So I previously asked a question about how to create a banner like the one shown here and I got a really good answer to start me off. I have been working on it since and I'm having a lot of problems getting the animation to slide back to it's original position.
Here is my animation: http://jsfiddle.net/43nCF/ (don't click the green block first)
Issue: After the first time you toggle a block, clicking another block will not move it to the left.
I also have some other minor issues which I would be grateful if someone helped me with.
How do I get the width and the moving of the blocks to animate simultaneously like in the banner animation I am trying to replicate?
How do I get the block to slide back to the original position instead of just kind of 'transporting' there?
I am only beginner at jQuery so any help would be amazing.Thanks.
As for the positioning problem: you need to drop the left declaration in your second function.
Regarding making the animation act simultanous: animate both the right and the width property for each element, in one call:
function() {
var position = $.data(this, 'position');
var ind = $(this).index();
//moves image back to original position
$('#container div').each(
function() {
$(this).animate({
right: "",
width: 100
});
});
});
Working example here.
I see you have a response.
In case this version is of any help to you:
http://jsfiddle.net/vCbcz/
Instead of altering the divs other than the one being affected, I wrapped them all in a #slider div and adjusted that one's left margin to push it to the left.
$('#slider').animate({
marginLeft: '-' + ind * 105 + 'px'
});
and back
$('#slider').animate({
marginLeft: 0 + 'px'
});
There is a much easier way altogether of doing this. By using jQuery's scrollTo plugin, this can be done in a mere few lines of code, without using indices, calculations, or anything of that nature.
Live Demo http://jsfiddle.net/Jaybles/WEzny/
Related
I'm trying to make an image carousel/slider that automatically scrolls smoothly and loops using jQuery. Here's the function I'm using:
function spinCarousel() {
$("ul li:first-child").animate({ marginLeft: -200 }, 3000, 'linear', function () {
$("ul li:first-child").appendTo('ul');
$("ul li:last-child").css('margin-Left', 0);
spinCarousel();
});
}
And here's an illustration: https://jsfiddle.net/T_Recks/aa43n7g0/
I tried adding it to a local development site (replacing the text and colored backgrounds with images) and it seems to work nicely. However, I'd like to make a version that scrolls right instead of left, but haven't been able to figure it out. I've tried changing ".append" to ".prepend" and playing with the margin changes, but no luck so far.
Any suggestions?
I forked and retooled your JSFiddle to make it scroll from left to right. Check it out here: https://jsfiddle.net/1jw8xpqe/
Had to change a few things to get it working. First, the list is parsed to reverse the order of the slides and shift a couple of them so the leftmost one is "Item #1" when the slider initializes:
// reverse items
var list = $('ul');
var listItems = list.children('li');
list.append(listItems.get().reverse());
// rearrange last two items so first slide starts on left
list.prepend($('ul li:last-child').prev('li').andSelf());
Then a few CSS/JS tweaks: The slide animates the first li from -200px (defined in the CSS) to 0, and after each cycle, prepends the last item of the ul to the start at -200px. Hope this helps!
I have a simple blog, and each blog post has a number of images ranging from 1 to 10. If you click on any of the images in the post, it should scroll you down to the next post. I thought something as simple as this would've worked:
$('.each-journal-entry .slider-container .journal-slider .each-slide img').on('click', function () {
var $this = $(this);
$('.journal-container').animate({
scrollTop: $this.closest('.each-journal-entry').next().offset().top
}, 500);
});
But when I click another image, except for the first one, it just scrolls to an odd position.
I managed to achieve this with some help, and you can see the output here: http://jsfiddle.net/w7rtcmp0/3/ which works great, but the difference for me is that my content is in a scrollable div (hence .journal-container and not html, body.
Any ideas why I am having this issue? I have created a jsFiddle with the scrollable div, and if you click an image further down... it replicates this issue... so hopefully this helps.
http://jsfiddle.net/w7rtcmp0/5/
Thanks.
jQuery adjusts offset().top() based on the current scroll position.
Using JavaScript's offsetTop property should fix the problem:
scrollTop: $this.closest('.each-journal-entry').next()[0].offsetTop
Fiddle: http://jsfiddle.net/m7cm5oL6/
So I think you were trying to use the wrong height.
