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Using translate and rotate in CSS

I'm trying to make a div rotate and move along the Y axis. I got it to work individually but not in the same time. This is the code i use to rotate the div:
function rotate_horizon_bg(deg){
var rotate = "rotate(" + (deg) + "deg);";
var tr = new Array(
"transform:" + rotate,
"-moz-transform:" + rotate,
"-webkit-transform:" + rotate,
"-ms-transform:" + rotate,
"-o-transform:" + rotate
);
var horizon_bg = document.getElementById("horizon_bg");
horizon_bg.setAttribute("style", tr.join(";"));
}
This works perfectly to rotate the div. If I make a new function to transelateY. Only transelateY will work.
Any ideas on how I can get this to work
simultaneous?

Just combine the effects. Here's a literal example:
transform: rotate(-45deg) translate(-120px,-30px)
function rotate_horizon_bg(rotateDeg, x, y){
var horizon_bg = document.getElementById("horizon_bg");
horizon_bg.style.transform = "rotate(" + rotateDeg + "deg) translate(" + x + "px, " + y + "px)";
}
rotate_horizon_bg(-30, 3, 3);
<div id="horizon_bg">Translate Me!</div>

Rotate element on mousemove that's larger than viewport

I'm having an issue trying to rotate an element on mousemove. I believe the issue is related to the fact that my element is much larger than the screen (set in CSS with vh/vw units) but essentially the element sound rotate, from the centre on mousemove.
I have set up a jsFiddle here:
https://jsfiddle.net/cLx290p1/
function themeLanding() {
var graphic = $('.landing-2016');
if (graphic.length > 0) {
var offset = graphic.offset();
function mouse(evt) {
var centerX = (offset.left) + (graphic.width()/2),
centerY = (offset.top) + (graphic.height()/2),
mouseX = evt.pageX,
mouseY = evt.pageY,
radians = Math.atan2(mouseX - centerX, mouseY - centerY);
degree = (radians * (180 / Math.PI) * -1) + 90;
graphic.css('-moz-transform', 'rotate(' + degree + 'deg) translate(-50%,-50%)');
graphic.css('-webkit-transform', 'rotate(' + degree + 'deg) translate(-50%,-50%)');
graphic.css('-o-transform', 'rotate(' + degree + 'deg) translate(-50%,-50%)');
graphic.css('-ms-transform', 'rotate(' + degree + 'deg) translate(-50%,-50%)');
graphic.css('transform', 'rotate(' + degree + 'deg) translate(-50%,-50%)');
}
$(document).mousemove(mouse);
}
}
themeLanding();
I have also applied the same idea, without mousemove as a debugging check, to rotate the same element using CSS3.
https://jsfiddle.net/psywr840/1/
This seems to work fine so I am unsure where I am going wrong.
Any ideas? Thanks.

When using css transform functions, the functions are processed in order from left to right.
In your case, what you want is to first translate the element and THEN rotate it. For example this answer on SO explains something similar, only instead of rotate they use scale, but the principle is the same.
So what you want, is to change the order of transform functions:
graphic.css('-moz-transform', 'translate(-50%,-50%) rotate(' + degree + 'deg)');
graphic.css('-webkit-transform', 'translate(-50%,-50%) rotate(' + degree + 'deg)');
graphic.css('-o-transform', 'translate(-50%,-50%) rotate(' + degree + 'deg)');
graphic.css('-ms-transform', 'translate(-50%,-50%) rotate(' + degree + 'deg)');
graphic.css('transform', 'translate(-50%,-50%) rotate(' + degree + 'deg)');

