How can I calculate the height of the parent so that the left div is only animated if there is empty space below itself. I have tried to calculate the parents height is greater then the question height + the margin-top.
This is a simplified version of the code: http://jsfiddle.net/rewsn/6/ as a example. Although in the real version the questions/answer are changed via AJAX so this is the reason I need to calculate the height each time.
If I understood correctly, then a simple condition like below should solve your problem.
if ((y + el.outerHeight()) < $container.height()) {
DEMO
var el = $('.answer');
var elpos = el.offset().top;
var $container = $('.container');
$(window).scroll(function() {
var y = $(this).scrollTop();
var mTop = y - elpos;
if ((y + el.outerHeight()) < $container.height()) {
if (y < elpos) {
el.stop().animate({
'margin-top': 0
}, 500);
}
else {
el.stop().animate({
'margin-top': y - elpos
}, 500);
}
}
});
not 100% sure what you mean - you want to stop "answers" being pushed lower than "questions"? something like this?
http://jsfiddle.net/X3cbB/1/
Related
I adapted this code to create a large div which scrolls horizontally inside a smaller div, depending on the position of the mouse.
You can see my example here.. http://thetally.efinancialnews.com/tallyassets/20years/index.html
What I am trying to achieve is for the inner (yellow) div to stop at a maximum of left:0px, in other words the far left of the yellow div will become stuck to the far left of the outer div if you go that far.
I tried to implement this with an 'if else' statement, however as this piece of code gets run every 30th of a second it creates a strange result, which I can't find a solution for. I'm sure its very simple but its stumped me
You can see my code here...
var x=0,
rate=0,
maxspeed=10;
var backdrop = $('.container');
var years = $('.events');
$('.direction', backdrop).mousemove(function(e){
var $this = $(this);
var left = $this.is('.left');
if (left){
var w = $this.width();
rate = (w - e.pageX - $(this).offset().left + 1)/w;
} else {
var w = $this.width();
rate = -(e.pageX - $(this).offset().left + 1)/w;
}
});
backdrop.hover(function(){
var scroller = setInterval( moveBackdrop, 30 );
$(this).data('scroller', scroller);
},
function(){
var scroller = $(this).data('scroller');
clearInterval( scroller );
});
function moveBackdrop(){
if ( parseInt(years.css("left"), 10) <= 0 ) {
x += maxspeed * rate;
var newpos = x+'px';
years.css('left',newpos);
} else {
years.css('left','0');
}
}
The code in question is right here at the end^
Is this what you were trying to do?
function moveBackdrop(){
if ( parseInt(years.css("left"), 10) <= 0 && rate < 0 ) {
// Means that the element is already at left: 0 or less,
// and we are trying to move it even more left with rate being negative.
// So keep the element at left: 0
years.css('left','0');
} else {
x += maxspeed * rate;
var newpos = x+'px';
years.css('left',newpos);
}
}
Extra note for future: parseInt uses base 10 by default :) so parseInt("20px") will equal 20
Final Edit: Ah there is an even better way to do it.
function moveBackdrop(){
x += maxspeed * rate;
if( x < 0 ) x = 0; // If left less than 0, fix it at 0
var newpos = x+'px';
years.css('left',newpos);
}
I'm trying to get the div to snap to the center of the viewport, right now it just snaps to the top. I was trying to put an offset of 50% but can only get it in px's.
EDIT
I added a new fiddle where I tried to include $(window).scrollTop() / 2)
http://jsfiddle.net/kZY9R/84/
$("#item").offset().top - 100
var body = $("html, body");
var items = $(".item");
var animating = false;
$(window).scroll(function() {
clearTimeout($.data(this, 'scrollTimer'));
if (!animating) {
$.data(this, 'scrollTimer', setTimeout(function() {
items.each(function(key, value) {
if ($(value).offset().top > $(window).scrollTop()) {
animating = true;
$(body).stop().animate( { scrollTop: $(value).offset().top }, 1000,'swing');
setTimeout(function() { animating = false; }, 2000);
return false;
}
});
}, 50));
}
});
I found this:
$('html, body').animate({scrollTop: $('#your-id').offset().top -100 }, 'slow');
Source: Run ScrollTop with offset of element by ID
Here's the trick to keep your viewport centralized on a particular div.
Prerequisites
You need to take into account the following three criteria to be able to centralize the viewport on a given item:
height of the last item that appeared on the viewport.
