i have an nested object as such:
options = {
religous: {
kosher: {
value: 'Kosher',
chosen: false
},
halal: {
value: 'Halal',
active: false
},
},
vegan: {
value: 'Vegan',
active: false
}
}
It contains nested objects of varying sizes. I would like to get an Array containing the values of any value propery. So for the above object the desired output would be:
['Kosher', 'Halal', 'Vegan']
Order doesn't really matter.
I tried to do so recursively as such:
getListOfLabels = obj => {
const lst = []
for (let key in obj) {
if (obj[key].value) lst.push(obj[key].value)
else return getListOfLabels(obj[key])
}
return lst
}
but I keep getting a RangeError: Maximum call stack size exceeded error.
Any suggestions?
The for...in loop assigns the key. To get the value use obj[key]. If the key is value add to lst, if it's an object, call getListOfLabels on it, and spread the results into lst.push():
const options = {"religous":{"kosher":{"value":"Kosher","chosen":false},"halal":{"value":"Halal","active":false}},"vegan":{"value":"Vegan","active":false}}
const getListOfLabels = obj => {
const lst = []
for (let key in obj) {
const val = obj[key] // get the value
if (key === 'value') lst.push(val) // if the key name is "value" push to lst
else if(typeof val === 'object') lst.push(...getListOfLabels(val)) // if type of value is object, iterate it with getListOfLabels and push the results into lst
}
return lst
}
const result = getListOfLabels(options)
console.log(result)
You could take a recursive approach and check if the object contains a value key.
function getValues(object, key) {
if (key in object) return [object[key]];
return Object.values(object).reduce((r, v) => {
if (v && typeof v === 'object') r.push(...getValues(v, key));
return r;
}, []);
}
var options = { religous: { kosher: { value: 'Kosher', chosen: false }, halal: { value: 'Halal', active: false } }, vegan: { value: 'Vegan', active: false } };
console.log(getValues(options, 'value'));
Here's a succinct approach using reduce :-D
const getValues = options => Object.values(options)
.reduce((acc, optionObj) => (
optionObj.value ? [ ...acc, optionObj.value ] : [
...acc,
...Object.values(optionObj).reduce((arr, { value }) => ([ ...arr, value ]), [])
]), [])
I figured this must be a dup, but I can't find it on SO. Given an object like this:
let obj = { keyA: { keyB: 'hi', keyC: { keyD: null } }, keyE: 'hi' }
Is there a way I can find key paths to a given value, like this:
keyPaths(obj, 'hi') // -> [ 'keyA.keyB', 'keyE' ]
keyPaths(obj) // -> [ 'keyA.keyB.keyD' ]
I tried to adapt some of the answers that find deep values knowing the key, and I was almost able to adapt this one that finds deep nulls, but I can't figure out how to get the path back, instead of just the deepest key.
I would go with a depth first search like this :
let obj = { keyA: { keyB: 'hi', keyC: { keyD: null } }, keyE: 'hi' }
function keyPaths(parent, value = null, chain) {
let allResults = [];
for (const prop in parent) {
if (parent.hasOwnProperty(prop)) {
const element = parent[prop];
const newChain = chain ? chain + '.' + prop : prop;
if (element === value) {
allResults.push(newChain);
}
else if (Object.keys(prop).length > 1) {
allResults = [...allResults, ...keyPaths(element, value, newChain)];
}
}
}
return allResults;
}
console.log(keyPaths(obj, 'hi')) // -> [ 'keyA.keyB', 'keyE' ]
console.log(keyPaths(obj)) // -> [ 'keyA.keyB.keyC' ]
Basically, I check all the properties of the given element for a matching value. If a property doesn't match the value, but has child properties, I recursively call the function, and merge the results from the call iteration and the recursive call.
