Based on this tutorial i made JSON menu. And now items sorted by id, but i need sort them alphabetically and can't understand how to do that. Not sure if array.sort(); will help in my case
Here is JS code:
var builddata = function () {
var source = [];
var items = [];
for (i = 0; i < data.length; i++) {
var item = data[i];
var label = item["text"];
var parentid = item["parentid"];
var id = item["id"];
if (items[parentid]) {
var item = { parentid: parentid, label: label, item: item };
if (!items[parentid].items) {
items[parentid].items = [];
}
items[parentid].items[items[parentid].items.length] = item;
items[id] = item;
}
else {
items[id] = { parentid: parentid, label: label, item: item };
source[id] = items[id];
}
}
return source;
}
var source = builddata();
var buildUL = function (parent, items) {
$.each(items, function () {
if (this.label) {
var li = $("<li>" + this.label + "</li>");
li.appendTo(parent);
if (this.items && this.items.length > 0) {
var ul = $("<ul></ul>");
ul.appendTo(li);
buildUL(ul, this.items);
}
}
});
}
var ul = $("<ul></ul>");
ul.appendTo("#jqxMenu");
buildUL(ul, source);
HTML:
<div id='jqxMenu'>
</div>
Here is JSFIDDLE
source.sort(function(a, b){
if(a.text < b.text) return -1;
if(a.text > b.text) return 1;
return 0;
})
...is the basis. However, recursive implementation is needed in this case I suppose.
Here: jsfiddle
Try sort the source u return
return source.sort();
See: DEMO
Related
I am trying to push elements to an array in a nested loop, but only the last item is getting repeated in the final array, where am I going wrong, very new to javascript asynchronous concept.Below is the function in which I push the items to an array.
$scope.showBeList = function(feed) {
if (feed[srcServ.KEY_CONTENT_TEXT]) {
var content = JSON.parse(feed[srcServ.KEY_CONTENT_TEXT])
if (content) {
$scope.beList = {};
for (var key in content) {
var decorationVal;
//reading value from a lokijs collection
var decoration = dataServ[srcServ.CONST_COLLECTION_DECORATION].find({
'name': key
});
if (decoration && decoration.length) {
decorationVal = decoration[0];
if (decorationVal != null) {
var tempObj = JSON.parse(decorationVal.value);
if (tempObj) {
var header = tempObj[key][key + '_HEADER'];
if (header) {
var counter = content[key].length;
var tempItems = [];
for (var j = 0; j < content[key].length; j++) {
(function(j) {
var obj = {};
obj[srcServ.KEY_MAIN_HEADER] = tempObj[key][srcServ.KEY_DESC];
obj[srcServ.KEY_SUB_HEADER] = header[srcServ.KEY_DESC];
obj.id = j;
var itemVal = content[key][j][key + '_HEADER'];
var details = [];
var notes = [];
for (var item in itemVal) {
var val = null;
var found = false;
for (var i = 0; i < header.field.length; i++) {
if (header.field[i].name == item) {
val = header.field[i];
found = true;
break;
}
}
if (found && val != null) {
val[srcServ.KEY_DESC_VALUE] = itemVal[item];
details.push(val);
}
}
obj.details = details;
counter--;
if (counter == 0) {
$scope.showMoreDetails = true;
$scope.beList.beItems = tempItems;
console.log(JSON.stringify($scope.beList));
}
tempItems.push(obj)
})(j);
// $scope.beList.beItems.push(obj);
}
}
}
}
}
}
}
}
}
I am trying to take data from a table and show/hide rows depending on the id.
var txnfilterbox = function(table, tabID)
{
if (table)
{
var filtervalue = $('#filterText').val();
if((filtervalue != undefined)&&(filtervalue.length > 0))
{
var tableData = table.fnSettings().aoData;
for (var index = 0; index < tableData.length; index++)
{
var rowData = tableData[index]._aData;
if (filtervalue === rowData.id)
{
rowData.show();
}
else
{
rowData.hide();
}
}
}
}
};
following adds items to array:
var arrayOptions = [];
function AddToFilterOptionList(mode) {
arrayOptions.push(mode);
}
remove item from array:
function RemoveFromFilterOptionList(mode) {
var index = arrayOptions.indexOf(mode);
if (index !== -1) {
arrayOptions.splice(index, 1);
}}
for example if i call
AddToFilterOptionList('APPLE') - APPLE should be added to array.
