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I have a text in a textarea and I read it out using the .value attribute.
Now I would like to remove all linebreaks (the character that is produced when you press Enter) from my text now using .replace with a regular expression, but how do I indicate a linebreak in a regex?
If that is not possible, is there another way?
How you'd find a line break varies between operating system encodings. Windows would be \r\n, but Linux just uses \n and Apple uses \r.
I found this in JavaScript line breaks:
someText = someText.replace(/(\r\n|\n|\r)/gm, "");
That should remove all kinds of line breaks.
Line breaks (better: newlines) can be one of Carriage Return (CR, \r, on older Macs), Line Feed (LF, \n, on Unices incl. Linux) or CR followed by LF (\r\n, on WinDOS). (Contrary to another answer, this has nothing to do with character encoding.)
Therefore, the most efficient RegExp literal to match all variants is
/\r?\n|\r/
If you want to match all newlines in a string, use a global match,
/\r?\n|\r/g
respectively. Then proceed with the replace method as suggested in several other answers. (Probably you do not want to remove the newlines, but replace them with other whitespace, for example the space character, so that words remain intact.)
var str = " \n this is a string \n \n \n"
console.log(str);
console.log(str.trim());
String.trim() removes whitespace from the beginning and end of strings... including newlines.
const myString = " \n \n\n Hey! \n I'm a string!!! \n\n";
const trimmedString = myString.trim();
console.log(trimmedString);
// outputs: "Hey! \n I'm a string!!!"
Here's an example fiddle: http://jsfiddle.net/BLs8u/
NOTE! it only trims the beginning and end of the string, not line breaks or whitespace in the middle of the string.
You can use \n in a regex for newlines, and \r for carriage returns.
var str2 = str.replace(/\n|\r/g, "");
Different operating systems use different line endings, with varying mixtures of \n and \r. This regex will replace them all.
The simplest solution would be:
let str = '\t\n\r this \n \t \r is \r a \n test \t \r \n';
str = str.replace(/\s+/g, ' ').trim();
console.log(str); // logs: "this is a test"
.replace() with /\s+/g regexp is changing all groups of white-spaces characters to a single space in the whole string then we .trim() the result to remove all exceeding white-spaces before and after the text.
Are considered as white-spaces characters:
[ \f\n\r\t\v\u00a0\u1680\u2000-\u200a\u2028\u2029\u202f\u205f\u3000\ufeff]
If you want to remove all control characters, including CR and LF, you can use this:
myString.replace(/[^\x20-\x7E]/gmi, "")
It will remove all non-printable characters. This are all characters NOT within the ASCII HEX space 0x20-0x7E. Feel free to modify the HEX range as needed.
This will replace the line break by empty space.
someText = someText.replace(/(\r\n|\n|\r)/gm,"");
Read more on this article.
var str = "bar\r\nbaz\nfoo";
str.replace(/[\r\n]/g, '');
>> "barbazfoo"
To remove new line chars use this:
yourString.replace(/\r?\n?/g, '')
Then you can trim your string to remove leading and trailing spaces:
yourString.trim()
USE THIS FUNCTION BELOW AND MAKE YOUR LIFE EASY
The easiest approach is using regular expressions to detect and replace newlines in the string. In this case, we use replace function along with string to replace with, which in our case is an empty string.
function remove_linebreaks( var message ) {
return message.replace( /[\r\n]+/gm, "" );
}
In the above expression, g and m are for global and multiline flags
I often use this regex for (html) strings inside jsons:
replace(/[\n\r\t\s]+/g, ' ')
The strings come from a html editor of a CMS or a i18n php. The common scenarios are:
- lorem(.,)\nipsum
- lorem(.,)\n ipsum
- lorem(.,)\n
ipsum
- lorem ipsum
- lorem\n\nipsum
- ... many others with mixed whitespaces (\t\s) and even \r
The regex avoids this ugly things:
lorem\nipsum => loremipsum
lorem,\nipsum => lorem,ipsum
lorem,\n\nipsum => lorem, ipsum
...
Surely not for all use cases and not the fastest one, but enough for most textareas and texts for websites or webapps.
The answer provided by PointedEars is everything most of us need. But by following Mathias Bynens's answer, I went on a Wikipedia trip and found this: https://en.wikipedia.org/wiki/Newline.
The following is a drop-in function that implements everything the above Wiki page considers "new line" at the time of this answer.
If something doesn't fit your case, just remove it. Also, if you're looking for performance this might not be it, but for a quick tool that does the job in any case, this should be useful.