You do this pretty cleanly by using reduce inside a recursive function. The function will return an array, which you can than map() to whatever string values you want.
let obj = { keyA: { keyB: 'hi', keyC: { keyD: null } }, keyE: 'hi' }
function keyPaths(obj, val, path = [] ){
if (!obj) return
return Object.entries(obj).reduce((res, [k, v]) => {
let p = [...path, k]
if (v == val) res.push(p)
else if (v && typeof v == 'object') res.push(...keyPaths(v, val, p))
return res
}, [])
}
console.log(keyPaths(obj, 'hi').map(a => a.join('.')))
console.log(keyPaths(obj).map(a => a.join('|')))
If it's ok to use Lodash+Deepdash, then:
let paths = _(obj).filterDeep((v)=>v=='hi').paths().value();
Codepen is here
I have a requirement to replace the available keys with the desired keys in an object for which I was trying to execute below code, which later I found out to be incorrect usage of filter for desired output. hence I need help in getting the desired results using es6 array functions.
const columns = Object.keys(someArray).filter((columnName) => {
if (someCheck === "somecheck") {
if (columnName === 'MyName') {
const newcolumnName = `Pranav`;
return newcolumnName;
} else if (columnName === 'YourName') {
const newcolumnName = `Alex`;
return newcolumnName;
}
} else {
return (columnName !== 'sometingelse') ? columnName : '';
}
}
);
Here the someArray is as below:
someArray{
abc:"djfhdjf",
xyz:"ssss",
MyName:"onename",
YourName:"somename",
sometingelse:'somevalue'
}
I am expecting columns to be:
columns{
abc:"djfhdjf",
xyz:"ssss",
Pranav:"onename",
Alex:"somename",
sometingelse:'somevalue'
}
Please suggest how can I achieve the above expected output?
Note: I dont want to use function keyword in callbacks to avoid eslint errors
You could filter the wanted keys for replacement and replace the keys by using a new key and eleting the old one.
const
object = { abc: "djfhdjf", xyz: "ssss", MyName: "onename", YourName: "somename", sometingelse: 'somevalue' },
replacements = { MyName: 'Pranav', YourName: 'Alex', sometingelse: '' };
Object
.keys(object)
.filter(k => k in replacements)
.forEach(k => {
object[replacements[k]] = object[k];
delete object[k];
});
console.log(object);
For generating an object, you could map new objects and assign them to a single object.
const
object = { abc: "djfhdjf", xyz: "ssss", MyName: "onename", YourName: "somename", sometingelse: 'somevalue' },
replacements = { MyName: 'Pranav', YourName: 'Alex', sometingelse: '' },
result = Object.assign(...Object
.entries(object)
.map(([k, v]) => ({ [k in replacements ? replacements[k] : k]: v }))
);
console.log(result);
const obj = {
abc: 'djfhdjf',
xyz: 'ssss',
MyName: 'onename',
YourName: 'somename',
sometingelse: 'somevalue'
};
const newObj = Object.keys(obj).reduce((acc, key) => {
if (key === 'MyName') {
acc.newMyName = obj[key];
} else if (key === 'YourName') {
acc.newYourName = obj[key];
} else {
acc[key] = obj[key];
}
return acc;
}, {});
console.log('newObj = ', newObj);
Here is my approach, a bit long solution, but its on purpose so you can see how to do it simple without too much abstraction:
const someArray = {
abc:"djfhdjf",
xyz:"ssss",
MyName:"onename",
YourName:"somename",
sometingelse:'somevalue'
}
let foo = Object.keys(someArray).map(key => {
if(key === 'MyName') {
return 'Alex'
} else if(key === 'YourName') {
key = 'Pranav'
}
return key;
})
let bar = Object.entries(someArray).map((el, i) => {
el[0] = res[i];
return el;
})
let baz = r.reduce((acc, el)=>{
acc[`${el[0]}`] = el[1];
return acc;
},{})
console.log(baz);
You could use .reduce like so. It uses a similar idea that Nina proposed by using an object to hold your replacements. Here I have used the spread syntax to add the changed key to the accumulated object, along with it's associated value.