The distance of the last item from the top of the page, i.e. the offset().top of the item.
The height value of the viewport (i.e the window object).
Calculating Vertical Position of the Item
The required scrollTop value for the window can be calculated as in the following:
var scrollValue = itemOffset // offset of the item from the top of the page
- .5 * windowHeight // half the height of the window
+ .5 * itemHeight; // half the height of the item
You are basically, moving the top of your viewport to the item under view's top offset initially. This, as you've already experienced, snaps the item to the top of the window.
The real magic part comes when you subtract half of the window's height to go halfway along it vertically, and then shifting your view back down by adding half the item's height. This makes the item appear vertically centralized with regards to the viewport.
Note:
To be able to query the last item that appeared on the viewport, you have to iterate over all of the elements that have a top offset value (i.e. offset().top) less than or equal to that of the window's scrollTop value:
$.each($('.item'), function(i, value) {
if ($(viewport).scrollTop() >= $(this).offset().top) {
lastItemInView = $(this);
}
});
With the above, the lastItemInView variable will always end up with the last element visible in the window.
Demo
Not sure if you figured this out yet or not but I took some code from this answer (How to tell if a DOM element is visible in the current viewport?) that shows how to tell if an element is visible in the view port.
Using that I modified your code to loop through each item and find the first visible one in the viewport and then center that one also factoring in the margin-top you have. Let me know if this helps!
Fiddle: http://jsfiddle.net/kZY9R/86/
var body = $("html, body");
var items = $(".item");
var animating = false;
$(window).scroll(function() {
clearTimeout($.data(this, 'scrollTimer'));
if (!animating) {
$.data(this, 'scrollTimer', setTimeout(function() {
items.each(function(key, value) {
if (elementInViewport(value)) {
animating = true;
var margin = parseInt($(value).css('margin-top'));
$('html,body').animate({
scrollTop: $(value).offset().top - ($(window).height() + margin - $(value).outerHeight(true)) / 2
}, 200);
setTimeout(function() {
animating = false;
}, 2000);
return false;
}
});
}, 50));
}
});
function elementInViewport(el) {
var top = el.offsetTop;
var left = el.offsetLeft;
var width = el.offsetWidth;
var height = el.offsetHeight;
while (el.offsetParent) {
el = el.offsetParent;
top += el.offsetTop;
left += el.offsetLeft;
}
return (
top < (window.pageYOffset + window.innerHeight) &&
left < (window.pageXOffset + window.innerWidth) &&
(top + height) > window.pageYOffset &&
(left + width) > window.pageXOffset
);
}
I need to retrieve the visible height of a div within a scrollable area. I consider myself pretty decent with jQuery, but this is completely throwing me off.
Let's say I've got a red div within a black wrapper:
In the graphic above, the jQuery function would return 248, the visible portion of the div.
Once the user scrolls past the top of the div, as in the above graphic, it would report 296.
Now, once the user has scrolled past the div, it would again report 248.
Obviously my numbers aren't going to be as consistent and clear as they are in this demo, or I'd just hard code for those numbers.
I have a bit of a theory:
Get the height of the window
Get the height of the div
Get the initial offset of the div from the top of the window
Get the offset as the user scrolls.
If the offset is positive, it means the top of the div is still visible.
if it's negative, the top of the div has been eclipsed by the window. At this point, the div could either be taking up the whole height of the window, or the bottom of the div could be showing
If the bottom of the div is showing, figure out the gap between it and the bottom of the window.
It seems pretty simple, but I just can't wrap my head around it. I'll take another crack tomorrow morning; I just figured some of you geniuses might be able to help.
Thanks!
UPDATE: I figured this out on my own, but looks like one of the answers below is more elegant, so I'll be using that instead. For the curious, here's what I came up with:
$(document).ready(function() {
var windowHeight = $(window).height();
var overviewHeight = $("#overview").height();
var overviewStaticTop = $("#overview").offset().top;
var overviewScrollTop = overviewStaticTop - $(window).scrollTop();
var overviewStaticBottom = overviewStaticTop + $("#overview").height();
var overviewScrollBottom = windowHeight - (overviewStaticBottom - $(window).scrollTop());
var visibleArea;
if ((overviewHeight + overviewScrollTop) < windowHeight) {
// alert("bottom is showing!");
visibleArea = windowHeight - overviewScrollBottom;
// alert(visibleArea);
} else {
if (overviewScrollTop < 0) {
// alert("is full height");
visibleArea = windowHeight;
// alert(visibleArea);
} else {
// alert("top is showing");
visibleArea = windowHeight - overviewScrollTop;
// alert(visibleArea);
}
}
});
Calculate the amount of px an element (height) is in viewport
Fiddle demo
This tiny function will return the amount of px an element is visible in the (vertical) Viewport:
function inViewport($el) {
var elH = $el.outerHeight(),
H = $(window).height(),
r = $el[0].getBoundingClientRect(), t=r.top, b=r.bottom;
return Math.max(0, t>0? Math.min(elH, H-t) : Math.min(b, H));
}
Use like:
$(window).on("scroll resize", function(){
console.log( inViewport($('#elementID')) ); // n px in viewport
});
that's it.
