I am currently using the following code to (at least visually) replace the contents of a div, whose id is 'box3' (by hiding the current content and showing the new content) but by making the new content slide into appearance (the old content is just hidden without sliding).
var tabIndex = 1;
function nextButtonClick() {
$("#box3").hide();
$(".tab" + tabIndex).hide();
$(".tab" + (tabIndex + 1)).show();
$("#box3").animate({ width: 'toggle' });
tabIndex++;
}
The problem is that this method makes the new content slide from left to right, whereas I want to slide right to left. I have tried looking around for how to change the slide direction, but nothing seems to work; it normally just makes all content disappear, leaving 'box3# visually empty.
(I am using this code as regular Javascript by the way; it is not within the 'ready' function.)
Can anyone suggest anything? Thanks, Conor.
Related
I'm using a tiny library called '$.scrollTo' to animate a scroll to a div element in my html. at the top of my page I have a fixed navgation bar.
at the end of the animation, I would like to have that div focused (for accessibility). if my div is to large, at the end of the animation, the fact that it gets focus - simply sends it a bit off the screen.
This does not happen with small divs.
here is my code (check jsfiddle below):
$('#buttonid').on("click", function() {
//fixed nav bar height (to compensate when scrolling)
var fixed_navbar_height = $("#navbar-id").height();
//the element to scroll to
var $go_to_selector = $("#topic2");
$.scrollTo($go_to_selector, {
duration: 1000,
offset: -fixed_navbar_height,
onAfter: function() {
//if you comment out this .focus it works as intended.
$go_to_selector.focus();
}
});
});
here is a JSFIDDLE example:
https://jsfiddle.net/dy35obpq/3/
obviously the onAfter messes it up, but i would like both the animation and the focus. Any ideas on how to implement a focus on a large div without letting it change the scroll bar ? suggestions are more than welcome.
Try this.
onAfter: function() {
$go_to_selector.focus();
$(window).scrollTop($($go_to_selector).offset().top - fixed_navbar_height);
}
I have simply added this line in your onAfter callback.
$(window).scrollTop($($go_to_selector).offset().top - fixed_navbar_height);
and it seems to have fixed the problem while still retaining focus. You might want to use css to disable the focus blue highlight.
I made a jsfiddle so you can reproduce the bug:
FIDDLE
I implemented a carousel to display 3 images. There's a current image (the image being displayed) and the other two remain hidden until I click one of the lateral arrows, causing the next image to slide from the side overlaying the (now previous) current image.
I've been 2 hours trying to figure out why there are certain specific 'transitions' in which the animation doesn't seem to work. For example, when clicking the left arrow to pass from the first image to the second and from the second to the third the animation works fine, but when clicking it again, the transition from 3 to 1 doesn't perform the slide animation. When moving in the opposite direction (using the right arrow) only one transition is animated. I think the problem has to do with that if in the click event handler function, but couldn't spot what's causing it.
Any help would be greatly appreciated.
TIA
The underlying issue here is related to the z-order of the three images. Your slide animations are only showing up where the image being slid in is above the displayed image; the "broken" transitions are actually occurring, they're just obscured by the "higher" visible image.
You can fix this by explicitly setting the z-index of the new and current image. For example, on the right transition:
prevLandscape.zIndex(1);
currLandscape.zIndex(0);
If you do this, you'll also need to increase the z-index of the arrows so they're above the images.
Fiddle
jsfiddle
The issue is with the hide method you just simply hide it add the slide transition for the hide method.
change this line currLandscape.hide(); to currLandscape.hide("slide");
there seemed to be a problem with the order of the images also. please try this code out. The code is reuse of the previous image arrow code. Just try it out.
