I have two submit buttons in a form that Lets user Update/ Delete content. I want a confirm pop only if the user clicks Delete button.
<html>
<head>
<script type="text/javascript">
function confirmation() {
// I need to know which submit button was pressed.
if (value==Delete){
var answer = confirm("Cancel?")
if (answer){
return true;
//Continue as intended
}
else{
return false
}
}
}
</script>
</head>
<body>
<form id="Edit_Data">
//form input fields go here
<input name="action" type="submit" onclick="confirmation()" value="Update">
<input name="action" type="submit" onclick="confirmation()" value="Delete">
</form>
</body>
</html>
Any Ideas?
First of all you have several problems with your code. The value in your if statement is an undefined variable secondly you need to put quotes around the delete. Here is working fiddle http://jsfiddle.net/SMBWd/ and the relevant code change. Also, I would encourage you to look how to do this without using javascript in your HTML.
function confirmation(e) {
// I need to know which submit button was pressed.
if (e.value=='Delete'){
and in the HTML
<input name="action" type="button" onclick="confirmation(this)" value="Update">
<input name="action" type="button" onclick="confirmation(this)" value="Delete">
For your onclick event definition in the html tag, why not call separate functions?
The simplest way would be to NOT call the javascript on the Update button.
If your form is static, then you do this in your IDE. If it's dynamic, then the dynamic code can create the form element accordingly.
If the form elements are generated automatically, then you should setup an event handler in JavaScript dynamically. Find all elements of type input with type attribute button or submit, and assign
elems[i].onclick = confirmation;
You'd then get the event object as a method parameter, and you could query that for the value of the button.
Related
I just found out that every time onclick event for my <button> placed inside <form> tag triggers, form submits it's data as if i clicked <input type='submit'>.
I don't want that. Buttons inside my form serve other task, form shouldn't submit data after i clicked one of them.
To be more clear, i want this code:
<form action="http://www.google.com" method="POST">
<button onclick="alert('hi!')">Button</button>
<br>
<input type="submit" value="submit"/>
</form>
to show alert "hi!" when i click on the Button and it shouldn't open Google after that. It should only show Google when i press "submit".
Specify type="button":
<button type="button" onclick="alert('hi!')">Button</button>
From the linked article:
This [submit] is the default if the attribute is not specified
Try this..
onclick="alert('hi!'); return false;"
With jQuery use a span rather than an input, put use the .button call and then set a click event.
In PHP program, I have JS function which validates submit <form ...onsubmit='return isOK();'>. It works OK. The problem is I want it to work only for particular submits, not for all. Is there any way inside the JS function to find out which submit was pressed, or some PHP trick
instead of onsubmit u can use onClick.
<input type="submit" onclick="return pressSubmit1()" value="submit1" />
<input type="submit" onclick="return pressSubmit2()" value="submit2" />
<form action="action.php" method="post">
...
<input name="submit" type="button" value="check me" onclick="submitform('check')" />
<input name="submit" type="button" value="do not check me" onclick="submitform('not check')"/>
</form>
in javascript:
function submitform(check)
{
if(check=='check') checkfrom();
}
in PHP
if($_POST['submit']=="check me")
checkform();
<form class="allowed" onsubmit='return isOK();'>
----
function isOK() {
if($(this).hasClass('allowed')) {
// Do stuff
}
}
your question is not clear, are you using a single submit button or different ones. If you're using different submit buttons then ofcourse you can make checks based on the id of the submit button. On the other hand if is a single submit button then it depends on what the conditions are for submitting or not submitting
It's better you write some HTML and Java Script code which you are using. So, it's easy to correct mistake is you have made somewhere in code snippet.
We can check which submit button is clicked, using PHP.
In the PHP page corresponding to the form submit, write
if(extract($_POST) && isset($submitbtn1)) {
// some validation for first submit button
}
elseif(extract($_POST) && isset($submitbtn2)) {
// some validation for second submit button
}
Note: we can use $ followed by submit button name inside the extract function. ie. $submitbtn1 is same as $_POST['submitbtn1']
Yes different onclick looks fine as mentioned in the accepted answer. But in the event handler you should have the
code as below. Note the preventDefault.