jQuery .inViewport() Plugin
jsFiddle demo
from the above you can extract the logic and create a plugin like this one:
/**
* inViewport jQuery plugin by Roko C.B.
* http://stackoverflow.com/a/26831113/383904
* Returns a callback function with an argument holding
* the current amount of px an element is visible in viewport
* (The min returned value is 0 (element outside of viewport)
*/
;(function($, win) {
$.fn.inViewport = function(cb) {
return this.each(function(i,el) {
function visPx(){
var elH = $(el).outerHeight(),
H = $(win).height(),
r = el.getBoundingClientRect(), t=r.top, b=r.bottom;
return cb.call(el, Math.max(0, t>0? Math.min(elH, H-t) : Math.min(b, H)));
}
visPx();
$(win).on("resize scroll", visPx);
});
};
}(jQuery, window));
Use like:
$("selector").inViewport(function(px) {
console.log( px ); // `px` represents the amount of visible height
if(px > 0) {
// do this if element enters the viewport // px > 0
}else{
// do that if element exits the viewport // px = 0
}
}); // Here you can chain other jQuery methods to your selector
your selectors will dynamically listen to window scroll and resize but also return the initial value on DOM ready trough the first callback function argument px.
Here is a quick and dirty concept. It basically compares the offset().top of the element to the top of the window, and the offset().top + height() to the bottom of the window:
function getVisible() {
var $el = $('#foo'),
scrollTop = $(this).scrollTop(),
scrollBot = scrollTop + $(this).height(),
elTop = $el.offset().top,
elBottom = elTop + $el.outerHeight(),
visibleTop = elTop < scrollTop ? scrollTop : elTop,
visibleBottom = elBottom > scrollBot ? scrollBot : elBottom;
$('#notification').text(`Visible height of div: ${visibleBottom - visibleTop}px`);
}
$(window).on('scroll resize', getVisible).trigger('scroll');
html,
body {
margin: 100px 0;
}
#foo {
height: 1000px;
background-color: #C00;
width: 200px;
margin: 0 auto;
}
#notification {
position: fixed;
top: 0;
left: 0;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.6.0/jquery.min.js"></script>
<div id="foo"></div>
<div id="notification"></div>
The logic can be made more succinct if necessary, I've just declared separate variables for this example to make the calculation as clear as I can.
Here is a version of Rory's approach above, except written to function as a jQuery plugin. It may have more general applicability in that format. Great answer, Rory - thanks!
$.fn.visibleHeight = function() {
var elBottom, elTop, scrollBot, scrollTop, visibleBottom, visibleTop;
scrollTop = $(window).scrollTop();
scrollBot = scrollTop + $(window).height();
elTop = this.offset().top;
elBottom = elTop + this.outerHeight();
visibleTop = elTop < scrollTop ? scrollTop : elTop;
visibleBottom = elBottom > scrollBot ? scrollBot : elBottom;
return visibleBottom - visibleTop
}
Can be called with the following:
$("#myDiv").visibleHeight();
jsFiddle
Here is the improved code for jquery function visibleHeight: $("#myDiv").visibleHeight();
$.fn.visibleHeight = function() {
var elBottom, elTop, scrollBot, scrollTop, visibleBottom, visibleTop, height;
scrollTop = $(window).scrollTop();
scrollBot = scrollTop + $(window).height();
elTop = this.offset().top;
elBottom = elTop + this.outerHeight();
visibleTop = elTop < scrollTop ? scrollTop : elTop;
visibleBottom = elBottom > scrollBot ? scrollBot : elBottom;
height = visibleBottom - visibleTop;
return height > 0 ? height : 0;
}
I try to make sure that a div "filter" becomes fixed when scrolling and then stop when it comes down to "outside_footer_wrapper". use the following script but can not get it to work?
