I have a var that contains a big list of words (millions) in this format:
var words = "
car
house
home
computer
go
went
";
I want to make a function that will replace the newline between each word with space.
So the results would something look like this:
car house home computer go went
You can use the .replace() function:
words = words.replace(/\n/g, " ");
Note that you need the g flag on the regular expression to get replace to replace all the newlines with a space rather than just the first one.
Also, note that you have to assign the result of the .replace() to a variable because it returns a new string. It does not modify the existing string. Strings in Javascript are immutable (they aren't directly modified) so any modification operation on a string like .slice(), .concat(), .replace(), etc... returns a new string.
let words = "a\nb\nc\nd\ne";
console.log("Before:");
console.log(words);
words = words.replace(/\n/g, " ");
console.log("After:");
console.log(words);
In case there are multiple line breaks (newline symbols) and if there can be both \r or \n, and you need to replace all subsequent linebreaks with one space, use
var new_words = words.replace(/[\r\n]+/g," ");
See regex demo
To match all Unicode line break characters and replace/remove them, add \x0B\x0C\u0085\u2028\u2029 to the above regex:
/[\r\n\x0B\x0C\u0085\u2028\u2029]+/g
The /[\r\n\x0B\x0C\u0085\u2028\u2029]+/g means:
[ - start of a positive character class matching any single char defined inside it:
\r - (\x0D) - \n] - a carriage return (CR)
\n - (\x0A) - a line feed character (LF)
\x0B - a line tabulation (LT)
\x0C - form feed (FF)
\u0085 - next line (NEL)
\u2028 - line separator (LS)
\u2029 - paragraph separator (PS)
] - end of the character class
+ - a quantifier that makes the regex engine match the previous atom (the character class here) one or more times (consecutive linebreaks are matched)
/g - find and replace all occurrences in the provided string.
var words = "car\r\n\r\nhouse\nhome\rcomputer\ngo\n\nwent";
document.body.innerHTML = "<pre>OLD:\n" + words + "</pre>";
var new_words = words.replace(/[\r\n\x0B\x0C\u0085\u2028\u2029]+/g," ");
document.body.innerHTML += "<pre>NEW:\n" + new_words + "</pre>";
Code : (FIXED)
var new_words = words.replace(/\n/g," ");
Some simple solution would look like
words.replace(/(\n)/g," ");
No need for global regex, use replaceAll instead of replace
myString.replaceAll('\n', ' ')
const words = `He had
concluded that pigs
must be able
to fly in Hog Heaven.
`
document.body.innerHTML = "<pre>without-Trim-And-Remove:\n" + words + "</pre>";
trimAndRemoveSymbols=(text)=>{
return text.replace(/[\n]+/g, '').trim();
}
document.body.innerHTML += "<pre>Trim-And-Remove:\n" + trimAndRemoveSymbols(words) + "</pre>";
Related
For example
let myString = "This is my string";
let replacedString = myString.replace(/\ /g, "") //Thisismystring
Now that all the whitespaces have been removed, how do I put them back in the exact position?
Additionally, let's suppose the replaced string undergoes some change and becomes
let myChangedString = "(T)(h)(i)(s)(i)(s)(m)(y)(s)(t)(r)(i)(n)(g)";
Now I want to put the whitespaces back where they used to be i.e after (s) and before (i), after (s) and before (m), after (y) before (s)
I've spent a couple of hours on this and been stuck in the same position, any form of help would be greatly appreciated.
EDIT: Solved, thank you very much.
The trick here is to replace the spaces with another character - rather than just removing the space. That way - its a simple matter to replace the added character with a space to return the spaces to where they started. When I do this - I always use the tilde character "~" since it is easily recognisable as well as unlikely to actually be used in a string.
