I tried this:
// mod.js
var a = 1;
this.b = 2;
exports.c = 3;
// test.js
var mod = require('./mod.js');
console.log(mod.a); // undefined
console.log(mod.b); // 2
console.log(mod.c); // 3, so this === exports?
So I image that require() may be implement like this:
var require = function (file) {
var exports = {};
var run = function (file) {
// include "file" here and run
};
run.apply(exports, [file]);
return exports;
}
Is that right? Please help me to understand require(), or where can I find the source code. Thanks!
Source code is here. exports/require are not keywords, but global variables. Your main script is wrapped before start in a function which has all the globals like require, process etc in its context.
Note that while module.js itself is using require(), that's a different require function, and it is defined in the file called "node.js"
Side effect of above: it's perfectly fine to have "return" statement in the middle of your module (not belonging to any function), effectively "commenting out" rest of the code
var mod = require('./mod.js');
The require is a function that takes one argument called path, in this case the path is ./mod.js
when the require is invoked, a sequences of tasks are happened:
call Module.prototype.require function declared in lib/module.js which assert that the path exists and was a string
call Module._load which is a function in lib/module.js that resolve the file through Module._resolveFilename(request, parent, isMain),
the Module._resolveFilename function is called and checks if the module is native (The native modules are returned by NativeModule function defined in lib/internal/bootstrap_node.js),
if yes it will return the module else it checks the number of characters of the parh (Must 2 character at least) and some characters (the path must started by ./)
via Module._resolveLookupPaths function defined in defined in lib/internal/bootstrap_node.js
check the directory that contains the file
If the path contains an extension (in our example yes: mod.js), the basename function defined in lib/path.js checks that the extension is "js"
then it will create a new module for the file given in argument var module = new Module(filename, parent);
the content will be compiled via v8 through the function NativeModule.prototype.compile defined in lib/internal/bootstrap_node.js
the NativeModule.wrap defined in lib/internal/bootstrap_node.js takes the javascript content compiled of mod.js and wraps it : It wraps it in some other code that makes all this work.
So the code you've written in mod.js is wrapped in a function expression. that means everything you write in node is run in V8
a module.exports is what's returned
Andrey showed the source code, but if you also wonder how to use it, the easy and simple explanation is here (http://nodejs.org/api/modules.html).
These were two good examples for me.
//foo.js, multiple methods
var circle = require('./circle.js');
console.log( 'The area of a circle of radius 4 is ' + circle.area(4));
//circle.js
var PI = Math.PI;
exports.area = function (r) {
return PI * r * r;
};
exports.circumference = function (r) {
return 2 * PI * r;
};
//bar.js
var square = require('./square.js');
var mySquare = square(2);
console.log('The area of my square is ' + mySquare.area());
//square.js, single method
module.exports = function(width) {
return {
area: function() {
return width * width;
}
};
}
My favourite pattern is
(function (controller) {
controller.init = function (app) {
app.get("/", function (req, res) {
res.render("index", {});
});
};
})(module.exports);
I dig a little more of nodejs source code/2/ and make a sequence diagram/1/, hope this could give you a intuitive overview. There is another article http://fredkschott.com/post/2014/06/require-and-the-module-system/ which also explain the require() mechanism in a easy way, go through this article first could help you to understand the diagram quickly.
Ref:
/1/ diagram source repo: https://github.com/z1yuan/nodejs.git
/2/ https://github.com/nodejs/node-v0.x-archive.git
Try This.
This is a snippet of what I used to create the same functionality as Node.js
/*
FILE: require.js
*/
/*
This is the file used
*/
window.require = function(src, ret) {
if (src === 'jsmediatags') {
src = 'https://cdnjs.cloudflare.com/ajax/libs/jsmediatags/3.9.5/jsmediatags.js';
};
var d = document.createElement('script');
d.src = src;
document.head.appendChild(d);
var fullURL = src.split('://');
var neededURL = fullURL[1];
var nameParts = neededURL.split('/');
var nameNUM = nameParts.length - 1;
var fileName = nameParts[nameNUM];
var g = fileName.split('.');
var global = g[0];
if (ret === true) {
return window[global]
};
};
See if this works, and to add more files to its library, just type more in. (if (src===yourfilenamehere) { src = "path/to/your/file" }
The module loading mechanism in Node.js is caching the modules on the first require call. It means that every time you use require('xyz-module') you will get the same instance of xyz-module, which ensures that the modules are singleton-like and have the same state across your application.
