I have been trying to change the content of a <div> with a JQuery Ajax Call.
But nothing happens when I press the onclick <a> element.
This is my current code that I'm testing with:
Front.php:
<html>
<head>
<script type="text/javascript" src="jquery.js">
function testAjax()
{
$.ajax({
type: "GET",
url: 'Back.php',
data: "id=", // Not using this yet >.<
success: function(data) {
$('#test').html(data);
}
});
}
</script>
</head>
<body><div id="test">HELLO</div>
Change this</body>
</html>
and here is my Back.php:
<?php
echo "test";
?>
Nothing happens when I click on "Change this" however the content in <div id="test"> should change to "test". Can someone help me with what I'm doing wrong? Thanks.
You didn't close your first script tag and open a new one for your inline script.
<script type="text/javascript" src="jquery.js"></script>
<script>
function testAjax()
{
...
You should apply contentType: "html" on it. May be that will help.
Related
I have a JS script that scrapes a bit of data and outputs the result to the screen. That works fine. What I now need to do is wrap that output in some pre and post content php files for formatting purposes, and I can't seem to get it to work.
Here's where the script stands now:
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8"/>
<meta content="width=device-width; initial-scale=1.0; maximum-scale=1.0; user-scalable=0;" name="viewport">
<script src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
<link rel="stylesheet" type="text/css" href="css/main.css">
</head>
<body>
<img id="loading-gif">
<script>
$('#loading-gif').hide();
$(document).ready(function () {
$('#loading-gif').show();
$.ajax({
url: "https://aajumpseat.com/dev/include/pre.content.php'); ?>",
type: 'GET',
dataType:"json",
success: function(data) {
pre = JSON.parse(data);
document.write(pre);
}
});
$.ajax({url: "https://aajumpseat.com/dev/scrape/getSegments.php"}).done(function (data) {
$('#loading-gif').hide();
output = JSON.parse(data);
document.write(output);
});
$.ajax({
url: "https://aajumpseat.com/dev/include/post.content.php'); ?>",
type: 'GET',
dataType:"json",
success: function(data) {
post = JSON.parse(data);
document.write(post);
}
});
});
</script>
</body>
</html>
The second ajax call works perfectly and outputs the result to the screen, which is what I want. What I would like to do is place the contents of pre.content.php before the result and the contents of post.content.php after the result so that the result is properly formatted.
There is some php being executed in 'pre.content.php is addition to the formatting html, while 'post.content.php contains only the closing body and html tags.
If need be, I can hardcode the required html into the above script, but if someone has an elegant, or not so elegant, solution on how to include these two files I'd appreciate it.
Thanks.
There's a function specifically for this called $.load(). It's always better to have a <div> with id and then use .innerHTML instead of using document.write().
$(function () {
$("#stuff").load("/path/to/api/call");
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="stuff"></div>
If you have got multiple calls, that's fine too. Just have multiple containers.
$(function () {
$("#stuff").load("/path/to/api/call");
$("#pre").load("/path/to/api/code");
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div id="stuff"></div>
<pre id="code"></pre>
One thing to note is that, $.load() fires an AJAX GET request.
place the contents of pre.content.php before the result and the contents of post.content.php
Don't use document.write. It gives you no control over where in the document you write anything. Instead, define the elements where you want to write your output:
<div id="pre-output"></div>
<div id="main-output"></div>
<div id="post-output"></div>
Then write your output to those specific locations:
pre = JSON.parse(data);
$('#pre-output').html(pre);
(Or maybe .text(pre)? It's strange to me that you're outputting raw JSON...)
******* SOLUTION *******
My main php has multiple tasks, so for this particular task the PHP is:
$output = " <div id='loading-gif'><img src='images/loading3.gif';></div>
<div id='main-output'></div>
<script>
$('#loading-gif').hide();
$(document).ready(function () {
$('#loading-gif').show();
$.ajax({url: 'https://aajumpseat.com/dev/scrape/getSegments.php'}).done(function (data) {
$('#loading-gif').hide();
output = JSON.parse(data);
//document.write(output);
$('#main-output').html(output);
});
});
</script>
<div class='bottom-border'></div>
";
and further down the page I have:
include('include/pre.content.php');
echo $output;
include('include/post.content.php');
And it is perfect.
I have simple code with html, JavaScript and PHP. I am trying to pass a variable from HTML to PHP through ajax.
A text box appears on screen with button, user inputs in the text field and clicks the button. The field text should appear before the field. But in my case, nothing happens when clicking the button. I am posting my code below. These are the three files I have made:
index.html
<!doctype html>
<html lang="en">
<body>
<input id="name" type="text" /> <input id="button" type="button" value="Load" />
<div id="content"></div>
<script type="text/javascript" src="ajax.js"></script>
</body>
</html>
ajax.js
$('#button').click(function() {
document.write("this is javascript");
var name = $('#name').val();
$.ajax({
url: 'page.php',
data: name,
success: function(data) {
$('#content').html(data);
}
});
});
page.php
<?php
if(isset($_GET['name'])) {
echo "lllllllllllllllll";
echo $name=$_GET['name'];
}
?>
Add CDN as mentioned above. Also make sure you load the jquery CDN or jquery.lib.js before including external js file, ajax.js in index.html.
