I have 2 objects array as follows:
arr1 = [ { 'v1': 'abcde',
'pv_45': 13018,
'geolocation': '17.340291,76.842807'
}]
arr2 =[{ 'v1':'abcde',
'pv_50': 13010,
geolocation: '17.340291,76.842807'
}]
I want to merge the above 2 array int0 single based on condition that 'v1' and 'geolocation' should be same as follows:
[{'v1':'abcde',
'pv_45': 13018,
'pv_50': 13010,
'geolocation': '17.340291,76.842807'}]
I used _.extend, but its not checking any condition blindly it will merge. Please share your ideas. Thanks in advance.
you can use underscore js union and uniq to do that.
var mergedArray = _.uniq(_.union(c1, c2), false, function(item, key, a){ return item; });
Using pure JavaScript it could be done like this:
var arr1 = [ { 'v1': 'abcde',
'pv_45': 13018,
'geolocation': '17.340291,76.842807'
}],
arr2 =[{ 'v1':'abcde',
'pv_50': 13010,
geolocation: '17.340291,76.842807'
}],
mergeOnV1Geo = function (arr1, arr2) {
var mergeObj = {},
merge = function (item) {
var key = item.v1 + ',' + item.geolocation;
// if this is the first object with this key
// create a new object and copy v1, geolocation info
if (!mergeObj[key]) {
mergeObj[key] = {
v1: item.v1,
geolocation: item.geolocation
};
}
// add other props
Object.keys(item).forEach(function (prop) {
if (!prop.match(/v1|geolocation/)) {
mergeObj[key][prop] = item[prop];
}
});
};
arr1.forEach(merge);
arr2.forEach(merge);
// map back into an array
return Object.keys(mergeObj).map(function (key) {
return mergeObj[key];
});
};
mergeOnV1Geo(arr1, arr2);
You could do the following:
var arr3 = [].concat.apply([], arr1, arr2);
var temp =_.groupBy(arr3, 'geolocation');
var result = Object.keys(_.groupBy(arr3, 'geolocation')).map(function(x) { return _.extend.apply(0, p[x]); })
if you prefer ES-6 arrow functions the result becomes
Object.keys(_.groupBy(arr3, 'geolocation')).map((x) => _.extend.apply(0, p[x]);)
ES6: Using spread operator and reduce.
arr1 = [{ v1: 'abcde',
pv_45: 13018,
geolocation: '17.340291,76.842807'
}]
arr2 =[{ v1:'abcde',
pv_50: 13010,
geolocation: '17.340291,76.842807'
}]
// Keys to be grouped i.e whose values should be equal
groupableKeys = ['v1', 'geolocation'];
// Reducer that creates an Object with Key as the
// groupable key values value1::value2 and Value as
// the list of objects whose v1 and geolocation are same
groupableReducer = (a, b) => {
const uniqKey = groupableKeys.map(key => b[key]).join("::");
a[uniqKey] = [...(a[uniqKey] || []), b];
return a;
}
// Merges two objects using the spread operator
mergableReducer = (a, b) => ({...a, ...b})
// Merge two arrays and start processing
groupableKeyObject = [...arr1, ...arr2].reduce(groupableReducer, {})
output = Object.keys(groupableKeyObject)
.map(key =>
groupableKeyObject[key].reduce(mergableReducer, {})
)
console.log(output);
Related
i´m struggling with a Array in a Object stored in a Array with Objects from which I want return all Indicies.
Function to generate Object looks like this:
const addArray = function(a, b) {
const object = {
name: a,
rooms: b
};
testArray.push(object);
};
What I want to achieve is to cycle through the "testArray" and return every Index from the Object where the Array Rooms contains "Office" for example.
I´ve already tried to use a function like this but I don´t seem to be able to get the right Syntax for the Array in the Object:
function getAllIndexes(arr, val) {
var indexes = [], i = -1;
while ((i = arr.rooms.indexOf(val, i+1)) != -1){
indexes.push(i);
}
return indexes;
};
Thanks in advance!