const someArray = {abc: "djfhdjf", xyz: "ssss", MyName: "onename", YourName: "somename", sometingelse: 'somevalue'},
toUse = {MyName: "Pranav", YourName: "Alex"}, // define the keys you want to change and what they should change to
res = Object.keys(someArray).reduce((acc, key) =>
({...acc, [key in toUse ? toUse[key] : key]:someArray[key]})
, {});
console.log(res);
I am running a reduce on the keys of some array starting with an empty object. The ...acc spreads out all the properties in the reduced object. ...{ [keysMap[key] || key]: obj[key] } checks if the current key is present in keysMap.If it is present,it uses that key (keysMap[key]) otherwise it just uses the keys of the existing object.(|| key).Hope that makes sense
const renameKeys = (keysMap, obj) =>
Object.keys(obj).reduce(
(acc, key) => ({
...acc,
...{ [keysMap[key] || key]: obj[key] }
}),
{}
)
const columns = renameKeys({'MyName':'Pranav','YourName':'Alex'},someArray)
i have this type of object which fetched from Redis
{
'username': 'hamet',
'username_Type': 'string',
'meta': 'object',
'meta_Type': 'object',
'meta.avatar': '/avatar.png',
'meta.avatar_Type': 'string',
'meta.active': 'false',
'meta.active_Type': 'boolean',
'meta.someArr': 'array',
'meta.someArr_Type': 'array',
'meta.someArr.0': 'object',
'meta.someArr.0_Type': 'object',
'meta.someArr.0.field': '123',
'meta.someArr.0.field_Type': 'number',
'meta.someArr.1': 'object',
'meta.someArr.1_Type': 'object',
'meta.someArr.1.field': '321',
'meta.someArr.1.field_Type': 'number'
}
all i want is convert this object to valid object like this:
{
username: 'hamet',
meta: {
avatar: '/avatar.png',
active: false,
someArr: [
{ field: 123 },
{ field: 321 }
]
}
}
once i created iterated function, but there was a problem with that. is it possible to convert with Iterated function and how?
You could create object with value types that you will use for creating new instances of different data types and then use reduce() method to build your object.
const data = {"username":"hamet","username_Type":"string","meta":"object","meta_Type":"object","meta.avatar":"/avatar.png","meta.avatar_Type":"string","meta.active":"false","meta.active_Type":"boolean","meta.someArr":"array","meta.someArr_Type":"array","meta.someArr.0":"object","meta.someArr.0_Type":"object","meta.someArr.0.field":"123","meta.someArr.0.field_Type":"number","meta.someArr.1":"object","meta.someArr.1_Type":"object","meta.someArr.1.field":"321","meta.someArr.1.field_Type":"number"}
const result = {}
const create = {'string': String,'number': Number,'boolean': Boolean,'array': Array,'object': Object}
const findType = (key, obj) => obj[key]
Object.keys(data).forEach(key => {
if (!key.includes('Type')) {
key.split('.').reduce((r, e, i, arr) => {
let type = findType(key + '_Type', data);
let value = create[data[key]] || arr[i + 1] ? new create[type] : new create[type](data[key]).valueOf()
if (data[key] == 'false') value = false
r[e] = r[e] || value;
return r[e]
}, result)
}
})
console.log(result)
Get an array of keys with Object.keys(). Filter out the _Type keys. Sort the keys to ensure that parents (shorter) keys are first, since keys` order in an object is not ensured.
Reduce the array of keys, and for each key get it's value by type. If the type is not object/array use the actual key value. Iterate the result object with Array.forEach(), until you get to the leaf. Add the key with the value.
