I use Number.toString method to convert numbers to string.
Number(100).toString(16);
Number(1000).toString(36);
How can I convert them back to the original numbers?
By using parseInt.
parseInt(Number(100).toString(16), 16);
parseInt(Number(1000).toString(36), 36);
Number("10") === 10
You can pass any string into Number and it will turn it into a number object. I prefer this method since if it contains any non-number characters, it will resolve to NaN which is what you want most of the time.
If you're parsing a string which begins with a number but may contain alpha characters afterwards, parseInt and parseFloat both will parse the leading numerics out - but you can forget about any numbers which may be mixed into the string elsewhere.
Related
Let's say I have a hexadecimal, for example "0xdc", how do I convert this hexadecimal string to a hexadecimal Number type in JS?
Literally just losing the quotes. The Number() constructor and parseInt() just converted it to an integer between 0 and 255, I just want 0xdc.
EDIT:
To make my point more clear:
I want to go from "0xdc" (of type String), to 0xdc (of type Number)
You can use the Number function, which parses a string into a number according to a certain format.
console.log(Number("0xdc"));
JavaScript uses some notation to recognize numbers format like -
0x = Hexadecimal
0b = Binary
0o = Octal
if you want convert string to hex representation, you can covert to number with 16 as radix.
parseInt("0xdc", 16) // gives you 0xdc
TL;DR
#dhaker 's answer of
parseInt(Number("0xdc"), 10) is correct.
In-Memory Number Representation
Both numbers 0xdc and 220 are represented in the same way in javascript
so
0xdc == 220 will return true.
the prefix 0x is used to tell javascript that the number is hex
So wherever you are passing 220 you can safely pass 0xdc or vice-versa
String Format
Numbers are always shown in base 10 unless specified not to.
'0x' + Number(220).toString(16) gives '0xdc' if you want to print it as string.
In a nutshell
parseInt('0x' + Number(220).toString(16),16) => 220
I am trying to understand how parseInt() will work in javascript, my scenarios are
var x = parseInt("123");
console.log(x); // outputs 123
var x = parseInt("1abc");
console.log(x); // outputs 1
var x = parseInt("abc");
console.log(x); // outputs NaN
as of my observation parseInt() converts a string to integer(not really an integer of string like "12sv") when the string begins with number.
but in reality it should return NaN.
From: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/parseInt
"If the first character cannot be converted to a number, parseInt returns NaN."
From Mozilla's docs: "If parseInt encounters a character that is not a numeral in the specified radix, it ignores it and all succeeding characters and returns the integer value parsed up to that point."
So it will parse up to the first invalid character, drop the rest of the string, and return the int it managed to parse until then. If there's no valid characters it will return NaN.
parseInt()->it simply parse the provided value to its equivalent radix conversion,if specified without radix it converts to decimal equivalent.
for coercion purpose, we should avoid using parseInt,we can use Number() function instead.
I have already tried the following:
discval = 2.833423
discval = discval.toFixed(2).toString().replace("." , ",");
discval = parseFloat(discval);
The output is 2 and not 2,83
Any idea?
parseFloat("2,83") will return 2 because , is not recognized as decimal separator, while . is.
If you want to round the number to 2 decimal places just use parseFloat(discval.toFixed(2)) or Math.round(discval * 100) / 100;
If you need this jut for display purposes, then leave it as a string with a comma. You can also use Number.toLocaleString() to format numbers for display purposes. But you won't be able to use it in further calculations.
BTW .toFixed() returns a string, so no need to use .toString() after that.
From https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/parseFloat
parseFloat parses its argument, a string, and returns a floating point
number. If it encounters a character other than a sign (+ or -),
numeral (0-9), a decimal point, or an exponent, it returns the value
up to that point and ignores that character and all succeeding
characters. Leading and trailing spaces are allowed.
If the first character cannot be converted to a number, parseFloat
returns NaN.
, is not an expected character so the number is truncated to that.
It's not possible to change the representation of floating point numbers in Javascript, you will need to treat your number as a string if you want to separate decimals with a comma instead of dot.
I have just observed that the parseInt function doesn't take care about the decimals in case of integers (numbers containing the e character).
Let's take an example: -3.67394039744206e-15
> parseInt(-3.67394039744206e-15)
-3
> -3.67394039744206e-15.toFixed(19)
-3.6739e-15
> -3.67394039744206e-15.toFixed(2)
-0
> Math.round(-3.67394039744206e-15)
0
I expected that the parseInt will also return 0. What's going on at lower level? Why does parseInt return 3 in this case (some snippets from the source code would be appreciated)?
In this example I'm using node v0.12.1, but I expect same to happen in browser and other JavaScript engines.
I think the reason is parseInt converts the passed value to string by calling ToString which will return "-3.67394039744206e-15", then parses it so it will consider -3 and will return it.