Here I set a variable of height and set it to the height of the current journal/blog object. This allows me to scroll my height all the way down to the next available blog object.
http://jsfiddle.net/w7rtcmp0/24/
$('.each-journal-entry .slider-container .journal-slider .each-slide img').on('click', function() {
$this = $(this);
var height = $this.closest('.each-journal-entry').height();
$('.scrollable').animate({
scrollTop: height
}, 2000);
});
You may want to look at Ariel Flesler's jQuery scrollTo plugin, I had the same issue and using this saved me hours of debugging.
I'm trying to add in previous and next buttons to my content slider but seem to be having problems, what I would really like to do is move the $slideCtn left or right by the width slideWidth each time the previous or next button is clicked but i'm unsure how to increment each click by the value of slideWidth. I've tried ++ and -- etc but with no results, would anyone be able to show me the best way to do something like this? Also any other advice very welcome!
Or should I create a global index variable that gets set at 0, then as the pagination x's are clicked or the prev/next arrows are clicked update this global variable?
JS Snippet
//Add previous + next arrows
$dirArrows.on('click', function(e){
var arrDir = $(this).data('dir');
$slideCtn.css('left', ( arrDir === 'prev' ) ? -(slideWidth) : +(slideWidth));
e.preventDefault();
});
JS Fiddle
http://jsfiddle.net/SG5ad/10/
At the moment, you're telling it to move to an absolute position - either -200px or +200px (never 0px, 400px, 600px, etc).
You'll need to take into account its current position as well as how much you want to adjust it: http://jsfiddle.net/SG5ad/12/
var arrDir = $(this).data('dir')
iLeft = parseInt( $slideCtn.css('left') );
$slideCtn.css('left', ( arrDir === 'prev' ) ? iLeft - slideWidth : iLeft + slideWidth);
A bug you'll want to fix as well is that the Next/Prev buttons do nothing until you've already jumped to a specific slide with the "x" navigation.
As an entirely separate issue, about 6 months ago I wrote something like this as part of a project at work (it had a few more bells and whistles, but nothing drastically different), and there's one important thing I'd say is worth changing.
In order to go from slide a to slide d at the moment, you animate slides a,b,c and d, which means that
a) 4 slides are animating instead of 1 (plus all their child elements)
b) you have to pass through slides b and c even though they're not relevant
I'd have a look at changing the base position of all your slides to be stacked on top of each other using z-index, then simply animating the top slide off to one side to reveal the one underneath it. It requires a bit of code to track which slides are where ($.data() may help there) but gives you a much more performant slider at the end of it.
You've gotta do it with .animate()
$dirArrows.on('click', function(e){
var arrDir = $(this).data('dir');
if (arrdir == left){
$slideCtn.animate({
left: "+=250"
});
}
});
See the following fiddle:
[edit: updated fiddle => http://jsfiddle.net/NYZf8/5/ ]
http://jsfiddle.net/NYZf8/1/ (view in different screen sizes, so that ideally the image fits inside the %-width layouted div)
The image should start the animation from the position where it correctly appears after the animation is done.
I don't understand why the first call to setMargin() sets a negative margin even though the logged height for container div and img are the very same ones, that after the jqueryui show() call set the image where I would want it (from the start on). My guess is that somehow the image height is 0/undefined after all, even though it logs fine :?
js:
console.log('img: ' + $('img').height());
console.log('div: ' + $('div').height());
$('img').show('blind', 1500, setMargin);
function setMargin() {
var marginTop =
( $('img').closest('div').height() - $('img').height() ) / 2;
console.log('marginTop: ' + marginTop);
$('img').css('marginTop', marginTop + 'px');
}
setMargin();
Interesting problem...after playing around with your code for a while (latest update), I saw that the blind animation was not actually firing in my browser (I'm testing on Chrome, and maybe it was firing but I wasn't seeing it as the image was never hidden in the first place), so I tried moving it inside the binded load function:
$('img').bind('load', function() {
...
$(this).show('blind', 500);
});
Now that it was animating, it seemed to 'snap' or 'jump' after the animation was complete, and also seemed to appear with an incorrect margin. This smacks of jQuery not being able to correctly calculate the dimensions of something that hadn't been displayed on the screen yet. On top of that, blind seems to need more explicit dimensions to operate correctly. So therein lies the problem: how to calculate elements' rendered dimensions before they've actually appeared on the screen?