const obj = {"meta.someArr.1.field":"321","username":"hamet","username_Type":"string","meta":"object","meta_Type":"object","meta.avatar":"/avatar.png","meta.avatar_Type":"string","meta.active":"false","meta.active_Type":"boolean","meta.someArr":"array","meta.someArr_Type":"array","meta.someArr.0":"object","meta.someArr.0_Type":"object","meta.someArr.0.field":"123","meta.someArr.0.field_Type":"number","meta.someArr.1":"object","meta.someArr.1_Type":"object","meta.someArr.1.field_Type":"number"};
const byType = {
object: Object,
array: Array
};
const result = Object.keys(obj)
.filter((k) => !k.includes('_Type')) // remove Type keys
.sort((a, b) => a.length - b.length) // ensures that shorter (parent) keys are first
.reduce((r, k) => {
const type = obj[`${k}_Type`];
const valueByType = byType[type] && byType[type]();
const value = valueByType ? valueByType : obj[k];
const keys = k.split('.');
let current = r;
keys.forEach((key, i) => {
if(!(key in current)) current[key] = value;
else current = current[key];
});
return r;
}, {});
console.log(result);
const result = {};
function apply(obj, value, key, ...keys) {
if(keys.length) {
apply(obj[key] || (obj[key] = {}), value ...keys);
} else {
obj[key] = value;
}
}
for(const [key, value] of Object.entries(yourObj))
apply(result, value, ...key.split("."));
You could use a recursive approach to generate the nested structure. I havent included a check if key is a number so that it creates an array, thats your job ;)
If you prefer functional programming:
const apply = (obj, value, ...keys) => keys.slice(1).reduce((obj, key) => obj[key] || (obj[key] = {}), obj)[keys.pop()] = value;
ECMAScript 5 has the filter() prototype for Array types, but not Object types, if I understand correctly.
How would I implement a filter() for Objects in JavaScript?
Let's say I have this object:
var foo = {
bar: "Yes"
};
And I want to write a filter() that works on Objects:
Object.prototype.filter = function(predicate) {
var result = {};
for (key in this) {
if (this.hasOwnProperty(key) && !predicate(this[key])) {
result[key] = this[key];
}
}
return result;
};
This works when I use it in the following demo, but when I add it to my site that uses jQuery 1.5 and jQuery UI 1.8.9, I get JavaScript errors in FireBug.
Object.prototype.filter = function(predicate) {
var result = {};
for (key in this) {
if (this.hasOwnProperty(key) && !predicate(this[key])) {
console.log("copying");
result[key] = this[key];
}
}
return result;
};
var foo = {
bar: "Yes",
moo: undefined
};
foo = foo.filter(function(property) {
return typeof property === "undefined";
});
document.getElementById('disp').innerHTML = JSON.stringify(foo, undefined, ' ');
console.log(foo);
#disp {
white-space: pre;
font-family: monospace
}
<div id="disp"></div>
First of all, it's considered bad practice to extend Object.prototype. Instead, provide your feature as stand-alone function, or if you really want to extend a global, provide it as utility function on Object, just like there already are Object.keys, Object.assign, Object.is, ...etc.
I provide here several solutions:
Using reduce and Object.keys
As (1), in combination with Object.assign
Using map and spread syntax instead of reduce
Using Object.entries and Object.fromEntries
1. Using reduce and Object.keys
With reduce and Object.keys to implement the desired filter (using ES6 arrow syntax):
Object.filter = (obj, predicate) =>
Object.keys(obj)
.filter( key => predicate(obj[key]) )
.reduce( (res, key) => (res[key] = obj[key], res), {} );
// Example use:
var scores = {
John: 2, Sarah: 3, Janet: 1
};
var filtered = Object.filter(scores, score => score > 1);
console.log(filtered);
Note that in the above code predicate must be an inclusion condition (contrary to the exclusion condition the OP used), so that it is in line with how Array.prototype.filter works.
2. As (1), in combination with Object.assign
In the above solution the comma operator is used in the reduce part to return the mutated res object. This could of course be written as two statements instead of one expression, but the latter is more concise. To do it without the comma operator, you could use Object.assign instead, which does return the mutated object:
Object.filter = (obj, predicate) =>
Object.keys(obj)
.filter( key => predicate(obj[key]) )
.reduce( (res, key) => Object.assign(res, { [key]: obj[key] }), {} );
// Example use:
var scores = {
John: 2, Sarah: 3, Janet: 1
};
var filtered = Object.filter(scores, score => score > 1);
console.log(filtered);
3. Using map and spread syntax instead of reduce
Here we move the Object.assign call out of the loop, so it is only made once, and pass it the individual keys as separate arguments (using the spread syntax):
Object.filter = (obj, predicate) =>
Object.assign(...Object.keys(obj)
.filter( key => predicate(obj[key]) )
.map( key => ({ [key]: obj[key] }) ) );
// Example use:
var scores = {
John: 2, Sarah: 3, Janet: 1
};
var filtered = Object.filter(scores, score => score > 1);
console.log(filtered);
4. Using Object.entries and Object.fromEntries
As the solution translates the object to an intermediate array and then converts that back to a plain object, it would be useful to make use of Object.entries (ES2017) and the opposite (i.e. create an object from an array of key/value pairs) with Object.fromEntries (ES2019).