Edit:
Additional Informations to Data:
A Object with data filled would look like this:
const device = {
name: "TV",
rooms: ["Living Room", "Bedroom"]
};
After generating Objects like this I push them to an array witch only contains this objects (see function addArray)
You can use Array.flatMap() to map each value of the array at matches val to it's index, and the rest to empty array, which will be removed by the flatMap:
const getAllIndexes =(arr, val) => arr.flatMap((v, i) => v === val ? i : [])
const arr = [1, 2, 3, 1, 2, 1, 1, 2]
const result = getAllIndexes(arr, 1)
console.log(result)
Using your array of objects, you'll need to compare a value, or check if an object meets some condition. It's better in this case to replace val with a predicate function:
const getAllIndexes =(arr, pred) => arr.flatMap((v, i) => pred(v) ? i : [])
const arr = [{ rooms: [1, 2, 3] }, { rooms: [2, 1, 1] }, { rooms: [3, 2, 2] }, { rooms: [1, 2, 1] }]
const result = getAllIndexes(arr, o => o.rooms.includes(1))
console.log(result)
Try using Array.prototype.map and Array.prototype.filter
function getAllIndexes(arr, val) {
return arr.map(i=> {
let room = i.rooms;
return room.indexOf(val);
}).filter(a=>{
a != -1;
});
};
You could destructure rooms from the device and get the index, if the wanted value is found.
const
room = 'Office',
indices = array.flatMap(({ rooms }, i) => rooms.includes(room) ? i : []);
The above code features a former solution from me with hacking Array#flatMap.
My below code is working fine and gives the correct desired output. But I am trying to use map, filter etc. instead of for loop. Lodash map and filter also works.
var arr = [
{"comp_id":1, desc: 'from comp1', updated: true},
{
"comp_id":2, desc: 'from comp2', updated: false}
];
var complaint_sources = [
{"comp_id":2,"consumer_source":"Hotline In","description_option":"English"},
{"comp_id":1,"consumer_source":"Online","description_option":"Other"},
{"comp_id":1,"consumer_source":"Email","description_option":null},
{"comp_id":2,"consumer_source":"Email","description_option":null}]
for(let i =0 ;i<arr.length;i++) {
let x=[];
for(let j=0;j<complaint_sources.length;j++){
if(arr[i].comp_id === complaint_sources[j].comp_id){
x.push(complaint_sources[j]);
arr[i].comp_src = x;
}
}
}
console.log(arr);
Basically I am looping through arr array and inside that looping through the complaint_sources array and when the comp_id matches I am modifying the arr array and adding a comp_src property to the object of arr array. This comp_src property will be an array of complaint_sources matched by comp_id.
this will work:
var arr = [
{"comp_id":1, desc: 'from comp1', updated: true},
{"comp_id":2, desc: 'from comp2', updated: false}
];
var complaint_sources = [
{"comp_id":2,"consumer_source":"Hotline In","description_option":"English"},
{"comp_id":1,"consumer_source":"Online","description_option":"Other"},
{"comp_id":1,"consumer_source":"Email","description_option":null},
{"comp_id":2,"consumer_source":"Email","description_option":null}
];
const grouped_sources = complaint_sources.reduce((acc, value) => {
(acc[value.comp_id] = acc[value.comp_id] || []).push(value);
return acc;
}, {})
const data = arr.map((comp) => ({
...comp,
comp_src: grouped_sources[comp.comp_id]
}));
console.log(data);
Say I have an array of objects that looks like this
let myArray = [
{item1: true},
{item2: false},
{item3: true},
{item4: false}
]
How would I iterate though this to return a new array of true values that looks like this:
let newArray = ['item1', 'item3']
I found this function but it only returns single items:
function findKey(map, term) {
var found = [];
for(var property in map) {
if(map.hasOwnProperty(property)) {
for(var key in map[property]) {
if(map[property].hasOwnProperty(key) && key === term) {
found.push(property);
}
}
}
}
return found;
}
Assuming myArray always contains objects with only 1 property.
let newArray = myArray
.map(item => Object.entries(item)[0])
.filter(([key, value]) => value)
.map(([key, value]) => key)
You could access the first key of each array item via Object.keys(), and use this to filter items with a true value for that first key, and then complete the process with a call to map() to transform the item to a value based on the same "first key" technique:
let myArray = [
{item1: true},
{item2: false},
{item3: true},
{item4: false}
]
let result = myArray
.filter(item => item[ Object.keys(item)[0] ] === true)
.map(item => Object.keys(item)[0])
console.log(result)
Use the function reduce to build the desired output. The handler of the function reduce will get the keys and check for each value === true.
