I am trying to create a carousel, where clicking on any element will slide it leftwards, simultaneously sliding the right element into viewport. For that, I need to have the divs stacked side by side. I am trying it out as a float based layout (see Fiddle ).
Problem is that here clicking the red colored div slides it leftward alright, but not the green element leftwards. This is probably due to the fact that they are actually lying below another, as visible when the overflow: hidden is removed from #cont's style. How elese to stack them side by side so that sliding one leftward automatically slides the next one leftwards as well? (Creating the to-be-next element on the fly while clicking and animating it into viewport is a no-no, the element should be present in the DOM!)
I'd suggest you use a plugin, as there is more to this than you may realize. There are many plugins out there for this, here's a list to get you started: http://www.tripwiremagazine.com/2012/12/jquery-carousel.html
I modified your Javascript, HTML, and CSS to get you pointed in the right direction:
http://jsfiddle.net/nf5Dh/2/
You need a container contContent, positioned absolutely, and that container gets moved within the container div. You just float the elements in contContent to get them next to each other.
HTML:
<div id='cont'>
<div id="contContent">
<div id='i1'></div>
<div id='i2'></div>
<div id='i3'></div>
</div>
</div>
CSS:
#cont {
width: 50px;
padding-top: 10px;
background: blue;
height: 50px;
overflow: hidden;
position: relative;
}
#contContent {
height: 50px;
width: 150px;
position: absolute;
top: 0;
left: 0;
}
#contContent > div {
float: left;
display: inline-block;
height: 50px;
width: 50px;
}
#i1 { background: red; }
#i2 { background: green; }
#i3 { background: yellow; }
And the JS:
$("#contContent > div").click(function(){
$("#contContent").animate({left: "-=50px"},1000);
});
You'd probably be better off using an ul instead of all divs, this is at least more semantically correct, though not technically necessary.
<div id="carousel">
<ul id="carouselContent">
<li id="slide1"></li>
<li id="slide2"></li>
<li id="slide3"></li>
</ul>
</div>
This:
#cont {
white-space:nowrap;
overflow: hidden;
}
.pane { // or whatever the slide divs are called. get rid of the float.
float: none;
display: inline-block;
*zoom:1;
*display:inline;
}
You can use that carousel where you can generate javascript for the carousel http://caroufredsel.dev7studios.com/configuration-robot.php
I've used http://sorgalla.com/jcarousel/ for things like this in the past, that's based on postion: relative and left/right offsets. Probably easier than messing with floats.
You can try using a list item instead, and display them inline.
Related
The problem:
I have a form with a button underneath it to submit (post) from data with jQuery ajax(). I want for the button to be replaced with a spinner (animated png) for the duration of server ajax call. But such a trivial task is impossible in css to do right.
What i have tried:
I have placed button and image inside a bootstrap row. Ox ajax call I have set button display to none and img display to block. But because this two are not of the same size makes the whole page flicker, breaks the positioning of other elements and so on.
Another idea was to try to place both elements on top of each other with absolute positioning. But, stupid as css is I cannot center it on the middle of the row.
Is there a way to position both elements on top of each other so I can control their visibility?
Please bear in mind that I cannot used absolute position in pixel, because this is a web page and I do not not how wide the browser will be, image can change in the future, text in the button can change in the future, all this things affect absolute size.
If there is another solution to my problem which would prevent the page from jumping up and down it would also be great.
EDIT
Link to one of fiddle experiments:
https://jsfiddle.net/ofb2qdt8/
.button {
position: relative;
margin: auto;
height: 50px;
width: 30px;
background: blue;
z-index: 1;
display: block;
}
.spinner {
position: relative;
margin: auto;
height: 30px;
width: 50px;
background:red;
z-index: 2;
}
This renders second element underneath on screen. Not on different z layer.
Experiment 2:
https://jsfiddle.net/ofb2qdt8/
.button {
position: absolute;
margin: auto;
height: 50px;
width: 30px;
background: blue;
z-index: 1;
display: block;
}
.spinner {
position: absolute;
margin: auto;
height: 30px;
width: 50px;
background:red;
z-index: 2;
}
This does not center both elements, and they are pushed to the top of the containing div. The element with less height should be centered.
Check this working demo: https://jsfiddle.net/ofb2qdt8/3/
Add in a few lines of jquery and update your css.
Position your loading div according to button div's position, width, height using jquery.