I have added a few variations / modifications as well as the example you have provided with every character being wrapped in parentheses - just note that you will need to escape these when replaceing the (~) for the " " space character.
let myString = "This is my string";
let replacedString = myString.replace(/\ /g, "~");
console.log(replacedString);//This~is~my~string
let modifiedString = replacedString.replace(/my/g, "your");
console.log(modifiedString);//This~is~your~string
let spacedString = modifiedString.replace(/~/g, " ");
console.log(spacedString);//This is your string
// using your example of wrapping each character in parentheses
let myChangedString = "(" + modifiedString.split('').join(")(") + ")";
console.log(myChangedString); //(T)(h)(i)(s)(~)(i)(s)(~)(y)(o)(u)(r)(~)(s)(t)(r)(i)(n)(g)
let mySpacedString = myChangedString.replace(/\(~\)/g, " ");
console.log(mySpacedString); //(T)(h)(i)(s) (i)(s) (y)(o)(u)(r) (s)(t)(r)(i)(n)(g)
Why not replace only the parts you need to be replaced?
For example search for word character and replace with the wanted parts.
console.log("This is my string".replace(/\w/g, '($&)'));
Better you just transform your original array. Loop through array and modify the char is not empty.
let myString = "This is my string";
let chars = [...myString].map(item => item !== ' ' ? '(' + item + ')': item)
console.log(chars.join(''))
Are you looking for this...
var result = "thisismystring".replace(/^(.{4})(.{2})(.{2})(.*)$/, "$1 $2 $3 $4");
alert(result);
var searchTerms = escape(jQuery('input#q').val());
var st = searchTerms.trim();
var res = st.replaceAll("TITLE","ti").replaceAll("%20","%20and%20").replaceAll("AUTHOR","au");
I have the above code and need the search term values in double quotes as the result
It gives result URL as : '&query=heartmate%20and%20owens'
But I need it as : '&query="heartmate"%20and%20"owens"'
The simplest way is to map the values to new values before you inject them into the request. But first you need to split the string into its individual terms...
let terms = st.split(' ');
that will return an array of the individual elements of the string, split on a space character,
then you can trim and append the term...
terms.map(term => {
term.trim(); // <-- this removes all of the whitespace characters, including
// space, tab, no-break space, and all the line terminator
// characters, including LF, CR, etc. from the beginning and end
// of the string
return '"' + term + '"';
});
You may find the need to check a condition of term before applying the map, it really depends on what you're doing.
You can use backslash \ to escape your character
var test = " \" \" ";
console.log(test);
I am trying to remove some spaces from a few dynamically generated strings. Which space I remove depends on the length of the string. The strings change all the time so in order to know how many spaces there are, I iterate over the string and increment a variable every time the iteration encounters a space. I can already remove all of a specific type of character with str.replace(' ',''); where 'str' is the name of my string, but I only need to remove a specific occurrence of a space, not all the spaces. So let's say my string is
var str = "Hello, this is a test.";
How can I remove ONLY the space after the word "is"? (Assuming that the next string will be different so I can't just write str.replace('is ','is'); because the word "is" might not be in the next string).
I checked documentation on .replace, but there are no other parameters that it accepts so I can't tell it just to replace the nth instance of a space.
If you want to go by indexes of the spaces:
var str = 'Hello, this is a test.';
function replace(str, indexes){
return str.split(' ').reduce(function(prev, curr, i){
var separator = ~indexes.indexOf(i) ? '' : ' ';
return prev + separator + curr;
});
}
console.log(replace(str, [2,3]));
http://jsfiddle.net/96Lvpcew/1/
As it is easy for you to get the index of the space (as you are iterating over the string) , you can create a new string without the space by doing:
str = str.substr(0, index)+ str.substr(index);
where index is the index of the space you want to remove.
I came up with this for unknown indices
function removeNthSpace(str, n) {
var spacelessArray = str.split(' ');
return spacelessArray
.slice(0, n - 1) // left prefix part may be '', saves spaces
.concat([spacelessArray.slice(n - 1, n + 1).join('')]) // middle part: the one without the space
.concat(spacelessArray.slice(n + 1)).join(' '); // right part, saves spaces
}
Do you know which space you want to remove because of word count or chars count?