This approach checks for the whole set of keys within an object. Further, this way you only use one loop.
let myArray = [{item1: true},{item2: false},{item3: true},{item4: false}],
result = myArray.reduce((a, c) => a.concat(Object.keys(c).filter(k => c[k] === true)), []);
console.log(result);
Something much optimized than the accepted answer would look like this:
const arr = [
{ item1: true },
{ item2: false },
{ item3: true },
{ item4: false }
]
const result = [];
const len = arr.length;
for (let i = 0; i < len; ++i) {
const obj = arr[i];
const key = Object.keys(obj)[0];
if(obj[key]) {
result.push(key);
}
}
console.log(result);
There is only one loop over the array, instead of map and filter which ends up looping twice.
Shortest
let newArray = myArray.map( x=>Object.keys(x)[0] ).filter( (k,i)=>myArray[i][k] );
In above solution first we use: map which works as for-loop to get array of keys (using Object.keys) ["item1", "item2", "item3", "item4"]. Then we filter that array by choose only those keys for which original array object has true. e.g myArray[0]["item1"] -> true (we use fact that filter funtion takes array element (k) and its index (i) which is the same for elements in myArray). In map and filter we use arrow functions.
I would like to know how would I merge this bidimensional array
let arr[
['Reference', 'Price'],
['232323DD, 15.00]
];
I want to convert this into
[
{name: 'Reference', value: '232323DD'},
{name: 'Price', value: 15.00}
]
I've tried this:
Convert a two dimensional array into an array of objects
but It didn't work for me.
You can use .map():
let [keys, values] = [
['Reference', 'Price'],
['232323DD', 15.00]
];
let result = keys.map((k, i) => ({name: k, value: values[i]}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
You can map through the first array in that array and use their values as the keys to an object:
let arr = [
['Reference', 'Price'],
['232323DD', '15.00']
];
console.log(
arr[0].map((name, i) => ({name, value:arr[1][i]}))
)
If you are unsure about the size of the two arrays, you should first check whether their lengths are equal, to avoid undefined.
Other solution if you are not familiar with map (I think using map for this example make it a bit hard to read)...
const arr = [
['Reference', 'Price'],
['232323DD', 15.00]
]
const obj = []
arr.forEach(x => obj.push({name: x[0], value: x[1]}))
console.log(obj)
You can use the map function. It will run the callback on each array item, return it in a new array.
// where 'arr' is your original array
const new_arr = arr.map((item) => {
// this is called a 'destructuring assignment'
const [name, value] = item;
// return the values as fields in an object
return {name, value};
});
const arrArr = [['Reference', 'Price'], ['232323DD, 15.00]];
const objArr = [];
for (const item of arrArr) {
objArr.push({name: item[0], value: item[1]});
}
let arr = [
['Reference', 'Price'],
['232323DD', '15.00']
];
let result = arr[0].map((key, i) => ({name: key, value: arr[1] ? arr[1][i] : null}));
console.log(result);
I'll try to break this down:
// 1. create a new arr object:
let convertedArr = [];
// 2. loop over the original array:
for(let i = 0; i < arr.length; i++){
let currentItem = arr[i];
//create a temp object
let obj = {name:currentItem[0], value: name:currentItem[1] };
//push a new object to the array
convertedArr.push(obj);
}
I'm fetching json data with ajax. Then I want to output it in Griddle using griddle-react. The problem is I cannot convert my array to a Griddle readable array.