Also since submit is A button that submits the form. You can use button type instead of submit type and then there is no need for preventDefault. Here is the link of the code http://jsbin.com/wikose/4/
function testlogin(){
event.preventDefault();
var test = 'not validated';
if(test === "validated")
alert("not valid login");
else
$('form').submit();
return false;
}
How can I specify which submit button to submit with?
The current example just submits the first submit button, with $("form").submit(); but how can I make it so it chooses the submit button by id or name?
<html>
<script>
$("form").submit();
</script>
<form action="<?=$_SERVER['PHP_SELF']?>" method="post" />
//other inputs
<input type="submit" value="Enter" name="enter" id="enter">
<input type="submit" value="Void" name="void" id="void">
<input type="submit" value="Refund" name="refund" id="refund">
</form>
</html>
Simulate a click to that element:
$("#circle2").click();
Also, you don't need action="<?=$_SERVER['PHP_SELF']?>". Forms submit to the current page by default.
First of all, why do you want to submit the same form with 3 different buttons?
It is a bad structure. Your code also has all the 3 buttons with the "id" attribute which is included in the <input> tag twice.
Based on your question, I could figure out you would want the submit button to say different things under different conditions.
Have a single button like this :
<input type="submit" name="submit" value="Enter">
You could always change what your button says, or how it looks like with JQuery :
if(condition){
$('#submit').val('.....');
// You can also change more stuff as you want.
}
Then you would want to submit the form
$('#submit').click(function(e)){
e.preventDefault();
$('form').submit();
}
By id
You can select the element by id easily with $('#my_btn') and you can click on it using the jQuery method click().
By name (or any other attribute
Other attributes are a bit harded (but not complex)
You select the element with $('input[name=some_name]')
Examlpe using your code
Here is an example which shows how you can get elements by name and click on them, click the submit buttons to see what happens: http://jsfiddle.net/nabil_kadimi/99v93/2/
I have form and the form submission can be done by either clicking on a hyper link or on a submit button. However I want my server to realize what has been used for form submission.
Current code snippet looks like this:
<a href=javascript:{} onclick="formSubmit()";>Next</a>
<input type="button" name="search" value="Get Result" onclick = "formSubmit();">
And my formSubmit() looks like this
<script type="text/javascript">
function formSubmit()
{
document.getElementById('form1').submit();
return false;
}
Any pointers as to how to go about it.
Thanks
Use a hidden parameter in your form.
< input type="hidden" value="0" name="flag"/>
When the form is submitted using javascript change flag value to '1' in the script.
function formSubmit()
{
document.form1.flag.value="1";
document.getElementById('form1').submit();
return false;
}
in case submit button is pressed the flag = '0'.
you can get this parameter on the server to determine how the form is submitted
edit : change your button type to 'submit' or call different scripts for both actions.
Pass a value (say an int or boolean) into the function. The value passed can be used to determine the source.
you invoke the same function to submit the form,so if you want your server to realize what has been used for form submission,i think you must pass a parameter to your server
You can use event.target to get the source that triggered the event and then set a flag to pass to server. See the example below:
<!DOCTYPE html>
<html>
<head>
<script>
function myFunction(e)
{
alert(e.target);
}
</script>
</head>
<p>
Click on a paragraph. An alert box will alert the element that triggered the event.</p>
<p>
<strong>Note:</strong> The target property returns the element that triggered the event, and not necessarily the eventlistener's element.</p>
This Link Click will return "javascript:{}"
<a href=javascript:{} onclick="myFunction(event)";>Next</a>
<p>
This Button Click will return "[objectHTMLInputElement]"
<input type="button" name="search" value="Get Result" onclick = "myFunction(event);">
</p>
</body>
</html>
I just found out that every time onclick event for my <button> placed inside <form> tag triggers, form submits it's data as if i clicked <input type='submit'>.
I don't want that. Buttons inside my form serve other task, form shouldn't submit data after i clicked one of them.
To be more clear, i want this code:
<form action="http://www.google.com" method="POST">
<button onclick="alert('hi!')">Button</button>
<br>
<input type="submit" value="submit"/>
</form>
to show alert "hi!" when i click on the Button and it shouldn't open Google after that. It should only show Google when i press "submit".
Specify type="button":
<button type="button" onclick="alert('hi!')">Button</button>
From the linked article:
This [submit] is the default if the attribute is not specified
Try this..
onclick="alert('hi!'); return false;"
With jQuery use a span rather than an input, put use the .button call and then set a click event.