*Click the button to see loading div, and try to play the margin of the button to any pixel.
###JQUERY
$(document).ready(function () {
$('.c2').each(function () {
$(this).css({
'width': $(this).siblings('.c1').outerWidth(),
'height': $(this).siblings('.c1').outerHeight(),
'top': $(this).siblings('.c1').offset().top,
'left': $(this).siblings('.c1').offset().left
});
});
$('.c2').on('click', function () {
$(this).hide(0);
});
});
###CSS
.c1 {
margin: 100px auto;
width: 100px;
text-align: center;
padding: 5px 10px;
background: blue;
z-index: 1;
}
.c2 {
position: fixed;
text-align: center;
background: red;
z-index: 2;
cursor: pointer;
}
Rough, ready and untested:
HTML
<div>
<input type='submit' />
<img src="spinneyIMage.gif" />
</div>
CSS
div{ text-align: center; }
div img{ display: none; }
jQuery
$('submit').click(function(e){
e.preventDefault();
$(this).hide().next().show();
});
After the Ajax call completes reverse the above jQuery.
As I haven't been able to find a working solution I have reverted to my first idea which I discarded at first. Albeit with a little twist.
HTML
<div class="row>
<div id="container-button" class="col-xs-12>
<button id="button" onclick="button_OnClick(e)">submit form via ajax</button>
<img src="img/spinner.png" sytle="display: none" />
</div>
</div>
JS
function btnContact_OnClick() {
// show the soinner and hide the button
showSpinner();
$.ajax(
{
type: 'POST',
url: "someurl.com/target",
data: $("#form").serialize(),
dataType: "json",
complete: function() { hideSpinner();},
success: onAjaxSuccess,
error : onAjaxError
});
}
function hideSpinner() {
$("#spinner").hide();
$("#button").show();
// make container height non-fixed and content adjustable again
$("#container-button").height('auto');
}
function showSpinner() {
// THis is the trick !!!
// Make the container fixed height as it was before displaying spinner, so it does not change with content (spinner is not the same height as button
$("#container-button").height($("#container-button").height());
$("#button").hide();
$("#spinner").show();
}
This is not the perfect solution but the best I could make.
Drawbacks:
it is not clean, you have to use javasript to fix what is css layout
problem
it still causes a little flicker
the height of container while displaying spinner is dependant on button, this may cause clipping if spinner is too big
I want to implement a button that adds a X number of elements next to each other (horizontally), but lets say everything should look centered, so the first div should appear in the middle, but if I clic again, the second div should appear next to the first one, but they both must look equally centered, and so on.
I really don't know if I explained myself and thanks in advance.
Center-align the container of the divs, and display the divs inline.
$('.newDiv').on('click', function() {
$('.container').append('<div class="test">test</div>');
});
.container {
height: 30px;
width: 100%;
background: aqua;
text-align: center;
}
.test {
display: inline;
background: gold;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<a class="newDiv" href="#">add div</a>
<div class="container"></div>
I want to have a long page, with a fixed top 100px div, and a fixed 50px bottom div. However, I want the bottom div to scroll as you scroll down the page.
Its hard to explain, but the best example of this is on the front page of PayPal.com
On the first page load, the bottom div looks like it is fixed, and as you adjust the height of the browser window, that div stays at the bottom. Yet as you scroll down the page it is not fixed.
Can anyone explain how they have done this? I am trying to re-create something similar, but cant see how they have managed it.
As far as I can see they have this html...
<div id="fixed-top">
<header class="table-row">
// header content
</header>
<div class="table-row table-row-two">
// Video content
</div>
<div class="table-row">
//bottom content
</div>
</div>
And this CSS...
#fixed-top {
height: 100%;
width: 100%;
display: table;
position: relative;
top: 0;
left: 0;
z-index: 1;
}
.table-row {
display: table-row;
}
But that alone doesn't do it. I also can't see any js thats getting window height and applying it to the main fixed div.
Help! :)
EDIT:
Have just found a way to do it with javascript, controlling the height of the middle row using the window height, minus the 150px for the header and third row.
jQuery(document).ready(function(){
$('div.table-row-two').css({'height':(($(window).height())-150)+'px'});
$(window).resize(function(){
$('div.table-row-two').css({'height':(($(window).height())-150)+'px'});
});
});
But saying that, Zwords CSS only method seems like a winner.
