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Making flip effect on hover, on blur go fade with CSS + jQuery

I have to do something like pexeso. When you hover element, it will flip front to back side (they have different texts) and when your mouse is out, it will fade from back to front side. This is example HTML, how it looks like:
<div class="pexeso">
<div class="pad">
<div class="front">1</div>
<div class="back">ONE</div>
</div>
etc...
There is some CSS, to look it well (it is in the jsFiddle source, attached bellow). Then Handling mouse enter and leave with jQuery:
$('.pexeso .pad').each(function() {
var el = $(this);
var back = el.find('.back');
el.on('mouseenter', function() {
back.removeAttr('style');
el.removeClass('before-fade').addClass('do-flip');
});
el.on('mouseleave', function() {
el.removeClass('do-flip').addClass('before-fade');
back.stop(true, true).fadeOut(250, function() {
el.removeClass('before-fade');
});
});
});
Here is full example in jsFiddle: DEMO
Try to hover any element from left or right side of your screen, it will works great. But now try to hover from top or bottom, it will do weird things to graphic and also, sometimes it stucks and remains invisible.
Probably know the problem: When you hover from top or bottom, it will start flipping, and when you are too slow, it also fires event mouseleave, because flipping is in progress and you are actually at empty space. Then it calls 1st function, then second, a lot of time and it got stuck. But I don't know how to fix it, can you help me?

Ok guys, don't try anymore, I already found a solution. Whoever is interested, how I fixed it, here is solution:
In CSS, make .back element always visible, so find this line &.do-flip { and add this style .back { display: block !important; }
In jQuery, there is no need to have back.removeAttr('style');, also this did mess with opacity style (fading effect)
Now wrap every "pad" with parent, for example .pad-container and give him exact sizes as .pads, now we will manipulate with him
Each function will take these wrappers, not "pads", so in jQuery $('.pexeso .pad-container').each(function() {...
Bind events mouseenter and mouseleave on this wrapper, but changing classes remain on "pads" and fadeOut effect on back element. Also, add function .show() to this back element before fadeOut.
That's all. Here is updated version: UPDATED DEMO

fadeIn background image on click

I have a working code that changes my document background image when links in my navbar are clicked. The background image changes instantly with no animation. How could I make the new background image fadeIn(); ?
js
$('.navigation a').click(function() {
currentBg = $(this).attr('href').replace('#', '') +'.jpg';
$('.background').css({'background-image':'url(images/skins/'+currentBg+')'});
});

I don't believe you can, the only way (that I know of) would be to have a block element (div for example) which has the background and that appears behind the rest of your content (positioned absolutely) and fade that in instead of switching backgrounds.

You cannot animate the background image changing its opacity.
May be you can have a image with required opacity at different sections and then animate the background position so that it gives a fadeIn behavior.
Take a look at this link it will help you.

There is no possiblity to fade the background image, you have to create a container and set its background image to let it fade in and fade out.

I've done something like this before by floating a foreground image on a separate div on top of the background image you'd like to 'fade' in and then creating a jquery fade-out effect on the foreground image.
You can use a similar trick to set solid text on a semi-transparent "background".
http://css-tricks.com/non-transparent-elements-inside-transparent-elements/

I agree with int0x90.
What you can do is this:
Stack your images in a div, style position absolute, style of each image position absolute
set an id for the div
add a class active, with a z-index of 10
set all inactive images in div z-index to 0
you can use the z-index to pull the image with the highest z-index to the top of the stack
add class active to the on-click of nav bar link and remove this class from the previous on click so that the image's z-index is set back to 0 and not overridden.
in jquery, you may now be able to use opacity change and the speed of the change
hope this helps get you started!

As many others already said, it's impossible unless you use a block element as background.
But if you only want an animation, you could have a .gif as background then when it's animation has finished replace it with the real Image so the .gif doesn't iterate itself

Hover over a hidden element to show it

Is there any way to hover over an element that's already hidden. I am trying to mimic what Steam does with their arrow navigation on their home page. You'll notice that when you first get to the page, there are no arrows showing:
Then when you hover over the area where there should be an arrow, it shows itself:
I've tried setting my divs that contain the arrow images to display: none and have also tried visibility: hidden but neither seems to work with the hover or mouseover methods in jQuery. I would have thought visibility: hidden would make it work, but that doesn't seem to be the case. Is there any other way I can hide these divs from the start but still be able to have hover events work on them?

Set it to zero opacity instead:
$('#blah').hover(function() {
$(this).fadeTo(1,1);
},function() {
$(this).fadeTo(1,0);
});
http://jsfiddle.net/mblase75/bzaax/

You cannot hover over an invisible element or an undisplayed element. You can hover over a visible element and then use that to show a different previously hidden element. Or you can hover over a transparent element and make it opaque.
Here is an example of the opacity technique using just CSS, it would also work with jQuery's hover.
CSS:
#it {
opacity: 0;
width: 500px;
height:500px;
}
#it:hover {
opacity: 1;
}
Here is an example of showing one element when another is hovered over:
HTML:
<div id="me">Hover over me to display something else</div>
<div id="else">Something else</div>
jQuery:
$("#me").hover(function(){
$("#else").show();
},function(){
$("#else").hide();
});

Use the .fadeTo jQuery method to change the opacity of the element on hover state.
The jQuery site contains an example but something like this should suffice
$("element").hover(//On Hover Callback
function() {$(this).fadeOut(100);} ,
//Off Hover Callback
function() {$(this).fadeIn(500);})
From the jQuery Hover page.