You can load native modules and path references from your file system or installed modules. If the identifier passed to the require function is not a native module or a file reference (beginning with /, ../, ./ or similar), then Node.js will look for installed modules. It will walk your file system looking for the referenced module in the node_modules folder. It starts from the parent directory of your current module and then moves to the parent directory until it finds the right module or until the root of the file system is reached.
The source is available here next to the downloads : http://nodejs.org/ exports/require are keywords, I don't think they are coded in javascript directly. Node is coded in C++ , javascript is just a scripting shell around the C++ core.
Related
I am working on supporting a REST API that literally has thousands of functions/objects/stats/etc., and placing all those calls into one file does not strike me as very maintainable. What I want to do is have a 'base' file that has the main constructor function, a few utility and very common functions, and then files for each section of API calls.
The Problem: How do you attach functions from other files to the 'base' Object so that referencing the main object allows for access from the subsections you have added to your program??
Let me try and illustrate what I am looking to do:
1) 'base' file has the main constructor:
var IPAddr = "";
var Token = "";
exports.Main = function(opts) {
IPAddr = opts.IPAddr;
Token = opts.Token;
}
2) 'file1' has some subfunctions that I want to define:
Main.prototype.Function1 = function(callback) {
// stuff done here
callback(error, data);
}
Main.prototype.Function2 = function(callback) {
// stuff done here
callback(error,data);
}
3) Program file brings it all together:
var Main = require('main.js');
var Main?!? = require('file1.js');
Main.Function1(function(err,out) {
if(err) {
// error stuff here
}
// main stuff here
}
Is there a way to combine an Object from multiple code files?? A 120,000 line Node.JS file just doesn't seem to be the way to go to me....not to mention it takes too long to load! Thanks :)
SOLUTION: For those who may stumble upon this in the future... I took the source code for Object.assign and back ported it to my v0.12 version of Node and got it working.
I used the code from here: https://github.com/sindresorhus/object-assign/blob/master/index.js and put it in a separate file that I just require('./object-assign.js') without assigning it to a var. Then my code looks something like this:
require('./object-assign.js');
var Main = require('./Main.js');
Object.assign(Main.prototype, require('./file1.js'));
Object.assign(Main.prototype, require('./file2.js'));
And all my functions from the two files show up under the Main() Object...too cool :)
At first each file works in its own scope, so all local variables are not shared.
However, as hacky approach, you may just add Main into global scope available everywhere by writing global.Main = Main right after you define it, please make sure that you require main file first in list of requires.
The better(who said?) approach is to extend prototype of Main later, but in this case you may need to update a lot of code. Just mix-in additional functionality into base class
file1.js
module.exports = {
x: function() {/*****/}
}
index.js
var Main = require('main.js');
Object.assign(Main.prototype, require('file1.js'));
Shure.
constructor.js
module.exports = function(){
//whatever
};
prototype.js
module.exports = {
someMethod(){ return "test";}
};
main.js
const Main = require("./constructor.js");
Object.assign( Main.prototype, require("./prototype.js"));
Does anyone know how to get the name of a module in node.js / javascript
so lets say you do
var RandomModule = require ("fs")
.
.
.
console.log (RandomModule.name)
// -> "fs"
If you are trying to trace your dependencies, you can try using require hooks.
Create a file called myRequireHook.js
var Module = require('module');
var originalRequire = Module.prototype.require;
Module.prototype.require = function(path) {
console.log('*** Importing lib ' + path + ' from module ' + this.filename);
return originalRequire(path);
};
This code will hook every require call and log it into your console.
Not exactly what you asked first, but maybe it helps you better.
And you need to call just once in your main .js file (the one you start with node main.js).
So in your main.js, you just do that:
require('./myRequireHook');
var fs = require('fs');
var myOtherModule = require('./myOtherModule');
It will trace require in your other modules as well.
This is the way transpilers like babel work. They hook every require call and transform your code before load.
I don't know why you would need that, but there is a way.
The module variable, which is loaded automatically in every node.js file, contains an array called children. This array contains every child module loaded by require in your current file.