// replaces all "new line" characters contained in `someString` with the given `replacementString`
const replaceNewLineChars = ((someString, replacementString = ``) => { // defaults to just removing
const LF = `\u{000a}`; // Line Feed (\n)
const VT = `\u{000b}`; // Vertical Tab
const FF = `\u{000c}`; // Form Feed
const CR = `\u{000d}`; // Carriage Return (\r)
const CRLF = `${CR}${LF}`; // (\r\n)
const NEL = `\u{0085}`; // Next Line
const LS = `\u{2028}`; // Line Separator
const PS = `\u{2029}`; // Paragraph Separator
const lineTerminators = [LF, VT, FF, CR, CRLF, NEL, LS, PS]; // all Unicode `lineTerminators`
let finalString = someString.normalize(`NFD`); // better safe than sorry? Or is it?
for (let lineTerminator of lineTerminators) {
if (finalString.includes(lineTerminator)) { // check if the string contains the current `lineTerminator`
let regex = new RegExp(lineTerminator.normalize(`NFD`), `gu`); // create the `regex` for the current `lineTerminator`
finalString = finalString.replace(regex, replacementString); // perform the replacement
};
};
return finalString.normalize(`NFC`); // return the `finalString` (without any Unicode `lineTerminators`)
});
Simple we can remove new line by using text.replace(/\n/g, " ")
const text = 'Students next year\n GO \n For Trip \n';
console.log("Original : ", text);
var removed_new_line = text.replace(/\n/g, " ");
console.log("New : ", removed_new_line);
A linebreak in regex is \n, so your script would be
var test = 'this\nis\na\ntest\nwith\newlines';
console.log(test.replace(/\n/g, ' '));
I am adding my answer, it is just an addon to the above,
as for me I tried all the /n options and it didn't work, I saw my text is comming from server with double slash so I used this:
var fixedText = yourString.replace(/(\r\n|\n|\r|\\n)/gm, '');
Try the following code. It works on all platforms.
var break_for_winDOS = 'test\r\nwith\r\nline\r\nbreaks';
var break_for_linux = 'test\nwith\nline\nbreaks';
var break_for_older_mac = 'test\rwith\rline\rbreaks';
break_for_winDOS.replace(/(\r?\n|\r)/gm, ' ');
//output
'test with line breaks'
break_for_linux.replace(/(\r?\n|\r)/gm, ' ');
//output
'test with line breaks'
break_for_older_mac.replace(/(\r?\n|\r)/gm, ' ');
// Output
'test with line breaks'
If it happens that you don't need this htm characte   shile using str.replace(/(\r\n|\n|\r)/gm, "") you can use this str.split('\n').join('');
cheers
1st way:
const yourString = 'How are you \n I am fine \n Hah'; // Or textInput, something else
const newStringWithoutLineBreaks = yourString.replace(/(\r\n|\n|\r)/gm, "");
2nd way:
const yourString = 'How are you \n I am fine \n Hah'; // Or textInput, something else
const newStringWithoutLineBreaks = yourString.split('\n').join('');
On mac, just use \n in regexp to match linebreaks. So the code will be string.replace(/\n/g, ''), ps: the g followed means match all instead of just the first.
On windows, it will be \r\n.
This will remove all your newlines, spaces, unnecessary characters
str = '\n \n\n\n\n\n\n\n\n\n\n\n\n \n \n \n \n Books\n \n \n \n \n\n\n'
console.log(str)
var output = str.replace(/\n|\r|\W/g, "");
console.log(output)
'Books'
const text = 'test\nwith\nline\nbreaks'
const textWithoutBreaks = text.split('\n').join(' ')
I have a text in a textarea and I read it out using the .value attribute.
Now I would like to remove all linebreaks (the character that is produced when you press Enter) from my text now using .replace with a regular expression, but how do I indicate a linebreak in a regex?
If that is not possible, is there another way?
How you'd find a line break varies between operating system encodings. Windows would be \r\n, but Linux just uses \n and Apple uses \r.
I found this in JavaScript line breaks:
someText = someText.replace(/(\r\n|\n|\r)/gm, "");
That should remove all kinds of line breaks.
Line breaks (better: newlines) can be one of Carriage Return (CR, \r, on older Macs), Line Feed (LF, \n, on Unices incl. Linux) or CR followed by LF (\r\n, on WinDOS). (Contrary to another answer, this has nothing to do with character encoding.)
