How to save the graphics drawn using jsDraw2D as a img? - javascript

I am using jsDraw2D javascript library to draw diagrams like circle ,rectangle,line etc.in a div. Now u want to save these graphics whatever i have drawn as a div data , so that i can display it whenever i want . Is that possible ?? or as a image to the some directory? Any help is greatly appreciated
var canvasDiv=document.getElementById("canvas");
var gr=new jsGraphics(canvasDiv);
var penWidth;
var col;
var pen;
var d1,d2;
setPenColor(true);
var point;
var pointDiv;
canvasDiv.onmousemove = getMouseXY;
canvasDiv.onclick=drawPoint;
var mouseX = 0;
var mouseY = 0;
var points=new Array();
//Get mouse position
function getMouseXY(e)
{
if (ie)
{
mouseX = event.clientX + document.body.parentElement.scrollLeft;
mouseY = event.clientY + document.body.parentElement.scrollTop;
} else {
mouseX = e.pageX
mouseY = e.pageY
}
if (mouseX < 0){mouseX = 0}
if (mouseY < 0){mouseY = 0}
mouseX =mouseX - canvasDiv.offsetLeft;
mouseY =mouseY - canvasDiv.offsetTop;
return true;
}
function setPenColor(noAlert)
{
col=new jsColor("blue");
pen=new jsPen(col,1);
if(!noAlert)
{
if(!point)
{
alert("Please click at any location on the blank canvas at left side to plot the point!");
return false;
}
}
return true;
}
function drawPoint() {
pointDiv = gr.fillRectangle(new jsColor("green"),new jsPoint(mouseX-6,mouseY-6),6,6);
point = new jsPoint(mouseX-3,mouseY-3);
}
etc.

Related

JavaScript Magnifying glass

I built a magnifying glass in JavaScript, which works well when I click on it or click and dragging it, but it should not hide from the screen.
$(".menu-left-preview-box-preview").bind('click', function (e) {
window.location = "page" + ($(this).index() + 1) + ".html";
});
var native_width = 0;
var native_height = 0;
var magnifyIsMouseDown = false;
$(".magnify").parent().mousedown(function (e) {
magnifyIsMouseDown = true;
});
$(".magnify").mousemove(function (e) {
if (magnifyIsMouseDown) {
if (!native_width && !native_height) {
var image_object = new Image();
image_object.src = $(".small").attr("src");
native_width = image_object.width;
native_height = image_object.height;
} else {
var magnify_offset = $(this).offset();
var mx = e.pageX - magnify_offset.left;
var my = e.pageY - magnify_offset.top;
if (mx < $(this).width() && my < $(this).height() && mx > 0 && my > 0) {
$(".large").fadeIn(100);
} else {
$(".large").fadeOut(100);
}
if ($(".large").is(":visible")) {
var rx = Math.round(mx / $(".small").width() * native_width - $(".large").width() / 2) * -1;
var ry = Math.round(my / $(".small").height() * native_height - $(".large").height() / 2) * -1;
var bgp = rx + "px " + ry + "px";
var px = mx - $(".large").width() / 2;
var py = my - $(".large").height() / 2;
$(".large").css({ left: px, top: py, backgroundPosition: bgp });
}
}
}
});
$(".magnify").parent().mouseup(function (e) {
magnifyIsMouseDown = false;
$(".large").fadeOut(100);
});
$(".magnify").parent().mouseleave(function (e) {
$(".large").fadeOut(100);
});
manageSlide();
By default the magnifying glass must be there on the screen. The magnifying glass can be dragged and after it's dropped it must remain there at it's dropped position.
On clicking and dragging the magnify glass is working well, but it should not hide from the screen. It should be there on screen.
Provide handle of magnify glass with that circle (in design).
Working example: http://jsfiddle.net/mohsin80/4ww8efx5/
I replaced the if (magnifyIsMouseDown) { by if (isDragging) { and created the following methods:
var isDragging = false;
$(".magnify").parent().mouseup(function(e) {
isDragging = false;
});
$(".magnify").parent().mousedown(function(e) {
isDragging = true;
});
To make a simulated drag event with jQuery.
Here is the fiddle. Hope it helped :)