This way, you need to strict compare your loaded reference with the cached object version in this array in order to discover which element of the array corresponds to your module.
Look this sample:
var pieces = require('../src/routes/headers');
var childModuleId = discoverChildModuleId(pieces, module);
console.log(childModuleId);
function discoverChildModuleId(object, moduleObj) {
"use strict";
var childModule = moduleObj.children.find(function(child) {
return object === child.exports;
});
return childModule && childModule.id;
}
This code will find the correspondence in children object and bring its id.
I put module as a parameter of my function so you can export it to a file. Otherwise, it would show you modules of where discoverChildModule function resides (if it is in the same file won't make any difference, but if exported it will).
Notes:
Module ids have the full path name. So don't expect finding ../src/routes/headers. You will find something like: /Users/david/git/...
My algorithm won't detect exported attributes like var Schema = require('mongoose').Schema. It is possible to make a function which is capable of this, but it will suffer many issues.
From within a module (doesn't work at the REPL) you can...
console.log( global.process.mainModule.filename );
And you'll get '/home/ubuntu/workspace/src/admin.js'
One of my dependencies uses the following to pass in window to its closure
(function (window) {
//
})(this)
For the time being I can just change it to something more sensible so that it doesn't break browserify, but is there some method whereby I can force a value for this in a browserified module?
I wrote a browserify transform called "moduleify" that should generally do what you want, i.e. wrap the offending code in an IIFE that looks kinda like this:
(function () {
// this === window
}.call(window));
In fact, my implementation is not much more sophisticated than that.
The original idea was to export a globals-polluting "module" as if it were a CommonJS module (e.g. have AngularJS export window.angular), but because it contains that wrapper, it should do the trick.
For instructions, see the README. If the offending script doesn't actually have anything it could reasonably export, just have it export window (which will result in module.exports = window['window']) or an arbitrary name that doesn't exist (resulting in undefined).
If you want to access the window object in your own browserify code, also check out the global module, which provides a nice wrapper to access browser globals safely in CommonJS modules.
To solve this specific problem, a simple transform, that wraps the code in a self calling function, will do the job.
CoffeeScript
through = require('through')
fenestrate = (file) ->
data = ';(function() {\n';
write = (buf) ->
data += buf
end = ->
data += '\n}).call(window);'
this.queue(data)
this.queue(null)
through(write, end)
JavaScript
var through = require('through');
var fenestrate = function(file) {
var data, end, write;
data = ';(function() {\n';
write = function(buf) {
return data += buf;
};
end = function() {
data += '\n}).call(window);';
this.queue(data);
return this.queue(null);
};
return through(write, end);
};
Writing Transforms: https://github.com/substack/browserify-handbook#transforms
There are some third party Javascript libraries that have some functionality I would like to use in a Node.js server. (Specifically I want to use a QuadTree javascript library that I found.) But these libraries are just straightforward .js files and not "Node.js libraries".
As such, these libraries don't follow the exports.var_name syntax that Node.js expects for its modules. As far as I understand that means when you do module = require('module_name'); or module = require('./path/to/file.js'); you'll end up with a module with no publicly accessible functions, etc.
My question then is "How do I load an arbitrary javascript file into Node.js such that I can utilize its functionality without having to rewrite it so that it does do exports?"
I'm very new to Node.js so please let me know if there is some glaring hole in my understanding of how it works.
EDIT: Researching into things more and I now see that the module loading pattern that Node.js uses is actually part of a recently developed standard for loading Javascript libraries called CommonJS. It says this right on the module doc page for Node.js, but I missed that until now.
It may end up being that the answer to my question is "wait until your library's authors get around to writing a CommonJS interface or do it your damn self."
Here's what I think is the 'rightest' answer for this situation.
Say you have a script file called quadtree.js.
You should build a custom node_module that has this sort of directory structure...
./node_modules/quadtree/quadtree-lib/
./node_modules/quadtree/quadtree-lib/quadtree.js
./node_modules/quadtree/quadtree-lib/README
./node_modules/quadtree/quadtree-lib/some-other-crap.js
./node_modules/quadtree/index.js
Everything in your ./node_modules/quadtree/quadtree-lib/ directory are files from your 3rd party library.