One way to do this is to fade in the element whose dimensions you're trying to calculate very slightly - not enough to see yet - do some calculations, then hide it again and prep it for the appearance animation. You can achieve this with jQuery using the fadeTo function:
$('img').bind('load', function() {
$(this).fadeTo(0, 0.01, function() {
// do calculations...
}
}
You would need to work out dimensions, apply them with the css() function, blind the image in and then reset the image styles back to their original states, all thanks to a blind animation that needs these dimensions explicitly. I would also recommend using classes in the css to help you manage things a little better. Here's a detailed working example: jsfiddle working example
Not the most elegant way of doing things, but it's a start. There are a lot more easier ways to achieve seemingly better results, and I guess I just want to know why you're looking to do image blinds and explicit alignment this way? It's just a lot more challenging achieving it with the code you used...anyways, hope this helps! :)
For a site I'm making for myself and a friend, I have a div container/wrapper with 2 other divs within it: one occupies the left half and has a black background and the other occupies the right with a white background. Essentially, this lets me get a split colored background. Each div holds half of a logo. Here's the page, temporarily hosted so you guys can see it.
http://djsbydesign.com/tempsite/index.htm
At any rate, I'd like to have links on the left and right hand sides of the page that, on click, cause their respective divs to expand from 50% to 100%. I have a few ideas, but am not sure entirely how to go about doing this (I'm rather new to javascript). The first would be to have the expanding div's z-index set to something higher than the non-expanding one, and then have it expand (somehow), and the other is to have the expanding div expand to 100% while the other shrinks to 0% at an equal rate.
The bottom line is, I have no idea how to go about doing this. I don't mind using mootools or jQuery, for the record.
The following seems to work:
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
});
Albeit I'm not sure how you'd plan to bring back the the 'other' div.
JS Fiddle demo.
Edited to add a button (via jQuery) that allows both divs to be reverted to original dimensions:
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
});
$('.show').live('click',
function(){
$('#left-bg').animate(
{
'width': '50%'
},600);
$('#right-bg').animate(
{
'width': '50%'
},600);
$(this).remove();
});
Updated JS Fiddle.
Edited to address the question left by OP in the comments:
is there a way to have a page redirect after the animation completes?
Yep, just add the line window.location.href = "http://path.to.url.com/";
$('#left-bg, #right-bg').click(
function(){
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
window.location.href = "http://www.google.com/" // <-- this line redirects.
});
$('.show').live('click',
function(){
$('#left-bg').animate(
{
'width': '50%'
},600);
$('#right-bg').animate(
{
'width': '50%'
},600);
$(this).remove();
});
Updated JS Fiddle.
Edited in response to bug report (in comments):
The one other bug (easy fix) is that any time you click on either of the divs, it creates a new button. So say you clicked on the left half, and it expanded and filled the page, etc., and then you clicked on it again (it being anywhere on the page now). It would attempt to add a second button.
To prevent a second button being added to the div just add an if:
$('#left-bg, #right-bg').click(
function(){
if (!$('.show').length) {
$(this).animate({'width': '100%'},600).siblings().animate({'width':'0'},600);
$('<button class="show">Show all</button>')
.appendTo('#wrapper');
window.location.href = "http://www.google.com/" // <-- this line redirects.
}
});
Which, will only append a button, or indeed animate the divs, so long as the $('.show') selector returns no matches.
However if you're also redirecting to another page by clicking the button it shouldn't be an issue anyway, since none of the jQuery on the original page will exectute/be able to access the page to which the user is redirected (unless it's a page on your own domain, and you've explicitly chosen to add the same button).
If you give absolute positions to your div's such that - 1st is positioned at top left corner and other is positioned at top right corner. And then in click event you can change the position of the other top corner of the div to be expanded.
You can use jquery to do this easily. Check jquery documentation for setting css.
Looks like you've got jQuery included, so use that! It's totes the easiest library to do simple animations with.
Here's an example click function that will slide the right background to be 100% like you said:
$('a#link').click(function(e) {
e.preventDefault();
$('#left-bg').animate({ width : '0%' }, 'slow');
$('#right-bg').animate({ width : '100%' }, 'slow');
});
Obviously to go in the other direction you'd switch the width values in the object passed to the animate functions.
If you're not familiar with the animate function, check the docs, but basically you just pass CSS rules in a key : value object to it, and it'll change the CSS values over time - animating it!
Hope this helps!