If i again call
AddToFilterOptionList('APPLE+FRUIT') - it should remove the the item 'APPLE' from array arrayOptions and should add APPLE+FRUIT
Any time only one word that starts with APPLE can be in array.
How to find the word like 'APPLE' in javascript.
I tried with Match() which returns the matching word. IndexOf() returns 1 only if whole word is match but not start of word.
Cycle through the Array and then use the startsWith method.
void AddToFilterOptionList(String mode) {
for (i=0; i<arrayOptions.length; i++) {
if (mode.startsWith(arrayOptions[i] == 1)) {
array[i] = mode;
return; // found, so return
}
}
arrayOptions.push(mode); // should only get here if string did not exist.
}
You need to split by + characted and then loop over produced array to add/remove all items:
var arrayOptions = [];
function AddToFilterOptionList(mode) {
mode.split(/\+/g).forEach(function(el) {
var index = arrayOptions.indexOf(el);
if (index !== -1) {
arrayOptions.splice(index, 1);
}
else {
arrayOptions.push(el);
}
});
}
function RemoveFromFilterOptionList(mode) {
var index = arrayOptions.indexOf(mode);
if (index !== -1) {
arrayOptions.splice(index, 1);
}
}
AddToFilterOptionList('APPLE');
document.write('<p>' + arrayOptions); // expect: APPLE
AddToFilterOptionList('APPLE+FRUIT');
document.write('<p>' + arrayOptions); // expect: FRUIT
AddToFilterOptionList('APPLE+FRUIT+CARROT');
document.write('<p>' + arrayOptions); // expect: APPLE,CARROT
This will work assuming the 'this+that' pattern is consistent, and that we only care about the starting item.
http://jsbin.com/gefasuqinu/1/edit?js,console
var arr = [];
function remove(item) {
var f = item.split('+')[0];
for (var i = 0, e = arr.length; i < e; i++) {
if (arr[i].split('+')[0] === f) {
arr.splice(i, 1);
break;
}
}
}
function add(item) {
remove(item);
arr.push(item);
}
UPDATE:
function add (array, fruits) {
var firstFruit = fruits.split('+')[0]
var secondFruit = fruits.split('+')[1]
var found = false
var output = []
output = array.map(function (item) {
if (item.indexOf(firstFruit) > -1) {
found = true
return fruits
}
else return item
})
if (! found) {
array.push(fruits)
}
return output
}
var fruits = []
add(fruits, 'APPLE')
fruits = add(fruits, 'APPLE+GRAPE')
console.log(fruits[0]) // 'APPLE+GRAPE'
fruits = add(fruits, 'APPLE')
console.log(fruits[0]) // 'APPLE'
Try this, the code is not optimised though :P
<html>
<head>
<script src = "jquery-1.10.2.min.js"></script>
<script type = "text/javascript">
var itemList = [];
function addItem()
{
var item = $('#item').val();
if(item != '' || item != 'undefined')
{
if(itemList.length == 0)
itemList.push(item);
else
{
for(i=0;i<itemList.length;i++)
{
var splittedInputItems = [];
splittedInputItems = item.split("+");
var splittedListItems = [];
splittedListItems = itemList[i].split("+");
if(splittedListItems[0] == splittedInputItems[0])
{
itemList.splice(i,1);
itemList.push(item);
return;
}
}
itemList.push(item);
}
}
}
</script>
</head>
<body>
<input id="item" type = "text"/>
<input type = "button" value="Add" onclick="addItem()">
</body>
</html>
let items = [1, 2, 3, 2, 4, 5, 2, 7];
let item = 2;
for (let i = 0; i < items.length; i++) {
if (items[i] === item) {
items.splice(i, 1);
i = i - 1;
}
}
If you want to remove the element '2' from items array, it is a way.