Then your ./node_modules/quadtree/index.js file will just load that library from the filesystem and do the work of exporting things properly.
var fs = require('fs');
// Read and eval library
filedata = fs.readFileSync('./node_modules/quadtree/quadtree-lib/quadtree.js','utf8');
eval(filedata);
/* The quadtree.js file defines a class 'QuadTree' which is all we want to export */
exports.QuadTree = QuadTree
Now you can use your quadtree module like any other node module...
var qt = require('quadtree');
qt.QuadTree();
I like this method because there's no need to go changing any of the source code of your 3rd party library--so it's easier to maintain. All you need to do on upgrade is look at their source code and ensure that you are still exporting the proper objects.
There is a much better method than using eval: the vm module.
For example, here is my execfile module, which evaluates the script at path in either context or the global context:
var vm = require("vm");
var fs = require("fs");
module.exports = function(path, context) {
context = context || {};
var data = fs.readFileSync(path);
vm.runInNewContext(data, context, path);
return context;
}
And it can be used like this:
> var execfile = require("execfile");
> // `someGlobal` will be a global variable while the script runs
> var context = execfile("example.js", { someGlobal: 42 });
> // And `getSomeGlobal` defined in the script is available on `context`:
> context.getSomeGlobal()
42
> context.someGlobal = 16
> context.getSomeGlobal()
16
Where example.js contains:
function getSomeGlobal() {
return someGlobal;
}
The big advantage of this method is that you've got complete control over the global variables in the executed script: you can pass in custom globals (via context), and all the globals created by the script will be added to context. Debugging is also easier because syntax errors and the like will be reported with the correct file name.
The simplest way is: eval(require('fs').readFileSync('./path/to/file.js', 'utf8'));
This works great for testing in the interactive shell.
AFAIK, that is indeed how modules must be loaded.
However, instead of tacking all exported functions onto the exports object, you can also tack them onto this (what would otherwise be the global object).
So, if you want to keep the other libraries compatible, you can do this:
this.quadTree = function () {
// the function's code
};
or, when the external library already has its own namespace, e.g. jQuery (not that you can use that in a server-side environment):
this.jQuery = jQuery;
In a non-Node environment, this would resolve to the global object, thus making it a global variable... which it already was. So it shouldn't break anything.
Edit:
James Herdman has a nice writeup about node.js for beginners, which also mentions this.
I'm not sure if I'll actually end up using this because it's a rather hacky solution, but one way around this is to build a little mini-module importer like this...
In the file ./node_modules/vanilla.js:
var fs = require('fs');
exports.require = function(path,names_to_export) {
filedata = fs.readFileSync(path,'utf8');
eval(filedata);
exported_obj = {};
for (i in names_to_export) {
to_eval = 'exported_obj[names_to_export[i]] = '
+ names_to_export[i] + ';'
eval(to_eval);
}
return exported_obj;
}
Then when you want to use your library's functionality you'll need to manually choose which names to export.
So for a library like the file ./lib/mylibrary.js...
function Foo() { //Do something... }
biz = "Blah blah";
var bar = {'baz':'filler'};
When you want to use its functionality in your Node.js code...
var vanilla = require('vanilla');
var mylibrary = vanilla.require('./lib/mylibrary.js',['biz','Foo'])
mylibrary.Foo // <-- this is Foo()
mylibrary.biz // <-- this is "Blah blah"
mylibrary.bar // <-- this is undefined (because we didn't export it)
Don't know how well this would all work in practice though.
I was able to make it work by updating their script, very easily, simply adding module.exports = where appropriate...
For example, I took their file and I copied to './libs/apprise.js'. Then where it starts with
function apprise(string, args, callback){
I assigned the function to module.exports = thus:
module.exports = function(string, args, callback){
Thus I'm able to import the library into my code like this:
window.apprise = require('./libs/apprise.js');
And I was good to go. YMMV, this was with webpack.