javascript find same position in rotated element

I have a "base" reference rect (red)
Inside a rotated div (#map), I need a clone rect (yellow), it has to be same size and position of "base" rect, independent of its parent (#map) rotation.
This is where I am so far, any help would be welcoming.
http://codepen.io/christianpugliese/pen/oXKOda
var controls = { degrees: 0, rectX:125, rectY:55 };
var wBounds = document.getElementById("wrapper").getBoundingClientRect(),
mapBounds = document.getElementById("map").getBoundingClientRect(),
rectBounds = document.getElementById("rect").getBoundingClientRect();
var _x = ((mapBounds.width - wBounds.width) / 2) + $('#rect').position().left,
_y = ((mapBounds.height - wBounds.height) / 2) + $('#rect').position().top;
$('#rect').css({top: controls.rectY+'px', left:controls.rectX+'px'});
$('#mapRect').width(rectBounds.width);
$('#mapRect').height(rectBounds.height);
$('#mapRect').css({top: _y+'px',
left:_x+'px',
'transform': 'rotate('+ Math.round(-controls.degrees) +'deg)'});
$('#map').css('transform', 'rotate('+ Math.round(controls.degrees) +'deg)');

Since you're rotating the #mapRect an equal amount in the opposite direction you're getting rotation/orientation right but not the origin. The transform-origin would be the center of the #mapBounds, but relative to the #rect;
Fork of your pen: http://codepen.io/MisterCurtis/pen/vNBYZJ?editors=101
Since there is some rounding/subpixel positioning happening the yellow rect doesn't align pixel perfect.
function updateUI(){
var _x = ((mapBounds.width - wBounds.width) / 2) + $('#rect').position().left,
_y = ((mapBounds.height - wBounds.height) / 2) + $('#rect').position().top,
_ox = mapBounds.width/2 - _x, // origin x
_oy = mapBounds.height/2 - _y; // origin y
...
$('#mapRect').css({
'transform-origin': _ox + 'px ' + _oy + 'px', // now it rotates by the bounds
top: _y + 'px',
left: _x + 'px',
'transform': 'rotate(' + Math.round(-controls.degrees) + 'deg)'
});
}
Edit: Updated the pen. You'll have to ditch using Rectangle and instead use Polygon. This way you can use a plugin like https://github.com/ahmadnassri/google-maps-polygon-rotate to perform the rotation along the map center.

Adjusting scaleX and scaleY of Div with HTML5 Slider

Experimenting with JQuery and HTML5 for a college assignment at the moment. I would like to update the css values of the div when the slider is moved.
HTML
Scale<input id="slider" type="range" name="points" min="1" max="10">
Currently this is my script:
$("#slider").change(function(){
size = $("#slider").val();
console.log("Size: " + size);
//Update the size of box while dragging
b1.css({
"-webkit-transform":"scaleX"+size/10,
"-webkit-transform":"scaleY"+size/10
});
});
It works however the values do not seem to be updating in my CSS and I am guessing it is because I am assigning them incorrectly.
Does anyone have a solution as to how I can fix the problem?
JSFiddle
http://jsfiddle.net/JQ7vD/

The main problem was that you forgot your parenthesis before and after the scale value. To make it scale both the X and Y, however, you need to combine the jQuery lines into one, i.e.
b1.css({
"-webkit-transform": "scaleX(" + size / 10 + ") scaleY(" + size / 10 + ")"
});
This is because if you have them in separate lines then the second one will always override the first because it does so in CSS. Take the following example
#image {
background:url('/exampleImage.jpg');
background:red;
}
The background would be red, not the image declared first. To support all browsers you need to include the browser prefixes in the jQuery as well

b1.css({
'-webkit-transform': 'scale3d(' + size/10 + ',' + size/10 + ',1)',
'-moz-transform': 'scale3d(' + size/10 + ',' + size/10 + '1)',
'-ms-transform': 'scale3d(' + size/10 + ',' + size/10 + ',1)',
'transform': 'scale3d(' + size/10 + ',' + size/10 + ',1)'
});
DEMO: http://jsfiddle.net/JQ7vD/4/

How to zoom to mouse pointer while using my own mousewheel smoothscroll?

