i need to get part of string into variable. (note, i will always use exactly 4 names)
var names = "Andrew Peter Bob Mark"
I need to get the last one to
var last = "Mark"
Thanks for help in advance
var last = names.split(/\s+/).pop(); // "Mark"
Explanation: .split splits a string on a given separator and returns an array. /\s+/ is a regular expression for "one or more whitespaces" (space, tab, newline, etc). .pop() grabs the last value from the array that .split returns.
Answer from Roatin Marth is correct, but in case if you need 4 times faster version (in IE) of same operation:
var last = names.substr(names.lastIndexOf(" "));
It is working without regular expressions and temp arrays - just with index operations of string.
Related
I don't understand this behaviour:
var string = 'a,b,c,d,e:10.';
var array = string.split ('.');
I expect this:
console.log (array); // ['a,b,c,d,e:10']
console.log (array.length); // 1
but I get this:
console.log (array); // ['a,b,c,d,e:10', '']
console.log (array.length); // 2
Why two elements are returned instead of one? How does split work?
Is there another way to do this?
You could add a filter to exclude the empty string.
var string = 'a,b,c,d,e:10.';
var array = string.split ('.').filter(function(el) {return el.length != 0});
A slightly easier version of #xdazz version for excluding empty strings (using ES6 arrow function):
var array = string.split('.').filter(x => x);
This is the correct and expected behavior. Given that you've included the separator in the string, the split function (simplified) takes the part to the left of the separator ("a,b,c,d,e:10") as the first element and the part to the rest of the separator (an empty string) as the second element.
If you're really curious about how split() works, you can check out pages 148 and 149 of the ECMA spec (ECMA 262) at http://www.ecma-international.org/publications/files/ECMA-ST/Ecma-262.pdf
Use String.split() method with Array.filter() method.
var string = 'a,b,c,d,e:10.';
var array = string.split ('.').filter(item => item);
console.log(array); // [a,b,c,d,e:10]
console.log (array.length); // 1
https://developer.mozilla.org/en-US/docs/JavaScript/Reference/Global_Objects/String/split
trim the trailing period first
'a,b,c,d,e:10.'.replace(/\.$/g,''); // gives "a,b,c,d,e:10"
then split the string
var array = 'a,b,c,d,e:10.'.replace(/\.$/g,'').split('.');
console.log (array.length); // 1
That's because the string ends with the . character - the second item of the array is empty.
If the string won't contain . at all, you will have the desired one item array.
The split() method works like this as far as I can explain in simple words:
Look for the given string to split by in the given string. If not found, return one item array with the whole string.
If found, iterate over the given string taking the characters between each two occurrences of the string to split by.
In case the given string starts with the string to split by, the first item of the result array will be empty.
In case the given string ends with the string to split by, the last item of the result array will be empty.
It's explained more technically here, it's pretty much the same for all browsers.
According to MDN web docs:
Note: When the string is empty, split() returns an array containing
one empty string, rather than an empty array. If the string and
separator are both empty strings, an empty array is returned.
const myString = '';
const splits = myString.split();
console.log(splits);
// ↪ [""]
Well, split does what it is made to do, it splits your string. Just that the second part of the split is empty.
Because your string is composed of 2 part :
1 : a,b,c,d,e:10
2 : empty
If you try without the dot at the end :
var string = 'a,b,c:10';
var array = string.split ('.');
output is :
["a,b,c:10"]
You have a string with one "." in it and when you use string.split('.') you receive array containing first element with the string content before "." character and the second element with the content of the string after the "." - which is in this case empty string.
So, this behavior is normal. What did you want to achieve by using this string.split?
try this
javascript gives two arrays by split function, then
var Val = "abc#gmail.com";
var mail = Val.split('#');
if(mail[0] && mail[1]) { alert('valid'); }
else { alert('Enter valid email id'); valid=0; }
if both array contains length greater than 0 then condition will true
I have the following text string:
test-shirt-print
I want to filter the text string so that it only returns me:
test-shirt
Meaning that everything that comes after the second hyphen should be removed including the hyphen.