The mdn documentation
The parseInt function converts its first argument to a string, parses
it, and returns an integer or NaN
parseInt(-3.67394039744206e-15) === -3
The parseInt function expects a string as the first argument. JavaScript will call toString method behind the scene if the argument is not a string. So the expression is evaluated as follows:
(-3.67394039744206e-15).toString()
// "-3.67394039744206e-15"
parseInt("-3.67394039744206e-15")
// -3
-3.67394039744206e-15.toFixed(19) === -3.6739e-15
This expression is parsed as:
Unary - operator
The number literal 3.67394039744206e-15
.toFixed() -- property accessor, property name and function invocation
The way number literals are parsed is described here. Interestingly, +/- are not part of the number literal. So we have:
// property accessor has higher precedence than unary - operator
3.67394039744206e-15.toFixed(19)
// "0.0000000000000036739"
-"0.0000000000000036739"
// -3.6739e-15
Likewise for -3.67394039744206e-15.toFixed(2):
3.67394039744206e-15.toFixed(2)
// "0.00"
-"0.00"
// -0
If the parsed string (stripped of +/- sign) contains any character that is not a radix digit (10 in your case), then a substring is created containing all the other characters before such character discarding those unrecognized characters.
In the case of -3.67394039744206e-15, the conversion starts and the radix is determined as base 10 -> The conversion happens till it encounters '.' which is not a valid character in base 10 - Thus, effectively, the conversion happens for 3 which gives the value 3 and then the sign is applied, thus -3.
For implementation logic - http://www.ecma-international.org/ecma-262/5.1/#sec-15.1.2.2
More Examples -
alert(parseInt("2711e2", 16));
alert(parseInt("2711e2", 10));
TO note:
The radix starts out at base 10.
If the first character is a '0', it switches to base 8.
If the next character is an 'x', it switches to base 16.
It tries to parse strings to integers. My suspicion is that your floats are first getting casted to strings. Then rather than parsing the whole value then rounding, it uses a character by character parsing function and will stop when it gets to the first decimal point ignoring any decimal places or exponents.
Some examples here http://www.w3schools.com/jsref/jsref_parseint.asp
parseInt has the purpose of parsing a string and not a number:
The parseInt() function parses a string argument and returns an
integer of the specified radix (the base in mathematical numeral
systems).
And parseInt calls the function ToString wherein all the non numerical characters are ignored.
You can use Math.round, which also parses strings, and rounds a number to the nearest integer:
Math.round("12.2e-2") === 0 //true
Math.round("12.2e-2") may round up or down based on the value. Hence may cause issues.
new Number("3.2343e-10").toFixed(0) may solve the issue.
Looks like you try to calculate using parseFloat, this will give you the correct answer.
parseInt as it says, returns an integer, whereas parseFloat returns a floating-point number or exponential number:
parseInt(-3.67394039744206e-15) = -3
parseFloat(-3.67394039744206e-15) = -3.67394039744206e-15
console.log('parseInt(-3.67394039744206e-15) = ' , parseInt(-3.67394039744206e-15));
console.log('parseFloat(-3.67394039744206e-15) = ',parseFloat(-3.67394039744206e-15));
I'm passing as parameter an id to a javascript function, because it comes from UI, it's left zero padded. but it seems to have (maybe) "strange" behaviour?
console.log(0000020948); //20948
console.log(0000022115); //9293 which is 22115's octal
console.log(parseInt(0000022115, 10)); // 9293 which is 22115's octal
console.log(0000033959); //33959
console.log(20948); //20948
console.log(22115); //22115
console.log(33959); //33959
how can I make sure they are parsing to right numebr they are? (decimal)
EDIT:
just make it clearer:
those numbers come from the server and are zero padded strings. and I'm making a delete button for each one.
like:
function printDelButton(value){
console.log(typeof value); //output string
return '<img src="images/del.png">'
}
and
function printDelButton(value){
console.log(typeof value); //output numeric
console.log(value); //here output as octal .... :S
}
I tried :
console.log(parseInt(0000022115, 10)); // 9293 which is 22115's octal
and still parsing as Octal
If you receive your parameters as string objects, it should work to use
parseInt(string, 10)
to interpret strings as decimal, even if they are beginning with 0.
In your test, you pass the parseInt method a number, not a string, maybe that's why it doesn't return the expected result.
Try
parseInt('0000022115', 10)
instead of
parseInt(0000022115, 10)
that does return 221115 for me.
If you start it with a 0, it's interpreted as an Octal number.
See http://www.hunlock.com/blogs/The_Complete_Javascript_Number_Reference#quickIDX2
Note the article's warning here:
You should never precede a number with a zero unless you are
specifically looking for an octal conversion!
Consider looking here for ideas on removing the leadings 0s:
Truncate leading zeros of a string in Javascript
Leading 0s indicate that the number is octal.
parseInt parses a string containing a number.
parseInt(0000022115, 10) passes a numeric literal. The literal is parsed in octal by the JS interpreter, so you're passing a raw numeric value to parseInt.
Unless you can intercept a string version of this number, you're out of luck.
That being said, if you can get a string version of your octal (calling toString() won't help), this will work:
parseInt(variable_string.replace(/^0+/, ''), 10);
Try
/^[0]*([1-9]\d)/.exec(numberFromUI)[0]
That should give you just the numbers stripping the zeros (if you have to support decimals, you'll need to edit to account for the '.', and of course ',' is fun too... and I really hope you don't have to handle all the crazy different ways Europeans write numbers! )
If number came from server as zero padded string then use +"0000022115"
console.log(+"0000022115")
if (021 < 019) console.log('Paradox');
JS treat zero padded numbers like octal only if they are valid octal - if not then it treat it as decimal. To not allow paradox 'use strict' mode
'use strict'
if (021 < 019) console.log('Paradox');