I have this loop that produces many elements with different positions:
if ( $row['Type'] == "house") { ?>
<div class="itemW" style="margin-left: <?=$row['X']?>px; margin-top: <?=$row['Y']?>px;">
Item
</div> <?
}
I need to change all the divs left position, I'm trying this:
var items = document.getElementsByClassName("itemW");
items[0].style.left = land.width() / items[0].style.left * 100;
The problem is that items[0].style.left doesn't get the position of the first div. Also I don't know how to do it with all the divs.
You can get all elements with a particular class name with
document.getElementsByClassName("classname");
for anything but IE < 9 at least :P
Then it's just a matter of looping through them like so
var meh = document.getElementsByClassName("classname");
for (var i = 0; i < meh.length; i++)
meh[i].style.left = land.width() / items[0].style.left * 100 + "px"; // "px" is very important.
// also this will only work
// if you have first set the
// element's style attribute.
Try this with jQuery:
$('.itemW').each(function () {
var item = $(this);
var pos = item.position();
item.css('left', (item.width() / pos.left * 100) + 'px');
item.css('top', (item.height() / pos.top * 100) + 'px');
});
Related
I do not know much about css, but I think this code could help me generate a marquee. basically I want the animation that is done with the boxes, be done with the texts.
My main problem occurs with the animation, it is not very fluid, I want it to be more fluid and it starts from the end of the container to the left. How can I do it? I would be very grateful.
http://jsfiddle.net/joof5dhx/
<div id="horizontalScroller">
<div>it is a message a little more of 100 characteres</div>
<div>it is a message a little more of 110 characteres</div>
<div>it is a message a little more of 120 characteres</div>
<div>it is a message a little more of 130 characteres</div>
</div>
window.horizontalScroller = function($elem) {
var left = parseInt($elem.css("left"));
var temp = -1 * $('#horizontalScroller > div').height();
if(left < temp) {
left = $('#horizontalScroller').height()
$elem.css("left", left);
}
$elem.animate({ left: (parseInt(left)-60) }, 900, function () {
window.horizontalScroller($(this))
});
}
$(document).ready(function() {
var i = 0;
$("#horizontalScroller > div").each(function () {
$(this).css("left", i);
i += 60;
window.horizontalScroller($(this));
});
});
http://jsfiddle.net/hhcbtyyg/
You could just:
window.horizontalScroller = function($elem)
{
var left = parseInt($elem.css("left"));
$elem.animate({ left: (parseInt(left)-60) }, 900, function ()
{
// get the current left of the element
var currentLeft = parseInt($(this).css("left"));
// get the width of the element
var width = $(this).width();
// get the container
var container = $(this).parent("#horizontalScroller");
// get the width of the container
var containerWidth = $(container).width();
// check if the element goes out of the view item X + item w < 0
if ((currentLeft + width) <= 0)
{
// put it on the opposite side: simply container w + item w
$(this).css("left", (containerWidth + width) + "px");
}
window.horizontalScroller($(this))
});
}
I just don't understand why you use height in your code above. If there is something I don't know let me know.
UPDATED:
To make the items appear on the leftmost by default:
$(document).ready(function() {
var container = $("#horizontalScroller");
var children = $(container).children();
var containerW = $(container).width();
// Loop through each item of container
for (var i = 0; i < children.length; i++)
{
var item = children[i];
var itemW = $(item).width();
// this is simply the space between them, remove if you don't need it
var padding = 10 * (i + 1);
// simply: padding + Container Width + (Item Width * (i + 1))
// (Item Width * (i + 1)) because you need to position each element beside each other.
$(item).css("left", (padding + containerW + itemW * (i + 1)) + "px");
window.horizontalScroller($(item));
}
});
your updated fiddle
hope that helps
Hi checked this version of your jsfiddle, i did some modificaitons, since your animation starts from whatever the value of height is your div had. check this I tried to match the height of your css and width in your css, i just noticed that the "left" var in your js gets the height of your element.