There is an issue in your $.ajax code:
$.ajax({
url: 'page.php',
data: name,
success: function(data) {
$('#content').html(data);
}
});
change this to:
$.ajax(
{
type:'GET',
url: 'page.php',
data:"name=test"
},
success: function(data) {
$('#content').html(data);
}
);
only add before axaj.js
<script type="text/javascript" src="https://code.jquery.com/jquery-3.3.1.min.js"></script>
add this in your javascript ajax: type : 'GET'.
In your php code :
$name=$_GET['name'];
echo $name;
I have two .cshtml webforms, in one webform I have Bootstrap header and in other webform I have one div containg form. Now I want to implement such thing like when I click any of links available in Header that time Jquery function will be called and it should get desired page and load it into defined div block.
My code is seems as bellow (header.cshtml) :
<html>
<head>
<script type="text/javascript" src="../assest/js/jquery-3.1.1.js"></script>
<script type="text/javascript">
function myFunction(str) {
$(document).ready(function () {
//alert(str);
$.ajax({
type: "GET",
url: str + ".cshtml",
dataType: "html",
success: function (data) {
$("#form_load").html(data);
},
error: function (data) {
alert(data);
}
})
});
}
</script>
</head>
<body>
<div>
<a id="nav_link" onclick="myFunction(this.name)" name="farmer_master">Farmer</a>
</div>
<div id="form_load"></div>
</body>
</html>
other webform (farmer_master.cshtml) :
<div>
Hi I shoud be called !
</div>
I currently have a problem with php and javascript. Here is the thing : I'm trying to edit every few second a text file stored on the server, with the text the client wrote in a textarea (which id is 'area1')
The PHP :
<span id="write">
<?php
if(isset($_POST['text']))
{
file_put_contents('file.txt', $_POST['text']);
}
?>
</span>
The Javascript :
window.onload = function(){
t = setInterval(load, 2000);
function load()
{
$.ajax({
type: "POST",
url: "test.php",
data: {
text: $('#area1').val()
},
dataType: "text",
success: function(data) {
$('#write').load('test.php #write');
}
});
}
}
Nevertheless, nothing is ever written in file.txt, even if we enter the isset condition (that I tested).
Why isn't it working ? Can't we use jquery load with file_put_contents ? Or maybe it is a silly mistake that I can't see...
Thank you !
Have you tried using $.post? It is simpler and clearer.
Below is the full working code.
<html>
<head>
<script src="//code.jquery.com/jquery-2.1.4.min.js"></script>
</head>
<body>
<form>
<textarea id="area1"></textarea>
<textarea id="write"></textarea>
</form>
<script>
$(document).ready(function(){
t = setInterval(load, 2000);
function load()
{
$.post( "test.php", { text: $('#area1').val() })
.done(function( data ) {
$('#write').load('test.php #write');
});
}
});
</script>
</body>
</html>
And also make sure your php script has a privilege to add files.
Use (sudo) chown apache *folder* or similar.
Good luck!
I am trying to send post data to my post data file handler called postinfo.php with jQuery but so far I can make it.
Here is my post.php code:
<HTML>
<head>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
</head>
<script type="text/javscript">
$('#form_id').on('submit', function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "http://www.vemvo.com/test/postinfo.php",
data: $(this).serialize(),
success: function() {
alert('success');
}
});
});
</script>
<form method="post" id="form_id">
<input type="text" name="ime">
<input type="submit" id="submit" name="submit" value="Send">
</form>
You can see the page here: http://www.vemvo.com/test/post.php
Here is the code from my postinfo.php:
<?PHP
$ime = $_POST['ime'];
echo "Your name is $ime";
?>
Here is located postinfo.php - http://www.vemvo.com/test/postinfo.php
So where is my mistake and how I can make it work?
Now it's not sending the data and not giving me the success alert.
Your jQuery selector isn't going to find that form, since the selector is running before the form tag exists in the DOM. Try wrapping it in the jQuery function to wait for the document to be ready:
$(function () {
$('#form_id').on('submit', function(e){
// the rest of your code
});
});
It also might be a good idea to return false at the end, to further suppress the form's default post action:
e.preventDefault();
$.ajax({
type: "POST",
url: "./postinfo.php",
data: $(this).serialize(),
success: function() {
alert('success');
}
});
return false;
Currently the form is posting as normal. Since the AJAX handler is never attached (because the element doesn't exist when the selector executes), it's just doing a normal document-level form post. And since there's no action attribute specified in the form tag, the page is posting to itself by default. Which just responds with the current page.
Edit: You also have a typo which may be preventing the browser from executing your JavaScript code at all:
<script type="text/javscript">
You're missing the second "a". This should be:
<script type="text/javascript">
You MUST spell text/javascript correctly
You need to assign the event handler on load
There should not be any need to return false as posted by some other people here
NEVER call anything submit in a form
Wrap your html in body tags
Use a correct DOCTYPE
For files you can have a look at uploadify or How can I upload files asynchronously?
Fixed code for point 1 to 6
<!DOCTYPE html>
<html>
<head>
<title>Test Ajax</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript">
$(function(){
$('#form_id').on('submit', function(e){
e.preventDefault();
$.ajax({
type: "POST",
url: "./postinfo.php",
data: $(this).serialize(),
success: function() {
alert('success');
}
});
});
});
</script>
</head>
<body>
<form method="post" id="form_id">
<input type="text" name="ime">
<input type="submit" value="Send">
</form>
</body>
</html>