In my code i am trying to hide a div element which contains a image, but when i run the code i get - ReferenceError: jQuery is not defined
})( jQuery ); in the file jquery-ui.js (line 314). My code is given below
<!DOCTYPE html>
<html>
<head>
<title>Sliding a div</title>
<script type="text/javascript" src="plugin/ui/jquery-ui.js"></script>
<script type="text/javascript" src="plugin/jquery-1.9.1.js"></script>
<script type="text/javascript">
$(document).ready(function(){
$('#1').click(function(){
console.log("i am inside");
$('#element').hide('slide',{direction:'left'},1000);
});
});
</script>
</head>
<body>
<div id="headder" style="width: 1300px; height: 100px">
<h1>Slide the div</h1>
</div>
<div id="element" style="width: 600px; height: 400px; border: 2px solid red; position: relative">
<img src="images/aa.jpg" width="600" height="400">
</div>
<div id="control" style="position: relative">
<input type="button" id="1" value="PRESS">
</div>
</body>
</html>
Please let me know the reason behind this.
You need to reference jQuery before jQuery UI:
<script type="text/javascript" src="plugin/jquery-1.9.1.js"></script>
<script type="text/javascript" src="plugin/ui/jquery-ui.js"></script>
Related
I have a finished JQuery for moving a 360° object (picture) with mouse actions.
The code is working:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>jQuery j360 Plugin Demo</title>
<script src="js/jquery-1.4.4.min.js"></script>
<script type="text/javascript" src="js/j360.js" ></script>
</head>
<body>
<div class="jquery-script-clear"></div>
<h1 style="margin-top: 150px;">jQuery j360 Plugin Demo</h1>
<script type="text/javascript">
jQuery(document).ready(function() {
jQuery('#product').j360();
});
</script>
<center>
<div id="product" style="width: 1920px; height: 1080px; overflow: hidden;">
<img src="v/1.png" />
<img src="v/2.png" />
<img src="v/3.png" />
<img src="v/4.png" />
<img src="v/5.png" />
</div>
</center>
</body>
</html>
The needed pictures are received on demand from a server, so I have to create this code on demand after receiving the pictures. I use therefore document.write commands - I know they are not best practice, but usually it works ... Anyway this is the code I use - basically the same (even when I'm debugging I can't find a difference in the created HTML to the "original" HTML)
So basically it's like that:
<button id="click1" onclick="myFunction()">click me</button>
<script>
function myFunction() {
document.writeln('<html>');
document.writeln('<head>');
document.writeln('<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">');
document.writeln('<title>jQuery j360 Plugin Demo</title>');
document.write('<scr');
document.write('ipt src="js/jquery-1.4.4.min.js"></scr');
document.write('ipt>');
document.write('<scr');
document.write('ipt type="text/javascr');
document.write('ipt" src="js/j360.js" ></scr');
document.writeln('ipt>');
document.writeln('</head>');
document.writeln('<body>');
document.writeln('<div class="jquery-script-clear"></div>');
document.write('<scr');
document.writeln('ipt type="text/javascript">');
document.write(' jQuery(document).ready(func');
document.writeln('tion() {');
document.write(" jQuery('");
document.write('#');
document.writeln("product').j360();");
document.writeln(' });');
document.write('</scr');
document.writeln('ipt>');
document.writeln('<center>');
document.writeln('<div id="product" style="width: 960px; height: 540px; overflow: hidden;">');
document.write('<img src="images/01.jpg" />');
document.write('<img src="images/02.jpg" />');
document.write('<img src="images/03.jpg" />');
document.writeln('</div>');
document.writeln('</center>');
document.writeln('</body>');
document.writeln('</html>');
}
</script>
The created HTML shows the picture but the jQuery plugin is not working. The JS are the same.
Thank for your help!
document.write overwrites any code you have.
Example:
function overwrite() {
document.write("Oops, I've overwritten the code!");
}
<!doctype html>
<html>
<body>
<h1>This is a heading</h1>
<p>This is a paragraph</p>
<button onclick="overwrite()">Click me!</button>
</body>
</html>
Well i'm new to html/js scripting but i'm working on a project and i want to using hyperlink to show/hide divs
for example if i click on first hyperlink it should show div id:1 only and if i click on second hyperlink it should show 2nd div only.
