In subsequent slots are the bits of the string matched by the parenthesized subgroups. So match[1] contains the bit of the string matched by "(.*?)" in your example.

you can use
while (match = /<nobr>(.*?)<\/nobr>/img.exec("foo <nobr> hello </nobr> bar <nobr> world </nobr> foobar"))
alert (match[1]);

If the strings you're using aren't xml elements, and you're sticking with regexes the return value you're getting can be explained by the bracketing. .exec returns the whole matching string followed by the contents of the bracketed expressions.
If your doc contains:
This is out.
Bzz. This is in. unBzz.
then
/Bzz.(.*?)unBzz./img.exec(document.documentElement.innerHTML)
Will give you 'Bzz. This is in. unBzz.' in element 0 of the returned array and 'This is in.' in element 1. Trying to display the whole array gives both as a comma separated list because that's what JavaScript does to try to display it.
So
alert($match[1]);
is what you're after.

it takes to steps but you could do it like this
match = document.documentElement.innerHTML.match(/<nobr>(.*?)<\/nobr>/img)
alert(match)//includes '<nobr>'
match_length = match.length;
for (var i = 0; i < match_length; i++)
{
var match2 = match[i].match(/<nobr>(.*?)<\/nobr>/im);//same regex without the g option
alert(match2[1]);
}