CSS:
#horizontalScroller {
position: absolute;
width:300px;
height: 300px;
border: 1px solid red;
overflow: hidden;
}
Maybe you can get some tips how to accomplish it in responsive way.
JSFIDDLE
I adapted this code to create a large div which scrolls horizontally inside a smaller div, depending on the position of the mouse.
You can see my example here.. http://thetally.efinancialnews.com/tallyassets/20years/index.html
What I am trying to achieve is for the inner (yellow) div to stop at a maximum of left:0px, in other words the far left of the yellow div will become stuck to the far left of the outer div if you go that far.
I tried to implement this with an 'if else' statement, however as this piece of code gets run every 30th of a second it creates a strange result, which I can't find a solution for. I'm sure its very simple but its stumped me
You can see my code here...
var x=0,
rate=0,
maxspeed=10;
var backdrop = $('.container');
var years = $('.events');
$('.direction', backdrop).mousemove(function(e){
var $this = $(this);
var left = $this.is('.left');
if (left){
var w = $this.width();
rate = (w - e.pageX - $(this).offset().left + 1)/w;
} else {
var w = $this.width();
rate = -(e.pageX - $(this).offset().left + 1)/w;
}
});
backdrop.hover(function(){
var scroller = setInterval( moveBackdrop, 30 );
$(this).data('scroller', scroller);
},
function(){
var scroller = $(this).data('scroller');
clearInterval( scroller );
});
function moveBackdrop(){
if ( parseInt(years.css("left"), 10) <= 0 ) {
x += maxspeed * rate;
var newpos = x+'px';
years.css('left',newpos);
} else {
years.css('left','0');
}
}
The code in question is right here at the end^
Is this what you were trying to do?
function moveBackdrop(){
if ( parseInt(years.css("left"), 10) <= 0 && rate < 0 ) {
// Means that the element is already at left: 0 or less,
// and we are trying to move it even more left with rate being negative.
// So keep the element at left: 0
years.css('left','0');
} else {
x += maxspeed * rate;
var newpos = x+'px';
years.css('left',newpos);
}
}
Extra note for future: parseInt uses base 10 by default :) so parseInt("20px") will equal 20
Final Edit: Ah there is an even better way to do it.
function moveBackdrop(){
x += maxspeed * rate;
if( x < 0 ) x = 0; // If left less than 0, fix it at 0
var newpos = x+'px';
years.css('left',newpos);
}
var move = function() {
Xpos = Math.round(Math.random() * 95);
food[num].css('left', Xpos + '%');
interval = setInterval(function() {
console.log(i);
var posTop = food[num].offset().top / $(window).height() * 100;
while(posTop < 80) {
if(posTop === 80) {
num++;
break;
}
posTop += 1;
food[num].css('top', posTop + '%');
break;
}
}, speed);
}
//Color the circle
circleColor();
move();
}
OK so this is my code. It creates a circle(a <div> element) on top of the screen and gives it a random x coordinate. Than it puts it in food[] array. The entire code starts by clicking the button, but every time I press the button again the circle that was last moving stops, function creates a new one and the new one moves. Is there a way I can make all elements in the array move without depending on each other?
http://jsfiddle.net/yqwjqx31/
I understand why this happens but I have no idea how to fix it.
First you're using a global variable num in setInterval function handler, so its value get modified while using it in new cercle create, secondly you're clearing interval of the last cercle you created before creating a new cercle. It means you're sharing the same interval between all cercles. Use instead an array of intervals just like var food =[] and use a temporary variable to prevent the index value modification inside your setInterval handler. Here's a working fiddle
//Interval
var interval =[];
var tempNum = num;
interval[num] = setInterval(function() {
var posTop = food[tempNum].offset().top / $(window).height() * 100;
while(posTop < 80) {
if(posTop === 80) {
break;
}
posTop += 1;
food[tempNum].css('top', posTop + '%');
break;
}
}, speed);
Increment your num variable
//Color the circle
circleColor();
move();
num++;
Your move function is only responsible for moving the last generated div via createCircle. If you want to move them all till collision, you need to loop through them all and move them accordingly. Or, you can animate them via CSS.