A simple include(filename) function with better error messaging (stack, filename etc.) for eval, in case of errors:
var fs = require('fs');
// circumvent nodejs/v8 "bug":
// https://github.com/PythonJS/PythonJS/issues/111
// http://perfectionkills.com/global-eval-what-are-the-options/
// e.g. a "function test() {}" will be undefined, but "test = function() {}" will exist
var globalEval = (function() {
var isIndirectEvalGlobal = (function(original, Object) {
try {
// Does `Object` resolve to a local variable, or to a global, built-in `Object`,
// reference to which we passed as a first argument?
return (1, eval)('Object') === original;
} catch (err) {
// if indirect eval errors out (as allowed per ES3), then just bail out with `false`
return false;
}
})(Object, 123);
if (isIndirectEvalGlobal) {
// if indirect eval executes code globally, use it
return function(expression) {
return (1, eval)(expression);
};
} else if (typeof window.execScript !== 'undefined') {
// if `window.execScript exists`, use it
return function(expression) {
return window.execScript(expression);
};
}
// otherwise, globalEval is `undefined` since nothing is returned
})();
function include(filename) {
file_contents = fs.readFileSync(filename, "utf8");
try {
//console.log(file_contents);
globalEval(file_contents);
} catch (e) {
e.fileName = filename;
keys = ["columnNumber", "fileName", "lineNumber", "message", "name", "stack"]
for (key in keys) {
k = keys[key];
console.log(k, " = ", e[k])
}
fo = e;
//throw new Error("include failed");
}
}
But it even gets dirtier with nodejs: you need to specify this:
export NODE_MODULE_CONTEXTS=1
nodejs tmp.js
Otherwise you cannot use global variables in files included with include(...).
Is it easy/possible to do a simple include('./path/to/file') type of command in node.js?
All I want to do is have access to local variables and run a script. How do people typically organize node.js projects that are bigger than a simple hello world? (A fully functional dynamic website)
For example I'd like to have directories like:
/models
/views
... etc
Just do a require('./yourfile.js');
Declare all the variables that you want outside access as global variables.
So instead of
var a = "hello" it will be
GLOBAL.a="hello" or just
a = "hello"
This is obviously bad. You don't want to be polluting the global scope.
Instead the suggest method is to export your functions/variables.
If you want the MVC pattern take a look at Geddy.
You need to understand CommonJS, which is a pattern to define modules. You shouldn't abuse GLOBAL scope that's always a bad thing to do, instead you can use the 'exports' token, like this:
// circle.js
var PI = 3.14; // PI will not be accessible from outside this module
exports.area = function (r) {
return PI * r * r;
};
exports.circumference = function (r) {
return 2 * PI * r;
};
And the client code that will use our module:
// client.js
var circle = require('./circle');
console.log( 'The area of a circle of radius 4 is '
+ circle.area(4));
This code was extracted from node.js documentation API:
http://nodejs.org/docs/v0.3.2/api/modules.html
Also, if you want to use something like Rails or Sinatra, I recommend Express (I couldn't post the URL, shame on Stack Overflow!)
If you are writing code for Node, using Node modules as described by Ivan is without a doubt the way to go.
However, if you need to load JavaScript that has already been written and isn't aware of node, the vm module is the way to go (and definitely preferable to eval).
For example, here is my execfile module, which evaluates the script at path in either context or the global context:
var vm = require("vm");
var fs = require("fs");
module.exports = function(path, context) {
var data = fs.readFileSync(path);
vm.runInNewContext(data, context, path);
}
Also note: modules loaded with require(…) don't have access to the global context.
If you are planning to load an external javascript file's functions or objects, load on this context using the following code – note the runInThisContext method:
var vm = require("vm");
var fs = require("fs");
var data = fs.readFileSync('./externalfile.js');
const script = new vm.Script(data);
script.runInThisContext();
// here you can use externalfile's functions or objects as if they were instantiated here. They have been added to this context.
Expanding on #Shripad's and #Ivan's answer, I would recommend that you use Node.js's standard module.export functionality.
In your file for constants (e.g. constants.js), you'd write constants like this:
const CONST1 = 1;
module.exports.CONST1 = CONST1;
const CONST2 = 2;
module.exports.CONST2 = CONST2;
Then in the file in which you want to use those constants, write the following code:
const {CONST1 , CONST2} = require('./constants.js');
If you've never seen the const { ... } syntax before: that's destructuring assignment.
Sorry for resurrection. You could use child_process module to execute external js files in node.js
var child_process = require('child_process');
//EXECUTE yourExternalJsFile.js
child_process.exec('node yourExternalJsFile.js', (error, stdout, stderr) => {
console.log(`${stdout}`);
console.log(`${stderr}`);
if (error !== null) {
console.log(`exec error: ${error}`);
}
});