I have an data.url string. I want to get some data from it with the following regex
var filename = data.url.match(/file=(.+)&/gi);
All I want is the data inside the parenthesis -a file name actually- but what I get back is "file=example.jpg&".
Why is this happening? Shouldn't only the the matches found in the parentheses be returned?
How can I get rid of those unnecessary characters? Thanks
Javascript returns both the whole matched pattern(usually known as group-0) along with the other matched groups. You can use this one:
var filename = /file=(.+)&/gi.exec(data.url).slice(1);
Use
var filename = data.url.match(/file=([^&]+)/i)[1];
Example:
"file=example.jpg".match(/file=([^&]+)/i)[1] == "example.jpg"
"file=example.jpg&b=ttt&c=42".match(/file=([^&]+)/i)[1] == "example.jpg"
"http://example.com/index.php?file=example.jpg&b=ttt&c=42".match(/file=([^&]+)/i)[1] == "example.jpg"
match() returns an array with the first searched group at the second place, i.e. at match(...)[1].
Note: The result of the above code will be a String. If you still want to have a singleton array with your filename as the only element, then you should take the solution of #Sabuj Hassan.
Related
I have a Javascript array of string that contains urls like:
http://www.example.com.tr/?first=DSPN47ZTE1BGMR&second=NECEFT8RYD
http://www.example.com.tr/?first=RTR22414242144&second=YUUSADASFF
http://www.example.com.tr/?first=KOSDFASEWQESAS&second=VERERQWWFA
http://www.example.com.tr/?first=POLUJYUSD41234&second=13F241DASD
http://www.example.com.tr/?first=54SADFD14242RD&second=TYY42412DD
I want to extract "first" query parameter values from these url.
I mean i need values DSPN47ZTE1BGMR, RTR22414242144, KOSDFASEWQESAS, POLUJYUSD41234, 54SADFD14242RD
Because i am not good using regex, i couldnt find a way to extract these values from the array. Any help will be appreciated
Instead of using regex, why not just create a URL object out of the string and extract the parameters natively?
let url = new URL("http://www.example.com.tr/?first=54SADFD14242RD&second=TYY42412DD");
console.log(url.searchParams.get("first")); // -> "54SADFD14242RD"
If you don't know the name of the first parameter, you can still manually search the query string using the URL constructor.
let url = new URL("http://www.example.com.tr/?first=54SADFD14242RD&second=TYY42412DD");
console.log(url.search.match(/\?([^&$]+)/)[1]); // -> "54SADFD14242RD"
The index of the search represents the parameter's position (with index zero being the whole matched string). Note that .match returns null for no matches, so the code above would throw an error if there's no parameters in the URL.
Does it have to use regex? Would something like the following work:
var x = 'http://www.example.com.tr/?first=DSPN47ZTE1BGMR&second=NECEFT8RYD';
x.split('?first=')[1].split('&second')[0];
Try this regex:
first=([^&]*)
Capture the contents of Group 1
Click for Demo
Code
Explanation:
first= - matches first=
([^&]*) - matches 0+ occurences of any character that is not a & and stores it in Group 1
You can use
(?<=\?first=)[^&]+?
(?<=\?first=) - positive look behind to match ?first=
[^&]+? - Matches any character up to & (lazy mode)
Demo
Without positive look behind you do like this
let str = `http://www.example.com.tr/?first=DSPN47ZTE1BGMR&second=NECEFT8RYD
http://www.example.com.tr/?first=RTR22414242144&second=YUUSADASFF
http://www.example.com.tr/?first=KOSDFASEWQESAS&second=VERERQWWFA
http://www.example.com.tr/?first=POLUJYUSD41234&second=13F241DASD
http://www.example.com.tr/?first=54SADFD14242RD&second=TYY42412DD`
let op = str.match(/\?first=([^&]+)/g).map(e=> e.split('=')[1])
console.log(op)
So I currently pass two variables into the url for use on another page. I get the last variable (ie #12345) with location.hash. Then from the other part of the url (john%20jacob%202) all I need is the '2'. I've got it working but feel there must be a cleaner and succinct way to handle this. The (john%20jacob%202) will change all the time to have different string lengths.
url: http://localhost/index.html?john%20jacob%202?#12345
<script>
var hashUrl = location.hash.replace("?","");
// function here to use this data
var fullUrl = window.location.href;
var urlSplit = fullUrl.split('?');
var justName = urlSplit[1];
var nameSplit = justName.split('%20');
var justNumber = nameSplit[2];
// function here to use this data
</script>
A really quick one-liner could be something like:
let url = 'http://localhost/index.html?john%20jacob%202?#12345';
url.split('?')[1].split('').pop();
// returns '2'
How about something like
decodeURI(window.location.search).replace(/\D/g, '')
Since your window.location.search is URI encoded we start by decoding it. Then replace everything that is not a number with nothing. For your particular URL it will return 2
Edit for clarity:
Your example location http://localhost/index.html?john%20jacob%202?#12345 consists of several parts, but the interesting one here is the part after the ? and before the #.