I am thinking that the solution could be to split on hyphen and somehow select the two first values, and combine them again.
I am unaware of which functionality is best practice to use here, I also thinking that if it would be possible to use a regular expression in order to be able to select everything before the second hyphen.
You can use split slice and join together to remove everything after the second hyphen
var str = "test-shirt-print";
console.log(str.split("-").slice(0, 2).join('-'))
You can try with String.prototype.slice()
The slice() method extracts a section of a string and returns it as a new string, without modifying the original string.
and String.prototype.lastIndexOf()
The lastIndexOf() method returns the index within the calling String object of the last occurrence of the specified value, searching backwards from fromIndex. Returns -1 if the value is not found.
var str = 'test-shirt-print';
var res = str.slice(0, str.lastIndexOf('-'));
console.log(res);
You can also use split() to take the first two items and join them:
var str = 'test-shirt-print';
var res = str.split('-').slice(0,2).join('-');
console.log(res);
In my web page, I have:
var res = number.match(/[0-9\+\-\(\)\s]+/g);
alert(res);
As you can see, I want to get only numbers, the characters +, -, (, ) and the space(\s)
When I tried number = '98+66-97fffg9', the expected result is: 98+66-979
but I get 98+66-97,9
the comma is an odd character here! How can eliminate it?
Its probably because you get two groups that satisfied your expression.
In other words: match mechanism stops aggregating group when it finds first unwanted character -f. Then it skips matching until next proper group that, in this case, contains only one number - 9. This two groups are separated by comma.
Try this:
var number = '98+66-97fffg9';
var res = number.match(/[0-9\+\-\(\)\s]+/g);
// res is an array! You have to join elements!
var joined = res.join('');
alert(joined);
You're getting this because your regex matched two results in the number string, not one. Try printing res, you'll see that you've matched both 98+66-979 as well as 9
String.match returns an array of matched items. In your case you have received two items ['98+66-97','9'], but alert function outputs them as one string '98+66-97,9'. Instead of match function use String.replace function to remove(filter) all unallowable characters from input number:
var number = '98+66-97fffg9',
res = number.replace(/[^0-9\+\-\(\)\s]+/g, "");
console.log(res); // 98+66-979
stringvariable.match(/[0-9\+\-\(\)\s]+/g); will give you output of matching strings from stringvariable excluding unmatching characters.
In your case your string is 98+66-97fffg9 so as per the regular expression it will eliminate "fffg" and will give you array of ["98+66-97","9"].
Its default behavior of match function.
You can simply do res.join('') to get the required output.
Hope it helps you
As per documents from docs, the return value is
An Array containing the entire match result and any parentheses-captured matched results, or null if there were no matches.
S,your return value contains
["98+66-97", "9"]
So if you want to skip parentheses-captured matched results
just remove g flag from regular expression.
So,your expression should like this one
number.match(/[0-9\+\-\(\)\s]+/); which gives result ["98+66-97"]
I am trying to fetch the value after equal sign, its works but i am getting duplicated values , any idea whats wrong here?
// Regex for finding a word after "=" sign
var myregexpNew = /=(\S*)/g;
// Regex for finding a word before "=" sign
var mytype = /(\S*)=/g;
//Setting data from Grid Column
var strNew = "QCById=20";
var matchNew = myregexpNew.exec(strNew);
var newtype = mytype.exec(strNew);
alert(matchNew);
https://jsfiddle.net/6vjjv0hv/
exec returns an array, the first element is the global match, the following ones are the submatches, that's why you get ["=20", "20"] (using console.log here instead of alert would make it clearer what you get).
When looking for submatches and using exec, you're usually interested in the elements starting at index 1.
Regarding the whole parsing, it's obvious there are better solution, like using only one regex with two submatches, but it depends on the real goal.
You can try without using Regex like this:
var val = 'QCById=20';
var myString = val.substr(val.indexOf("=") + 1);
alert(myString);
Presently exec is returning you the matched value.
REGEXP.exec(SOMETHING) returns an array (see https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/RegExp/exec).
The first item in the array is the full match and the rest matches the parenthesized substrings.