$('.arrowRight').on('click',function(e) {
var currLandscape = $(this).siblings(".currImg");
var nextLandscape = currLandscape.nextAll(".hiddenImg").first();
var currDesc= $(".currDesc");
var nextDesc= currDesc.nextAll(".hiddenDesc").first();
if (nextLandscape.length == 0) {
nextLandscape = currLandscape.siblings('.hiddenImg').first();
}
if (nextDesc.length == 0) {
nextDesc= currDesc.siblings('.hiddenDesc').first();
}
nextLandscape.show("slide", { direction: "right" }, 400, function() {
currLandscape.hide("slide");
});
currDesc.fadeOut().removeClass('currDesc').addClass('hiddenDesc');
nextDesc.fadeIn().removeClass('hiddenDesc').addClass('currDesc');
currLandscape.removeClass('currImg').addClass('hiddenImg');
nextLandscape.removeClass('hiddenImg').addClass('currImg');
});
I do not know how to solve this situation:
I`ve got the html/css looks like this:
Image showing how my css/html looks like and what is displayed on the screen after landing on page:
The when I scroll down I see green element:
scrolling down ->
After continuing to scrolling down I saw full green element and the if I scroll down I want to have this element like in css language: position fixed bottom 0. See image below:
I ve saw full element -> same link but image called problem3.png
and then I scroll below and I want to have it fixed at the bottom of the page, like on this image:
Fixed element on screen - What I want and I do not know how to do that -> same link but image called problem4.png (stupid spam prevention mechanism)
Is it possible to solve this situation ?
To sum up: I`ve got two divs, one above and second below, Wheen I scroll down I suddenly see another element (green div) and when i continue to scroll down I WANT TO HAVE THIS GREEN DIV FIXED AT THE BOTTOM OF THE PAGE.
Ofcourse, when I scroll up (back on the top) I want to "park" that green div at the top of the second div.
Is there any way to solve this situation with jQuery (Javascript) / html / css ?
Thank you in advance
I think you'll have to show some of your html structure. There are lots of ways to achieve this kind of effect. Fundamentally, in javascript terms you'll be looking to:
Add an event listener to the window scroll that checks whether the green element is fully in view
If it is in view, add a class (or change it's css) that fixes it's position where you want
Change your window scroll method so that it's checking the relative offset of the red div to the top of the screen. If it goes below the position where the green div should be fixed, remove the class you added earlier.
That sounds complicated, but it's not too bad. The javascript would be something like:
$(function() {
$(window).scroll(function() {
if($(".divToFix").hasClass("fixedAtBase")){
if(Utils.underView($(".redDiv"), $(".divToFix").height())) $(".divToFix").removeClass("fixedAtBase");
} else {
if(Utils.inView($(".divToFix"))) $(".divToFix").addClass("fixedAtBase");
}
});
});
Utils = {
underView: function(element, offset) {
return (($(window).height() + $(window).scrollTop() - offset) <= element.offset().top);
},
aboveView: function(element) {
return ($(window).scrollTop() >= element.offset().top + element.height());
},
inView: function(element) {
return (Utils.aboveView(element) !== true && Utils.underView(element, element.height()) !== true);
}
};
Bear in mind I've not tested that or anything.
edit - here's a demo
I'm trying to hide a div on click (well i'm trying to slide it to the left), but what it will have to do is also from the main page div swap the background and also i think, swap the width of another div. I've got it swapping the background and removing the things I don't want (although they slide down rather then to the left)
This video shows what happens (and then at the end i use firebug to show you what i want to happen) http://www.youtube.com/watch?v=tti_L_ofelg&feature=youtu.be (edit: video online now)
Here is my html for the sliding div:
The CSS:
.slidingDiv {
}
.show_hide {
display:none;
}
And the jQuery:
var defOpen = 1;
jQuery(".slidingDiv").show();
jQuery(".show_hide").show();
jQuery('.show_hide').click(function(){
if(defOpen == 1)
{
jQuery(".show_hide").show();
jQuery("#bgwrap").css("background","url(assets/stripeclear.png) fixed 0 0 repeat-y")
jQuery("#primary_right").css("width","")
jQuery(".slidingDiv").slideToggle();
defOpen = 0
} else {
jQuery(".show_hide").show();
jQuery("#bgwrap").css("background","url(assets/stripe.png) fixed 0 0 repeat-y")
jQuery(".slidingDiv").slideToggle();
defOpen = 1
}
So it's bgwrap that has the image in it that i have to swap to a clear one (to stop it being there as it's a fixed image on the left)
and primary_right seems to be the one when I remove the width goes full screen (what i'm really trying to acheive)
It also needs to be able to toggle closed and open!