Part of my app contains functionality similar to google maps in that the user should be able to zoom in and out on an image within a container.
In the same way that google maps does I want the user to be able to scroll with the mousewheel and the pixel on the image to remain directly under the mousepointer at all times. So essentially the user will be zooming to wherever their mouse pointer is.
For the zooming/translating I am using css transforms like so:
visible
$('#image').css({
'-moz-transform': 'scale(' + ui.value + ') translate(' + self.zoomtrans.xNew + 'px, ' + self.zoomtrans.yNew + 'px)',
'-moz-transform-origin' : self.zoomtrans.xImage + 'px ' + self.zoomtrans.yImage + 'px',
'-webkit-transform': 'scale(' + ui.value + ') translate(' + self.zoomtrans.xNew + 'px, ' + self.zoomtrans.yNew + 'px)',
'-webkit-transform-origin' : self.zoomtrans.xImage + 'px ' + self.zoomtrans.yImage + 'px',
'-o-transform': 'scale(' + ui.value + ') translate(' + self.zoomtrans.xNew + 'px, ' + self.zoomtrans.yNew + 'px)',
'-o-transform-origin' : self.zoomtrans.xImage + 'px ' + self.zoomtrans.yImage + 'px',
'-ms-transform': 'scale(' + ui.value + ') translate(' + self.zoomtrans.xNew + 'px, ' + self.zoomtrans.yNew + 'px)',
'-ms-transform-origin' : self.zoomtrans.xImage + 'px ' + self.zoomtrans.yImage + 'px',
'transform': 'scale(' + ui.value + ') translate(' + self.zoomtrans.xNew + 'px, ' + self.zoomtrans.yNew + 'px)',
'transform-origin' : self.zoomtrans.xImage + 'px ' + self.zoomtrans.yImage + 'px'
});
I have managed to find various implementations of how to go about doing this however I am using a self rolled smooth scroll technique to interpolate the mouse events and provide momentum.
Trying to get the two to work correctly together is proving troublesome.
Rather than paste a whole load of code here I have created a jsFiddle that includes the mousewheel smoothscroll technique along with the zoom function that I have so far.
http://jsfiddle.net/gordyr/qGGwx/2/
This is essentially a fully functioning demo of this part of my app.
If you scroll the mousewheel you will see that the jqueryui slider interpolates and provides the momentum/deceleration correctly. However the zoom does not react correctly.
If you scroll your mousewheel only one point the zoom works perfectly but any further scrolls do not work. I assume this is because the scale of the image has now changed causing the calculations to be incorrect. I have attempted to compensate for this but have not had any luck so far.
So to summarise, I would like to modify the code in my jsFiddle so that the image zooms directly to the mousepointer at all times.
Huge thanks in advance to anyone willing to help.

You can do it more easily with css3 transitions.
Exemple: http://jsfiddle.net/BaliBalo/xn75a/
The main center-mouse algorithm is here:
//Center the image if it's smaller than the container
if(scale <= 1)
{
currentLocation.x = im.width() / 2;
currentLocation.y = im.height() / 2;
}
else
{
currentLocation.x += moveSmooth * (mouseLocation.x - currentLocation.x) / currentScale;
currentLocation.y += moveSmooth * (mouseLocation.y - currentLocation.y) / currentScale;
}
If you want to keep your already-existing code, I think you can do it approximatively the same: the trick to get the mouse position on the zoomed image when the image itself is zoomed by a css scale transform and using transform-origin is to substract the transform origin to your point then multiply by the factor and finally re-add the transform-origin.
You can also use translate as in this updated example: http://jsfiddle.net/BaliBalo/xn75a/15/
As you can see it even simplifies the formulas but don't forget to sub the center of the element to mouse point as a translation of {0, 0} will zoom on the middle of the image.
EDIT:
I stumbled on this answer of mine today and figured it wasn't really the behaviour you wanted. I didn't understand correctly the first time that you didn't want to center the point under the mouse but to keep it in the same spot. As I did it recently for a personnal project I tried to correct myself. So here is a more accurate answer :
http://jsfiddle.net/BaliBalo/7ozrc1cq/
The main part is now (if currentLocation is the top-left point of the image in the container) :
var factor = 1 - newScale / currentScale;
currentLocation.x += (mouseLocation.x - currentLocation.x) * factor;
currentLocation.y += (mouseLocation.y - currentLocation.y) * factor;
I also removed the CSS transition. I think the best way to achieve a smooth scrolling would be to use requestAnimationFrame to create an animation loop and instead of changing values directly in the zoom function, store values and animate towards them in the loop.