From what I understand, you are looking for something like a sticky footer. So basically if the content is not enough, the footer should go sit at the bottom like its fixed, but if content comes in, it should scroll down like other content.
Try this - http://css-tricks.com/snippets/css/sticky-footer/
First off, you'll need to set the height of the body and html tag, otherwise the table won't take the full screen. Then I altered your code, made it a bit easier.
HTML:
<div id="fixed-top">
<header>
// header content
</header>
<div>
// Video content
</div>
<div>
//bottom content
</div>
</div>
CSS:
html, body {
margin: 0;
padding: 0;
height: 100%;
min-height: 100%;
}
#fixed-top {
display: table;
width: 100%;
height: 100%;
}
#fixed-top > * { /* makes all the direct children of #fixed-top a table row*/
display: table-row;
background: lightblue;
}
#fixed-top > *:nth-child(1) {
background: lightgreen;
height: 40px;
}
#fixed-top > *:nth-child(3) {
background: lightgreen;
height: 25%;
}
You can either set the height to a fix height (in px) or percentages. If you only give two of the three rows a height, the third one will automaticly fill up the rest space.
Also, check this demo.
Check this fiddle / Fullscreen
Using display:table;,display:table-row;,min-height to adjust to screen
HTML
<div class="wrapper">
<div class="row">menu</div>
<div class="row">content</div>
<div class="row">footer</div>
</div>
<div class="wrapper">
<div class="row">content1</div>
<div class="row">content2</div>
<div class="row">content3</div>
</div>
CSS
html,body,.wrapper{
width:100%;
height:100%;
margin:0px auto;
padding:0px;
}
.wrapper{
display:table;
border:1px solid black;
}
.wrapper .row{
display:table-row;
background-color:rgb(220,220,220);
}
.wrapper .row:nth-of-type(1){
min-height:15px;
}
.wrapper .row:nth-of-type(2){
height:100%;
background-color:white;
}
.wrapper .row:nth-of-type(3){
min-height:15px
}
You can do this easily with jQuery using $(window).height() and subtracting your footer/header's heights. See Fiddle for an example.
so I wanted an animated footer for my webpage using jquery. There's supposed to be a button which should trigger the animation. I found a nice example for all this, and everything is fine and dandy. Except that the button (including the footer) has this code that makes it stick to the bottom of your web browser, rather than to the bottom of the page. I do [i]not[/i] want it to, like, "scroll" along with the page, I realy want it to be underneath all my other divs. I tried putting it in the div container (which has all my other divs in it as well), but that doesn't seem to work.
Now, (after 2.5 hours of googling) I found out that it might/may/could have something to do with "absolute" positioning in the CSS, so I tried switching some things around such as giving the footer's container a relative position or giving it an "overflow: hidden;" along with the rest a left float but nothing seemed to solve my problem. (I could've done something wrong, not that great with CSS after all :-/)
I hope someone is able/willing to help.
P.S. Here's the example I used:
http://return-true.com/2010/04/jquery-pop-up-footer-version-2/
and here's the code:
Javascript:
jQuery(function($) {
var open = false;
$('#footerSlideButton').click(function () {
if(open === false) {
$('#footerSlideContent').animate({ height: '300px' });
$(this).css('backgroundPosition', 'bottom left');
open = true;
} else {
$('#footerSlideContent').animate({ height: '0px' });
$(this).css('backgroundPosition', 'top left');
open = false;
}
});
});
HTML:
<div id="footerPlacement">
<div id="footerSlideContainer">
<div id="footerSlideButton"></div>
<div id="footerSlideContent">
<div id="footerSlideText">
<h3>Hey! I'm a Sliding Footer</h3>
<p>What's a Sliding Footer? Well I'm a cool little element which can be hidden from view, and revealed when the user wants to see me.</p>
<p>What can you use me for? Well look at all this stuff:</p>
<ul>
<li>Sales information</li>
<li>Important updates</li>
<li>Unobtrusive about panel</li>
<li>Or just a good ol' footer</li>
</ul>
<p>There are obviously many other uses, but these are the few useful ones I can think of.</p>
</div>
</div>
</div>
</div>
CSS:
#footerPlacement {
margin-bottom: 0px;
width: 1000px;
margin-left: auto;
margin-right: auto;
}
#footerSlideContainer {
position: fixed;
margin-left: 0px;
bottom:0px;
width: 1000px;
}
#footerSlideButton {
background: url('../images/footer/footerbtn.png') top left no-repeat transparent;
position: absolute;
top: -55px;
right: 20px;
width:50px;
height:50px;
border: none;
cursor: pointer;
}
#footerSlideContent {
width: 100%;
height: 10px;
background: #251b15;
color: #CCCCCC;
font-size: 0.8em;
border: none;
font-family: DejaVuSansBook, Sans-Serif;
}
#footerSlideText {
padding: 15px 10px 25px 25px;
}
Thanks in advance!
if you change your #footerPlacement to include position:relative, you can change #footerSlideContainer to be position:absolute and then your footer will sit below any content above it.