Thanks for any help you can give!
question is not clear..but as far as i understood...you want to hide a left side division by which the right side division occupies full screen and vice versa..is it?????
if yes defOpen variable will not help u..use JQuery toggle function...datz the best way to do it...
I think you need to set the width to "inherit". That's essentially what you're doing when you are selecting the delete style in Firebug.
jQuery("#primary_right").css("width","inherit")
For a site I'm making for myself and a friend, I have a div container/wrapper with 2 other divs within it: one occupies the left half and has a black background and the other occupies the right with a white background. Essentially, this lets me get a split colored background. Each div holds half of a logo. Here's the page, temporarily hosted so you guys can see it.
http://djsbydesign.com/tempsite/index.htm
At any rate, I'd like to have links on the left and right hand sides of the page that, on click, cause their respective divs to expand from 50% to 100%. I have a few ideas, but am not sure entirely how to go about doing this (I'm rather new to javascript). The first would be to have the expanding div's z-index set to something higher than the non-expanding one, and then have it expand (somehow), and the other is to have the expanding div expand to 100% while the other shrinks to 0% at an equal rate.
The bottom line is, I have no idea how to go about doing this. I don't mind using mootools or jQuery, for the record.
The following seems to work:
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
});
Albeit I'm not sure how you'd plan to bring back the the 'other' div.
JS Fiddle demo.
Edited to add a button (via jQuery) that allows both divs to be reverted to original dimensions:
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
});
$('.show').live('click',
function(){
$('#left-bg').animate(
{
'width': '50%'
},600);
$('#right-bg').animate(
{
'width': '50%'
},600);
$(this).remove();
});
Updated JS Fiddle.
Edited to address the question left by OP in the comments:
is there a way to have a page redirect after the animation completes?
Yep, just add the line window.location.href = "http://path.to.url.com/";
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
window.location.href = "http://www.google.com/" // <-- this line redirects.
});
$('.show').live('click',
function(){
$('#left-bg').animate(
{
'width': '50%'
},600);
$('#right-bg').animate(
{
'width': '50%'
},600);
$(this).remove();
});
Updated JS Fiddle.
Edited in response to bug report (in comments):
The one other bug (easy fix) is that any time you click on either of the divs, it creates a new button. So say you clicked on the left half, and it expanded and filled the page, etc., and then you clicked on it again (it being anywhere on the page now). It would attempt to add a second button.
To prevent a second button being added to the div just add an if:
$('#left-bg, #right-bg').click(
function(){
if (!$('.show').length) {
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
window.location.href = "http://www.google.com/" // <-- this line redirects.
}
});
Which, will only append a button, or indeed animate the divs, so long as the $('.show') selector returns no matches.
However if you're also redirecting to another page by clicking the button it shouldn't be an issue anyway, since none of the jQuery on the original page will exectute/be able to access the page to which the user is redirected (unless it's a page on your own domain, and you've explicitly chosen to add the same button).
If you give absolute positions to your div's such that - 1st is positioned at top left corner and other is positioned at top right corner. And then in click event you can change the position of the other top corner of the div to be expanded.
You can use jquery to do this easily. Check jquery documentation for setting css.
Looks like you've got jQuery included, so use that! It's totes the easiest library to do simple animations with.
Here's an example click function that will slide the right background to be 100% like you said:
$('a#link').click(function(e) {
e.preventDefault();
$('#left-bg').animate({ width : '0%' }, 'slow');
$('#right-bg').animate({ width : '100%' }, 'slow');
});
Obviously to go in the other direction you'd switch the width values in the object passed to the animate functions.
If you're not familiar with the animate function, check the docs, but basically you just pass CSS rules in a key : value object to it, and it'll change the CSS values over time - animating it!
Hope this helps!