In Javascript this interesting part, the query string (or search), is available through window.location.search. For your specific location window.location.search will return ?john%20jacob%202?.
The %20 is a URI encoded space. To decode (ie. remove) all the URI encodings I first run the search string through the decodeURI function. Then I replace everything that is not a number in that string with an empty string using a regular expression.
The regular expression /\D/ matches any character that is not a number, and the g is a modifier specifying that I want to match everything (not just stop after the first match), resulting in 2.
If you know you are always after a tag, you could replace everything up until the "#"
url.replace(/^.+#/, '');
Alternatively, this regex will match the last numbers in your URL:
url.match(/(?<=\D)\d+$/);
//(positive look behind for any non-digit) one more digits until the end of the string
I am trying to fetch the value after equal sign, its works but i am getting duplicated values , any idea whats wrong here?
// Regex for finding a word after "=" sign
var myregexpNew = /=(\S*)/g;
// Regex for finding a word before "=" sign
var mytype = /(\S*)=/g;
//Setting data from Grid Column
var strNew = "QCById=20";
var matchNew = myregexpNew.exec(strNew);
var newtype = mytype.exec(strNew);
alert(matchNew);
https://jsfiddle.net/6vjjv0hv/
exec returns an array, the first element is the global match, the following ones are the submatches, that's why you get ["=20", "20"] (using console.log here instead of alert would make it clearer what you get).
When looking for submatches and using exec, you're usually interested in the elements starting at index 1.
Regarding the whole parsing, it's obvious there are better solution, like using only one regex with two submatches, but it depends on the real goal.
You can try without using Regex like this:
var val = 'QCById=20';
var myString = val.substr(val.indexOf("=") + 1);
alert(myString);
Presently exec is returning you the matched value.
REGEXP.exec(SOMETHING) returns an array (see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/exec).
The first item in the array is the full match and the rest matches the parenthesized substrings.
You do not get duplicated values, you just get an array of a matched value and the captured text #1.
See RegExp#exec() help:
If the match succeeds, the exec() method returns an array and updates properties of the regular expression object. The returned array has the matched text as the first item, and then one item for each capturing parenthesis that matched containing the text that was captured.
Just use the [1] index to get the captured text only.
var myregexpNew = /=(\S*)/g;
var strNew = "QCById=20";
var matchNew = myregexpNew.exec(strNew);
if (matchNew) {
console.log(matchNew[1]);
}
To get values on both sides of =, you can use /(\S*)=(\S*)/g regex:
var myregexpNew = /(\S*)=(\S*)/g;
var strNew = "QCById=20";
var matchNew = myregexpNew.exec(strNew);
if (matchNew) {
console.log(matchNew[1]);
console.log(matchNew[2]);
}
Also, you may want to add a check to see if the captured values are not undefined/empty since \S* may capture an empty string. OR use /(\S+)=(\S+)/g regex that requires at least one non-whitespace character to appear before and after the = sign.
I am pulling in a string from another web page. I want to read that string into a variable but only after a certain point. Eg:
#stringexample
var variable;
I want variable to equal stringexample but not contain the # how could I do this?
This is how I am using the variable at the moment.
$("#Outputajax").load("folder/"+ variable +".html");
This is the way that works but isn't a variable.
$("#Outputajax").load("folder/webpage.html");
If you just want to trim of the first character, then you can use substring...
var input = "#stringexample";
input = input.substring(1);
//input = "stringexample"
Here is a working example
var myVariable = stringExample.replace('#','');
Could just use variable.substr(1) to cut off the first character.
If you want to specifically remove the hash from the start (but do nothing if the hash isn't there), try variable.replace(/^#/,"")
I understand you want to get everything in the string AFTER the hashtag. The other solutions will leave anything ahead of the hashtag in as well. And substring does not work if the hashtag is not the first symbol.
variable= "#stringexample".split("#")[1];
This splits the string into an array of strings, with the parameter as the point where to split, without including the parameter itself. There will be an empty string as the first parameter, and everything after the hashtag is the second string.
var slicer = function(somestring){
var parsedString = somestring;
parsedString = parsedString.slice(1);
return parsedString
}
// run from yors function with some string
var someYouVar = slicer("#something")
I have a dynamically formed string like - part1.abc.part2.abc.part3.abc
In this string I want to get the substring based on second to last occurrence of "." so that I can get and part3.abc
Is there any direct method available to get this?
You could use:
'part1.abc.part2.abc.part3.abc'.split('.').splice(-2).join('.'); // 'part3.abc'
You don't need jQuery for this.
Nothing to do with jQuery. You can use a regular expression:
var re = /[^\.]+\.[^\.]+$/;
var match = s.match(re);
if (match) {
alert(match[0]);
}
or
'part1.abc.part2.abc.part3.abc'.match(/[^.]+\.[^.]+$/)[0];
but the first is more robust.
You could also use split and get the last two elements from the resulting array (if they exist).