Here is the working version :
http://jsfiddle.net/yqwjqx31/3/
Notice how the setInterval callback loops through all the div and pushes them down until their height is 80.
var move = function () {
interval = setInterval(function () {
for (var i = 0; i < food.length; ++i) {
var posTop = food[i].offset().top / $(window).height() * 100;
if (posTop < 80) posTop += 1;
food[i].css('top', posTop + '%');
}
}, speed);
}
Okay, I've seen a few things that sort of * answer my question, but none of them quite do what I want to do / I'd like to understand how to do this myself from start to finish as a learning exercise. I'm a novice at all this, so bear with me!
What I'm Trying to Do:
I have a black page and I'd like 20-30 small, white div boxes to fadeIn at random positions on the page (like stars is sort of the vibe I'm going for).
Ideally, they wouldn't overlap and they would be randomly sized between 5px and 10px, but I recognize that this might be getting a little too complicated.
Here's what I have so far
I've been working off this jsfiddle and well as this one. This is what I've come up with (that doesn't work, they all fade in equally spaced in a line and don't stay confined from to the site)
Here's my jsfiddle, code below
function randomPosition() {
var h = $(window).height()-10;
var w = $(window).width()-10;
var newHeight = Math.floor(Math.random() * h);
var newWidth = Math.floor(Math.random() * w);
return [newHeight, newWidth];
}
$(document).ready(function() {
var newPosition = randomPosition();
$('.star').css( {
'margin-left':newPosition[1]+'px',
'margin-top':newPosition[0]+'px'
}).each(function(index) { $(this).delay(1500*index).fadeIn('slow');
})
});
CSS
body {
background-color: black;
}
.star {
height: 10px;
width: 10px;
background-color: white;
display: none;
}
HTML (is there a way to do this with just a for loop or something similar?)
<div class="star"> </div>
<div class="star"> </div>
<div class="star"> </div>
<div class="star"></div>
The sizing and positioning isn't too hard. The thing is to do it all in the each loop - currently you get 1 position and use it for everything. Also you will want to make them position:absolute so they don't go off the page.
I've updated your fiddle to set the random position and a size between 5 and 10px:
The overlapping is a bit harder. You need to keep track of the sizes and positions you have generated and in the same .each function compare the current generated size+position to the previous ones to check for overlapping.
http://jsfiddle.net/5ocb5aww/3/
function randomPosition() {
var h = $(window).height()-10;
var w = $(window).width()-10;
var newHeight = Math.floor(Math.random() * h);
var newWidth = Math.floor(Math.random() * w);
return [newHeight, newWidth];
}
function randomSize() {
return Math.round(Math.random() * 5) + 5;
}
$(document).ready(function() {
// stores generated star positions
var stars = [];
$('.star').each(function(index) {
var newPosition, newSize;
// check for overlap
var isOverlap = true;
while(isOverlap)
{
newPosition = randomPosition();
newSize = randomSize();
// check previous stars to see if an edge of this one overlaps
isOverlap = $.grep(stars, function(s) {
return (
(newPosition[1] >= s.x1 && newPosition[1] <= s.x2)
|| (newPosition[1]+newSize >= s.x1 && newPosition[1]+newSize <= s.x2)
)
&& (
(newPosition[0] >= s.y1 && newPosition[0] <= s.y2)
|| (newPosition[0]+newSize >= s.y1 && newPosition[0]+newSize <= s.y2)
);
}).length > 0;
}
// store to check later stars against it
stars.push({
x1: newPosition[1],
x2: newPosition[1] + newSize,
y1: newPosition[0],
y2: newPosition[0] + newSize,
size: newSize});
$(this).css({
'margin-left':newPosition[1]+'px',
'margin-top':newPosition[0]+'px',
'width':newSize + 'px',
'height':newSize + 'px'
});
$(this).delay(800*index).fadeIn('slow');
})
});
Here is my approach to your exercise ... the overlapping position would require a little bit more effort ... I'll leave you that to sort for yourself (may require restructuring the code I'm handing here)
