I am trying to animate the background of an element from it's current position when the user clicks a button. I am able to do this on the first click but the subsequent clicks fail.
Here's my code...
var testme;
$(document).ready(function(){
$(".navleft").live("click", function() {
testme = parseInt($(this).css("background-position").replace("% 0%", "").replace("px 0%", ""));
$(this).parent().animate({backgroundPosition: (testme + 297) + "px"}, 500);
$(this).parent().find("p").text(testme);
});
});
EDIT:
$(".navleft").live("click", function() {
$(this).parent().animate({backgroundPosition: "+=297"}, 500);
});
As suggested below, this works great unless you're using IE where it resets back to 0 at each click then animates again.
Here's a link to what I mean... http://jsfiddle.net/TdaSV/
Solution (as a result of being pushed in the right direction):
$(".navleft").live("click", function() {
$(this).parent().animate({'background-position-x': '+=297'}, 500);
});
You should first stop the previous animation and then start a new one:
$(this).parent().stop(true, true).animate({backgroundPosition:...
also if you need to add 297 pixels to the current background position, you don't need to read the current position, following shoudl work:
$(this).parent().animate({backgroundPosition: "+=297"}, 500);
see more examples in jquery website.
Related
I have a jQuery simple slider it has 15 picture each five show in a slide. I have a previous button and next button.
Each next click generate a left movement by 855px with a slider animation.
Each previous click generate a right movement by 855px with a slider animation.
This is my jQuery code :
$(document).ready(function(){
$(".prev_button").click(function(){
$("ul.slider").animate({
left: "+=855"
}, 3000, function(){
$("ul.slider").css('left', '0');
li_no = 0;
$("ul.slider").find("li").each(function(){
li_no = li_no + 1;
});
slide_after_this = li_no - 6;
$('ul.slider li:gt('+slide_after_this+')').prependTo('ul.slider'); // << line changed
});
});
$(".next_button").click(function(){
//alert($("ul.slider").css("right"));
$("ul.slider").animate({
right: "+=855"
}, 3000, function(){
//alert($("ul.slider").css("right"));
$("ul.slider").css('right', '0');
$('ul.slider li:not(:nth-child(n+6))').appendTo('ul.slider');
});
});
});
Now I have two problems :
First one is with the previous button (left arrow) When I click it the animation shows and the elements changed but they do not wrapped with each other (I mean does not show the last elements immidiatly before the first element). I can not find the reason of this.
Second problem is with both right and left arrows it is like following :
If I click just the right arrow the slider working fine it animates and change the elements but If I click the both button in order (I mean right then left or left then right ) the elements change but the animation does not show. but I check if the routine go inside the animate function by some alerts and it is going inside but does not animate on the screen .
This is a link that may help you:
http://jsfiddle.net/mpx83tpv/18/
you are really close try overflow:hidden for .slider_container
div.slider_container
{
height:380px;
width:855px;
margin-left:auto;
margin-right:auto;
overflow:hidden;
}
edit js:
also use below code as you are using both right and left in the end the slider has both of them one of them is always zero.
$(document).ready(function(){
$(".prev_button").click(function(){
$("ul.slider").animate({
left: "+=855"
}, 3000);
});
$(".next_button").click(function(){
//alert($("ul.slider").css("right"));
$("ul.slider").animate({
left: "-=855"
}, 3000);
});
});
if you want a infinite scrolling you need to use right and left in this case replace your $("ul.slider").css('right', '0'); line to $("ul.slider").css('right', ''); do same for left as well, as you need the remove them.
for adding the next visible div implement you logic before the animation as you callbacks do it after the animation.
the tricky part would be the prev button for this after calculation of the div count you also need the set new left without animation and then call left move animation.
hope these make sense.
I want to achieve some kind of smooth scrolling, so I made this script:
$('a').click(function(){
var sclink = $(this).attr('href');
$('.menu').animate({
scrollTop: $(sclink).offset().top
}, 500);
return false;
});
The problem? When I click on the 'a' the offset.top() value changes in another weird value and toggle between them? Why does this happen and how do I resolve it?
http://jsfiddle.net/StartStep/9SDLw/2947/
I think the problem is with the scroll.top() that gets the value in another way...
jsfiddle.net/9SDLw/2950/
$('a').click(function(){
var sclink = $(this).attr('href');
$('.menu').animate({
scrollTop: $(sclink).position().top
}, 500);
logit('Anchor: '+sclink+'; Offset top value: <b>'+$(sclink).offset().top+'</b>')
return false;
});
Use position instead of offset.
The reason is offset is relative to the viewport, as such it looks like you've scrolled too far, but this is because the top of your viewport area is being obscured by your layout, so offset is actually not what you want, instead, position is.
You should also add a reference to stop before calling animate to ensure if a user clicks in quick succession the behaviour is as expected (the animation queue is essentially flushed)
With that in mind your HTML also needs some work- the clickable link hasnt got closing tags for example.
Change your scrolling code to:
$('.menu').stop(true,true).animate({
scrollTop: $(sclink).position().top
}, 500);
Demo Fiddle
I've re-created a simple version of what I'm trying to do here (jsFiddle)
The header should stay where it is, and as you scroll down, when you click the header div it should scroll back up to the top, which it does. But if you focus on the input, or click the "logo", the scroll should stay where it is.
With the first method I've tried is by using jQuery's .css and setting the input/logo's z-index as higher than the header, then getting the current scroll and keeping it at that position.
This sort of works, but once you click the input or logo, the header scroll no longer works.
I've also tried changing the logo/input jQuery to .animate with a slow speed, and it stays static for a couple seconds and then scrolls to the top even though I've not set it to do so. Here is the second example - jsFiddle
Doing it with the second example however doesn't stop the other function from working.