It leads to this "one-liner" method on Object:
Object.filter = (obj, predicate) =>
Object.fromEntries(Object.entries(obj).filter(predicate));
// Example use:
var scores = {
John: 2, Sarah: 3, Janet: 1
};
var filtered = Object.filter(scores, ([name, score]) => score > 1);
console.log(filtered);
The predicate function gets a key/value pair as argument here, which is a bit different, but allows for more possibilities in the predicate function's logic.
Never ever extend Object.prototype.
Horrible things will happen to your code. Things will break. You're extending all object types, including object literals.
Here's a quick example you can try:
// Extend Object.prototype
Object.prototype.extended = "I'm everywhere!";
// See the result
alert( {}.extended ); // "I'm everywhere!"
alert( [].extended ); // "I'm everywhere!"
alert( new Date().extended ); // "I'm everywhere!"
alert( 3..extended ); // "I'm everywhere!"
alert( true.extended ); // "I'm everywhere!"
alert( "here?".extended ); // "I'm everywhere!"
Instead create a function that you pass the object.
Object.filter = function( obj, predicate) {
let result = {}, key;
for (key in obj) {
if (obj.hasOwnProperty(key) && !predicate(obj[key])) {
result[key] = obj[key];
}
}
return result;
};
Solution in Vanilla JS from year 2020.
let romNumbers={'I':1,'V':5,'X':10,'L':50,'C':100,'D':500,'M':1000}
You can filter romNumbers object by key:
const filteredByKey = Object.fromEntries(
Object.entries(romNumbers).filter(([key, value]) => key === 'I') )
// filteredByKey = {I: 1}
Or filter romNumbers object by value:
const filteredByValue = Object.fromEntries(
Object.entries(romNumbers).filter(([key, value]) => value === 5) )
// filteredByValue = {V: 5}
If you're willing to use underscore or lodash, you can use pick (or its opposite, omit).
Examples from underscore's docs:
_.pick({name: 'moe', age: 50, userid: 'moe1'}, 'name', 'age');
// {name: 'moe', age: 50}
Or with a callback (for lodash, use pickBy):
_.pick({name: 'moe', age: 50, userid: 'moe1'}, function(value, key, object) {
return _.isNumber(value);
});
// {age: 50}
ES6 approach...
Imagine you have this object below:
const developers = {
1: {
id: 1,
name: "Brendan",
family: "Eich"
},
2: {
id: 2,
name: "John",
family: "Resig"
},
3: {
id: 3,
name: "Alireza",
family: "Dezfoolian"
}
};
Create a function:
const filterObject = (obj, filter, filterValue) =>
Object.keys(obj).reduce((acc, val) =>
(obj[val][filter] === filterValue ? acc : {
...acc,
[val]: obj[val]
}
), {});
And call it:
filterObject(developers, "name", "Alireza");
and will return:
{
1: {
id: 1,
name: "Brendan",
family: "Eich"
},
2: {
id: 2,
name: "John",
family: "Resig"
}
}
As patrick already stated this is a bad idea, as it will almost certainly break any 3rd party code you could ever wish to use.
All libraries like jquery or prototype will break if you extend Object.prototype, the reason being that lazy iteration over objects (without hasOwnProperty checks) will break since the functions you add will be part of the iteration.