Therefore, the most efficient RegExp literal to match all variants is
/\r?\n|\r/
If you want to match all newlines in a string, use a global match,
/\r?\n|\r/g
respectively. Then proceed with the replace method as suggested in several other answers. (Probably you do not want to remove the newlines, but replace them with other whitespace, for example the space character, so that words remain intact.)
var str = " \n this is a string \n \n \n"
console.log(str);
console.log(str.trim());
String.trim() removes whitespace from the beginning and end of strings... including newlines.
const myString = " \n \n\n Hey! \n I'm a string!!! \n\n";
const trimmedString = myString.trim();
console.log(trimmedString);
// outputs: "Hey! \n I'm a string!!!"
Here's an example fiddle: http://jsfiddle.net/BLs8u/
NOTE! it only trims the beginning and end of the string, not line breaks or whitespace in the middle of the string.
You can use \n in a regex for newlines, and \r for carriage returns.
var str2 = str.replace(/\n|\r/g, "");
Different operating systems use different line endings, with varying mixtures of \n and \r. This regex will replace them all.
The simplest solution would be:
let str = '\t\n\r this \n \t \r is \r a \n test \t \r \n';
str = str.replace(/\s+/g, ' ').trim();
console.log(str); // logs: "this is a test"
.replace() with /\s+/g regexp is changing all groups of white-spaces characters to a single space in the whole string then we .trim() the result to remove all exceeding white-spaces before and after the text.
Are considered as white-spaces characters:
[ \f\n\r\t\v\u00a0\u1680\u2000-\u200a\u2028\u2029\u202f\u205f\u3000\ufeff]
If you want to remove all control characters, including CR and LF, you can use this:
myString.replace(/[^\x20-\x7E]/gmi, "")
It will remove all non-printable characters. This are all characters NOT within the ASCII HEX space 0x20-0x7E. Feel free to modify the HEX range as needed.
This will replace the line break by empty space.
someText = someText.replace(/(\r\n|\n|\r)/gm,"");
Read more on this article.
var str = "bar\r\nbaz\nfoo";
str.replace(/[\r\n]/g, '');
>> "barbazfoo"
To remove new line chars use this:
yourString.replace(/\r?\n?/g, '')
Then you can trim your string to remove leading and trailing spaces:
yourString.trim()
USE THIS FUNCTION BELOW AND MAKE YOUR LIFE EASY
The easiest approach is using regular expressions to detect and replace newlines in the string. In this case, we use replace function along with string to replace with, which in our case is an empty string.
function remove_linebreaks( var message ) {
return message.replace( /[\r\n]+/gm, "" );
}
In the above expression, g and m are for global and multiline flags
I often use this regex for (html) strings inside jsons:
replace(/[\n\r\t\s]+/g, ' ')
The strings come from a html editor of a CMS or a i18n php. The common scenarios are:
- lorem(.,)\nipsum
- lorem(.,)\n ipsum
- lorem(.,)\n
ipsum
- lorem ipsum
- lorem\n\nipsum
- ... many others with mixed whitespaces (\t\s) and even \r
The regex avoids this ugly things:
lorem\nipsum => loremipsum
lorem,\nipsum => lorem,ipsum
lorem,\n\nipsum => lorem, ipsum
...
Surely not for all use cases and not the fastest one, but enough for most textareas and texts for websites or webapps.
The answer provided by PointedEars is everything most of us need. But by following Mathias Bynens's answer, I went on a Wikipedia trip and found this: https://en.wikipedia.org/wiki/Newline.
The following is a drop-in function that implements everything the above Wiki page considers "new line" at the time of this answer.
If something doesn't fit your case, just remove it. Also, if you're looking for performance this might not be it, but for a quick tool that does the job in any case, this should be useful.
// replaces all "new line" characters contained in `someString` with the given `replacementString`
const replaceNewLineChars = ((someString, replacementString = ``) => { // defaults to just removing
const LF = `\u{000a}`; // Line Feed (\n)
const VT = `\u{000b}`; // Vertical Tab
const FF = `\u{000c}`; // Form Feed
const CR = `\u{000d}`; // Carriage Return (\r)
const CRLF = `${CR}${LF}`; // (\r\n)
const NEL = `\u{0085}`; // Next Line
const LS = `\u{2028}`; // Line Separator
const PS = `\u{2029}`; // Paragraph Separator
const lineTerminators = [LF, VT, FF, CR, CRLF, NEL, LS, PS]; // all Unicode `lineTerminators`
let finalString = someString.normalize(`NFD`); // better safe than sorry? Or is it?