If char count, you can Rafaels Cardoso's answer,
If word count you can split them with space and join however you want:
var wordArray = str.split(" ");
var newStr = "";
wordIndex = 3; // or whatever you want
for (i; i<wordArray.length; i++) {
newStr+=wordArray[i];
if (i!=wordIndex) {
newStr+=' ';
}
}
I think your best bet is to split the string into an array based on placement of spaces in the string, splice off the space you don't want, and rejoin the array into a string.
Check this out:
var x = "Hello, this is a test.";
var n = 3; // we want to remove the third space
var arr = x.split(/([ ])/); // copy to an array based on space placement
// arr: ["Hello,"," ","this"," ","is"," ","a"," ","test."]
arr.splice(n*2-1,1); // Remove the third space
x = arr.join("");
alert(x); // "Hello, this isa test."
Further Notes
The first thing to note is that str.replace(' ',''); will actually only replace the first instance of a space character. String.replace() also accepts a regular expression as the first parameter, which you'll want to use for more complex replacements.
To actually replace all spaces in the string, you could do str.replace(/ /g,""); and to replace all whitespace (including spaces, tabs, and newlines), you could do str.replace(/\s/g,"");
To fiddle around with different regular expressions and see what they mean, I recommend using http://www.regexr.com
A lot of the functions on the JavaScript String object that seem to take strings as parameters can also take regular expressions, including .split() and .search().
I have hit a brick wall with this one....
I have managed to remove the Chars, but looking for the removal of all WhiteSpaces, Carrige Returns & the 0's at the start of each entry after the Chars have been removed.
var p_string = 'OPS010001 BLW020002 MKS030003';
var p_data = p_string.split(/[^0-9]+/g);
$('body').html(p_data + '<BR>');
JSFiddle
You want something like this
var p_data = p_string.split(/[^0-9]+/g).map(function(x){
return x.replace(/^0|\s/g, ""); // remove space, carriage return and 0 at start
}); // you can use Array.join to join the array with separator of your choice
Use string.replace function.
string.replace(/^0|\s/g, "");
\s matches white space characters including line breaks.
In Javascript I have several words separated by either a dot or one ore more whitepaces (or the end of the string).
I'd like to replace certain parts of it to insert custom information at the appropriate places.
Example:
var x = "test1.test test2 test3.xyz test4";
If there's a dot it should be replaced with ".X_"
If there's one or more space(s) and the word before does not contain a dot, replace with ".X "
So the desired output for the above example would be:
"test1.X_test test2.X test3.X_xyz test4.X"
Can I do this in one regex replace? If so, how?
If I need two or more what would they be?
Thanks a bunch.
Try this:
var str = 'test1.test test2 test3.xyz test4';
str = str.replace(/(\w+)\.(\w+)/g, '$1.X_$2');
str = str.replace(/( |^)(\w+)( |$)/g, '$1$2.X$3');
console.log(str);
In the first replace it replaces the dot in the dotted words with a .X_, where a dotted word is two words with a dot between them.
In the second replace it adds .X to words that have no dot, where words that have no dot are words that are preceded by a space OR the start of the string and are followed by a space OR the end of the string.
To answer this:
If there's a dot it should be replaced with ".X_"
If there's one or more spaces it should be replaced with ".X"
Do this:
x.replace(/\./g, '.X_').replace(/\s+/g, '.X');
Edit: To get your desired output (rather than your rules), you can do this:
var words = x.replace(/\s+/g, ' ').split(' ');
for (var i = 0, l = words.length; i < l; i++) {
if (words[i].indexOf('.') === -1) {
words[i] += ".X";
}
else {
words[i] = words[i].replace(/\./g, '.X_');
}
}
x = words.join(' ');
Basically...
Strip all multiple spaces and create an array of "words"
Loop through each word.
If it doesn't have a period in it, then add ".X" to the end of the word
Else, replace the periods with ".X_"
Join the "words" back into a string and separate it by spaces.
Edit 2:
Here's a solution using only javascript's replace function:
x.replace(/\s+/g, ' ') // replace multiple spaces with one space
.replace(/\./g, '.X_') // replace dots with .X_
// find words without dots and add a ".X" to the end
.replace(/(^|\s)([^\s\.]+)($|\s)/g, "$1$2.X$3");