Given
object = {firstname: 'abd', lastname:'tm', age:16, school:'insat'};
keys = ['firstname', 'age'];
then :
keys.reduce((result, key) => ({ ...result, [key]: object[key] }), {});
// {firstname:'abd', age: 16}
// Helper
function filter(object, ...keys) {
return keys.reduce((result, key) => ({ ...result, [key]: object[key] }), {});
};
//Example
const person = {firstname: 'abd', lastname:'tm', age:16, school:'insat'};
// Expected to pick only firstname and age keys
console.log(
filter(person, 'firstname', 'age')
)
Plain ES6:
var foo = {
bar: "Yes"
};
const res = Object.keys(foo).filter(i => foo[i] === 'Yes')
console.log(res)
// ["bar"]
How about:
function filterObj(keys, obj) {
const newObj = {};
for (let key in obj) {
if (keys.includes(key)) {
newObj[key] = obj[key];
}
}
return newObj;
}
Or...
function filterObj(keys, obj) {
const newObj = {};
Object.keys(obj).forEach(key => {
if (keys.includes(key)) {
newObj[key] = obj[key];
}
});
return newObj;
}
I have created an Object.filter() which does not only filter by a function, but also accepts an array of keys to include. The optional third parameter will allow you to invert the filter.
Given:
var foo = {
x: 1,
y: 0,
z: -1,
a: 'Hello',
b: 'World'
}
Array:
Object.filter(foo, ['z', 'a', 'b'], true);
Function:
Object.filter(foo, function (key, value) {
return Ext.isString(value);
});
Code
Disclaimer: I chose to use Ext JS core for brevity. Did not feel it was necessary to write type checkers for object types as it was not part of the question.
// Helper function
function print(obj) {
document.getElementById('disp').innerHTML += JSON.stringify(obj, undefined, ' ') + '<br />';
console.log(obj);
}
Object.filter = function (obj, ignore, invert) {
let result = {}; // Returns a filtered copy of the original list
if (ignore === undefined) {
return obj;
}
invert = invert || false;
let not = function(condition, yes) { return yes ? !condition : condition; };
let isArray = Ext.isArray(ignore);
for (var key in obj) {
if (obj.hasOwnProperty(key) &&
!(isArray && not(!Ext.Array.contains(ignore, key), invert)) &&
!(!isArray && not(!ignore.call(undefined, key, obj[key]), invert))) {
result[key] = obj[key];
}
}
return result;
};
let foo = {
x: 1,
y: 0,
z: -1,
a: 'Hello',
b: 'World'
};
print(Object.filter(foo, ['z', 'a', 'b'], true));
print(Object.filter(foo, (key, value) => Ext.isString(value)));
#disp {
white-space: pre;
font-family: monospace
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/extjs/4.2.1/builds/ext-core.min.js"></script>
<div id="disp"></div>
My opinionated solution:
function objFilter(obj, filter, nonstrict){
r = {}
if (!filter) return {}
if (typeof filter == 'string') return {[filter]: obj[filter]}
for (p in obj) {
if (typeof filter == 'object' && nonstrict && obj[p] == filter[p]) r[p] = obj[p]
else if (typeof filter == 'object' && !nonstrict && obj[p] === filter[p]) r[p] = obj[p]
else if (typeof filter == 'function'){ if (filter(obj[p],p,obj)) r[p] = obj[p]}
else if (filter.length && filter.includes(p)) r[p] = obj[p]
}
return r
}
Test cases:
obj = {a:1, b:2, c:3}
objFilter(obj, 'a') // returns: {a: 1}
objFilter(obj, ['a','b']) // returns: {a: 1, b: 2}
objFilter(obj, {a:1}) // returns: {a: 1}
objFilter(obj, {'a':'1'}, true) // returns: {a: 1}
objFilter(obj, (v,k,o) => v%2===1) // returns: {a: 1, c: 3}
https://gist.github.com/bernardoadc/872d5a174108823159d845cc5baba337
var foo = {
bar: "Yes",
pipe: "No"
};
const ret = Object.entries(foo).filter(([key, value])=> value === 'Yes');
https://masteringjs.io/tutorials/fundamentals/filter-object
If you have Symbol properties in your object, that should be filtered too, you can not use: Object.keys Object.entries Object.fromEntries, ... because:
Symbol keys are not enumerable !