jsFiddle Demo
JS
function starDust(wdt, hgt, tSt, tAp){
var timer = tAp * 1000;
var defInt = tSt,
starInt = setInterval(function(){
var posX = Math.floor((Math.random() * wdt) + 1),
posY = Math.floor((Math.random() * hgt) + 1),
size = Math.floor((Math.random() * 10) + 1);
$('body').append('<div class="star"></div>');
$('.star:last').css({'width':size,'height':size,'left':posX,'top':posY}).hide().fadeIn('slow');
var totalStars = $('.star').length;
if(totalStars == defInt){
clearInterval(starInt);
}
}, timer);
}
$(function(){
// Function arguments: starDust(max X position in px, max Y position in px, total number of stars, time in seconds between stars show);
starDust(600,300,25,1);
});
CSS
body{
background-color:#000;
}
.star{
position: absolute;
background-color:#fff;
min-width:5px;
min-height:5px;
}
I would like to make all these boxes behave like they are floated. However, they can’t be, they need to be absolutely positioned in order for me to interact with this positioned number.
Here's my attempt:
var $item = $('#wrapper div'),
len = $item.length,
itemWidth = $item.innerWidth(),
winWidth = $('#wrapper').innerWidth(),
cols = Math.floor(winWidth / itemWidth),
moveX = itemWidth + 10;
function absPos() {
for (var i = 0; i < len; i += 1) {
$('.item-' + i).css({
'position' : 'absolute',
'left' : moveX * i
});
}
}
I just can't figure out how to wrap them to fit, and also re-position when the window is resized.
Here’s a demo. http://jsfiddle.net/Fgcqs/3/ . If you un-commment the absPos() function you will see my start.
Thanks for any help!
I have edited your jsfiddle to move the items like they are floated. It assumes your margins and widths are the same for each of the divs within wrapper and will automatically work out the width and height of the spacing if your css changes
var wrapper = $('#wrapper'),
items = wrapper.children('div'),
len = items.length,
itemWidth = items.innerWidth() + parseInt(items.css('margin-left')) + parseInt(items.css('margin-right')),
itemHeight = items.innerHeight() + parseInt(items.css('margin-top')) + parseInt(items.css('margin-bottom'));
items.css('float', 'none');
function absPos() {
var cols = Math.floor(wrapper.width() / itemWidth);
items.each(function() {
var left = ($(this).index() % cols) * itemWidth; //the bit in brackets calculates which column the div should be in (the remainder of the current index of your item divided by the number of columns per row), then you times that by item width as worked out above, you use the index as this will allow you to start at left:0
var height = Math.floor($(this).index() / cols) * itemHeight //the bit in brackets calculates which row the div should be in, then you times that by item height as worked out above, you use the Math.floor as this will allow you to start at top:0. Should have really called this top!
$(this).css({
'position' : 'absolute',
'top': height,
'left': left
});
});
wrapper.height((Math.ceil(len / cols)) * itemHeight);
}
$(window).resize(function() {
absPos();
});
absPos();
http://jsfiddle.net/Fgcqs/12/
You have to keep track of both column index and row index: once column index * item width exceeds window width, reset column index and increment row index to simulate next row. Here's simple example of this approach:
function absPos() {
var colIndex = 0;
var rowIndex = 0;
for (var i = 0; i < len; i += 1) {
if (moveX * colIndex + itemWidth > winWidth) {
colIndex = 0;
rowIndex++;
top += itemHeight + 10;
}
var left = moveX * colIndex;
var top = moveY * rowIndex;
$('.item-' + i).css({
'position' : 'absolute',
'left' : left,
'top' : top
});
colIndex++;
}
}
http://jsfiddle.net/N4S4L/1/
You should check if your left value plus the width of an item exceeds the width of your container, in which case introduce a top value and reset left to 0 to start building a new row.