However you will need to make the content have a min-height of around 350px for the footer to work properly and if your content isn't long enough, the footer won't be at the bottom of the browser.
I also added overflow:hidden to #footerSlideContent. I have made a fiddle to demonstrate:
http://jsfiddle.net/tc6b8/
I have a page, where I'm showing images side by side according to the category they belong to, each image array begins with the category it belongs to. Images vary in their width & height, but are put into a div with an absolute height of 330px.
CSS:
.front-index {
margin: 0 1em 0 2em;
}
.front-work {
margin: 0 2em 2em 0;
display: table;
width: 66px;
position: relative;
height: 330px;
background-color:#f0f0f0;
}
.front-work img {
margin: .3em 0 .3em 0;
}
.wraptocenter {
display: table-cell;
text-align: center;
vertical-align: middle;
}
.wraptocenter * {
vertical-align: middle;
}
.front-index,
.front-work {
float: left;
}
HTML:
<div class="front-index"><p>How to get<br /> this text on the same line with<br /> yellow image on the right?</p></div>
<div class="front-work">
<div class="wraptocenter">
<img width="162" height="250" src="http://images.fanpop.com/images/image_uploads/Yellow-Wallpaper-yellow-646738_800_600.jpg"/>
</div>
</div>
<div class="front-work">
<div class="wraptocenter">
<img width="250" height="166" src="http://www.takenseriouslyamusing.com/wp-content/uploads/2012/08/Blue.png"/>
</div>
</div>
…
JSFIDDLE: http://jsfiddle.net/rCAKa/9/
I'd like to align the text to the same line as the first image on the right.
What I had in mind, is that may-be this should be done in jquery. Ie. somehow measure the image distance from the top inside the .front-work div and then assign the value to the .front-index div as an inline code (top: whatever px ).
Maybe someone of you have faced this kind of problem and know a solution to this kind of problem? CSS or JS.
In my humble opinion I don't think that what you're doing is possible through CSS - it requires some simple JavaScript trickery because you have to know the relative position (from the top of the container) of the first image on the right in order to position the text - something which CSS isn't quite designed for.
The strategy in JS would be:
Loop through each element with text that you want to position
Fetch the vertical top offset of the first image to the right (relative to containing parent)
Set top padding matching to top position of image. Alternatively, you can set the top position, paddings or margins of the child elements, or other ways to reposition the text.
$(document).ready(function() {
$(".front-index").each(function() {
var fromTop = $(this).next().find("img").position().top;
$(this).css({
"padding-top":fromTop
});
});
});
I have forked your fiddle, and you can see it in action here - http://jsfiddle.net/teddyrised/LT54V/1/
p/s: On a related note, .wraptocenter * { } is probably not the best (as in, most efficient) selector out there, because if you have many child elements in the element (who may or may have even more child elements), CSS will have to iterate through all of them. Instead, try using .wraptocenter > * { } or just .wraptocenter img { } :)
I first tried to solve the problem using css. After a while I figured out the following logics:
Create a div with the same height as the cell on the right with the display set as table
Make a table-cell div in the first one that centers vertically
In this div make another subdiv with the same height as the image.
The HTML code is then this:
<div class="front-index">
<div class="front-index-inner">
<div style="height:250px;">
<p>How to get<br /> this text on the same line with<br /> yellow image on the right?</p>
</div>
</div>
</div>
and as my CSS part this:
.front-index {
margin: 0 1em 0 2em;
display: table;
height: 330px;
overflow: hidden;
}
.front-index-inner {
display: table-cell;
width: 100%;
vertical-align: middle;
}
You can see the result over here: http://jsfiddle.net/rCAKa/10/
I hope this brings a solution to you that is clear, understandable and useful.
Greetings,
Jef