You could set it to opacity: 0.
In order to make it cross-browser you probably would like to do it with jQuery tho.

One way to do this is by using an alternate hit-test div, such that it has no content, but when hovered over it shows the "arrow" div. When the "arrow" div (or the hit-test div) is exited, then the "arrow" div would be hidden once again.
Alternatively, you could use the same div for the hit-test and the "arrow", such that a background image is used for the visual elements of the div. When hovered, you could instruct the image's offset to be set to a position which would show the "arrow". When exited, you would set the offset of the background to a position where the arrow image would not longer be shown.
And, finally, if the content will always be in the same position as the hit-test area, you could set the opacity of the div to zero, and toggle accordingly.

You could set the opacity of the elements to 0. That would allow them to receive the hover events (actually mouseenter and mouseleave), but as a practical matter, make them invisible to users.

Jquery detect hover over an element but not the elements contents

Here is the page i am working with: http://jimeagle.com/new/music/
I want to make it so when you hover over a row the image shows and when you leave the row the image shows, but because (i think) the image is in the hover div, the image stays visible when you hover out of the row but over the image.
I tried to move the image out of the hover div but it caused some horrible flickering because when your over the image you are no longer over the hover div.
Any way around this? Thanks.

Get the height of the div with the class "music_row". If the mouse y-position (on mousemove) is higher then the calculated height, hide the image.
$(document).ready(function() {
var iHeight = $(".music_row").height();
$(".music_wrapper")
.mouseover(function() {
$(this).find('.image').show();
})
.mousemove(function(o) {
if (o.layerY > iHeight) {
$(this).find('.image').hide();
}
})
.mouseout(function() {
$(this).find('.image').hide();
});
});
Also see my jsfiddle.

Because the image is a child of the element you bind the handlers on, it will prevent the mouseout event being triggered unless the pointer also leaves the container, .music_wrapper in your case.
To work around this, you could create an absolute positioned 'ghost' element with zero opacity and use this for triggering your hover events. Something like this:
$(function() {
$('.music_wrapper').each(function() {
var ghost = $(this).find('.music_row').clone();
ghost.css({opacity: 0, position: 'absolute', overflow: 'hidden' });
ghost.hover(
function() { $(this).parent().find('img').show(); },
function() { $(this).parent().find('img').hide(); }
);
$(this).append(ghost);
});
})
Not tested, but this should recreate your .music_row div element in every .music_wrapper, set some css properties, bind the hover handlers and append it to the wrapper element.
Now image and hover element are seperated, which can hide the image even when the mouse is still over it.

I would suggest not doing this, actually. I think the intuitive thing is that when you hover over the number / text the image pops up, but moving your mouse inside the image shouldn't do anything.
How about just moving the images to the right a little so that the big numbers are still at least partly visible? Then it would feel natural to move over to the next # to see the next image.

Homemade Jquery lightbox, but z-index won't change back afterwards

So I'm trying to make a simple lightbox on a concert listings page. You click a listing (.performer), and then an info box (.lightboxinfo) gets overlaid while a semi-opaque white div lightens the rest of the screen (#whitepage). Then, you click anywhere on the screen, and the box and white div disappear.
Everything works fine except the final z-index changes. The box and white div become fully transparent, but the z-index clearly haven't been changed since I can't click on any links.
Anyone know what I'm doing wrong? Thanks so much!
The javascript is below:
$('.performer a').click(
function(){
$('.lightboxinfo').css('z-index','110').animate({opacity:'1'}, {queue:false,duration:500});
$('#whitepage').css('z-index','100').animate({opacity:'0.4'}, {queue:false,duration:500});
});
$(document).click(
function(){
$('#whitepage').css('z-index','-100').animate({opacity:'0'},{queue:false,duration:100});
$('.lightboxinfo').css('z-index','-110').animate({opacity:'0'},{queue:false,duration:100});
});
});

Why mess around with the z-index when you can set 'display:none' after your opacity becomes 0?
// when appearing
$('#whitepage').css('opacity','0').show().animate({opacity:'0.4'}, 500);
// when disappearing
$('#whitepage').animate({opacity:'0'}, 100, function () {
$('#whitepage').hide();
});
Also, each time you click on the performer link, you're adding another event handler to the document. You may want to do that only once, outside of the click and only if the whitepage is visible.
$('.performer a').click(function () {
});
$(document).click(function () {
$('#whitepage:visible').animate(...
});

This is a bit difficult to answer as you haven't given the HTML and CSS, but there are a few things you should probably look at.
I assume your lightbox divs are positioned absolutely. Any (container) elements that you want to appear over them must be positioned relatively or absolutely or z-index will have no effect and relatively / absolutely positioned elements will always be on top of them.
You're animating the opacity manually, rather than using jQuery's built in fadeOut animation. Apart from giving compatibility with browsers that don't support opacity, fadeOut also sets the hidden element to display: none. This allows you to click on stuff that would otherwise be underneath the lightbox, whereas just reducing the opacity to 0 still leaves the element there and able to accept and block clicks. (So using fadeOut also means you'd no longer have to toggle the z-index.)
This is not directly related to the problem you mentioned, but both of the events you've set up will fire when you click on a .performer a link. (I think this is why you've prevented the animations from being queued: both will run together and the one that sets the opacity to 1 wins as it finishes last.) This does, however, stop the lightbox getting the z-index you want. To prevent this happening, you either need to set the close lightbox click event to #whitepage or stop the event propagating.
$('.performer a').click(function(event)
{
$('.lightboxinfo, #whitepage').fadeIn(500);
event.stopPropagation();
});