Is there any reason for this behaviour that I'm missing?
You can prevent the click event from propagating to the header.
$("#logo, #input").click(function(e) {
e.stopPropagation();
});
Check out this interesting article about event order, all you have to do is stop propagation. Here your modified Fiddle
$("#logo, #input").click(function(e) {
e.stopPropagation();
var y = window.scrollY;
$('html').animate({
scrollTop: y
}, 'slow');
$('body').animate({
scrollTop: y
}, 'slow');
});
All you need to do is stop the propegation of the event. To do this you return false from your click function.
$("#logo, #input").click(function() {
return false; // Add this line
});
Here is your fiddle updated: http://jsfiddle.net/BRnvT/
So I previously asked a question about how to create a banner like the one shown here and I got a really good answer to start me off. I have been working on it since and I'm having a lot of problems getting the animation to slide back to it's original position.
Here is my animation: http://jsfiddle.net/43nCF/ (don't click the green block first)
Issue: After the first time you toggle a block, clicking another block will not move it to the left.
I also have some other minor issues which I would be grateful if someone helped me with.
How do I get the width and the moving of the blocks to animate simultaneously like in the banner animation I am trying to replicate?
How do I get the block to slide back to the original position instead of just kind of 'transporting' there?
I am only beginner at jQuery so any help would be amazing.Thanks.
As for the positioning problem: you need to drop the left declaration in your second function.
Regarding making the animation act simultanous: animate both the right and the width property for each element, in one call:
function() {
var position = $.data(this, 'position');
var ind = $(this).index();
//moves image back to original position
$('#container div').each(
function() {
$(this).animate({
right: "",
width: 100
});
});
});
Working example here.
I see you have a response.
In case this version is of any help to you:
http://jsfiddle.net/vCbcz/
Instead of altering the divs other than the one being affected, I wrapped them all in a #slider div and adjusted that one's left margin to push it to the left.
$('#slider').animate({
marginLeft: '-' + ind * 105 + 'px'
});
and back
$('#slider').animate({
marginLeft: 0 + 'px'
});
There is a much easier way altogether of doing this. By using jQuery's scrollTo plugin, this can be done in a mere few lines of code, without using indices, calculations, or anything of that nature.
Live Demo http://jsfiddle.net/Jaybles/WEzny/
For a site I'm making for myself and a friend, I have a div container/wrapper with 2 other divs within it: one occupies the left half and has a black background and the other occupies the right with a white background. Essentially, this lets me get a split colored background. Each div holds half of a logo. Here's the page, temporarily hosted so you guys can see it.
http://djsbydesign.com/tempsite/index.htm
At any rate, I'd like to have links on the left and right hand sides of the page that, on click, cause their respective divs to expand from 50% to 100%. I have a few ideas, but am not sure entirely how to go about doing this (I'm rather new to javascript). The first would be to have the expanding div's z-index set to something higher than the non-expanding one, and then have it expand (somehow), and the other is to have the expanding div expand to 100% while the other shrinks to 0% at an equal rate.
The bottom line is, I have no idea how to go about doing this. I don't mind using mootools or jQuery, for the record.
The following seems to work:
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
});
Albeit I'm not sure how you'd plan to bring back the the 'other' div.
JS Fiddle demo.
Edited to add a button (via jQuery) that allows both divs to be reverted to original dimensions:
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
});
$('.show').live('click',
function(){
$('#left-bg').animate(
{
'width': '50%'
},600);
$('#right-bg').animate(
{
'width': '50%'
},600);
$(this).remove();
});
Updated JS Fiddle.
Edited to address the question left by OP in the comments:
is there a way to have a page redirect after the animation completes?
Yep, just add the line window.location.href = "http://path.to.url.com/";
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
window.location.href = "http://www.google.com/" // <-- this line redirects.
});
$('.show').live('click',
function(){
$('#left-bg').animate(
{
'width': '50%'
},600);
$('#right-bg').animate(
{
'width': '50%'
},600);
$(this).remove();
});
Updated JS Fiddle.
Edited in response to bug report (in comments):
The one other bug (easy fix) is that any time you click on either of the divs, it creates a new button. So say you clicked on the left half, and it expanded and filled the page, etc., and then you clicked on it again (it being anywhere on the page now). It would attempt to add a second button.
To prevent a second button being added to the div just add an if:
$('#left-bg, #right-bg').click(
function(){
if (!$('.show').length) {
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
window.location.href = "http://www.google.com/" // <-- this line redirects.
}
});
Which, will only append a button, or indeed animate the divs, so long as the $('.show') selector returns no matches.
However if you're also redirecting to another page by clicking the button it shouldn't be an issue anyway, since none of the jQuery on the original page will exectute/be able to access the page to which the user is redirected (unless it's a page on your own domain, and you've explicitly chosen to add the same button).
If you give absolute positions to your div's such that - 1st is positioned at top left corner and other is positioned at top right corner. And then in click event you can change the position of the other top corner of the div to be expanded.
You can use jquery to do this easily. Check jquery documentation for setting css.
Looks like you've got jQuery included, so use that! It's totes the easiest library to do simple animations with.
Here's an example click function that will slide the right background to be 100% like you said:
$('a#link').click(function(e) {
e.preventDefault();
$('#left-bg').animate({ width : '0%' }, 'slow');
$('#right-bg').animate({ width : '100%' }, 'slow');
});
Obviously to go in the other direction you'd switch the width values in the object passed to the animate functions.
If you're not familiar with the animate function, check the docs, but basically you just pass CSS rules in a key : value object to it, and it'll change the CSS values over time - animating it!
Hope this helps!