i managed to find an example of what i need on internet but i have no idea,why whatever i try it doesnot work for me
an example of what i need - my fiddle
and this is my code
<!DOCTYPE html>
<html>
<head>
<style>
#myDIV {
width: 100%;
padding: 50px 0;
text-align: center;
background-color: lightblue;
margin-top:20px;
}
</style>
</head>
<body>
<body>
Click a button to make it visible:<br /><br />
One
Two
Three
Four<br /><br />
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<div id="four">Four</div><br/><br/>
</body>
<script>
$("div").hide();
// Show chosen div, and hide all others
$("a").click(function (e)
{
//e.preventDefault();
$("#" + $(this).attr("class")).show().siblings('div').hide();
});
</script>
</body>
</html>
so you ned to include JQuery that's what $() is.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<!DOCTYPE html>
<html>
<head>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<style>
#myDIV {
width: 100%;
padding: 50px 0;
text-align: center;
background-color: lightblue;
margin-top:20px;
}
</style>
</head>
<body>
<body>
Click a button to make it visible:<br /><br />
One
Two
Three
Four<br /><br />
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<div id="four">Four</div><br/><br/>
</body>
<script>
$("div").hide();
// Show chosen div, and hide all others
$("a").click(function (e)
{
//e.preventDefault();
$("#" + $(this).attr("class")).show().siblings('div').hide();
});
</script>
</body>
</html>
It is Working For me on JSFIDDLE. Add jquery library on your local project.
add This on your Head Tag
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
you forget to include $ jquery in you script tag
<!DOCTYPE html>
<html>
<head>
<style>
#myDIV {
width: 100%;
padding: 50px 0;
text-align: center;
background-color: lightblue;
margin-top:20px;
}
</style>
</head>
<body>
<body>
Click a button to make it visible:<br /><br />
One
Two
Three
Four<br /><br />
<div id="one">One</div>
<div id="two">Two</div>
<div id="three">Three</div>
<div id="four">Four</div><br/><br/>
</body>
<script
src="https://code.jquery.com/jquery-1.12.4.min.js"
integrity="sha256-ZosEbRLbNQzLpnKIkEdrPv7lOy9C27hHQ+Xp8a4MxAQ="
crossorigin="anonymous"></script>
<script>
$("div").hide();
// Show chosen div, and hide all others
$("a").click(function (e)
{
//e.preventDefault();
$("#" + $(this).attr("class")).show().siblings('div').hide();
});
</script>
</body>
</html>
You should add jquery in your project.
You can use a CDN
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
OR
you can include your own copy of library in project.
<script src="path/jquery.min.js"></script>
Probably super-basic question, but, why do the text on the first div of the table goes down when raphael creates its paper?
<!DOCTYPE HTML>
<html>
<head>
<script type="text/javascript" src="../js/jquery-1.8.3.js"></script>
<script type="text/javascript" src="../js/raphael-min.js"></script>
<script type="text/javascript">
$(document).ready(function() {
raph = new Raphael('canvas_container', 600, 600);
});
</script>
<title>Simple JS Page</title>
</head>
<body>
<br>
<div style="width: 100%; display: table;">
<div style="display: table-row">
<div id="text_container" style="height:600px;width:300px;border: 8px solid #f7f7f7;display:table-cell;-webkit-border-radius:8px;-moz-border-radius:8px;border-radius:8px;vertical-align:text-top;">
why am I in the bottom???
</div>
<div id="separator" style="height:600px;width:10px;display:table-cell">
</div>
<div id="canvas_container" style="height:600px;width:600px;border: 8px solid #f7f7f7;display: table-cell;-webkit-border-radius:8px;-moz-border-radius:8px;border-radius:8px;">
</div>
</div>
</div>
</body>
</html>
All of the table-imitation css is getting in the way. It looks like you are trying to create two vertical divs, one 300px wide the other 600px wide, with a 10px separator. The same thing can be accomplished using floating, and it plays a little nicer with Raphael.
#text_container, #separator, #canvas_container{
float: left;
}
Fiddle: http://jsfiddle.net/q0aka3s6/
Im trying to implement a simple plugin that resize image based on a container.