You could use Reflect.ownKeys and filter keys in reduce
Reflect.ownKeys(o).reduce((a, k) => allow.includes(k) && {...a, [k]: o[k]} || a, {});
(Open DevTools for log output - Symbols are not logged on Stackoverflow UI)
const bKey = Symbol('b_k');
const o = {
a: 1,
[bKey]: 'b',
c: [1, 3],
[Symbol.for('d')]: 'd'
};
const allow = ['a', bKey, Symbol.for('d')];
const z1 = Reflect.ownKeys(o).reduce((a, k) => allow.includes(k) && {...a, [k]: o[k]} || a, {});
console.log(z1); // {a: 1, Symbol(b_k): "b", Symbol(d): "d"}
console.log(bKey in z1) // true
console.log(Symbol.for('d') in z1) // true
This is equal to this
const z2 = Reflect.ownKeys(o).reduce((a, k) => allow.includes(k) && Object.assign(a, {[k]: o[k]}) || a, {});
const z3 = Reflect.ownKeys(o).reduce((a, k) => allow.includes(k) && Object.defineProperty(a, k, {value: o[k]}) || a, {});
console.log(z2); // {a: 1, Symbol(b_k): "b", Symbol(d): "d"}
console.log(z3); // {a: 1, Symbol(b_k): "b", Symbol(d): "d"}
Wrapped in a filter() function, an optional target object could be passed
const filter = (o, allow, t = {}) => Reflect.ownKeys(o).reduce(
(a, k) => allow.includes(k) && {...a, [k]: o[k]} || a,
t
);
console.log(filter(o, allow)); // {a: 1, Symbol(b_k): "b", Symbol(d): "d"}
console.log(filter(o, allow, {e: 'e'})); // {a: 1, e: "e", Symbol(b_k): "b", Symbol(d): "d"}
You could also do something like this where you are filtering on the entries to find the key provided and return the value
let func = function(items){
let val
Object.entries(this.items).map(k => {
if(k[0]===kind){
val = k[1]
}
})
return val
}
If you wish to mutate the same object rather than create a new one.
The following example will delete all 0 or empty values:
const sev = { a: 1, b: 0, c: 3 };
const deleteKeysBy = (obj, predicate) =>
Object.keys(obj)
.forEach( (key) => {
if (predicate(obj[key])) {
delete(obj[key]);
}
});
deleteKeysBy(sev, val => !val);
Like everyone said, do not screw around with prototype. Instead, simply write a function to do so. Here is my version with lodash:
import each from 'lodash/each';
import get from 'lodash/get';
const myFilteredResults = results => {
const filteredResults = [];
each(results, obj => {
// filter by whatever logic you want.
// sample example
const someBoolean = get(obj, 'some_boolean', '');
if (someBoolean) {
filteredResults.push(obj);
}
});
return filteredResults;
};
If you don't need the original object, this is a simple, very boring answer that doesn't waste memory:
const obj = {'a': 'want this', 'b': 'want this too', 'x': 'remove this'}
const keep = new Set(['a', 'b', 'c'])
function filterObject(obj, keep) {
Object.keys(obj).forEach(key => {
if (!keep.has(key)) {
delete obj[key]
}
})
}
If you're only filtering a small number of objects, and your objects don't have many keys, you might not want to bother with constructing a Set, in which case use array.includes instead of set.has.
I just wanted to add the way that I do it because it saves me creating extra functions, I think is cleaner and I didn't see this answer:
let object = {a: 1, b: 2, c: 3};
[object].map(({a,c}) => ({a,c}))[0]; // {a:1, c:2}
The cool thing is that also works on arrays of objects:
let object2 = {a: 4, b: 5, c: 6, d: 7};
[object, object2].map(({a,b,c,d}) => ({a,c})); //[{"a":1,"c":3},{"a":4,"c":6}]
[object, object2].map(({a,d}) => ({a,d})); //[{"a":1,"d":undefined},{"a":4,"d":7}]
In these cases I use the jquery $.map, which can handle objects. As mentioned on other answers, it's not a good practice to change native prototypes (https://developer.mozilla.org/en-US/docs/Web/JavaScript/Inheritance_and_the_prototype_chain#Bad_practice_Extension_of_native_prototypes)
Below is an example of filtering just by checking some property of your object. It returns the own object if your condition is true or returns undefined if not. The undefined property will make that record disappear from your object list;
$.map(yourObject, (el, index)=>{
return el.yourProperty ? el : undefined;
});