I am trying to make a drawImage change when mouseover and mouseout

I'm attempting to make it, so that when the mouse is within the boundaries set by var play, it changes image. I used the same method I've used for changing images on click, but mouseover and mouseout don't want to work here.
var play = {
x: 650,
y: 360,
width: 200,
height: 100
}
var playUpButton = new Image();
playUpButton.src = "images/PlayUp.png";
var playDownButton = new Image();
playDownButton.src = "images/PlayDown.png";
var playHovering = false;
thisCanvas.addEventListener('click', checkPlay);
thisCanvas.addEventListener('mouseover', hoverPlay, false);
thisCanvas.addEventListener('mouseout', hoverPlay, false);
function seen_move(e)
{
var bounding_box = thisCanvas.getBoundingClientRect();
mouseX = ((e.clientX-bounding_box.left) *(thisCanvas.width/bounding_box.width));
mouseY = ((e.clientY-bounding_box.top) * (thisCanvas.height/bounding_box.height));
}
function draw_start()
{
context.drawImage(menubg, menubg.x, menubg.y, menubg.width, menubg.height);
if(playHovering)
{
context.drawImage(playDownButton, play.x, play.y, play.width, play.height);
}
}
function mouseInArea(top, right, bottom, left)
{
if(mouseX >= left && mouseX < right && mouseY >= top && mouseY < bottom)
{
return true;
}
else
{
return false;
}
}
function hoverPlay()
{
if(mouseInArea(play.y, play.x + play.width, play.y + play.height, play.x))
{
console.log("Hovering");
if(playHovering)
{
playHovering = false;
}
else
{
playHovering = true;
}
}
}
It looks like the following is missing from your code.
var thisCanvas = document.getElementById("thisCanvas");
The function checkPlay also seems to be missing.
Take a look at these articles:
http://www.html5canvastutorials.com/advanced/html5-canvas-mouse-coordinates/
http://www.informit.com/articles/article.aspx?p=1903884&seqNum=6
You must call function seen_move(e) to get the mouse position.
BTW, I'm confused about what the extra code in seen_move is. I'm guessing you're making the mouse position relative to the bounding box. I just mention it in case that's also a problem:
// this usually get the mouse position
var bounding_box = thisCanvas.getBoundingClientRect();
mouseX = e.clientX-bounding_box.left;
mouseY = e.clientY-bounding_box.top;
// and you have this extra bit:
// *(thisCanvas.width/bounding_box.width)); and
// * (thisCanvas.height/bounding_box.height));
mouseX = ((e.clientX-bounding_box.left) *(thisCanvas.width/bounding_box.width));
mouseY = ((e.clientY-bounding_box.top) * (thisCanvas.height/bounding_box.height));

Removing an Event Listener For Mouse Click

I see other similar questions asked, but the answers don't actually solve the problem.
I have this event listener:
function bigButton(x, y, strTxt, doFunction)
{
var getID = document.getElementById("canvas_1");
if (getID.getContext)
{
var ctx = getID.getContext("2d");
var btnW = 150;
var btnH = 50;
var cx = x - btnW/2;
var cy = y - btnH/2;
var left = cx;
var right = cx + btnW;
var top = cy;
var bottom = cy + btnH;
bbWhite(cx, cy, btnW, btnH, strTxt);
getID.addEventListener("mousemove", function bbAnim(event)
{
var mousePos = getMousePos(getID, event);
var rect = getID.getBoundingClientRect();
var mouseX = mousePos.x;
var mouseY = mousePos.y;
if (mouseX >= left
&& mouseX <= right
&& mouseY >= top
&& mouseY <= bottom)
{
bbBlack(cx, cy, btnW, btnH, strTxt);
}
else
{
bbWhite(cx, cy, btnW, btnH, strTxt);
}
}, false);
getID.addEventListener("click", function bbClick(event)
{
var mousePos = getMousePos(getID, event);
var rect = getID.getBoundingClientRect();
var clickX = mousePos.x;
var clickY = mousePos.y;
if (clickX >= left
&& clickX <= right
&& clickY >= top
&& clickY <= bottom)
{
doFunction();
}
}, false);
}
}
I want to remove it, because once I click it, I want to clear the canvas and do other things. Yet I have to have a named function to remove it. As far as I know I can't have a named listener without losing all the variables used in the anonymous function. How do I have a named listener in this situation? This is one of the very first issues with events that I have come across with learning JavaScript for the canvas. I'm surprised this isn't one of the first things you find in any tutorial.
UPDATE:
I have made it into a named function, but I still have no way to remove it (and the mousemove event) after the button is clicked.
Removing it is pretty much the same as adding it
getID.addEventListener("click", handler, false);
function handler(event) {
this.removeEventListener('click', handler, false);
var mousePos = getMousePos(getID, event);
var rect = getID.getBoundingClientRect();
var clickX = mousePos.x;
var clickY = mousePos.y;
if (clickX >= left
&& clickX <= right
&& clickY >= top
&& clickY <= bottom)
{
doFunction();
}
}
and the event and value of this stays the same wether or not you reference it by name or not.

