My url looks like this: ://example/example/.com. I want to remove the last slash of the string. My attempt so far (but doesn't work):
.replace(/\/$/g, '');
Can someone help me along?
You have to escape the slash character in a regular expression literal. Capture the characters after the last slash until the end of the string and use in the replacement:
s = s.replace(/\/([^\/]*)$/, '$1');
(You don't need the g flag for this one, as you know that there is never more than one match.)
Demo: http://jsfiddle.net/Guffa/jkn52/
Alternatively, use a poositive look-ahead to match a slash that doesn't have another slash until the end of the string:
s = s.replace(/\/(?=[^\/]*$)/, '');
Demo: http://jsfiddle.net/Guffa/jkn52/2/
var str = "/1/2/3/4/5"
var index = str.lastIndexOf("/");
var newStr = str.substr(0, index ) + str.substr(index + 1);
console.log(newStr);
demo: http://jsfiddle.net/Jn9bm/
It's a little verbose, but it works:
var url = "//example/example/.com";
var slash_position = url.lastIndexOf('/');
url = url.substr(0, slash_position) + url.substr(slash_position+1);
Try This:
var s= someString.replace(/\//g, "");
Related
I have the next problem. I need to remove a part of the string before the first dot in it. I've tried to use split function:
var str = "P001.M003.PO888393";
str = str.split(".").pop();
But the result of str is "PO888393".
I need to remove only the part before the first dot. I want next result: "M003.PO888393".
Someone knows how can I do this? Thanks!
One solution that I can come up with is finding the index of the first period and then extracting the rest of the string from that index+1 using the substring method.
let str = "P001.M003.PO888393";
str = str.substring(str.indexOf('.')+1);
console.log(str)
You can use split and splice function to remove the first entry and use join function to merge the other two strings again as follows:
str = str.split('.').splice(1).join('.');
Result is
M003.PO888393
var str = "P001.M003.PO888393";
str = str.split('.').splice(1).join('.');
console.log(str);
You could use a regular expression with .replace() to match everything from the start of your string up until the first dot ., and replace that with an empty string.
var str = "P001.M003.PO888393";
var res = str.replace(/^[^\.]*\./, '');
console.log(res);
Regex explanation:
^ Match the beginning of the string
[^\.]* match zero or more (*) characters that are not a . character.
\. match a . character
Using these combined matches the first characters in the string include the first ., and replaces it with an empty string ''.
calling replace on the string with regex /^\w+\./g will do it:
let re = /^\w+\./g
let result = "P001.M003.PO888393".replace(re,'')
console.log(result)
where:
\w is word character
+ means one or more times
\. literally .
many way to achieve that:
by using slice function:
let str = "P001.M003.PO888393";
str = str.slice(str.indexOf('.') + 1);
by using substring function
let str = "P001.M003.PO888393";
str = str.substring(str.indexOf('.') + 1);
by using substr function
let str = "P001.M003.PO888393";
str = str.substr(str.indexOf('.') + 1);
and ...
var mystr = '\Data\Dashboard\myfolder\3.jpg';
mystr .replace(/\//g, '//');
It is removing all the slashes when i'm trying to replace. Can anyone tell me how to replace for this particular string.
End solution should be this '/Data/Dashboard/myfolder/3.jpg'
Any help will be appreciated!
Since you have \ in your string which is considered as escape sequence ( You need to escape it ). see console.log
var mystr = '\Data\Dashboard\myfolder\3.jpg';
console.log(mystr)
var mystr1 = '\\Data\\Dashboard\\myfolder\\3.jpg'; // Escaped '/' string
console.log(mystr1)
try with this one
var mystr = '\\Data\\Dashboard\\myfolder\\3.jpg';
var regex = /\\/g;
var replaced = mystr.replace(regex, '/');
console.log(replaced);
You can use the replace function:
str.replace('\\', "/");
Below is my code.
var str = 'test//123_456';
var new_str = str .replace(/\//g, '').replace(/_/g, '');
console.log(new_str);
It will print test123456 on the screen.