jsfiddle
$(function() {
var top = $('#filter').offset().top - parseFloat($('#filter').css('marginTop').replace(/auto/, 0));
var footTop = $('#outside_footer_wrapper').offset().top - parseFloat($('#outside_footer_wrapper').css('marginTop').replace(/auto/, 0));
var maxY = footTop - $('#filter').outerHeight();
$(window).scroll(function(evt) {
var y = $(this).scrollTop();
if (y > top) {
if (y < maxY) {
$('#filter').addClass('fixed').removeAttr('style');
} else {
$('#filter').removeClass('fixed').css({
position: 'absolute',
top: (maxY - top) + 'px'
});
}
} else {
$('#filter').removeClass('fixed');
}
});
});
If you want to stop the position:fixed after you reach the footer you can do something like this faking with the top:
$(function() {
var top = $('#filter').offset().top,
footTop = $('#outside_footer_wrapper').offset().top,
maxY = footTop - $('#filter').outerHeight();
$(window).scroll(function(evt) {
var y = $(this).scrollTop();
if (y > top) {
$('#filter').addClass('fixed').removeAttr('style');
if (y > maxY-20){
var min = y - maxY + 20;
$('#filter').css('top','-'+min+'px');
}
} else {
$('#filter').removeClass('fixed');
}
});
});
Also take in care with the CSS for the class fixed you need to make that with equal specificity of #filter I made this change:
#sidebar #filter.fixed /*Add #sidebar*/
Check This Demo Fiddle
if you know at which pixel number the filter have to be fixed and at which pixel number the footer starts you can try this function:
scrollTop
Is it something like this?
jsfiddle
// get box div position
var box = document.getElementById('box').offsetTop;
window.onscroll = function(){
// get current scroll position
var scroll_top = document.body.scrollTop || document.documentElement.scrollTop;
document.getElementById('scbox').innerText = scroll_top + ' ' + box;
// if current scroll position >= box div position then box position fixed
if(scroll_top >= box)
document.getElementById('box').style.position = 'fixed';
else
document.getElementById('box').style.position = 'relative';
}
try this:
#sidebar {
position: fixed;
}
jsfiddle here
ok so i have an interspire shopping cart so its hard to customize..
anyway,
here is a link to my code
http://jsfiddle.net/WTvQX/
im having trouble getting the scroll to work properly...
it works differently on my actual site here...
so i need help... re-doing it or just fixing..
let me kno
You need to add the "relatedLeft" ID to the left button, however try something like this...
Demo: http://jsfiddle.net/wdm954/WTvQX/3/
$('#relatedRight').click(function() {
$('#scool').animate({left: "+=100px"}, 'slow');
});
$('#relatedLeft').click(function() {
$('#scool').animate({left: "-=100px"}, 'slow');
});
You can adjust pixel distance and speed to your liking.
EDIT: Try something like this. The first part finds the width of all the images. Then the animates only fire when the offset is within range.
Demo: http://jsfiddle.net/wdm954/WTvQX/5/
var w = 0;
$('#scroll img').each(function (i, val) {
w += $(this).width();
});
$('#relatedRight').click(function() {
var offset = $('#scroll').offset();
if (offset.left < w) {
$('#scroll').animate({left: "+=100px"}, 'slow');
}
});
$('#relatedLeft').click(function() {
var offset = $('#scroll').offset();
if (offset.left > -w) {
$('#scroll').animate({left: "-=100px"}, 'slow');
}
});
EDIT: One more code option here. This one will stop scrolling sooner (note there are CSS changes here also).
Demo: http://jsfiddle.net/wdm954/WTvQX/7/
var w = 0;
$('#scroll img').each(function (i, val) {
w += $(this).width();
w += parseFloat($(this).css('paddingRight'));
w += parseFloat($(this).css('paddingLeft'));
w += parseFloat($(this).css('marginRight'));
w += parseFloat($(this).css('marginLeft'));
});
$('#scroll').css('width', w + 'px');
$('#relatedRight').click(function() {
var offset = $('#scroll').offset();
if (offset.left < 0) {
$('#scroll').stop().animate({left: "+=100px"}, 'slow');
}
});
$('#relatedLeft').click(function() {
var offset = $('#scroll').offset();
var b = $('#bar').width();
if (offset.left > b-w) {
$('#scroll').stop().animate({left: "-=100px"}, 'slow');
}
});