for (let lineTerminator of lineTerminators) {
if (finalString.includes(lineTerminator)) { // check if the string contains the current `lineTerminator`
let regex = new RegExp(lineTerminator.normalize(`NFD`), `gu`); // create the `regex` for the current `lineTerminator`
finalString = finalString.replace(regex, replacementString); // perform the replacement
};
};
return finalString.normalize(`NFC`); // return the `finalString` (without any Unicode `lineTerminators`)
});
Simple we can remove new line by using text.replace(/\n/g, " ")
const text = 'Students next year\n GO \n For Trip \n';
console.log("Original : ", text);
var removed_new_line = text.replace(/\n/g, " ");
console.log("New : ", removed_new_line);
A linebreak in regex is \n, so your script would be
var test = 'this\nis\na\ntest\nwith\newlines';
console.log(test.replace(/\n/g, ' '));
I am adding my answer, it is just an addon to the above,
as for me I tried all the /n options and it didn't work, I saw my text is comming from server with double slash so I used this:
var fixedText = yourString.replace(/(\r\n|\n|\r|\\n)/gm, '');
Try the following code. It works on all platforms.
var break_for_winDOS = 'test\r\nwith\r\nline\r\nbreaks';
var break_for_linux = 'test\nwith\nline\nbreaks';
var break_for_older_mac = 'test\rwith\rline\rbreaks';
break_for_winDOS.replace(/(\r?\n|\r)/gm, ' ');
//output
'test with line breaks'
break_for_linux.replace(/(\r?\n|\r)/gm, ' ');
//output
'test with line breaks'
break_for_older_mac.replace(/(\r?\n|\r)/gm, ' ');
// Output
'test with line breaks'
If it happens that you don't need this htm characte   shile using str.replace(/(\r\n|\n|\r)/gm, "") you can use this str.split('\n').join('');
cheers
1st way:
const yourString = 'How are you \n I am fine \n Hah'; // Or textInput, something else
const newStringWithoutLineBreaks = yourString.replace(/(\r\n|\n|\r)/gm, "");
2nd way:
const yourString = 'How are you \n I am fine \n Hah'; // Or textInput, something else
const newStringWithoutLineBreaks = yourString.split('\n').join('');
On mac, just use \n in regexp to match linebreaks. So the code will be string.replace(/\n/g, ''), ps: the g followed means match all instead of just the first.
On windows, it will be \r\n.
This will remove all your newlines, spaces, unnecessary characters
str = '\n \n\n\n\n\n\n\n\n\n\n\n\n \n \n \n \n Books\n \n \n \n \n\n\n'
console.log(str)
var output = str.replace(/\n|\r|\W/g, "");
console.log(output)
'Books'
const text = 'test\nwith\nline\nbreaks'
const textWithoutBreaks = text.split('\n').join(' ')
I have two html text input, out of that what ever user type in first text box that need to reflect on second text box while reflecting it should replace all spaces to semicolon. I did to some extant and it replacing for first space not for all, I think I need to use .each function of Jquery, I have used .each function but I didn't get the result see this
HTML :
Title : <input type="text" id="title"><br/>
Keyword : <input type="text" id="keyword">
Jquery:
$('#title').keyup(function() {
var replaceSpace = $(this).val();
var result = replaceSpace.replace(" ", ";");
$("#keyword").val(result);
});
Thanks.
var result = replaceSpace.replace(/ /g, ";");
Here, / /g is a regex (regular expression). The flag g means global. It causes all matches to be replaced.
Pure Javascript, without regular expression:
var result = replaceSpacesText.split(" ").join("");
takes care of multiple white spaces and replaces it for a single character
myString.replace(/\s+/g, "-")
http://jsfiddle.net/aC5ZW/340/
VERY EASY:
just use this to replace all white spaces with -:
myString.replace(/ /g,"-")
Simple code for replace all spaces
var str = 'How are you';
var replaced = str.split(' ').join('');
Out put:
Howareyou
$('#title').keyup(function () {
var replaceSpace = $(this).val();
var result = replaceSpace.replace(/\s/g, ";");
$("#keyword").val(result);
});
Since the javascript replace function do not replace 'all', we can make use the regular expression for replacement. As per your need we have to replace all space ie the \s in your string globally. The g character after the regular expressions represents the global replacement. The seond parameter will be the replacement character ie the semicolon.