My question is how to do it in same regular express? not replace string twice.
Thanks.
Use character class in the regex to match any character in the collection. Although use repetition (+, 1 or more) for replacing // in a single match.
var new_str = str .replace(/[/_]+/g, '');
var str = 'test//123_456';
var new_str = str.replace(/[/_]+/g, '');
console.log(new_str);
FYI : Inside the character class, there is no need to escape the forward slash(in case of Javascript RegExp).
Use the regex to match the list of character by using regex character class.
var str = "test//123_456";
var nstr = str.replace(/[\/_]/g, '');
Need to replace a substring in URL (technically just a string) with javascript.
The string like
http://blah-blah.com/search?par_one=test&par_two=anothertest&SearchableText=TO_REPLACE
or
http://blah-blah.com/search?par_one=test&SearchableText=TO_REPLACE&par_two=anothertest
means, the word to replace can be either at the most end of the URL or in the middle of it.
I am trying to cover these with the following:
var newWord = NEW_SEARCH_TERM;
var str = 'http://blah-blah.com/search?par_one=test&SearchableText=TO_REPLACE&par_two=anothertest';
var regex = /^\S+SearchableText=(.*)&?\S*$/;
str = str.replace(regex, newWord);
But no matter what I do I get str = NEW_SEARCH_TERM. Moreover the regular expression when I try it in RegExhibit, selects the word to replace and everything that follows it that is not what I want.
How can I write a universal expression to cover both cases and make the correct string be saved in the variable?
str.replace(/SearchableText=[^&]*/, 'SearchableText=' + newWord)
The \S+ and \S* in your regex match all non-whitespace characters.
You probably want to remove them and the anchors.
http://jsfiddle.net/mplungjan/ZGbsY/
ClyFish did it while I was fiddling
var url1="http://blah-blah.com/search?par_one=test&par_two=anothertest&SearchableText=TO_REPLACE";
var url2 ="http://blah-blah.com/search?par_one=test&SearchableText=TO_REPLACE&par_two=anothertest"
var newWord = "foo";
function replaceSearch(str,newWord) {
var regex = /SearchableText=[^&]*/;
return str.replace(regex, "SearchableText="+newWord);
}
document.write(replaceSearch(url1,newWord))
document.write('<hr>');
document.write(replaceSearch(url2,newWord))
I have a string which I need to run a replace.
string = replace('/blogs/1/2/all-blogs/','');
The values 1, 2 and all-blogs can change. Is it possible to make them wildcards?
Thanks in advance,
Regards
You can use .* as a placeholder for "zero or more of any character here" or .+ for "one or more of any character here". I'm not 100% sure exactly what you're trying to do, but for instance:
var str = "/blogs/1/2/all-blogs/";
str = str.replace(/\/blogs\/.+\/.+\/.+\//, '');
alert(str); // Alerts "", the string is now blank
But if there's more after or before it:
str = "foo/blogs/1/2/all-blogs/bar";
str = str.replace(/\/blogs\/.+\/.+\/.+\//, '');
alert(str); // Alerts "foobar"
Live example
Note that in both of the above, only the first match will be replaced. If you wanted to replace all matches, add a g like this:
str = str.replace(/\/blogs\/.+\/.+\/.+\//g, '');
// ^-- here
You can read up on JavaScript's regular expressions on MDC.
js> 'www.google.de/blogs/1/2/all-blogs'.replace(/\/blogs\/[^\/]+\/[^\/]+\/[^\/]+\/?/, '');
www.google.de
What about just splitting the string at slashes and just replacing the values?
var myURL = '/blogs/1/2/all-blogs/', fragments, newURL;
fragments = myURL.split('/');
fragments[1] = 3;
fragments[2] = 8;
fragments[3] = 'some-specific-blog';
newURL = fragments.join('/');
That should return:
'/blogs/3/8/some-specific-blog'
Try this
(/.+){4}
escape as appropriate