The problem is , I don't understand why it's not resizing my image when I placed it inside a container
This is the simple plugin demo page i'm trying to replicate
https://dl.dropboxusercontent.com/u/6983010/wserv/imgLiquid/examples/imgLiquid.html
This is my Code
<html>
<head>
<link rel="stylesheet" href="css/float.css">
<script type = "text/javascript" src ="http://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"></script>
<script type = "text/javascript" src ="https://raw.github.com/karacas/imgLiquid/master/src/js/imgLiquid-min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$(".imgLiquidFill").imgLiquid({fill:true, fadeInTime:500});
$(".imgLiquidNoFill").imgLiquid({fill:false});
});
</script>
</head>
<body>
<div class="container" >
<img src="Creek.jpg"/></div>
</div>
</body>
</html>
My CSS
.container {height: 440px; width: 950px; background:#FFFFFF}
<html>
<head>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" />
<title>Image</title>
<style>
.container{
background-color:#f7f7f7;
border:2px solid #ccc;
margin:10px;
display:inline-block;
}
.imgLiquid {
display:block;
overflow: hidden;
background:transparent url('http://www.lotienes.com/imagenes/loading.gif') no-repeat center center;
}
.imgLiquid img{
visibility:hidden;
}
</style>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js"
type="text/javascript"></script>
<script type="text/javascript"
src="https://raw.github.com/karacas/imgLiquid/master/src/js/imgLiquid-min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$(".imgLiquidFill").imgLiquid({
fill: true,
fadeInTime:200,
horizontalAlign: "center",
verticalAlign: "top"
});
});
</script>
</head>
<body>
<div class="container">
<span class="imgLiquidFill imgLiquid" style="width:250px; height:250px;">
<a href="/media/Woody.jpg" target="_blank" title="test">
<img alt="" src="/media/Woody.jpg"/>
</a>
</span>
</div>
</body>
</html>
Your changing the codes and you forgot to define the imgLiquidFill and imgLiquid in the class which is very important to make this plugin effective. In modifying the codes make sure you didn't forgot anything. Another thing is you can rename the class but make sure you also rename it in the script to make it the same.
Thanks ALOT guys! I've got it working now, thank you!
I have a hopefully easy question:
This: http://jsfiddle.net/gSAjV/2/
is what I want to achieve, but I can't seem to get it working.
I'm all new to javascript, so I'm not sure how to properly put the script in the html document.
I have tried the <script type="text/javascript"> and others, but it just doesn't work.
So i wondered if anyone would take the time to put it in a html document and get it working, and ofcourse posting the entire code. I would be very greatfull!
my doc:
<html>
<head>
<style>
.parentDiv{
border:1px solid black;
padding:10px;
width: 80px;
margin:5px;
display:relative;
}
.childDiv{
border:1px solid blue;
height: 50px;
margin:10px;
}
</style>
<script type='text/javascript'>
$('.childDiv').click(function(){
$(this)
.css('background-color','#00ff66')
.siblings()
.css('background-color','#ffffff');
});
</script>
</head>
<body>
<div id="divParent1" class="parentDiv">
Group 1
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
<div id="divParent2" class="parentDiv">
Group 2
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
</body>
</html>
Put this somewhere in your html file:
<script type="text/javascript">
$(document).ready(function() {
$('.childDiv').click(function(){
$(this).parent().find('.childDiv').css('background-color','#ffffff');
$(this).css('background-color','#ff0000');
});
});
</script>
You can put it more or less anywhere, but just before the </body> tag would be a good place.
And as #MarkK has rightly pointed out, you need to reference the jQuery library itself.
This goes between <head> and </head>:
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
In jsfiddle, you can right-click on the Results pane and View Source. This will give you the exact html that produces the result.
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=UTF-8">
<title> - jsFiddle demo</title>
<script type='text/javascript' src='http://code.jquery.com/jquery-1.4.4.min.js'></script>
<link rel="stylesheet" type="text/css" href="/css/normalize.css">
<link rel="stylesheet" type="text/css" href="/css/result-light.css">
<style type='text/css'>
.parentDiv{
border:1px solid black;
padding:10px;
width: 80px;
margin:5px;
display:relative;
}
.childDiv{
border:1px solid blue;
height: 50px;
margin:10px;
}
</style>
<script type='text/javascript'>//<![CDATA[
$(window).load(function(){
$('.childDiv').click(function(){
$(this).parent().find('.childDiv').css('background-color','#ffffff');
$(this).css('background-color','#ff0000');
});
});//]]>
</script>
</head>
<body>
<div id="divParent1" class="parentDiv">
Group 1
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
<div id="divParent2" class="parentDiv">
Group 2
<div id="child1" class="childDiv">
Child 1
</div>
<div id="child2" class="childDiv">
Child 2
</div>
</div>
</body>
</html>
You just need to import jQuery (the library that contains the $ functions). This is simple, just add
<script src="http.//ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
to your HTML, before your other script.
<html>
<head>
<!--inclue jquery - change the path 'src'. the default is jquery.js is on the same location of this html-->
<script type="text/javascript" src="jquery.js"></script>
<sript type="text/javascript">
jQuery().ready(function($){
$('.childDiv').click(function(){
$(this).parent().find('.childDiv').css('background-color','#ffffff');
$(this).css('background-color','#ff0000');
});
});
</script>
</head>
<body>
<!--the content paste your html here-->
</body>
</html>