You do not get duplicated values, you just get an array of a matched value and the captured text #1.
See RegExp#exec() help:
If the match succeeds, the exec() method returns an array and updates properties of the regular expression object. The returned array has the matched text as the first item, and then one item for each capturing parenthesis that matched containing the text that was captured.
Just use the [1] index to get the captured text only.
var myregexpNew = /=(\S*)/g;
var strNew = "QCById=20";
var matchNew = myregexpNew.exec(strNew);
if (matchNew) {
console.log(matchNew[1]);
}
To get values on both sides of =, you can use /(\S*)=(\S*)/g regex:
var myregexpNew = /(\S*)=(\S*)/g;
var strNew = "QCById=20";
var matchNew = myregexpNew.exec(strNew);
if (matchNew) {
console.log(matchNew[1]);
console.log(matchNew[2]);
}
Also, you may want to add a check to see if the captured values are not undefined/empty since \S* may capture an empty string. OR use /(\S+)=(\S+)/g regex that requires at least one non-whitespace character to appear before and after the = sign.
Here is the script;:
var output = []
output = this.getField("SelectedSoftware").value.match(/\$(\d{1,4}\.\d\d)/g);
Example text from the field:
Automate, Audition ($500.00), Citrix Receiver, AutoCAD ($54.93), Clarity Studio ($748.23), Audacity ($300.00), Audition ($500.00), Business Objects Dashboard, Audition ($500.00),
The problem I have is getting just the cost numbers so they can be added together to display a total. (?<=\$) doesn't seem to work. so I grouped the rest of the expression in Parentheses. However, I'm not sure how to get those group values instead of the full matches.
RegExp.exec(string) should be really helpful. In fact, it's the only way to obtain capture groups from a string. The implementation is a bit tough though, since .exec() only returns a single result.
Sample code:
var regex = /\$(\d{1,4}\.\d\d)/g,
text = this.getField("SelectedSoftware").value,
prices = [],
total = 0,
num;
// Assignments always return the value that is assigned.
// .exec will return null if no matches are found.
while((val = regex.exec(text)) !== null){
// Capture groups are referenced with 'val[x]', where x is the capture group number.
num = parseFloat(val[1]);
total += num;
prices.push(num);
}
Here's a fiddle.
This works because RegExp objects have a property called .lastIndex which it bases the next .exec() search on.
You can read more about .exec() on the MDN.
You can use (?: ) to create non-capturing groups, but I don't think you need it in this case.
MDN: Working with regular expressions
exec: A RegExp method that executes a search for a match in a string.
It returns an array of information. test: A RegExp method that tests
for a match in a string. It returns true or false. match: A String
method that executes a search for a match in a string. It returns an
array of information or null on a mismatch. search: A String method
that tests for a match in a string. It returns the index of the match,
or -1 if the search fails. replace: A String method that executes a
search for a match in a string, and replaces the matched substring
with a replacement substring. split: A String method that uses a
regular expression or a fixed string to break a string into an array
of substrings.
What you need is RegExp.exec, which will return an array of information form which you can get the captured group.
It returns an array with the whole match in [0], then each captured group in the following array slots. So what you want is:
var price = /\$(\d{1,4}\.\d\d)/.exec("$59.99")[1];
I have is getting just the cost numbers so they can be added together to display a total. String.prototype.match
always returns an array as you want.
See this complete DEMO
var output = []
output = "Automate, Audition ($500.00), "
+"Citrix Receiver, AutoCAD ($54.93), "+
+"Clarity Studio ($748.23), Audacity "
+"($300.00), Audition ($500.00), Business "
+"Objects Dashboard, Audition ($500.00),"
.match(/\$(\d{1,4}\.\d\d)/g);
Output:
["$500.00", "$54.93", "$748.23", "$300.00", "$500.00", "$500.00"]
Now you can simply add all number using This regex /(\d{1,4}\.\d\d)/g.
Getting sum of these values:
var total = 0;
for(var _=0; _<output.length; _++)
total += parseFloat(output[_]);
See OUTPUT 2603.16