I have an array like this:
var myObjArray = [{city: 'milwaukee', state: 'wi'},
{city:'madison', state: 'wi'},
{city:'greenbay', state: 'wi'},
{city:'madison', state: 'wi'}];
How would I compare the array against itself to find duplicates.
(Note: I need to keep the duplicates, so maybe I could add a property to the object as a flag).
How about something like:
var bucket = {};
for(var i=0;i<array.length;i++) {
var item = array[i];
var hash = JSON.stringify(item); //or some a hashing algorithm...
var prev = bucket[hash];
if(prev) {
prev.duplicate = item.duplicate = true;
} else {
bucket[hash] = item
}
}
Or same without dependending upon JSON.stringify:
var markDuplicates = function(array, hashFunc) {
var bucket = {};
for(var i=0;i<array.length;i++) {
var item = array[i];
var hash = hashFunc(item);
var prev = bucket[hash];
if(prev) {
prev.duplicate = item.duplicate = true;
} else {
bucket[hash] = item
}
}
return array;
};
markDuplicates(yourArray, function(item) { return item.city + item.state; });
I have an array of objects. Every object in the array has an id and an item property that is an array containing other object. I need to be able to find an element in an array by id. Here is a sample of what I have done so far, but the recursive function is always returning undefined.
How can I quit the function and return the item when I have called the function recursively several times?
$(function () {
var treeDataSource = [{
id: 1,
Name: "Test1",
items: [{
id: 2,
Name: "Test2",
items: [{
id: 3,
Name: "Test3"
}]
}]
}];
var getSubMenuItem = function (subMenuItems, id) {
if (subMenuItems && subMenuItems.length > 0) {
for (var i = 0; i < subMenuItems.length; i++) {
var item;
if (subMenuItems[i].Id == id) {
item = subMenuItems[i];
return item;
};
getSubMenuItem(subMenuItems[i].items, id);
};
};
};
var searchedItem = getSubMenuItem(treeDataSource, 3);
alert(searchedItem.id);
});
jsFiddle
You should replace
getSubMenuItem(subMenuItems[i].items, id);
with
var found = getSubMenuItem(subMenuItems[i].items, id);
if (found) return found;
in order to return the element when it is found.
And be careful with the name of the properties, javascript is case sensitive, so you must also replace
if (subMenuItems[i].Id == id) {
with
if (subMenuItems[i].id == id) {
Demonstration
Final (cleaned) code :
var getSubMenuItem = function (subMenuItems, id) {
if (subMenuItems) {
for (var i = 0; i < subMenuItems.length; i++) {
if (subMenuItems[i].id == id) {
return subMenuItems[i];
}
var found = getSubMenuItem(subMenuItems[i].items, id);
if (found) return found;
}
}
};
I know its late but here is a more generic approach
Array.prototype.findRecursive = function(predicate, childrenPropertyName){
if(!childrenPropertyName){
throw "findRecursive requires parameter `childrenPropertyName`";
}
let array = [];
array = this;
let initialFind = array.find(predicate);
let elementsWithChildren = array.filter(x=>x[childrenPropertyName]);
if(initialFind){
return initialFind;
}else if(elementsWithChildren.length){
let childElements = [];
elementsWithChildren.forEach(x=>{
childElements.push(...x[childrenPropertyName]);
});
return childElements.findRecursive(predicate, childrenPropertyName);
}else{
return undefined;
}
}
to use it:
var array = [<lets say an array of students who has their own students>];
var joe = array.findRecursive(x=>x.Name=="Joe", "students");
and if you want filter instead of find
Array.prototype.filterRecursive = function(predicate, childProperty){
let filterResults = [];
let filterAndPushResults = (arrayToFilter)=>{
let elementsWithChildren = arrayToFilter.filter(x=>x[childProperty]);
let filtered = arrayToFilter.filter(predicate);
filterResults.push(...filtered);
if(elementsWithChildren.length){
let childElements = [];
elementsWithChildren.forEach(x=>{
childElements.push(...x[childProperty]);
});
filterAndPushResults(childElements);
}
};
filterAndPushResults(this);
return filterResults;
}