I came across this as well, for me this has worked (covers most browsers):
myString.replace(/[\s\uFEFF\xA0]/g, ';');
Inspired by this trim polyfill after hitting some bumps:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/trim#Polyfill
You can do the following fix for removing Whitespaces with trim and # symbol:
var result = string.replace(/ /g, ''); // Remove whitespaces with trimmed value
var result = string.replace(/ /g, '#'); // Remove whitespaces with *#* symbol
I have strings with extra whitespace characters. Each time there's more than one whitespace, I'd like it be only one. How can I do this using JavaScript?
Something like this:
var s = " a b c ";
console.log(
s.replace(/\s+/g, ' ')
)
You can augment String to implement these behaviors as methods, as in:
String.prototype.killWhiteSpace = function() {
return this.replace(/\s/g, '');
};
String.prototype.reduceWhiteSpace = function() {
return this.replace(/\s+/g, ' ');
};
This now enables you to use the following elegant forms to produce the strings you want:
"Get rid of my whitespaces.".killWhiteSpace();
"Get rid of my extra whitespaces".reduceWhiteSpace();
Here's a non-regex solution (just for fun):
var s = ' a b word word. word, wordword word ';
// with ES5:
s = s.split(' ').filter(function(n){ return n != '' }).join(' ');
console.log(s); // "a b word word. word, wordword word"
// or ES2015:
s = s.split(' ').filter(n => n).join(' ');
console.log(s); // "a b word word. word, wordword word"
Can even substitute filter(n => n) with .filter(String)
It splits the string by whitespaces, remove them all empty array items from the array (the ones which were more than a single space), and joins all the words again into a string, with a single whitespace in between them.
using a regular expression with the replace function does the trick:
string.replace(/\s/g, "")
I presume you're looking to strip spaces from the beginning and/or end of the string (rather than removing all spaces?
If that's the case, you'll need a regex like this:
mystring = mystring.replace(/(^\s+|\s+$)/g,' ');
This will remove all spaces from the beginning or end of the string. If you only want to trim spaces from the end, then the regex would look like this instead:
mystring = mystring.replace(/\s+$/g,' ');
Hope that helps.
jQuery.trim() works well.
http://api.jquery.com/jQuery.trim/
I know I should not necromancy on a subject, but given the details of the question, I usually expand it to mean:
I want to replace multiple occurences of whitespace inside the string with a single space
...and... I do not want whitespaces in the beginnin or end of the string (trim)
For this, I use code like this (the parenthesis on the first regexp are there just in order to make the code a bit more readable ... regexps can be a pain unless you are familiar with them):
s = s.replace(/^(\s*)|(\s*)$/g, '').replace(/\s+/g, ' ');
The reason this works is that the methods on String-object return a string object on which you can invoke another method (just like jQuery & some other libraries). Much more compact way to code if you want to execute multiple methods on a single object in succession.
var x = " Test Test Test ".split(" ").join("");
alert(x);
Try this.
var string = " string 1";
string = string.trim().replace(/\s+/g, ' ');
the result will be
string 1
What happened here is that it will trim the outside spaces first using trim() then trim the inside spaces using .replace(/\s+/g, ' ').
How about this one?
"my test string \t\t with crazy stuff is cool ".replace(/\s{2,9999}|\t/g, ' ')
outputs "my test string with crazy stuff is cool "
This one gets rid of any tabs as well
If you want to restrict user to give blank space in the name just create a if statement and give the condition. like I did:
$j('#fragment_key').bind({
keypress: function(e){
var key = e.keyCode;
var character = String.fromCharCode(key);
if(character.match( /[' ']/)) {
alert("Blank space is not allowed in the Name");
return false;
}
}
});
create a JQuery function .
this is key press event.
Initialize a variable.
Give condition to match the character
show a alert message for your matched condition.
Okay I have a simple Javascript problem, and I hope some of you are eager to help me. I realize it's not very difficult but I've been working whole day and just can't get my head around it.
Here it goes: I have a sentence in a Textfield form and I need to reprint the content of a sentence but WITHOUT spaces.
For example: "My name is Slavisha" The result: "MynameisSlavisha"
Thank you
You can replace all whitespace characters:
var str = "My name is Slavisha" ;
str = str.replace(/\s+/g, ""); // "MynameisSlavisha"
The /\s+/g regex will match any whitespace character, the g flag is necessary to replace all the occurrences on your string.
Also, as you can see, we need to reassign the str variable because Strings are immutable -they can't really change-.
Another way to do it:
var str = 'My name is Slavisha'.split(' ').join('');