After the ajax fetch i made a callback function:
function convert(obj) {
console.log(obj);
Object.keys(obj).forEach(function (key) {
let format = JSON.stringify(obj[key]);
console.log(format);
self.setState(() => ({ data: key[format] }));
});
}
The first console.log output looks like this:
{
{
"BTC": {
"opening_price": "9845000",
"closing_price": "9967000",
"min_price": "9814000",
"max_price": "10047000",
"average_price": "9928071.5654",
"units_traded": "7242.04659594",
"volume_1day": "7242.04659594",
"volume_7day": "73491.92898643",
"buy_price": "9967000",
"sell_price": "9968000"
},
}
}
My functions makes it look like this: (second console.log):
{
"opening_price": "9846000",
"closing_price": "9965000",
"min_price": "9814000",
"max_price": "10047000",
"average_price": "9929422.0905",
"units_traded": "7200.46713802",
"volume_1day": "7200.467F13802",
"volume_7day": "73395.33311647",
"buy_price": "9959000",
"sell_price": "9964000"
}
I want it to convert to the following array, basically adding the name item, and thereafter Griddle can read it:
{
"name": "BTC",
"opening_price": "9845000",
"closing_price": "9967000",
"min_price": "9814000",
"max_price": "10047000",
"average_price": "9928071.5654",
"units_traded": "7242.04659594",
"volume_1day": "7242.04659594",
"volume_7day": "73491.92898643",
"buy_price": "9967000",
"sell_price": "9968000"
},
What I'm doing wrong here? I'm sure its pretty close to what I want, but I can't figure it out at this point.
You can use Object.entries to get the keys and values. Use Object.assign to make new objects
var obj = {
"BTC": {"opening_price": "9845000","closing_price": "9967000","min_price": "9814000","max_price": "10047000","average_price": "9928071.5654","units_traded": "7242.04659594","volume_1day": "7242.04659594","volume_7day": "73491.92898643","buy_price": "9967000","sell_price": "9968000"}
}
var newObj = Object.entries(obj).reduce((c, [i, v]) => Object.assign(c, {name: i}, v), {});
console.log(newObj);
If you have several keys, you can use map
var obj = {
"BTC": {"opening_price": "9845000","closing_price": "9967000","min_price": "9814000","max_price": "10047000","average_price": "9928071.5654","units_traded": "7242.04659594","volume_1day": "7242.04659594","volume_7day": "73491.92898643","buy_price": "9967000","sell_price": "9968000"},
"OTH": {"opening_price": "9845000","closing_price": "9967000","min_price": "9814000","max_price": "10047000","average_price": "9928071.5654","units_traded": "7242.04659594","volume_1day": "7242.04659594","volume_7day": "73491.92898643","buy_price": "9967000","sell_price": "9968000"},
}
var newArr = Object.entries(obj).map(([i, v]) => Object.assign({}, {name: i}, v));
console.log(newArr);
Without including date property
var obj = {
"KNC": {"opening_price": "2731","closing_price": "2788","min_price": "2693","max_price": "2849","average_price": "2790.5368","units_traded": "3178032.25814499211673","volume_1day": "3178032.25814499211673","volume_7day": "110687333.315264505902311000","buy_price": "2783","sell_price": "2788"},
"date": "1525269153470"
}
var newObj = Object.entries(obj).reduce((c, [i, v]) => i !== 'date' ? Object.assign(c, {name: i}, v) : c, {});
console.log(newObj);
Can you update your function to have this line in it?
obj[key]["name"] = key
function convert(obj) {
console.log(obj);
Object.keys(obj).forEach(function (key) {
obj[key]["name"] = key;
let format = JSON.stringify(obj[key]);
console.log(format);
//self.setState(() => ({ bithumbData: key[format] }));
});
}
function convert(obj){
var parentKey = Object.keys(obj)[0];//Getting parent first element key
obj = obj[parentKey];
var newObj = {}; //Creating new empty jason object
newObj['name'] = parentKey; //key apply as name element to new jason object
for(var key in obj) //looping each child element
newObj[key] = obj[key]; //child applying to new jason object
return newObj;
}
console.log(JSON.stringify(convert(obj)));