Pan Svg While dragging elements

I want to achieve 'Panning' in svg while 'dragging' an element in particular direction.
Let say i select an element and start 'dragging' it upward untill it reached top of screen, now my svg should pan upwards automatically, without causing any problem with dragging. how i can achieve this.?
i have made a small mockup of this, where user can select and drag elements. it also contain two button, which cause svg to pan upward and downward. I am achiveing 'Panning' by changing 'ViewBox' of svg. ( i have to use this logic, i cannot use any other solution);
here is the fiddle link : http://jsfiddle.net/9J25r/
Complete Code:-
addEventListener('mousedown', mousedown, false);
var mx, my;
var dx, dy;
var mainsvg = document.getElementById('svg');
var selectedElement;
var eleTx, eleTy;
function getSvgCordinates(event) {
var m = mainsvg.getScreenCTM();
var p = mainsvg.createSVGPoint();
var x, y;
x = event.pageX;
y = event.pageY;
p.x = x;
p.y = y;
p = p.matrixTransform(m.inverse());
x = p.x;
y = p.y;
x = parseFloat(x.toFixed(3));
y = parseFloat(y.toFixed(3));
return {x: x, y: y};
}
function mousedown(event) {
if (event.target.id === 'arrow_t') {
panning('up');
}
else if (event.target.id === 'arrow_b') {
panning('down');
}
else if (event.target.id.split('_')[0] === 'rect') {
selectedElement = event.target;
var translatexy = selectedElement.getAttribute('transform');
translatexy = translatexy.split('(');
translatexy = translatexy[1].split(',');
eleTx = translatexy[0];
translatexy = translatexy[1].split(')');
eleTy = translatexy[0];
eleTx = parseFloat(eleTx);
eleTy = parseFloat(eleTy);
var xy = getSvgCordinates(event);
mx = xy.x;
my = xy.y;
mx = parseFloat(mx);
my = parseFloat(my);
addEventListener('mousemove', drag, false);
addEventListener('mouseup', mouseup, false);
}
}
function drag(event) {
var xy = getSvgCordinates(event);
dx = xy.x - mx;
dy = xy.y - my;
selectedElement.setAttribute('transform', 'translate(' + (eleTx + dx) + ',' + (eleTy + dy) + ')');
}
function mouseup(event) {
removeEventListener('mousemove', drag, false);
removeEventListener('mouseup', mouseup, false);
}
function panning(direction) {
var viewBox = svg.getAttribute('viewBox');
viewBox = viewBox.split(' ');
var y = parseFloat(viewBox[1]);
if (direction === 'up')
{
y+=5;
}
else if (direction === 'down')
{
y-=5;
}
viewBox=viewBox[0]+' '+y+' '+viewBox[2]+' '+viewBox[3];
svg.setAttribute('viewBox',viewBox);
}
here is the fiddle link : http://jsfiddle.net/9J25r/
EDIT:- (UPDATE)
I use the solution of Ian , it works well on the sample, but when i applied it to my original application, it did not work. check the below gif. You can see the 'gap' between mouse pointer and element. how i can remove that? .
This is one way, I've just done it with the Y/vertical for the moment...
You may want to adjust it, so that if the cursor is off the screen it adjusts the viewBox automatically as well, depends how you want it to drag (otherwise you will need to keep wiggling it to kick the drag func in).
var viewBox = svg.getAttribute('viewBox');
viewBoxSplit = viewBox.split(' ');
if( ely < viewBoxSplit[1] ) {
panning('down');
} else if( ely + +event.target.getAttribute('height')> +viewBoxSplit[1] + 300 ) {
panning('up');
}
jsfiddle here

Javascript and AJAX : Floating an image next to the cursor - questions

I have got a javascript code that will make a floating image appear next to the mouse pointer (and through the use of php it shows the image that the mosue is hovering over, but full size because the image on the page itself is sized down a bit). But whilst it is OK if the image is on the left of the page, there is a problem if the image is on the right hand side.
The code:
<script>
var cX = 0; var cY = 0; var rX = 0; var rY = 0;
function UpdateCursorPosition(e){ cX = e.pageX; cY = e.pageY;}
function UpdateCursorPositionDocAll(e){ cX = event.clientX; cY = event.clientY;}
if(document.all) { document.onmousemove = UpdateCursorPositionDocAll; }
else { document.onmousemove = UpdateCursorPosition; }
function AssignPosition(d) {
if(self.pageYOffset) {
rX = self.pageXOffset;
rY = self.pageYOffset;
}
else if(document.documentElement && document.documentElement.scrollTop) {
rX = document.documentElement.scrollLeft;
rY = document.documentElement.scrollTop;
}
else if(document.body) {
rX = document.body.scrollLeft;
rY = document.body.scrollTop;
}
if(document.all) {
cX += rX;
cY += rY;
}
d.style.left = (cX+10) + "px";
d.style.top = (cY+10) + "px";
}
function HideContent(d) {
if(d.length < 1) { return; }
document.getElementById(d).style.display = "none";
}
function ShowContent(d,i) {
if(d.length < 1) { return; }
var dd = document.getElementById(d);
AssignPosition(dd);
dd.style.display = "block";
$(d).setHTML ('<img src="'+i'" />');
}
function ReverseContentDisplay(d) {
if(d.length < 1) { return; }
var dd = document.getElementById(d);
AssignPosition(dd);
if(dd.style.display == "none") { dd.style.display = "block"; }
else { dd.style.display = "none"; }
}
//-->
</script>
Here is a standard image that will trigger the floating content:
<a onmousemove="ShowContent('FloatingImage','image.jpg'); return true;" onmouseover="ShowContent('FloatingImage','image.jpg'); return true;" onmouseout="HideContent('FloatingImage','image.jpg'); return true;" href="javascript:ShowContent('FloatingImage','image.jpg')">standard html</a>
<div
id="FloatingImage"
style="display:none;
position:absolute;
border-style: solid;
background-color: white;
padding: 5px;
z-index:+1">
<img id="MouseImage" name="MouseImage" src="LR-10.jpg" />
</div>
--end code--
.... On its own this is fine and it works. as you can float the mouse over the next thumbnail image and the floating image changes accordingly whilst keeping aspect ratio. BUT if the thumbnail image is on the right hand side, the floating image is off the right hand edge of the screen and cannot be seen: is there any way of placing a 'block' within the JS code so that if the thumbnail image is close to the edge of the content (screen edge or edge of the containing DV layer) than it shows the image on the left hand side of the mouse pointer instead?
Next question: this code works fine if I open the page on its own - BUT my website design will be calling the page to open inside a DIV layer by means of AJAX. This breaks the code and it doesn't work then. This has happened with other scripts I have written: works fine by itself, but put in through an AJAX load request and it fails. How can this be solved?
Thanks.
I've modified your script so that the image will switch to the left when the mouse is too far to the right:
var cX = 0, cY = 0, rX = 0, rY = 0, vW;
function UpdateCursorPosition(e) { cX = e.pageX; cY = e.pageY; }
function UpdateCursorPositionDocAll(e) { cX = event.clientX; cY = event.clientY; }
if (document.all) { document.onmousemove = UpdateCursorPositionDocAll; }
else { document.onmousemove = UpdateCursorPosition; }
function AssignPosition(d) {
if (self.pageYOffset) {
rX = self.pageXOffset;
rY = self.pageYOffset;
} else if (document.documentElement && document.documentElement.scrollTop) {
rX = document.documentElement.scrollLeft;
rY = document.documentElement.scrollTop;
} else if (document.body) {
rX = document.body.scrollLeft;
rY = document.body.scrollTop;
}
if (document.all) {
cX += rX;
cY += rY;
}
var oW = d.offsetWidth;
if (cX + 10 + oW > vW) d.style.left = (cX - 10 - oW) + 'px';
else d.style.left = (cX+10) + 'px';
d.style.top = (cY+10) + 'px';
}
function HideContent(d) {
if (d.length < 1) return;
document.getElementById(d).style.display = 'none';
}
function ShowContent(d,i) {
vW = ViewportWidth();
if (d.length < 1) return;
var dd = document.getElementById(d);
AssignPosition(dd);
dd.style.display = 'block';
document.getElementById(d).innerHTML = '<img src="'+i+'" />';
}
function ReverseContentDisplay(d) {
if (d.length < 1) return;
var dd = document.getElementById(d);
AssignPosition(dd);
dd.style.display = (dd.style.display=='none')? 'block' : 'none';
}
function ViewportWidth() {
if (self.innerWidth) return self.innerWidth;
else if (document.documentElement && document.documentElement.clientWidth)
return document.documentElement.clientWidth;
else if (document.body) return document.body.clientWidth;
}

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